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“select is not valid at this position for the server version…” when subqueries are added


Why is in MySQL every valid SELECT not a valid VIEW?Reference - What does this error mean in PHP?mysql subquery in select joinConvert mysql query to laravel's DB facadesingle mysql query for choosing 25 records (9+16) using union all and based on 2 different conditionsMysql query from more tablesUsing WHERE clause on NATURAL JOINrewrite sql without with clauseselect is not valid at this position for this server version expecting '(' withError when selecting values with like and not like MySql






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0















I have a syntax error, and I don't know how to fix it. I'm kind of new to MySQL and the error message is just confusing me.



Select dept_name, total_student, total_instuctor, total_course
From department as d
natural left join ( select dept_name count( dept_name ) as total_student
from student
group by dept_name) as s
natural left join ( select dept_name count( dept_name ) as total_instructor
from instructor
group by dept_name) as i
natural left join ( select dept_name count( dept_name ) as total_course
from course
group by dept_name) as c
Group By dept_name
Order By count( total_student ) desc;


currently getting an error message "select is not valid at this position for this server version, expecting : '(', WITH" the Select that is underlined is the very first one.










share|improve this question




























    0















    I have a syntax error, and I don't know how to fix it. I'm kind of new to MySQL and the error message is just confusing me.



    Select dept_name, total_student, total_instuctor, total_course
    From department as d
    natural left join ( select dept_name count( dept_name ) as total_student
    from student
    group by dept_name) as s
    natural left join ( select dept_name count( dept_name ) as total_instructor
    from instructor
    group by dept_name) as i
    natural left join ( select dept_name count( dept_name ) as total_course
    from course
    group by dept_name) as c
    Group By dept_name
    Order By count( total_student ) desc;


    currently getting an error message "select is not valid at this position for this server version, expecting : '(', WITH" the Select that is underlined is the very first one.










    share|improve this question
























      0












      0








      0








      I have a syntax error, and I don't know how to fix it. I'm kind of new to MySQL and the error message is just confusing me.



      Select dept_name, total_student, total_instuctor, total_course
      From department as d
      natural left join ( select dept_name count( dept_name ) as total_student
      from student
      group by dept_name) as s
      natural left join ( select dept_name count( dept_name ) as total_instructor
      from instructor
      group by dept_name) as i
      natural left join ( select dept_name count( dept_name ) as total_course
      from course
      group by dept_name) as c
      Group By dept_name
      Order By count( total_student ) desc;


      currently getting an error message "select is not valid at this position for this server version, expecting : '(', WITH" the Select that is underlined is the very first one.










      share|improve this question














      I have a syntax error, and I don't know how to fix it. I'm kind of new to MySQL and the error message is just confusing me.



      Select dept_name, total_student, total_instuctor, total_course
      From department as d
      natural left join ( select dept_name count( dept_name ) as total_student
      from student
      group by dept_name) as s
      natural left join ( select dept_name count( dept_name ) as total_instructor
      from instructor
      group by dept_name) as i
      natural left join ( select dept_name count( dept_name ) as total_course
      from course
      group by dept_name) as c
      Group By dept_name
      Order By count( total_student ) desc;


      currently getting an error message "select is not valid at this position for this server version, expecting : '(', WITH" the Select that is underlined is the very first one.







      mysql mysql-workbench






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 23 at 17:40









      Amanda ErdmannAmanda Erdmann

      31




      31






















          1 Answer
          1






          active

          oldest

          votes


















          0














          You forgot all the , in the subquery selects:



          Select dept_name, total_student, total_instuctor, total_course
          From department as d
          natural left join ( select dept_name, count( dept_name ) as total_student
          from student
          group by dept_name) as s
          natural left join ( select dept_name, count( dept_name ) as total_instructor
          from instructor
          group by dept_name) as i
          natural left join ( select dept_name, count( dept_name ) as total_course
          from course
          group by dept_name) as c
          Group By dept_name
          Order By count( total_student ) desc;





          share|improve this answer























          • Thank you :). Sorry for the stupid question.

