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The modules in my package have got “self” attributes that bypass __init__.py

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I've built a package in Python 3. The problem is that when I import the package, every module has got those functions specified in __init__.py AND an attribute with the same name as the module (say package.package) that has got all the functions in the actual package.

I've tried to change my __init__.py files but I guess I'm not properly understanding how it works.
My package looks like that:

package/
 __init__.py
 package.py (same name used here)
 _someprivatestuff.py
 io/
 __init__.py
 io.py
 vis/
 __init__.py
 vis.py

The fist __init__.py contains the following imports:

from .package import exception1
from .package import exception2
from .package import class1
from .package import class2
from .package import class3

Exceptions and classes are in package.py.

Now, if I import the module, I've got access to every other functions in package.py and the modules imported in this python files:

import package

package.class1 # this should output 'package.class1'
>>> <class 'package.package.class1'>
package.package.someprivateclass # package.package is somehow accesible
>>> <class 'package.package.someprivateclass'>

python-3.x installation package

share|improve this question

asked Mar 28 at 12:54

carrascocarrasco

2588 bronze badges

add a comment
 | 

0

I've built a package in Python 3. The problem is that when I import the package, every module has got those functions specified in __init__.py AND an attribute with the same name as the module (say package.package) that has got all the functions in the actual package.

I've tried to change my __init__.py files but I guess I'm not properly understanding how it works.
My package looks like that:

package/
 __init__.py
 package.py (same name used here)
 _someprivatestuff.py
 io/
 __init__.py
 io.py
 vis/
 __init__.py
 vis.py

The fist __init__.py contains the following imports:

from .package import exception1
from .package import exception2
from .package import class1
from .package import class2
from .package import class3

Exceptions and classes are in package.py.

Now, if I import the module, I've got access to every other functions in package.py and the modules imported in this python files:

import package

package.class1 # this should output 'package.class1'
>>> <class 'package.package.class1'>
package.package.someprivateclass # package.package is somehow accesible
>>> <class 'package.package.someprivateclass'>

python-3.x installation package

share|improve this question

asked Mar 28 at 12:54

carrascocarrasco

2588 bronze badges

add a comment
 | 

I've built a package in Python 3. The problem is that when I import the package, every module has got those functions specified in __init__.py AND an attribute with the same name as the module (say package.package) that has got all the functions in the actual package.

I've tried to change my __init__.py files but I guess I'm not properly understanding how it works.
My package looks like that:

package/
 __init__.py
 package.py (same name used here)
 _someprivatestuff.py
 io/
 __init__.py
 io.py
 vis/
 __init__.py
 vis.py

The fist __init__.py contains the following imports:

from .package import exception1
from .package import exception2
from .package import class1
from .package import class2
from .package import class3

Exceptions and classes are in package.py.

Now, if I import the module, I've got access to every other functions in package.py and the modules imported in this python files:

import package

package.class1 # this should output 'package.class1'
>>> <class 'package.package.class1'>
package.package.someprivateclass # package.package is somehow accesible
>>> <class 'package.package.someprivateclass'>

python-3.x installation package

share|improve this question

asked Mar 28 at 12:54

carrascocarrasco

2588 bronze badges

package/
 __init__.py
 package.py (same name used here)
 _someprivatestuff.py
 io/
 __init__.py
 io.py
 vis/
 __init__.py
 vis.py

from .package import exception1
from .package import exception2
from .package import class1
from .package import class2
from .package import class3

import package

package.class1 # this should output 'package.class1'
>>> <class 'package.package.class1'>
package.package.someprivateclass # package.package is somehow accesible
>>> <class 'package.package.someprivateclass'>

share|improve this question

asked Mar 28 at 12:54

carrascocarrasco

2588 bronze badges

share|improve this question

asked Mar 28 at 12:54

carrascocarrasco

2588 bronze badges

asked Mar 28 at 12:54

carrascocarrasco

2588 bronze badges

asked Mar 28 at 12:54

carrascocarrasco

2588 bronze badges

1 Answer
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package.package is a module, it has functions in it, so you can access them as package.package.someprivateclass. Just because you've imported some names from .package into __init__.py doesn't mean that the names you haven't imported will be hidden.

share|improve this answer

answered Mar 28 at 21:52

Ned BatchelderNed Batchelder

275k5555 gold badges466466 silver badges584584 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you for your response, that makes sense. So would it be a good practice to rename package.py to something like core.py or is it ok the way it is? (Obviously 'package' isn't the real name of the package).
  
  – carrasco
  Mar 29 at 7:34
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  package.package is odd, I would change it.
  
  – Ned Batchelder
  Mar 29 at 11:48
  

  
  
  
  

add a comment
 | 

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0

package.package is a module, it has functions in it, so you can access them as package.package.someprivateclass. Just because you've imported some names from .package into __init__.py doesn't mean that the names you haven't imported will be hidden.

share|improve this answer

answered Mar 28 at 21:52

Ned BatchelderNed Batchelder

275k5555 gold badges466466 silver badges584584 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you for your response, that makes sense. So would it be a good practice to rename package.py to something like core.py or is it ok the way it is? (Obviously 'package' isn't the real name of the package).
  
  – carrasco
  Mar 29 at 7:34
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  package.package is odd, I would change it.
  
  – Ned Batchelder
  Mar 29 at 11:48
  

  
  
  
  

add a comment
 | 

0

package.package is a module, it has functions in it, so you can access them as package.package.someprivateclass. Just because you've imported some names from .package into __init__.py doesn't mean that the names you haven't imported will be hidden.

share|improve this answer

answered Mar 28 at 21:52

Ned BatchelderNed Batchelder

275k5555 gold badges466466 silver badges584584 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you for your response, that makes sense. So would it be a good practice to rename package.py to something like core.py or is it ok the way it is? (Obviously 'package' isn't the real name of the package).
  
  – carrasco
  Mar 29 at 7:34
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  package.package is odd, I would change it.
  
  – Ned Batchelder
  Mar 29 at 11:48
  

  
  
  
  

add a comment
 | 

package.package is a module, it has functions in it, so you can access them as package.package.someprivateclass. Just because you've imported some names from .package into __init__.py doesn't mean that the names you haven't imported will be hidden.

share|improve this answer

answered Mar 28 at 21:52

Ned BatchelderNed Batchelder

275k5555 gold badges466466 silver badges584584 bronze badges

share|improve this answer

answered Mar 28 at 21:52

Ned BatchelderNed Batchelder

275k5555 gold badges466466 silver badges584584 bronze badges

answered Mar 28 at 21:52

Ned BatchelderNed Batchelder

275k5555 gold badges466466 silver badges584584 bronze badges

answered Mar 28 at 21:52

Ned BatchelderNed Batchelder

275k5555 gold badges466466 silver badges584584 bronze badges