“select is not valid at this position for the server version…” when subqueries are addedWhy is in MySQL every valid SELECT not a valid VIEW?Reference - What does this error mean in PHP?mysql subquery in select joinConvert mysql query to laravel's DB facadesingle mysql query for choosing 25 records (9+16) using union all and based on 2 different conditionsMysql query from more tablesUsing WHERE clause on NATURAL JOINrewrite sql without with clauseselect is not valid at this position for this server version expecting '(' withError when selecting values with like and not like MySql
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“select is not valid at this position for the server version…” when subqueries are added
Why is in MySQL every valid SELECT not a valid VIEW?Reference - What does this error mean in PHP?mysql subquery in select joinConvert mysql query to laravel's DB facadesingle mysql query for choosing 25 records (9+16) using union all and based on 2 different conditionsMysql query from more tablesUsing WHERE clause on NATURAL JOINrewrite sql without with clauseselect is not valid at this position for this server version expecting '(' withError when selecting values with like and not like MySql
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I have a syntax error, and I don't know how to fix it. I'm kind of new to MySQL and the error message is just confusing me.
Select dept_name, total_student, total_instuctor, total_course
From department as d
natural left join ( select dept_name count( dept_name ) as total_student
from student
group by dept_name) as s
natural left join ( select dept_name count( dept_name ) as total_instructor
from instructor
group by dept_name) as i
natural left join ( select dept_name count( dept_name ) as total_course
from course
group by dept_name) as c
Group By dept_name
Order By count( total_student ) desc;
currently getting an error message "select is not valid at this position for this server version, expecting : '(', WITH" the Select that is underlined is the very first one.
mysql mysql-workbench
add a comment |
I have a syntax error, and I don't know how to fix it. I'm kind of new to MySQL and the error message is just confusing me.
Select dept_name, total_student, total_instuctor, total_course
From department as d
natural left join ( select dept_name count( dept_name ) as total_student
from student
group by dept_name) as s
natural left join ( select dept_name count( dept_name ) as total_instructor
from instructor
group by dept_name) as i
natural left join ( select dept_name count( dept_name ) as total_course
from course
group by dept_name) as c
Group By dept_name
Order By count( total_student ) desc;
currently getting an error message "select is not valid at this position for this server version, expecting : '(', WITH" the Select that is underlined is the very first one.
mysql mysql-workbench
add a comment |
I have a syntax error, and I don't know how to fix it. I'm kind of new to MySQL and the error message is just confusing me.
Select dept_name, total_student, total_instuctor, total_course
From department as d
natural left join ( select dept_name count( dept_name ) as total_student
from student
group by dept_name) as s
natural left join ( select dept_name count( dept_name ) as total_instructor
from instructor
group by dept_name) as i
natural left join ( select dept_name count( dept_name ) as total_course
from course
group by dept_name) as c
Group By dept_name
Order By count( total_student ) desc;
currently getting an error message "select is not valid at this position for this server version, expecting : '(', WITH" the Select that is underlined is the very first one.
mysql mysql-workbench
I have a syntax error, and I don't know how to fix it. I'm kind of new to MySQL and the error message is just confusing me.
Select dept_name, total_student, total_instuctor, total_course
From department as d
natural left join ( select dept_name count( dept_name ) as total_student
from student
group by dept_name) as s
natural left join ( select dept_name count( dept_name ) as total_instructor
from instructor
group by dept_name) as i
natural left join ( select dept_name count( dept_name ) as total_course
from course
group by dept_name) as c
Group By dept_name
Order By count( total_student ) desc;
currently getting an error message "select is not valid at this position for this server version, expecting : '(', WITH" the Select that is underlined is the very first one.
mysql mysql-workbench
mysql mysql-workbench
asked Mar 23 at 17:40
Amanda ErdmannAmanda Erdmann
31
31
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You forgot all the ,
in the subquery selects:
Select dept_name, total_student, total_instuctor, total_course
From department as d
natural left join ( select dept_name, count( dept_name ) as total_student
from student
group by dept_name) as s
natural left join ( select dept_name, count( dept_name ) as total_instructor
from instructor
group by dept_name) as i
natural left join ( select dept_name, count( dept_name ) as total_course
from course
group by dept_name) as c
Group By dept_name
Order By count( total_student ) desc;
Thank you :). Sorry for the stupid question.
– Amanda Erdmann
Mar 25 at 0:27
@AmandaErdmann if my answer solved it you could accept it
– nacho
Mar 25 at 7:07
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You forgot all the ,
in the subquery selects:
Select dept_name, total_student, total_instuctor, total_course
From department as d
natural left join ( select dept_name, count( dept_name ) as total_student
from student
group by dept_name) as s
natural left join ( select dept_name, count( dept_name ) as total_instructor
from instructor
group by dept_name) as i
natural left join ( select dept_name, count( dept_name ) as total_course
from course
group by dept_name) as c
Group By dept_name
Order By count( total_student ) desc;
Thank you :). Sorry for the stupid question.
– Amanda Erdmann
Mar 25 at 0:27
@AmandaErdmann if my answer solved it you could accept it
– nacho
Mar 25 at 7:07
add a comment |
You forgot all the ,
in the subquery selects:
Select dept_name, total_student, total_instuctor, total_course
From department as d
natural left join ( select dept_name, count( dept_name ) as total_student
from student
group by dept_name) as s
natural left join ( select dept_name, count( dept_name ) as total_instructor
from instructor
group by dept_name) as i
natural left join ( select dept_name, count( dept_name ) as total_course
from course
group by dept_name) as c
Group By dept_name
Order By count( total_student ) desc;
Thank you :). Sorry for the stupid question.
– Amanda Erdmann
Mar 25 at 0:27
@AmandaErdmann if my answer solved it you could accept it
– nacho
Mar 25 at 7:07
add a comment |
You forgot all the ,
in the subquery selects:
Select dept_name, total_student, total_instuctor, total_course
From department as d
natural left join ( select dept_name, count( dept_name ) as total_student
from student
group by dept_name) as s
natural left join ( select dept_name, count( dept_name ) as total_instructor
from instructor
group by dept_name) as i
natural left join ( select dept_name, count( dept_name ) as total_course
from course
group by dept_name) as c
Group By dept_name
Order By count( total_student ) desc;
You forgot all the ,
in the subquery selects:
Select dept_name, total_student, total_instuctor, total_course
From department as d
natural left join ( select dept_name, count( dept_name ) as total_student
from student
group by dept_name) as s
natural left join ( select dept_name, count( dept_name ) as total_instructor
from instructor
group by dept_name) as i
natural left join ( select dept_name, count( dept_name ) as total_course
from course
group by dept_name) as c
Group By dept_name
Order By count( total_student ) desc;
answered Mar 23 at 19:02
nachonacho
3,15011426
3,15011426
Thank you :). Sorry for the stupid question.
– Amanda Erdmann
Mar 25 at 0:27
@AmandaErdmann if my answer solved it you could accept it
– nacho
Mar 25 at 7:07
add a comment |
Thank you :). Sorry for the stupid question.
– Amanda Erdmann
Mar 25 at 0:27
@AmandaErdmann if my answer solved it you could accept it
– nacho
Mar 25 at 7:07
Thank you :). Sorry for the stupid question.
– Amanda Erdmann
Mar 25 at 0:27
Thank you :). Sorry for the stupid question.
– Amanda Erdmann
Mar 25 at 0:27
@AmandaErdmann if my answer solved it you could accept it
– nacho
Mar 25 at 7:07
@AmandaErdmann if my answer solved it you could accept it
– nacho
Mar 25 at 7:07
add a comment |
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