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Adding 0X80 + 0X80
Imply bit with constant 1 or 0 in SQL Serverhow many color combinations in a 24 bit imageHow to get the value of a bit at a certain position from a byte?Compiling C++11 with g++C Programming - Bitwise operators and knowing when to utilizeBitwise Logic in CHex transparency in colorsPrecisely when are ARM's condition flags cleared/modified?i8086 assembly: CF vs OF and SFbinary check for an operation
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As a preparation for my exam in Microcontrollers, I have this question:
How are the condition bits set when the Byte operation 0x80 + 0x80 is executed?
I understand how to add those 2, but I get 256 and I don't know which condition bits are set in this case.
hex conditional-statements bit flags
asked Mar 24 at 12:33
Alina KrichevskyAlina Krichevsky
61
add a comment |
As a preparation for my exam in Microcontrollers, I have this question:
How are the condition bits set when the Byte operation 0x80 + 0x80 is executed?
I understand how to add those 2, but I get 256 and I don't know which condition bits are set in this case.
hex conditional-statements bit flags
asked Mar 24 at 12:33
Alina KrichevskyAlina Krichevsky
61
add a comment |
As a preparation for my exam in Microcontrollers, I have this question:
How are the condition bits set when the Byte operation 0x80 + 0x80 is executed?
I understand how to add those 2, but I get 256 and I don't know which condition bits are set in this case.
hex conditional-statements bit flags
asked Mar 24 at 12:33
Alina KrichevskyAlina Krichevsky
61
As a preparation for my exam in Microcontrollers, I have this question:
How are the condition bits set when the Byte operation 0x80 + 0x80 is executed?
I understand how to add those 2, but I get 256 and I don't know which condition bits are set in this case.
hex conditional-statements bit flags
hex conditional-statements bit flags
asked Mar 24 at 12:33
Alina KrichevskyAlina Krichevsky
61
asked Mar 24 at 12:33
Alina KrichevskyAlina Krichevsky
61
asked Mar 24 at 12:33
Alina KrichevskyAlina Krichevsky
61
asked Mar 24 at 12:33
Alina KrichevskyAlina Krichevsky
61
asked Mar 24 at 12:33
Alina KrichevskyAlina Krichevsky
61
61
add a comment |
add a comment |
1 Answer
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First, the highest value one byte can hold is 255 (0xFF), so I do not think the result would be 256, but rather, overflow would cause the resulting value to be 0 (0x00).
Secondly, the condition bits would depend on your processor, but going by some ARM notes, I might reasonably expect:
Z: Zero
The Z flag is set if the result of the flag-setting instruction is zero.
C: Carry (or Unsigned Overflow)
The C flag is set if the result of an unsigned operation overflows the 32-bit result register. This bit can be used to implement 64-bit unsigned arithmetic, for example.
answered Mar 24 at 12:40
abelenkyabelenky
48.3k2184137
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
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oldest
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active
oldest
votes
First, the highest value one byte can hold is 255 (0xFF), so I do not think the result would be 256, but rather, overflow would cause the resulting value to be 0 (0x00).
Secondly, the condition bits would depend on your processor, but going by some ARM notes, I might reasonably expect:
Z: Zero
The Z flag is set if the result of the flag-setting instruction is zero.
C: Carry (or Unsigned Overflow)
The C flag is set if the result of an unsigned operation overflows the 32-bit result register. This bit can be used to implement 64-bit unsigned arithmetic, for example.
answered Mar 24 at 12:40
abelenkyabelenky
48.3k2184137
add a comment |
First, the highest value one byte can hold is 255 (0xFF), so I do not think the result would be 256, but rather, overflow would cause the resulting value to be 0 (0x00).
Secondly, the condition bits would depend on your processor, but going by some ARM notes, I might reasonably expect:
Z: Zero
The Z flag is set if the result of the flag-setting instruction is zero.
C: Carry (or Unsigned Overflow)
The C flag is set if the result of an unsigned operation overflows the 32-bit result register. This bit can be used to implement 64-bit unsigned arithmetic, for example.
answered Mar 24 at 12:40
abelenkyabelenky
48.3k2184137
add a comment |
First, the highest value one byte can hold is 255 (0xFF), so I do not think the result would be 256, but rather, overflow would cause the resulting value to be 0 (0x00).
Secondly, the condition bits would depend on your processor, but going by some ARM notes, I might reasonably expect:
Z: Zero
The Z flag is set if the result of the flag-setting instruction is zero.
C: Carry (or Unsigned Overflow)
The C flag is set if the result of an unsigned operation overflows the 32-bit result register. This bit can be used to implement 64-bit unsigned arithmetic, for example.
answered Mar 24 at 12:40
abelenkyabelenky
48.3k2184137
First, the highest value one byte can hold is 255 (0xFF), so I do not think the result would be 256, but rather, overflow would cause the resulting value to be 0 (0x00).
Secondly, the condition bits would depend on your processor, but going by some ARM notes, I might reasonably expect:
Z: Zero
The Z flag is set if the result of the flag-setting instruction is zero.
C: Carry (or Unsigned Overflow)
The C flag is set if the result of an unsigned operation overflows the 32-bit result register. This bit can be used to implement 64-bit unsigned arithmetic, for example.
answered Mar 24 at 12:40
abelenkyabelenky
48.3k2184137
answered Mar 24 at 12:40
abelenkyabelenky
48.3k2184137
answered Mar 24 at 12:40
abelenkyabelenky
48.3k2184137
answered Mar 24 at 12:40
abelenkyabelenky
48.3k2184137
48.3k2184137
add a comment |
add a comment |
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