Styjun

Temporarily moving a SQL Server 2016 database to SQL Server 2017 and then moving back. Is it possible?

How should I avoid someone patenting technology in my paper/poster?

What is a Heptagon Number™?

What can a pilot do if an air traffic controller is incapacitated?

I reverse the source code, you negate the input!

How to influence manager to not schedule team meetings during lunch?

Can planetary bodies have a second axis of rotation?

Linear independence of element-wise powers of positive vectors

Сardinality estimation of partially covering range predicates

Why are Fuji lenses more expensive than others?

Manager manipulates my leaves, what's in it for him?

How is the problem, G has no triangle in Logspace?

C# Fastest way to do Array Table Lookup with Integer Index

Minimize taxes now that I earn more

Cheap antenna for new HF HAM

How can I prevent soul energy from dissipating?

How to ask a man to not take up more than one seat on public transport while avoiding conflict?

Do the villains know Batman has no superpowers?

How does one calculate the distribution of the Matt Colville way of rolling stats?

Is it possible that the shadow of The Moon is a single dot during solar eclipse?

Why there so many pitch control surfaces on the Piaggio P180 Avanti?

Do liquid propellant rocket engines experience thrust oscillation?

As an employer, can I compel my employees to vote?

In a jam session, when asked which key my non-transposing instrument (like a violin) is in, what do I answer?

Get value from dynamic list of object using javascript [duplicate]

Add a property to a JavaScript object using a variable as the name?What is the most efficient way to deep clone an object in JavaScript?Which “href” value should I use for JavaScript links, “#” or “javascript:void(0)”?How can I merge properties of two JavaScript objects dynamically?How do I remove a property from a JavaScript object?How do you get a timestamp in JavaScript?How do I check if an array includes an object in JavaScript?How can I get query string values in JavaScript?Get the current URL with JavaScript?Checking if a key exists in a JavaScript object?How do I remove a particular element from an array in JavaScript?

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;

1

This question already has an answer here:

• 
  Add a property to a JavaScript object using a variable as the name?
  
  11 answers
  
  

Seeking the below result with dynamic list of object using javascript. Defined approach getting me undefined index of value.

Javascript Code

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_.key;
 


console.log(obj)

Desired Result

 "1": "abc",
 "2": "def"

javascript object

share|improve this question

edited Aug 26 at 8:59

Azzabi Haythem

1,70555 gold badges1717 silver badges2222 bronze badges

asked Mar 28 at 14:51

Query MasterQuery Master

4,96133 gold badges2626 silver badges5050 bronze badges

marked as duplicate by Nina Scholz, Robin Zigmond, Jaromanda X javascript
Users with the  javascript badge can single-handedly close javascript questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
);
);
Mar 28 at 14:57

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  obj_[key]; instead of obj_.key; - I can't believe this isn't a duplicate of about 100 questions
  
  – Jaromanda X
  Mar 28 at 14:54
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  your SO search foo is superior to mine @RobinZigmond
  
  – Jaromanda X
  Mar 28 at 14:56
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JaromandaX I confess I used Google, never tried using SO's own search :) As you say there are loads I could have marked this as a dupe of
  
  – Robin Zigmond
  Mar 28 at 14:57
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  ahh @RobinZigmond - that is indeed very wise
  
  – Jaromanda X
  Mar 28 at 14:58
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JaromandaX It might be is duplicate which i have posted here but sometime it happening with person was not be able to search exact indenfied thing which he has needed. Thankyou for you support its really helpful for me
  
  – Query Master
  Mar 28 at 15:05
  
  

  
  
  
  

 | 
show 1 more comment

1

This question already has an answer here:

• 
  Add a property to a JavaScript object using a variable as the name?
  
  11 answers
  
  

Seeking the below result with dynamic list of object using javascript. Defined approach getting me undefined index of value.

Javascript Code

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_.key;
 


console.log(obj)

Desired Result

 "1": "abc",
 "2": "def"

javascript object

share|improve this question

edited Aug 26 at 8:59

Azzabi Haythem

1,70555 gold badges1717 silver badges2222 bronze badges

asked Mar 28 at 14:51

Query MasterQuery Master

4,96133 gold badges2626 silver badges5050 bronze badges

marked as duplicate by Nina Scholz, Robin Zigmond, Jaromanda X javascript
Users with the  javascript badge can single-handedly close javascript questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
);
);
Mar 28 at 14:57

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  obj_[key]; instead of obj_.key; - I can't believe this isn't a duplicate of about 100 questions
  
  – Jaromanda X
  Mar 28 at 14:54
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  your SO search foo is superior to mine @RobinZigmond
  
