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Function overloading two functions only differ by a default parameter

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0

Two methods with the same name and have 2 same parameters and one of the methods has an extra optional(default) parameter.

So when I called a method as shown in the image why method with an optional parameter not called?

Why answer is ab not abc?

func call(x:String, y:String, z:String! = "c") -> String
 //z parameater is optional
 print("3 parameater!")
 return x+y+z;


func call(x:String, y:String) -> String
 print("2 parameater!")
 return x+y;


call(x: "a", y: "b")

function oop overloading

share|improve this question

edited Mar 28 at 14:50

Zohar Peled

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asked Mar 28 at 13:01

iCoderz DevelopersiCoderz Developers

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• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Post code, not screenshots of code.
  
  – jwismar
  Mar 28 at 13:06
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What language is that? .overload resolution is based on rules. These defer between different languages.
  
  – Zohar Peled
  Mar 28 at 14:51
  

  
  
  
  

add a comment
 | 

0

Two methods with the same name and have 2 same parameters and one of the methods has an extra optional(default) parameter.

So when I called a method as shown in the image why method with an optional parameter not called?

Why answer is ab not abc?

func call(x:String, y:String, z:String! = "c") -> String
 //z parameater is optional
 print("3 parameater!")
 return x+y+z;


func call(x:String, y:String) -> String
 print("2 parameater!")
 return x+y;


call(x: "a", y: "b")

function oop overloading

share|improve this question

edited Mar 28 at 14:50

Zohar Peled

62.2k77 gold badges3939 silver badges8080 bronze badges

asked Mar 28 at 13:01

iCoderz DevelopersiCoderz Developers

18322 silver badges1313 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Post code, not screenshots of code.
  
  – jwismar
  Mar 28 at 13:06
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What language is that? .overload resolution is based on rules. These defer between different languages.
  
  – Zohar Peled
  Mar 28 at 14:51
  

  
  
  
  

add a comment
 | 

Two methods with the same name and have 2 same parameters and one of the methods has an extra optional(default) parameter.

So when I called a method as shown in the image why method with an optional parameter not called?

Why answer is ab not abc?

func call(x:String, y:String, z:String! = "c") -> String
 //z parameater is optional
 print("3 parameater!")
 return x+y+z;


func call(x:String, y:String) -> String
 print("2 parameater!")
 return x+y;


call(x: "a", y: "b")

function oop overloading

share|improve this question

edited Mar 28 at 14:50

Zohar Peled

62.2k77 gold badges3939 silver badges8080 bronze badges

asked Mar 28 at 13:01

iCoderz DevelopersiCoderz Developers

18322 silver badges1313 bronze badges

func call(x:String, y:String, z:String! = "c") -> String
 //z parameater is optional
 print("3 parameater!")
 return x+y+z;


func call(x:String, y:String) -> String
 print("2 parameater!")
 return x+y;


call(x: "a", y: "b")

share|improve this question

edited Mar 28 at 14:50

Zohar Peled

62.2k77 gold badges3939 silver badges8080 bronze badges

asked Mar 28 at 13:01

iCoderz DevelopersiCoderz Developers

18322 silver badges1313 bronze badges

share|improve this question

edited Mar 28 at 14:50

Zohar Peled

62.2k77 gold badges3939 silver badges8080 bronze badges

asked Mar 28 at 13:01

iCoderz DevelopersiCoderz Developers

18322 silver badges1313 bronze badges

edited Mar 28 at 14:50

Zohar Peled

62.2k77 gold badges3939 silver badges8080 bronze badges

edited Mar 28 at 14:50

Zohar Peled

62.2k77 gold badges3939 silver badges8080 bronze badges

asked Mar 28 at 13:01

iCoderz DevelopersiCoderz Developers

18322 silver badges1313 bronze badges

asked Mar 28 at 13:01

iCoderz DevelopersiCoderz Developers

18322 silver badges1313 bronze badges

1 Answer
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Because when you omit the optional parameter, the method without it is a better match for the call.

The scenario you are describing makes no sense - if there's already an overload with the first two parameters, the third one should not be optional.

Overload resolution rules differ between languages/frameworks - but this is kind of an obvious choice and I seriously doubt any compiler would ever pick the method with an extra optional parameter.

In fact, I'm surprised this even compiles (I've checked an equivalent c# code, and it does compile, without even a warning)

share|improve this answer

edited Mar 28 at 15:57

jwismar

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answered Mar 28 at 14:55

Zohar PeledZohar Peled

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add a comment
 | 

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1

Because when you omit the optional parameter, the method without it is a better match for the call.

The scenario you are describing makes no sense - if there's already an overload with the first two parameters, the third one should not be optional.

Overload resolution rules differ between languages/frameworks - but this is kind of an obvious choice and I seriously doubt any compiler would ever pick the method with an extra optional parameter.

In fact, I'm surprised this even compiles (I've checked an equivalent c# code, and it does compile, without even a warning)

share|improve this answer

edited Mar 28 at 15:57

jwismar

11.2k33 gold badges2424 silver badges4242 bronze badges

answered Mar 28 at 14:55

Zohar PeledZohar Peled

62.2k77 gold badges3939 silver badges8080 bronze badges

add a comment
 | 

1

Because when you omit the optional parameter, the method without it is a better match for the call.

The scenario you are describing makes no sense - if there's already an overload with the first two parameters, the third one should not be optional.

Overload resolution rules differ between languages/frameworks - but this is kind of an obvious choice and I seriously doubt any compiler would ever pick the method with an extra optional parameter.

In fact, I'm surprised this even compiles (I've checked an equivalent c# code, and it does compile, without even a warning)

share|improve this answer

edited Mar 28 at 15:57

jwismar

11.2k33 gold badges2424 silver badges4242 bronze badges

answered Mar 28 at 14:55

Zohar PeledZohar Peled

62.2k77 gold badges3939 silver badges8080 bronze badges

add a comment
 | 

Because when you omit the optional parameter, the method without it is a better match for the call.

The scenario you are describing makes no sense - if there's already an overload with the first two parameters, the third one should not be optional.

Overload resolution rules differ between languages/frameworks - but this is kind of an obvious choice and I seriously doubt any compiler would ever pick the method with an extra optional parameter.

In fact, I'm surprised this even compiles (I've checked an equivalent c# code, and it does compile, without even a warning)

share|improve this answer

edited Mar 28 at 15:57

jwismar

11.2k33 gold badges2424 silver badges4242 bronze badges

answered Mar 28 at 14:55

Zohar PeledZohar Peled

62.2k77 gold badges3939 silver badges8080 bronze badges

share|improve this answer

edited Mar 28 at 15:57

jwismar

11.2k33 gold badges2424 silver badges4242 bronze badges

answered Mar 28 at 14:55

Zohar PeledZohar Peled

62.2k77 gold badges3939 silver badges8080 bronze badges

edited Mar 28 at 15:57

jwismar

11.2k33 gold badges2424 silver badges4242 bronze badges

edited Mar 28 at 15:57

jwismar

11.2k33 gold badges2424 silver badges4242 bronze badges

answered Mar 28 at 14:55

Zohar PeledZohar Peled

62.2k77 gold badges3939 silver badges8080 bronze badges

answered Mar 28 at 14:55

Zohar PeledZohar Peled

62.2k77 gold badges3939 silver badges8080 bronze badges