How to correctly use Array.map() for replacing string with alphabet positionHow can I format numbers as currency string in JavaScript?How to check empty/undefined/null string in JavaScript?How can I convert a string to boolean in JavaScript?How to check if a string “StartsWith” another string?How do I correctly clone a JavaScript object?How can I get query string values in JavaScript?How do I make the first letter of a string uppercase in JavaScript?How to replace all occurrences of a string?How to check whether a string contains a substring in JavaScript?Replace a letter with its alphabet position

Why did so many MPs not vote in Meaningful Vote 3?

The Sword in the Stone

Why do planes need a roll motion?

Why can't my huge trees be chopped down?

This message is flooding my syslog, how to find where it comes from?

Why does RPM for a fixed-pitch propeller change with an aircraft's pitch?

Does academia have a lazy work culture?

Problem in styling a monochrome plot

Is this photo showing a woman posing in the nude before teenagers real?

How do we explain the E major chord in this progression?

kids pooling money for Lego League and taxes

Suggestions for protecting jeans from saddle clamp bolt

Is it legal for private citizens to "impound" e-scooters?

Request for a Latin phrase as motto "God is highest/supreme"

Why did Saturn V not head straight to the moon?

Can the term divorcée apply if a woman has not only divorced, but subsequently remarried?

Heisenberg uncertainty principle in daily life

AC contactor 1 pole or 2?

Piece-drop Mate #3

Why isn't there a serious attempt at creating a third mass-appeal party in the US?

Get delta of days by current hour and added delta of days

Why isn't there a ";" after "do" in sh loops?

What to do when you reach a conclusion and find out later on that someone else already did?

How to avoid unconsciously copying the style of my favorite writer?



How to correctly use Array.map() for replacing string with alphabet position


How can I format numbers as currency string in JavaScript?How to check empty/undefined/null string in JavaScript?How can I convert a string to boolean in JavaScript?How to check if a string “StartsWith” another string?How do I correctly clone a JavaScript object?How can I get query string values in JavaScript?How do I make the first letter of a string uppercase in JavaScript?How to replace all occurrences of a string?How to check whether a string contains a substring in JavaScript?Replace a letter with its alphabet position






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2















Other SO 'Replace string with alphabet positions' questions didn't utilize map, which is what I'm trying to learn how to use to solve this.



Problem:
Given a string, replace every letter with its position in the alphabet.
If anything in the text isn't a letter, ignore it and don't return it.
"a" = 1, "b" = 2, etc.



What I've tried is:
-looping over a new array instance and setting the index value to String.fromCharCode()
- taking input string making it lowercase
-splitting to array
-return array.map().join(' ')



function alphabetPosition(text) 

let alphabet = new Array(26);
for (let i = 0; i<26; ++i)
let char = String.fromCharCode(97 + i);
alphabet[i] = char;


text = text.toLowerCase();

let arr = text.split('');

return arr.map(element => return element = alphabet.indexOf(element+1) ).join(' ');



expected it to return a string of alphabet positions, but got nothing at all. What is wrong with my implementation of Array.map()?










share|improve this question

















  • 1





    "nothing at all" really?

    – Jonas Wilms
    Mar 26 at 17:49











  • I think you're at least going to need to remove the 'element = ' portion of the second-to-last line

    – Andrew Castellano
    Mar 26 at 17:51






  • 1





    I guess you are looking for alphabet.indexOf(element)+1 instead of alphabet.indexOf(element+1). Other than that, it should work.

    – Bergi
    Mar 26 at 17:52

















2















Other SO 'Replace string with alphabet positions' questions didn't utilize map, which is what I'm trying to learn how to use to solve this.



Problem:
Given a string, replace every letter with its position in the alphabet.
If anything in the text isn't a letter, ignore it and don't return it.
"a" = 1, "b" = 2, etc.



What I've tried is:
-looping over a new array instance and setting the index value to String.fromCharCode()
- taking input string making it lowercase
-splitting to array
-return array.map().join(' ')



function alphabetPosition(text) 

let alphabet = new Array(26);
for (let i = 0; i<26; ++i)
let char = String.fromCharCode(97 + i);
alphabet[i] = char;


text = text.toLowerCase();

let arr = text.split('');

return arr.map(element => return element = alphabet.indexOf(element+1) ).join(' ');



expected it to return a string of alphabet positions, but got nothing at all. What is wrong with my implementation of Array.map()?










share|improve this question

















  • 1





    "nothing at all" really?

