Styjun

The ultimate goal is to take a multi-line user input and combine it all into one single string that can be used later in my code. When I use the code below every sinle line is printed perfectly as output. However, when I use the commented code my end result is not correct.

System.out.println("Enter a string: ");

StringBuilder sb1 = new StringBuilder();
Scanner scanner = new Scanner(System.in);
while (scanner.hasNext()) 
 System.out.println(scanner.nextLine());
 // String line = scanner.nextLine();
 // sb1.append(line);


// System.out.println(sb1.toString());

I'm assuming what you want is for a new line after every input so after

sb1.append(line);

add

sb1.append(System.getProperty("line.separator"));

Edit: (because i dont know how to post code in comments)
This will basically keep asking for input until user types in "exit" which it then will break from while loop and print out the string. You can append commas or spaces to separate them after appending line.

I'm not sure if your original problem was because you weren't breaking from loop or because you called nextLine twice in print and assigning it to line

 public static void main(String[] args) 
 System.out.println("Enter a string: ");
 StringBuilder sb = new StringBuilder();
 try (Scanner scanner = new Scanner(System.in)) 
 String input;
 while (!(input = scanner.nextLine()).equals("exit")) 
 sb.append(input);
 
 
 System.out.println(sb.toString());
 

You can try this.

private static String readFile(String pathname) throws IOException 

 File file = new File(pathname);
 StringBuilder fileContents = new StringBuilder((int)file.length()); 

 try (Scanner scanner = new Scanner(file)) 
 while(scanner.hasNextLine()) 
 fileContents.append(scanner.nextLine() );
 
 return fileContents.toString();
 

This code will read all lines from a text file and give us as a single string as return object.

The following is the pom.xml file for your reference:

<project xmlns="http://maven.apache.org/POM/4.0.0"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
 xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 
 http://maven.apache.org/xsd/maven-4.0.0.xsd">
 <modelVersion>4.0.0</modelVersion>
 <groupId>json_example</groupId>
 <artifactId>json_example</artifactId>
 <version>0.0.1-SNAPSHOT</version>
 <dependencies>
 <dependency>
 <groupId>javax.json</groupId>
 <artifactId>javax.json-api</artifactId>
 <version>1.1.4</version>
 </dependency>
 <dependency>
 <groupId>org.glassfish</groupId>
 <artifactId>javax.json</artifactId>
 <version>1.1.4</version>
 </dependency>
 </dependencies>
</project>

Then add maven dependent jar files to your classpath.

import javax.json.Json;
import javax.json.JsonObject;
import javax.json.JsonReader;

public static void main(String[] args) 
 System.out.println("Enter a valid JSON string: ");

 try (// Create JsonReader from Json.
 JsonReader reader = Json.createReader(System.in)) 
 // Get the JsonObject structure from JsonReader.
 JsonObject jsonObj = reader.readObject();
 System.out.println(jsonObj.toString());
 catch (Exception e) 
 e.printStackTrace();