            – Amanda Erdmann
            Mar 25 at 0:27











          • @AmandaErdmann if my answer solved it you could accept it

            – nacho
            Mar 25 at 7:07











          Your Answer






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          1 Answer
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          1 Answer
          1






          active

          oldest

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          active

          oldest

          votes






          active

          oldest

          votes









          0














          You forgot all the , in the subquery selects:



          Select dept_name, total_student, total_instuctor, total_course
          From department as d
          natural left join ( select dept_name, count( dept_name ) as total_student
          from student
          group by dept_name) as s
          natural left join ( select dept_name, count( dept_name ) as total_instructor
          from instructor
          group by dept_name) as i
          natural left join ( select dept_name, count( dept_name ) as total_course
          from course
          group by dept_name) as c
          Group By dept_name
          Order By count( total_student ) desc;





          share|improve this answer























          • Thank you :). Sorry for the stupid question.

            – Amanda Erdmann
            Mar 25 at 0:27











          • @AmandaErdmann if my answer solved it you could accept it

            – nacho
            Mar 25 at 7:07















          0














          You forgot all the , in the subquery selects:



          Select dept_name, total_student, total_instuctor, total_course
          From department as d
          natural left join ( select dept_name, count( dept_name ) as total_student
          from student
          group by dept_name) as s
          natural left join ( select dept_name, count( dept_name ) as total_instructor
          from instructor
          group by dept_name) as i
          natural left join ( select dept_name, count( dept_name ) as total_course
          from course
          group by dept_name) as c
          Group By dept_name
          Order By count( total_student ) desc;





          share|improve this answer























          • Thank you :). Sorry for the stupid question.

            – Amanda Erdmann
            Mar 25 at 0:27











          • @AmandaErdmann if my answer solved it you could accept it

            – nacho
            Mar 25 at 7:07













          0












          0








          0







          You forgot all the , in the subquery selects:



          Select dept_name, total_student, total_instuctor, total_course
          From department as d
          natural left join ( select dept_name, count( dept_name ) as total_student
          from student
          group by dept_name) as s
          natural left join ( select dept_name, count( dept_name ) as total_instructor
          from instructor
          group by dept_name) as i
          natural left join ( select dept_name, count( dept_name ) as total_course
          from course
          group by dept_name) as c
          Group By dept_name
          Order By count( total_student ) desc;





          share|improve this answer













          You forgot all the , in the subquery selects:



          Select dept_name, total_student, total_instuctor, total_course
          From department as d
          natural left join ( select dept_name, count( dept_name ) as total_student
          from student
          group by dept_name) as s
          natural left join ( select dept_name, count( dept_name ) as total_instructor
          from instructor
          group by dept_name) as i
          natural left join ( select dept_name, count( dept_name ) as total_course
          from course
          group by dept_name) as c
          Group By dept_name
          Order By count( total_student ) desc;






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 23 at 19:02









          nachonacho

          3,15011426




          3,15011426












          • Thank you :). Sorry for the stupid question.

            – Amanda Erdmann
            Mar 25 at 0:27











          • @AmandaErdmann if my answer solved it you could accept it

            – nacho
            Mar 25 at 7:07

















          • Thank you :). Sorry for the stupid question.

            – Amanda Erdmann
            Mar 25 at 0:27











          • @AmandaErdmann if my answer solved it you could accept it

            – nacho
            Mar 25 at 7:07
















          Thank you :). Sorry for the stupid question.

          – Amanda Erdmann
          Mar 25 at 0:27





          Thank you :). Sorry for the stupid question.

          – Amanda Erdmann
          Mar 25 at 0:27













          @AmandaErdmann if my answer solved it you could accept it

          – nacho
          Mar 25 at 7:07





          @AmandaErdmann if my answer solved it you could accept it

          – nacho
          Mar 25 at 7:07



















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