    – Jonas Wilms
    Mar 26 at 17:49











  • I think you're at least going to need to remove the 'element = ' portion of the second-to-last line

    – Andrew Castellano
    Mar 26 at 17:51






  • 1





    I guess you are looking for alphabet.indexOf(element)+1 instead of alphabet.indexOf(element+1). Other than that, it should work.

    – Bergi
    Mar 26 at 17:52













2












2








2








Other SO 'Replace string with alphabet positions' questions didn't utilize map, which is what I'm trying to learn how to use to solve this.



Problem:
Given a string, replace every letter with its position in the alphabet.
If anything in the text isn't a letter, ignore it and don't return it.
"a" = 1, "b" = 2, etc.



What I've tried is:
-looping over a new array instance and setting the index value to String.fromCharCode()
- taking input string making it lowercase
-splitting to array
-return array.map().join(' ')



function alphabetPosition(text) 

let alphabet = new Array(26);
for (let i = 0; i<26; ++i)
let char = String.fromCharCode(97 + i);
alphabet[i] = char;


text = text.toLowerCase();

let arr = text.split('');

return arr.map(element => return element = alphabet.indexOf(element+1) ).join(' ');



expected it to return a string of alphabet positions, but got nothing at all. What is wrong with my implementation of Array.map()?










share|improve this question














Other SO 'Replace string with alphabet positions' questions didn't utilize map, which is what I'm trying to learn how to use to solve this.



Problem:
Given a string, replace every letter with its position in the alphabet.
If anything in the text isn't a letter, ignore it and don't return it.
"a" = 1, "b" = 2, etc.



What I've tried is:
-looping over a new array instance and setting the index value to String.fromCharCode()
- taking input string making it lowercase
-splitting to array
-return array.map().join(' ')



function alphabetPosition(text) 

let alphabet = new Array(26);
for (let i = 0; i<26; ++i)
let char = String.fromCharCode(97 + i);
alphabet[i] = char;


text = text.toLowerCase();

let arr = text.split('');

return arr.map(element => return element = alphabet.indexOf(element+1) ).join(' ');



expected it to return a string of alphabet positions, but got nothing at all. What is wrong with my implementation of Array.map()?







javascript






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 26 at 17:45









JimJim

776 bronze badges




776 bronze badges







  • 1





    "nothing at all" really?

    – Jonas Wilms
    Mar 26 at 17:49











  • I think you're at least going to need to remove the 'element = ' portion of the second-to-last line

    – Andrew Castellano
    Mar 26 at 17:51






  • 1





    I guess you are looking for alphabet.indexOf(element)+1 instead of alphabet.indexOf(element+1). Other than that, it should work.

    – Bergi
    Mar 26 at 17:52












  • 1





    "nothing at all" really?

    – Jonas Wilms
    Mar 26 at 17:49











  • I think you're at least going to need to remove the 'element = ' portion of the second-to-last line

    – Andrew Castellano
    Mar 26 at 17:51






  • 1





    I guess you are looking for alphabet.indexOf(element)+1 instead of alphabet.indexOf(element+1). Other than that, it should work.

    – Bergi
    Mar 26 at 17:52







1




1





"nothing at all" really?

– Jonas Wilms
Mar 26 at 17:49





"nothing at all" really?

– Jonas Wilms
Mar 26 at 17:49













I think you're at least going to need to remove the 'element = ' portion of the second-to-last line

– Andrew Castellano
Mar 26 at 17:51





I think you're at least going to need to remove the 'element = ' portion of the second-to-last line

– Andrew Castellano
Mar 26 at 17:51




1




1





I guess you are looking for alphabet.indexOf(element)+1 instead of alphabet.indexOf(element+1). Other than that, it should work.

– Bergi
Mar 26 at 17:52





I guess you are looking for alphabet.indexOf(element)+1 instead of alphabet.indexOf(element+1). Other than that, it should work.

