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chaining fadeIn, fadeOut, animate, wrong execution order
change text of same element multiple timesCSS - IE7 & 8 IssuesHow to implement multiple popups?jQuery Animation, Chaining, .each() and .animate() (or fadeIn() and fadeOut())replace .animate() with fadeIn/ fadeOutinterval of animation fadeIn fadeOutfadeIn() / fadeOut() animation not playingJquery animation/fadeIn/fadeOutText fadein/fadeout animation in loopjquery animation for fadein and fadeoutTable CSS is not showing up at all
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I am trying to programmatically change some text, adding a class, animating it. So far I have this code:
.red
font-size: 150%;
color: red;
<font id="test" size="7">0000000000000000</font>
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () => $this.text('2222222222222222')
.css("color", "green"))
.addClass("red")
.fadeIn(500)
.animate('margin-left': '250px', duration: 3000, complete: function()
$this.fadeOut(200)
)
);
Unfortunately, the order seems to be messed up. The class "red" is added to the text "1111111....." instead to the text "222222...." and I don't understand why.
Here the jsFiddle: http://jsfiddle.net/3nus4wpy/2/
javascript jquery html
add a comment |
I am trying to programmatically change some text, adding a class, animating it. So far I have this code:
.red
font-size: 150%;
color: red;
<font id="test" size="7">0000000000000000</font>
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () => $this.text('2222222222222222')
.css("color", "green"))
.addClass("red")
.fadeIn(500)
.animate('margin-left': '250px', duration: 3000, complete: function()
$this.fadeOut(200)
)
);
Unfortunately, the order seems to be messed up. The class "red" is added to the text "1111111....." instead to the text "222222...." and I don't understand why.
Here the jsFiddle: http://jsfiddle.net/3nus4wpy/2/
javascript jquery html
add a comment |
I am trying to programmatically change some text, adding a class, animating it. So far I have this code:
.red
font-size: 150%;
color: red;
<font id="test" size="7">0000000000000000</font>
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () => $this.text('2222222222222222')
.css("color", "green"))
.addClass("red")
.fadeIn(500)
.animate('margin-left': '250px', duration: 3000, complete: function()
$this.fadeOut(200)
)
);
Unfortunately, the order seems to be messed up. The class "red" is added to the text "1111111....." instead to the text "222222...." and I don't understand why.
Here the jsFiddle: http://jsfiddle.net/3nus4wpy/2/
javascript jquery html
I am trying to programmatically change some text, adding a class, animating it. So far I have this code:
.red
font-size: 150%;
color: red;
<font id="test" size="7">0000000000000000</font>
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () => $this.text('2222222222222222')
.css("color", "green"))
.addClass("red")
.fadeIn(500)
.animate('margin-left': '250px', duration: 3000, complete: function()
$this.fadeOut(200)
)
);
Unfortunately, the order seems to be messed up. The class "red" is added to the text "1111111....." instead to the text "222222...." and I don't understand why.
Here the jsFiddle: http://jsfiddle.net/3nus4wpy/2/
javascript jquery html
javascript jquery html
edited Mar 23 at 21:49
Jack Bashford
22.1k52051
22.1k52051
asked Mar 23 at 21:47
user838531user838531
14919
14919
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You have to put everything asynchronous (except further fades) that you want to happen on fade inside the fade callback:
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this
.css("color", "green")
.addClass("red")
)
.fadeIn(500, () =>
$this.animate(
'margin-left': '250px'
,
duration: 3000,
complete: function()
$this.fadeOut(200)
);
);
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
You can also call delay
to create a delay before the next chained function runs, eg:
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this.css("color", "green").addClass("red")
)
.fadeIn(500)
.delay(500)
.animate(
'margin-left': '250px'
,
duration: 3000
)
.delay(3000)
.fadeOut(5500)
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
I don't get it. When I need to add more fadein, fadeout functions, where do I place them, in the callback of the animation? This here for example doesn't work:$('#test').fadeOut(500, function() const $this = $(this); $this.text('11111111111111111111') .fadeIn(500) .fadeOut(500, () => $this.text('2222222222222222'); $this .css("color", "green") .addClass("red") ) .fadeIn(500, () => $this.animate( 'margin-left': '250px' , duration: 3000) ) .fadeOut(5500) );
– user838531
Mar 23 at 22:54
It seems not possible to add another fadein or fadeout after the fadein having the animate() as callback function.
– user838531
Mar 23 at 22:55
I need to be able to chain unlimited number of fadeIn, fadeOut, animate. How do I do that?
– user838531
Mar 23 at 22:58
You can also usedelay
, see edit
– Snow
Mar 23 at 23:03
Ok, so it was actually wrong to put the animation() function as callback of the second fadeIn(), and I also don't need to use the callback of the animation() function here, right?
