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Golang JSON Serialization/Deserialization

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-1

I have a struct as follows:

type Node struct 
 Name string
 Children []*Node
 Values []string

I also have a set of json files describing my trees such as:

 "something": 
 "someblah": [
 "fluf",
 "glah"
 ],
 "someother": 
 "someotter": [
 "blib",
 "fnar"
 ]
 
 

How can I deserialize these files into the structs?

All the examples I found seem to require a different structure with named key/value pairs.

For this, the structure is key:

• the key is the struct name


• the map contents are children


• the lists contents are values

I cannot understand how to map this logic into the golang json serializer.

json go serialization

share|improve this question

asked Mar 23 at 22:02

WilbertWilbert

3,83242670

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  why not unmarshal into map[string]interface?
  
  – Abdullah
  Mar 23 at 22:45
  

  
  
  
  

add a comment | 

-1

I have a struct as follows:

type Node struct 
 Name string
 Children []*Node
 Values []string

I also have a set of json files describing my trees such as:

 "something": 
 "someblah": [
 "fluf",
 "glah"
 ],
 "someother": 
 "someotter": [
 "blib",
 "fnar"
 ]
 
 

How can I deserialize these files into the structs?

All the examples I found seem to require a different structure with named key/value pairs.

For this, the structure is key:

• the key is the struct name


• the map contents are children


• the lists contents are values

I cannot understand how to map this logic into the golang json serializer.

json go serialization

share|improve this question

asked Mar 23 at 22:02

WilbertWilbert

3,83242670

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  why not unmarshal into map[string]interface?
  
  – Abdullah
  Mar 23 at 22:45
  

  
  
  
  

add a comment | 

I have a struct as follows:

type Node struct 
 Name string
 Children []*Node
 Values []string

I also have a set of json files describing my trees such as:

 "something": 
 "someblah": [
 "fluf",
 "glah"
 ],
 "someother": 
 "someotter": [
 "blib",
 "fnar"
 ]
 
 

How can I deserialize these files into the structs?

All the examples I found seem to require a different structure with named key/value pairs.

For this, the structure is key:

• the key is the struct name


• the map contents are children


• the lists contents are values

I cannot understand how to map this logic into the golang json serializer.

json go serialization

share|improve this question

asked Mar 23 at 22:02

WilbertWilbert

3,83242670

type Node struct 
 Name string
 Children []*Node
 Values []string

 "something": 
 "someblah": [
 "fluf",
 "glah"
 ],
 "someother": 
 "someotter": [
 "blib",
 "fnar"
 ]
 
 

share|improve this question

asked Mar 23 at 22:02

WilbertWilbert

3,83242670

share|improve this question

asked Mar 23 at 22:02

WilbertWilbert

3,83242670

asked Mar 23 at 22:02

WilbertWilbert

3,83242670

asked Mar 23 at 22:02

WilbertWilbert

3,83242670

1 Answer
1

active

oldest

votes

2

The easiest approach is to decode to map[string]interface and convert that to the desired structure:

var m map[string]interface
err := json.Unmarshal(data, &m)
if err != nil 
 // handle error

node := convert(m, "")

...

func convert(name string, m map[string]interface) *Node 
 n := NodeName: name
 for k, v := range m 
 switch v := v.(type) 
 case []interface:
 nn := NodeName: k
 for _, e := range v 
 s, ok := e.(string)
 if !ok 
 panic(fmt.Sprintf("expected string, got %T", e))
 
 nn.Values = append(nn.Values, s)
 
 n.Children = append(n.Children, &nn)
 case map[string]interface:
 n.Children = append(n.Children, convert(k, v))
 default:
 panic("unexpected type")
 
 
 return &n

The convert function panics when it encounters a value of an unexpected type. Depending on the requirements of your application, you may want to ignore these values or return an error.

Run it on the playground.

share|improve this answer

edited Mar 24 at 20:38

answered Mar 23 at 23:04

Cerise LimónCerise Limón

57k57497

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, this helped me find the correct solution. However, there seems to be a bug in the example: In the values case, there is no node created and the values are attached to the parent. In the example, each node has either children or values.
  
  – Wilbert
  Mar 24 at 20:23
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Wilbert See updated answer. It would have been helpful if the question showed an example of the expected result.
  