  – Jaromanda X
  Mar 28 at 14:56
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JaromandaX I confess I used Google, never tried using SO's own search :) As you say there are loads I could have marked this as a dupe of
  
  – Robin Zigmond
  Mar 28 at 14:57
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  ahh @RobinZigmond - that is indeed very wise
  
  – Jaromanda X
  Mar 28 at 14:58
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JaromandaX It might be is duplicate which i have posted here but sometime it happening with person was not be able to search exact indenfied thing which he has needed. Thankyou for you support its really helpful for me
  
  – Query Master
  Mar 28 at 15:05
  
  

  
  
  
  

 | 
show 1 more comment

This question already has an answer here:

• 
  Add a property to a JavaScript object using a variable as the name?
  
  11 answers
  
  

Seeking the below result with dynamic list of object using javascript. Defined approach getting me undefined index of value.

Javascript Code

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_.key;
 


console.log(obj)

Desired Result

 "1": "abc",
 "2": "def"

javascript object

share|improve this question

edited Aug 26 at 8:59

Azzabi Haythem

1,70555 gold badges1717 silver badges2222 bronze badges

asked Mar 28 at 14:51

Query MasterQuery Master

4,96133 gold badges2626 silver badges5050 bronze badges

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_.key;
 


console.log(obj)

 "1": "abc",
 "2": "def"

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_.key;
 


console.log(obj)

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_.key;
 


console.log(obj)

share|improve this question

edited Aug 26 at 8:59

Azzabi Haythem

1,70555 gold badges1717 silver badges2222 bronze badges

asked Mar 28 at 14:51

Query MasterQuery Master

4,96133 gold badges2626 silver badges5050 bronze badges

share|improve this question

edited Aug 26 at 8:59

Azzabi Haythem

1,70555 gold badges1717 silver badges2222 bronze badges

asked Mar 28 at 14:51

Query MasterQuery Master

4,96133 gold badges2626 silver badges5050 bronze badges

edited Aug 26 at 8:59

Azzabi Haythem

1,70555 gold badges1717 silver badges2222 bronze badges

edited Aug 26 at 8:59

Azzabi Haythem

1,70555 gold badges1717 silver badges2222 bronze badges

asked Mar 28 at 14:51

Query MasterQuery Master

4,96133 gold badges2626 silver badges5050 bronze badges

asked Mar 28 at 14:51

Query MasterQuery Master

4,96133 gold badges2626 silver badges5050 bronze badges

4 Answers
4

active

oldest

votes

3

You can use bracket notation. You need to do obj_[key] and not obj_.key.

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj)

share|improve this answer

edited Mar 28 at 14:56

answered Mar 28 at 14:52

R3tepR3tep

9,24088 gold badges2929 silver badges6464 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  You save my day thankyou.
  
  – Query Master
  Mar 28 at 15:07
  

  
  
  
  

add a comment
 | 

1

You need a property accessor in bracket notation for the key.

obj[num] = obj_[key];
// ^^^^^

Then you could use startsWith instead of includes for checking the starting part of a string.

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.startsWith("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj);

share|improve this answer

answered Mar 28 at 14:52

Nina ScholzNina Scholz

226k1616 gold badges142142 silver badges209209 bronze badges

add a comment
 | 

0

Alternative chain way:

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"
;

Object.keys(obj_)
 .map(key=>key.replace(/^D+/g, ''))
 .map(key=>obj[key]=obj_[key]);

console.log(obj);

share|improve this answer

answered Mar 28 at 14:56

ZydnarZydnar

9801111 silver badges2222 bronze badges

add a comment
 | 

0

You can do:

const obj_ = "clist_1": "abc","clist_2": "def","branch_1": "efg";
const obj = Object.keys(obj_)
 .filter(k => k.startsWith('clist_'))
 .reduce((a, c) => (a[c.match(/d+/g)] = obj_[c], a), );
 
console.log(obj);

share|improve this answer

answered Mar 28 at 15:10

Yosvel QuinteroYosvel Quintero

12.9k44 gold badges2727 silver badges3131 bronze badges

add a comment
 | 

3

You can use bracket notation. You need to do obj_[key] and not obj_.key.

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj)

share|improve this answer

edited Mar 28 at 14:56

answered Mar 28 at 14:52

R3tepR3tep

9,24088 gold badges2929 silver badges6464 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  You save my day thankyou.
  
  – Query Master
  Mar 28 at 15:07
  

  
  
  
  

add a comment
 | 

3

You can use bracket notation. You need to do obj_[key] and not obj_.key.