– Bergi
Mar 26 at 17:52












4 Answers
4






active

oldest

votes


















1














Your map() last line of the function was returning the value of
an assignment.



return arr.map(element => return element = alphabet.indexOf(element+1) ).join(' ');


Just alphabet.indexOf(element) would have sufficed.



This will give you the result you want:






alphabetPosition = text => 
let alphabet = new Array(26);
for (let i = 0; i < 26; ++i)
let char = String.fromCharCode(97 + i);
alphabet[i] = char;


return text.toLowerCase().split('').map(element =>
alphabet.indexOf(element)
).join(' ');


console.log(alphabetPosition("This is a string"));





Hope this helps,






share|improve this answer






























    4














    In your map element would be a letter, "a" for example. Then you add (concat) 1 to it, which results in "a1" which is not in your alphabet. Also element = is unneccessary, returning the position is enough.






    share|improve this answer






























      2














      You've complicated the solution, the simplest approach would be to just find the charcode and return that.



      function alphabetPosition(text) 
      let str = '';
      for (var i = 0; i < text.length; i++)
      str += (text[i] + (text.charCodeAt(i) - 96));

      return str;






      share|improve this answer























      • how is str the positions of each letter of the string in the alphabet if you're using text.charCodeAt(i)?

        – Jim
        Mar 26 at 18:04











      • text.charCodeAt(i) will return the char code of the character in the position i. If your string is jim, then text.charCodeAt(0) will return the char code of j

        – varun agarwal
        Mar 26 at 18:07











      • the position of 'j' in the alphabet is 10, however...

        – Jim
        Mar 26 at 18:10






      • 1





        Yeah, hence the - 96 to normalize the values.

        – varun agarwal
        Mar 26 at 18:12


















      2














      I totally understand that is a coding challenge, interview question or likewise so if you really need to use map() you should only return the result of the callback passed to map as follows :



      return arr.map(x => alphabet.indexOf(x) + 1).join(' ')


      However reduce() seems more appropriate in your case :



      return arr.reduce((ac, cv) => ac + (alphabet.indexOf(cv) + 1) + ' ', '')





      share|improve this answer

























        Your Answer






        StackExchange.ifUsing("editor", function ()
        StackExchange.using("externalEditor", function ()
        StackExchange.using("snippets", function ()
        StackExchange.snippets.init();
        );
        );
        , "code-snippets");

        StackExchange.ready(function()
        var channelOptions =
        tags: "".split(" "),
        id: "1"
        ;
        initTagRenderer("".split(" "), "".split(" "), channelOptions);

        StackExchange.using("externalEditor", function()
        // Have to fire editor after snippets, if snippets enabled
        if (StackExchange.settings.snippets.snippetsEnabled)
        StackExchange.using("snippets", function()
        createEditor();
        );

        else
        createEditor();

        );

        function createEditor()
        StackExchange.prepareEditor(
        heartbeatType: 'answer',
        autoActivateHeartbeat: false,
        convertImagesToLinks: true,
        noModals: true,
        showLowRepImageUploadWarning: true,
        reputationToPostImages: 10,
        bindNavPrevention: true,
        postfix: "",
        imageUploader:
        brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
        contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
        allowUrls: true
        ,
        onDemand: true,
        discardSelector: ".discard-answer"
        ,immediatelyShowMarkdownHelp:true
        );



        );













        draft saved

        draft discarded


















        StackExchange.ready(
        function ()
        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55363340%2fhow-to-correctly-use-array-map-for-replacing-string-with-alphabet-position%23new-answer', 'question_page');

        );

        Post as a guest















        Required, but never shown

























        4 Answers
        4






        active

        oldest

        votes








        4 Answers
        4






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        1














        Your map() last line of the function was returning the value of
        an assignment.



        return arr.map(element => return element = alphabet.indexOf(element+1) ).join(' ');


        Just alphabet.indexOf(element) would have sufficed.



        This will give you the result you want:






        alphabetPosition = text => 
        let alphabet = new Array(26);
        for (let i = 0; i < 26; ++i)
        let char = String.fromCharCode(97 + i);
        alphabet[i] = char;


        return text.toLowerCase().split('').map(element =>
        alphabet.indexOf(element)
        ).join(' ');


        console.log(alphabetPosition("This is a string"));





        Hope this helps,






        share|improve this answer



























          1














          Your map() last line of the function was returning the value of
          an assignment.



          return arr.map(element => return element = alphabet.indexOf(element+1) ).join(' ');


          Just alphabet.indexOf(element) would have sufficed.