– user838531
Mar 23 at 23:15
|
show 1 more comment
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You have to put everything asynchronous (except further fades) that you want to happen on fade inside the fade callback:
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this
.css("color", "green")
.addClass("red")
)
.fadeIn(500, () =>
$this.animate(
'margin-left': '250px'
,
duration: 3000,
complete: function()
$this.fadeOut(200)
);
);
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
You can also call delay
to create a delay before the next chained function runs, eg:
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this.css("color", "green").addClass("red")
)
.fadeIn(500)
.delay(500)
.animate(
'margin-left': '250px'
,
duration: 3000
)
.delay(3000)
.fadeOut(5500)
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
I don't get it. When I need to add more fadein, fadeout functions, where do I place them, in the callback of the animation? This here for example doesn't work:$('#test').fadeOut(500, function() const $this = $(this); $this.text('11111111111111111111') .fadeIn(500) .fadeOut(500, () => $this.text('2222222222222222'); $this .css("color", "green") .addClass("red") ) .fadeIn(500, () => $this.animate( 'margin-left': '250px' , duration: 3000) ) .fadeOut(5500) );
– user838531
Mar 23 at 22:54
It seems not possible to add another fadein or fadeout after the fadein having the animate() as callback function.
– user838531
Mar 23 at 22:55
I need to be able to chain unlimited number of fadeIn, fadeOut, animate. How do I do that?
– user838531
Mar 23 at 22:58
You can also usedelay
, see edit
– Snow
Mar 23 at 23:03
Ok, so it was actually wrong to put the animation() function as callback of the second fadeIn(), and I also don't need to use the callback of the animation() function here, right?
– user838531
Mar 23 at 23:15
|
show 1 more comment
You have to put everything asynchronous (except further fades) that you want to happen on fade inside the fade callback:
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this
.css("color", "green")
.addClass("red")
)
.fadeIn(500, () =>
$this.animate(
'margin-left': '250px'
,
duration: 3000,
complete: function()
$this.fadeOut(200)
);
);
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
You can also call delay
to create a delay before the next chained function runs, eg:
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this.css("color", "green").addClass("red")
)
.fadeIn(500)
.delay(500)
.animate(
'margin-left': '250px'
,
duration: 3000
)
.delay(3000)
.fadeOut(5500)
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
I don't get it. When I need to add more fadein, fadeout functions, where do I place them, in the callback of the animation? This here for example doesn't work:$('#test').fadeOut(500, function() const $this = $(this); $this.text('11111111111111111111') .fadeIn(500) .fadeOut(500, () => $this.text('2222222222222222'); $this .css("color", "green") .addClass("red") ) .fadeIn(500, () => $this.animate( 'margin-left': '250px' , duration: 3000) ) .fadeOut(5500) );
– user838531
Mar 23 at 22:54
It seems not possible to add another fadein or fadeout after the fadein having the animate() as callback function.
– user838531
Mar 23 at 22:55
I need to be able to chain unlimited number of fadeIn, fadeOut, animate. How do I do that?
– user838531
Mar 23 at 22:58
You can also usedelay
, see edit
– Snow
Mar 23 at 23:03
Ok, so it was actually wrong to put the animation() function as callback of the second fadeIn(), and I also don't need to use the callback of the animation() function here, right?
– user838531
Mar 23 at 23:15
|
show 1 more comment
You have to put everything asynchronous (except further fades) that you want to happen on fade inside the fade callback:
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this
.css("color", "green")
.addClass("red")
)
.fadeIn(500, () =>
$this.animate(
'margin-left': '250px'
,
duration: 3000,
complete: function()
$this.fadeOut(200)
);
);
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
You can also call delay
to create a delay before the next chained function runs, eg:
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this.css("color", "green").addClass("red")
)
.fadeIn(500)
.delay(500)
.animate(
'margin-left': '250px'
,
duration: 3000
)
.delay(3000)
.fadeOut(5500)
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
You have to put everything asynchronous (except further fades) that you want to happen on fade inside the fade callback:
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this
.css("color", "green")
.addClass("red")
)
.fadeIn(500, () =>
$this.animate(
'margin-left': '250px'
,
duration: 3000,
complete: function()
$this.fadeOut(200)
);
);
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
You can also call delay
to create a delay before the next chained function runs, eg:
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this.css("color", "green").addClass("red")
)
.fadeIn(500)
.delay(500)
.animate(
'margin-left': '250px'
,
duration: 3000
)
.delay(3000)
.fadeOut(5500)
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this
.css("color", "green")
.addClass("red")
)
.fadeIn(500, () =>
$this.animate(
'margin-left': '250px'
,
duration: 3000,
complete: function()
$this.fadeOut(200)
);
);
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this
.css("color", "green")
.addClass("red")
)
.fadeIn(500, () =>
$this.animate(
'margin-left': '250px'
,
duration: 3000,
complete: function()
$this.fadeOut(200)
);
);
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this.css("color", "green").addClass("red")
)
.fadeIn(500)
.delay(500)
.animate(
'margin-left': '250px'
,
duration: 3000
)
.delay(3000)
.fadeOut(5500)
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
$('#test').fadeOut(500, function()
const $this = $(this);
$this.text('11111111111111111111')
.fadeIn(500)
.fadeOut(500, () =>
$this.text('2222222222222222');
$this.css("color", "green").addClass("red")
)
.fadeIn(500)
.delay(500)
.animate(
'margin-left': '250px'
,
duration: 3000
)
.delay(3000)
.fadeOut(5500)
);
.red
font-size: 150%;
color: red;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<font id="test" size="7">0000000000000000</font>
edited Mar 23 at 23:03
answered Mar 23 at 21:50
SnowSnow
1,017225
1,017225
I don't get it. When I need to add more fadein, fadeout functions, where do I place them, in the callback of the animation? This here for example doesn't work:$('#test').fadeOut(500, function() const $this = $(this); $this.text('11111111111111111111') .fadeIn(500) .fadeOut(500, () => $this.text('2222222222222222'); $this .css("color", "green") .addClass("red") ) .fadeIn(500, () => $this.animate( 'margin-left': '250px' , duration: 3000) ) .fadeOut(5500) );
– user838531
Mar 23 at 22:54
It seems not possible to add another fadein or fadeout after the fadein having the animate() as callback function.
