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How to generate number pattern inside loop?
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I have the following code:
for ( let i = 1; i <= 12; i++ )
console.log(i % 4);
It generates the output:
1
2
3
0
1
2
3
0
1
2
3
0
I'm trying to change the pattern (i % 4) so it gives me the following sequence instead:
1
1
1
1
2
2
2
2
3
3
3
3
I don't want to use a variable for it, just change the pattern inside the console.log to a good one that doesn't rely on for example multiple tenary operators.
It should keep increasing 1 every 4 iterations and work for more than 12 iterations.
javascript for-loop
asked 2 days ago
user7393973user7393973
979532
add a comment |
I have the following code:
for ( let i = 1; i <= 12; i++ )
console.log(i % 4);
It generates the output:
1
2
3
0
1
2
3
0
1
2
3
0
I'm trying to change the pattern (i % 4) so it gives me the following sequence instead:
1
1
1
1
2
2
2
2
3
3
3
3
I don't want to use a variable for it, just change the pattern inside the console.log to a good one that doesn't rely on for example multiple tenary operators.
It should keep increasing 1 every 4 iterations and work for more than 12 iterations.
javascript for-loop
asked 2 days ago
user7393973user7393973
979532
add a comment |
I have the following code:
for ( let i = 1; i <= 12; i++ )
console.log(i % 4);
It generates the output:
1
2
3
0
1
2
3
0
1
2
3
0
I'm trying to change the pattern (i % 4) so it gives me the following sequence instead:
1
1
1
1
2
2
2
2
3
3
3
3
I don't want to use a variable for it, just change the pattern inside the console.log to a good one that doesn't rely on for example multiple tenary operators.
It should keep increasing 1 every 4 iterations and work for more than 12 iterations.
javascript for-loop
asked 2 days ago
user7393973user7393973
979532
I have the following code:
for ( let i = 1; i <= 12; i++ )
console.log(i % 4);
It generates the output:
1
2
3
0
1
2
3
0
1
2
3
0
I'm trying to change the pattern (i % 4) so it gives me the following sequence instead:
1
1
1
1
2
2
2
2
3
3
3
3
I don't want to use a variable for it, just change the pattern inside the console.log to a good one that doesn't rely on for example multiple tenary operators.
It should keep increasing 1 every 4 iterations and work for more than 12 iterations.
for ( let i = 1; i <= 12; i++ )
console.log(i % 4);
for ( let i = 1; i <= 12; i++ )
console.log(i % 4);
javascript for-loop
javascript for-loop
asked 2 days ago
user7393973user7393973
979532
asked 2 days ago
user7393973user7393973
979532
edited 2 days ago
user7393973
asked 2 days ago
user7393973user7393973
979532
asked 2 days ago
user7393973user7393973
979532
asked 2 days ago
user7393973user7393973
979532
979532
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You could divide the value by 4 and take the value with Math.ceil for the next integer number.
for ( let i = 1; i <= 12; i++ )
console.log(Math.ceil(i / 4));
answered 2 days ago
Nina ScholzNina Scholz
193k15105177
Thanks. I could not remember at all what was it to make such sequence and was complicated to search it aswell.
– user7393973
2 days ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You could divide the value by 4 and take the value with Math.ceil for the next integer number.
for ( let i = 1; i <= 12; i++ )
console.log(Math.ceil(i / 4));
answered 2 days ago
Nina ScholzNina Scholz
193k15105177
Thanks. I could not remember at all what was it to make such sequence and was complicated to search it aswell.
– user7393973
2 days ago
add a comment |
You could divide the value by 4 and take the value with Math.ceil for the next integer number.
for ( let i = 1; i <= 12; i++ )
console.log(Math.ceil(i / 4));
answered 2 days ago
Nina ScholzNina Scholz
193k15105177
Thanks. I could not remember at all what was it to make such sequence and was complicated to search it aswell.
– user7393973
2 days ago
add a comment |
You could divide the value by 4 and take the value with Math.ceil for the next integer number.
for ( let i = 1; i <= 12; i++ )
console.log(Math.ceil(i / 4));
answered 2 days ago
Nina ScholzNina Scholz
193k15105177
You could divide the value by 4 and take the value with Math.ceil for the next integer number.
for ( let i = 1; i <= 12; i++ )
console.log(Math.ceil(i / 4));
for ( let i = 1; i <= 12; i++ )
console.log(Math.ceil(i / 4));
for ( let i = 1; i <= 12; i++ )
console.log(Math.ceil(i / 4));
answered 2 days ago
Nina ScholzNina Scholz
193k15105177
answered 2 days ago
Nina ScholzNina Scholz
193k15105177
answered 2 days ago
Nina ScholzNina Scholz
193k15105177
answered 2 days ago
Nina ScholzNina Scholz
193k15105177
193k15105177
Thanks. I could not remember at all what was it to make such sequence and was complicated to search it aswell.
– user7393973
2 days ago
add a comment |
Thanks. I could not remember at all what was it to make such sequence and was complicated to search it aswell.
– user7393973
2 days ago
Thanks. I could not remember at all what was it to make such sequence and was complicated to search it aswell.
– user7393973
2 days ago
Thanks. I could not remember at all what was it to make such sequence and was complicated to search it aswell.
– user7393973
2 days ago
add a comment |
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