          This will give you the result you want:






          alphabetPosition = text => 
          let alphabet = new Array(26);
          for (let i = 0; i < 26; ++i)
          let char = String.fromCharCode(97 + i);
          alphabet[i] = char;


          return text.toLowerCase().split('').map(element =>
          alphabet.indexOf(element)
          ).join(' ');


          console.log(alphabetPosition("This is a string"));





          Hope this helps,






          share|improve this answer

























            1












            1








            1







            Your map() last line of the function was returning the value of
            an assignment.



            return arr.map(element => return element = alphabet.indexOf(element+1) ).join(' ');


            Just alphabet.indexOf(element) would have sufficed.



            This will give you the result you want:






            alphabetPosition = text => 
            let alphabet = new Array(26);
            for (let i = 0; i < 26; ++i)
            let char = String.fromCharCode(97 + i);
            alphabet[i] = char;


            return text.toLowerCase().split('').map(element =>
            alphabet.indexOf(element)
            ).join(' ');


            console.log(alphabetPosition("This is a string"));





            Hope this helps,






            share|improve this answer













            Your map() last line of the function was returning the value of
            an assignment.



            return arr.map(element => return element = alphabet.indexOf(element+1) ).join(' ');


            Just alphabet.indexOf(element) would have sufficed.



            This will give you the result you want:






            alphabetPosition = text => 
            let alphabet = new Array(26);
            for (let i = 0; i < 26; ++i)
            let char = String.fromCharCode(97 + i);
            alphabet[i] = char;


            return text.toLowerCase().split('').map(element =>
            alphabet.indexOf(element)
            ).join(' ');


            console.log(alphabetPosition("This is a string"));





            Hope this helps,






            alphabetPosition = text => 
            let alphabet = new Array(26);
            for (let i = 0; i < 26; ++i)
            let char = String.fromCharCode(97 + i);
            alphabet[i] = char;


            return text.toLowerCase().split('').map(element =>
            alphabet.indexOf(element)
            ).join(' ');


            console.log(alphabetPosition("This is a string"));





            alphabetPosition = text => 
            let alphabet = new Array(26);
            for (let i = 0; i < 26; ++i)
            let char = String.fromCharCode(97 + i);
            alphabet[i] = char;


            return text.toLowerCase().split('').map(element =>
            alphabet.indexOf(element)
            ).join(' ');


            console.log(alphabetPosition("This is a string"));






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Mar 26 at 18:00









            Miroslav GlamuzinaMiroslav Glamuzina

            2,8922 gold badges13 silver badges23 bronze badges




            2,8922 gold badges13 silver badges23 bronze badges























                4














                In your map element would be a letter, "a" for example. Then you add (concat) 1 to it, which results in "a1" which is not in your alphabet. Also element = is unneccessary, returning the position is enough.






                share|improve this answer



























                  4














                  In your map element would be a letter, "a" for example. Then you add (concat) 1 to it, which results in "a1" which is not in your alphabet. Also element = is unneccessary, returning the position is enough.






                  share|improve this answer

























                    4












                    4








                    4







                    In your map element would be a letter, "a" for example. Then you add (concat) 1 to it, which results in "a1" which is not in your alphabet. Also element = is unneccessary, returning the position is enough.






                    share|improve this answer













                    In your map element would be a letter, "a" for example. Then you add (concat) 1 to it, which results in "a1" which is not in your alphabet. Also element = is unneccessary, returning the position is enough.







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Mar 26 at 17:48









                    Jonas WilmsJonas Wilms

                    75.9k7 gold badges42 silver badges67 bronze badges




                    75.9k7 gold badges42 silver badges67 bronze badges





















                        2














                        You've complicated the solution, the simplest approach would be to just find the charcode and return that.



                        function alphabetPosition(text) 
                        let str = '';
                        for (var i = 0; i < text.length; i++)
                        str += (text[i] + (text.charCodeAt(i) - 96));

                        return str;






                        share|improve this answer























                        • how is str the positions of each letter of the string in the alphabet if you're using text.charCodeAt(i)?