– user838531
Mar 23 at 22:55
I need to be able to chain unlimited number of fadeIn, fadeOut, animate. How do I do that?
– user838531
Mar 23 at 22:58
You can also usedelay
, see edit
– Snow
Mar 23 at 23:03
Ok, so it was actually wrong to put the animation() function as callback of the second fadeIn(), and I also don't need to use the callback of the animation() function here, right?
– user838531
Mar 23 at 23:15
|
show 1 more comment
I don't get it. When I need to add more fadein, fadeout functions, where do I place them, in the callback of the animation? This here for example doesn't work:$('#test').fadeOut(500, function() const $this = $(this); $this.text('11111111111111111111') .fadeIn(500) .fadeOut(500, () => $this.text('2222222222222222'); $this .css("color", "green") .addClass("red") ) .fadeIn(500, () => $this.animate( 'margin-left': '250px' , duration: 3000) ) .fadeOut(5500) );
– user838531
Mar 23 at 22:54
It seems not possible to add another fadein or fadeout after the fadein having the animate() as callback function.
– user838531
Mar 23 at 22:55
I need to be able to chain unlimited number of fadeIn, fadeOut, animate. How do I do that?
– user838531
Mar 23 at 22:58
You can also usedelay
, see edit
– Snow
Mar 23 at 23:03
Ok, so it was actually wrong to put the animation() function as callback of the second fadeIn(), and I also don't need to use the callback of the animation() function here, right?
– user838531
Mar 23 at 23:15
I don't get it. When I need to add more fadein, fadeout functions, where do I place them, in the callback of the animation? This here for example doesn't work:$('#test').fadeOut(500, function() const $this = $(this); $this.text('11111111111111111111') .fadeIn(500) .fadeOut(500, () => $this.text('2222222222222222'); $this .css("color", "green") .addClass("red") ) .fadeIn(500, () => $this.animate( 'margin-left': '250px' , duration: 3000) ) .fadeOut(5500) );
– user838531
Mar 23 at 22:54
I don't get it. When I need to add more fadein, fadeout functions, where do I place them, in the callback of the animation? This here for example doesn't work:$('#test').fadeOut(500, function() const $this = $(this); $this.text('11111111111111111111') .fadeIn(500) .fadeOut(500, () => $this.text('2222222222222222'); $this .css("color", "green") .addClass("red") ) .fadeIn(500, () => $this.animate( 'margin-left': '250px' , duration: 3000) ) .fadeOut(5500) );
– user838531
Mar 23 at 22:54
It seems not possible to add another fadein or fadeout after the fadein having the animate() as callback function.
– user838531
Mar 23 at 22:55
It seems not possible to add another fadein or fadeout after the fadein having the animate() as callback function.
– user838531
Mar 23 at 22:55
I need to be able to chain unlimited number of fadeIn, fadeOut, animate. How do I do that?
– user838531
Mar 23 at 22:58
I need to be able to chain unlimited number of fadeIn, fadeOut, animate. How do I do that?
– user838531
Mar 23 at 22:58
You can also use
delay
, see edit– Snow
Mar 23 at 23:03
You can also use
delay
, see edit– Snow
Mar 23 at 23:03
Ok, so it was actually wrong to put the animation() function as callback of the second fadeIn(), and I also don't need to use the callback of the animation() function here, right?
– user838531
Mar 23 at 23:15
Ok, so it was actually wrong to put the animation() function as callback of the second fadeIn(), and I also don't need to use the callback of the animation() function here, right?
– user838531
Mar 23 at 23:15
|
show 1 more comment
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