  – Cerise Limón
  Mar 24 at 20:40
  

  
  
  
  

add a comment | 

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2

The easiest approach is to decode to map[string]interface and convert that to the desired structure:

var m map[string]interface
err := json.Unmarshal(data, &m)
if err != nil 
 // handle error

node := convert(m, "")

...

func convert(name string, m map[string]interface) *Node 
 n := NodeName: name
 for k, v := range m 
 switch v := v.(type) 
 case []interface:
 nn := NodeName: k
 for _, e := range v 
 s, ok := e.(string)
 if !ok 
 panic(fmt.Sprintf("expected string, got %T", e))
 
 nn.Values = append(nn.Values, s)
 
 n.Children = append(n.Children, &nn)
 case map[string]interface:
 n.Children = append(n.Children, convert(k, v))
 default:
 panic("unexpected type")
 
 
 return &n

The convert function panics when it encounters a value of an unexpected type. Depending on the requirements of your application, you may want to ignore these values or return an error.

Run it on the playground.

share|improve this answer

edited Mar 24 at 20:38

answered Mar 23 at 23:04

Cerise LimónCerise Limón

57k57497

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, this helped me find the correct solution. However, there seems to be a bug in the example: In the values case, there is no node created and the values are attached to the parent. In the example, each node has either children or values.
  
  – Wilbert
  Mar 24 at 20:23
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Wilbert See updated answer. It would have been helpful if the question showed an example of the expected result.
  
  – Cerise Limón
  Mar 24 at 20:40
  

  
  
  
  

add a comment | 

2

The easiest approach is to decode to map[string]interface and convert that to the desired structure:

var m map[string]interface
err := json.Unmarshal(data, &m)
if err != nil 
 // handle error

node := convert(m, "")

...

func convert(name string, m map[string]interface) *Node 
 n := NodeName: name
 for k, v := range m 
 switch v := v.(type) 
 case []interface:
 nn := NodeName: k
 for _, e := range v 
 s, ok := e.(string)
 if !ok 
 panic(fmt.Sprintf("expected string, got %T", e))
 
 nn.Values = append(nn.Values, s)
 
 n.Children = append(n.Children, &nn)
 case map[string]interface:
 n.Children = append(n.Children, convert(k, v))
 default:
 panic("unexpected type")
 
 
 return &n

The convert function panics when it encounters a value of an unexpected type. Depending on the requirements of your application, you may want to ignore these values or return an error.

Run it on the playground.

share|improve this answer

edited Mar 24 at 20:38

answered Mar 23 at 23:04

Cerise LimónCerise Limón

57k57497

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, this helped me find the correct solution. However, there seems to be a bug in the example: In the values case, there is no node created and the values are attached to the parent. In the example, each node has either children or values.
  
  – Wilbert
  Mar 24 at 20:23
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Wilbert See updated answer. It would have been helpful if the question showed an example of the expected result.
  
  – Cerise Limón
  Mar 24 at 20:40
  

  
  
  
  

add a comment | 

The easiest approach is to decode to map[string]interface and convert that to the desired structure:

var m map[string]interface
err := json.Unmarshal(data, &m)
if err != nil 
 // handle error

node := convert(m, "")

...

func convert(name string, m map[string]interface) *Node 
 n := NodeName: name
 for k, v := range m 
 switch v := v.(type) 
 case []interface:
 nn := NodeName: k
 for _, e := range v 
 s, ok := e.(string)
 if !ok 
 panic(fmt.Sprintf("expected string, got %T", e))
 
 nn.Values = append(nn.Values, s)
 
 n.Children = append(n.Children, &nn)
 case map[string]interface:
 n.Children = append(n.Children, convert(k, v))
 default:
 panic("unexpected type")
 
 
 return &n

The convert function panics when it encounters a value of an unexpected type. Depending on the requirements of your application, you may want to ignore these values or return an error.

Run it on the playground.

share|improve this answer

edited Mar 24 at 20:38

answered Mar 23 at 23:04

Cerise LimónCerise Limón

57k57497

var m map[string]interface
err := json.Unmarshal(data, &m)
if err != nil 
 // handle error

node := convert(m, "")

...

func convert(name string, m map[string]interface) *Node 
 n := NodeName: name
 for k, v := range m 
 switch v := v.(type) 
 case []interface:
 nn := NodeName: k
 for _, e := range v 
 s, ok := e.(string)
 if !ok 
 panic(fmt.Sprintf("expected string, got %T", e))
 
 nn.Values = append(nn.Values, s)
 
 n.Children = append(n.Children, &nn)
 case map[string]interface:
 n.Children = append(n.Children, convert(k, v))
 default:
 panic("unexpected type")
 
 
 return &n

share|improve this answer

edited Mar 24 at 20:38

answered Mar 23 at 23:04

Cerise LimónCerise Limón

57k57497

answered Mar 23 at 23:04

Cerise LimónCerise Limón

57k57497

answered Mar 23 at 23:04

Cerise LimónCerise Limón

57k57497