                          – Jim
                          Mar 26 at 18:04











                        • text.charCodeAt(i) will return the char code of the character in the position i. If your string is jim, then text.charCodeAt(0) will return the char code of j

                          – varun agarwal
                          Mar 26 at 18:07











                        • the position of 'j' in the alphabet is 10, however...

                          – Jim
                          Mar 26 at 18:10






                        • 1





                          Yeah, hence the - 96 to normalize the values.

                          – varun agarwal
                          Mar 26 at 18:12















                        2














                        You've complicated the solution, the simplest approach would be to just find the charcode and return that.



                        function alphabetPosition(text) 
                        let str = '';
                        for (var i = 0; i < text.length; i++)
                        str += (text[i] + (text.charCodeAt(i) - 96));

                        return str;






                        share|improve this answer























                        • how is str the positions of each letter of the string in the alphabet if you're using text.charCodeAt(i)?

                          – Jim
                          Mar 26 at 18:04











                        • text.charCodeAt(i) will return the char code of the character in the position i. If your string is jim, then text.charCodeAt(0) will return the char code of j

                          – varun agarwal
                          Mar 26 at 18:07











                        • the position of 'j' in the alphabet is 10, however...

                          – Jim
                          Mar 26 at 18:10






                        • 1





                          Yeah, hence the - 96 to normalize the values.

                          – varun agarwal
                          Mar 26 at 18:12













                        2












                        2








                        2







                        You've complicated the solution, the simplest approach would be to just find the charcode and return that.



                        function alphabetPosition(text) 
                        let str = '';
                        for (var i = 0; i < text.length; i++)
                        str += (text[i] + (text.charCodeAt(i) - 96));

                        return str;






                        share|improve this answer













                        You've complicated the solution, the simplest approach would be to just find the charcode and return that.



                        function alphabetPosition(text) 
                        let str = '';
                        for (var i = 0; i < text.length; i++)
                        str += (text[i] + (text.charCodeAt(i) - 96));

                        return str;







                        share|improve this answer












                        share|improve this answer



                        share|improve this answer










                        answered Mar 26 at 17:54









                        varun agarwalvarun agarwal

                        1,0882 silver badges9 bronze badges




                        1,0882 silver badges9 bronze badges












                        • how is str the positions of each letter of the string in the alphabet if you're using text.charCodeAt(i)?

                          – Jim
                          Mar 26 at 18:04











                        • text.charCodeAt(i) will return the char code of the character in the position i. If your string is jim, then text.charCodeAt(0) will return the char code of j

                          – varun agarwal
                          Mar 26 at 18:07











                        • the position of 'j' in the alphabet is 10, however...

                          – Jim
                          Mar 26 at 18:10






                        • 1





                          Yeah, hence the - 96 to normalize the values.

                          – varun agarwal
                          Mar 26 at 18:12

















                        • how is str the positions of each letter of the string in the alphabet if you're using text.charCodeAt(i)?

                          – Jim
                          Mar 26 at 18:04











                        • text.charCodeAt(i) will return the char code of the character in the position i. If your string is jim, then text.charCodeAt(0) will return the char code of j

                          – varun agarwal
                          Mar 26 at 18:07











                        • the position of 'j' in the alphabet is 10, however...

                          – Jim
                          Mar 26 at 18:10






                        • 1





                          Yeah, hence the - 96 to normalize the values.

                          – varun agarwal
                          Mar 26 at 18:12
















                        how is str the positions of each letter of the string in the alphabet if you're using text.charCodeAt(i)?

                        – Jim
                        Mar 26 at 18:04





                        how is str the positions of each letter of the string in the alphabet if you're using text.charCodeAt(i)?

                        – Jim
                        Mar 26 at 18:04













                        text.charCodeAt(i) will return the char code of the character in the position i. If your string is jim, then text.charCodeAt(0) will return the char code of j

                        – varun agarwal
                        Mar 26 at 18:07





                        text.charCodeAt(i) will return the char code of the character in the position i. If your string is jim, then text.charCodeAt(0) will return the char code of j

                        – varun agarwal
                        Mar 26 at 18:07













                        the position of 'j' in the alphabet is 10, however...

                        – Jim
                        Mar 26 at 18:10





                        the position of 'j' in the alphabet is 10, however...

                        – Jim
                        Mar 26 at 18:10




                        1




                        1





                        Yeah, hence the - 96 to normalize the values.

                        – varun agarwal
                        Mar 26 at 18:12





                        Yeah, hence the - 96 to normalize the values.

                        – varun agarwal
                        Mar 26 at 18:12











                        2














                        I totally understand that is a coding challenge, interview question or likewise so if you really need to use map() you should only return the result of the callback passed to map as follows :



                        return arr.map(x => alphabet.indexOf(x) + 1).join(' ')


                        However reduce() seems more appropriate in your case :



                        return arr.reduce((ac, cv) => ac + (alphabet.indexOf(cv) + 1) + ' ', '')





                        share|improve this answer



























                          2














                          I totally understand that is a coding challenge, interview question or likewise so if you really need to use map() you should only return the result of the callback passed to map as follows :



                          return arr.map(x => alphabet.indexOf(x) + 1).join(' ')


                          However reduce() seems more appropriate in your case :



                          return arr.reduce((ac, cv) => ac + (alphabet.indexOf(cv) + 1) + ' ', '')





                          share|improve this answer

























                            2












                            2








                            2







                            I totally understand that is a coding challenge, interview question or likewise so if you really need to use map() you should only return the result of the callback passed to map as follows :



                            return arr.map(x => alphabet.indexOf(x) + 1).join(' ')


                            However reduce() seems more appropriate in your case :



                            return arr.reduce((ac, cv) => ac + (alphabet.indexOf(cv) + 1) + ' ', '')





                            share|improve this answer













                            I totally understand that is a coding challenge, interview question or likewise so if you really need to use map() you should only return the result of the callback passed to map as follows :



                            return arr.map(x => alphabet.indexOf(x) + 1).join(' ')


                            However reduce() seems more appropriate in your case :



                            return arr.reduce((ac, cv) => ac + (alphabet.indexOf(cv) + 1) + ' ', '')






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Mar 26 at 17:56









                            BJRINTBJRINT

                            3761 silver badge8 bronze badges




                            3761 silver badge8 bronze badges



























                                draft saved

                                draft discarded
















































                                Thanks for contributing an answer to Stack Overflow!


                                • Please be sure to answer the question. Provide details and share your research!

                                But avoid


                                • Asking for help, clarification, or responding to other answers.

                                • Making statements based on opinion; back them up with references or personal experience.

                                To learn more, see our tips on writing great answers.




                                draft saved


                                draft discarded














                                StackExchange.ready(
                                function ()
                                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55363340%2fhow-to-correctly-use-array-map-for-replacing-string-with-alphabet-position%23new-answer', 'question_page');

                                );

                                Post as a guest















                                Required, but never shown





















































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown

































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown







                                Popular posts from this blog

                                Kamusi Yaliyomo Aina za kamusi | Muundo wa kamusi | Faida za kamusi | Dhima ya picha katika kamusi | Marejeo | Tazama pia | Viungo vya nje | UrambazajiKuhusu kamusiGo-SwahiliWiki-KamusiKamusi ya Kiswahili na Kiingerezakuihariri na kuongeza habari

                                SQL error code 1064 with creating Laravel foreign keysForeign key constraints: When to use ON UPDATE and ON DELETEDropping column with foreign key Laravel error: General error: 1025 Error on renameLaravel SQL Can't create tableLaravel Migration foreign key errorLaravel php artisan migrate:refresh giving a syntax errorSQLSTATE[42S01]: Base table or view already exists or Base table or view already exists: 1050 Tableerror in migrating laravel file to xampp serverSyntax error or access violation: 1064:syntax to use near 'unsigned not null, modelName varchar(191) not null, title varchar(191) not nLaravel cannot create new table field in mysqlLaravel 5.7:Last migration creates table but is not registered in the migration table

                                은진 송씨 목차 역사 본관 분파 인물 조선 왕실과의 인척 관계 집성촌 항렬자 인구 같이 보기 각주 둘러보기 메뉴은진 송씨세종실록 149권, 지리지 충청도 공주목 은진현