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj)

share|improve this answer

edited Mar 28 at 14:56

answered Mar 28 at 14:52

R3tepR3tep

9,24088 gold badges2929 silver badges6464 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  You save my day thankyou.
  
  – Query Master
  Mar 28 at 15:07
  

  
  
  
  

add a comment
 | 

You can use bracket notation. You need to do obj_[key] and not obj_.key.

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj)

share|improve this answer

edited Mar 28 at 14:56

answered Mar 28 at 14:52

R3tepR3tep

9,24088 gold badges2929 silver badges6464 bronze badges

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj)

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj)

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.includes("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj)

share|improve this answer

edited Mar 28 at 14:56

answered Mar 28 at 14:52

R3tepR3tep

9,24088 gold badges2929 silver badges6464 bronze badges

answered Mar 28 at 14:52

R3tepR3tep

9,24088 gold badges2929 silver badges6464 bronze badges

answered Mar 28 at 14:52

R3tepR3tep

9,24088 gold badges2929 silver badges6464 bronze badges

1

You need a property accessor in bracket notation for the key.

obj[num] = obj_[key];
// ^^^^^

Then you could use startsWith instead of includes for checking the starting part of a string.

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.startsWith("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj);

share|improve this answer

answered Mar 28 at 14:52

Nina ScholzNina Scholz

226k1616 gold badges142142 silver badges209209 bronze badges

add a comment
 | 

1

You need a property accessor in bracket notation for the key.

obj[num] = obj_[key];
// ^^^^^

Then you could use startsWith instead of includes for checking the starting part of a string.

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.startsWith("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj);

share|improve this answer

answered Mar 28 at 14:52

Nina ScholzNina Scholz

226k1616 gold badges142142 silver badges209209 bronze badges

add a comment
 | 

You need a property accessor in bracket notation for the key.

obj[num] = obj_[key];
// ^^^^^

Then you could use startsWith instead of includes for checking the starting part of a string.

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.startsWith("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj);

share|improve this answer

answered Mar 28 at 14:52

Nina ScholzNina Scholz

226k1616 gold badges142142 silver badges209209 bronze badges

obj[num] = obj_[key];
// ^^^^^

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.startsWith("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj);

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.startsWith("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj);

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"

for (let key in obj_) 
 if (key.startsWith("clist_")) 
 let num = key.replace(/^D+/g, '');
 obj[num] = obj_[key];
 


console.log(obj);

share|improve this answer

answered Mar 28 at 14:52

Nina ScholzNina Scholz

226k1616 gold badges142142 silver badges209209 bronze badges

answered Mar 28 at 14:52

Nina ScholzNina Scholz

226k1616 gold badges142142 silver badges209209 bronze badges

answered Mar 28 at 14:52

Nina ScholzNina Scholz

226k1616 gold badges142142 silver badges209209 bronze badges

0

Alternative chain way:

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"
;

Object.keys(obj_)
 .map(key=>key.replace(/^D+/g, ''))
 .map(key=>obj[key]=obj_[key]);

console.log(obj);

share|improve this answer

answered Mar 28 at 14:56

ZydnarZydnar

9801111 silver badges2222 bronze badges

add a comment
 | 

0

Alternative chain way:

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"
;

Object.keys(obj_)
 .map(key=>key.replace(/^D+/g, ''))
 .map(key=>obj[key]=obj_[key]);

console.log(obj);

share|improve this answer

answered Mar 28 at 14:56

ZydnarZydnar

9801111 silver badges2222 bronze badges

add a comment
 | 

Alternative chain way:

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"
;

Object.keys(obj_)
 .map(key=>key.replace(/^D+/g, ''))
 .map(key=>obj[key]=obj_[key]);

console.log(obj);

share|improve this answer

answered Mar 28 at 14:56

ZydnarZydnar

9801111 silver badges2222 bronze badges

var obj = ;
var obj_ = 
 "clist_1": "abc",
 "clist_2": "def",
 "branch_1": "efg"
;

Object.keys(obj_)
 .map(key=>key.replace(/^D+/g, ''))
 .map(key=>obj[key]=obj_[key]);

console.log(obj);

share|improve this answer

answered Mar 28 at 14:56

ZydnarZydnar

9801111 silver badges2222 bronze badges

answered Mar 28 at 14:56

ZydnarZydnar

9801111 silver badges2222 bronze badges

answered Mar 28 at 14:56

ZydnarZydnar

9801111 silver badges2222 bronze badges

0

You can do:

const obj_ = "clist_1": "abc","clist_2": "def","branch_1": "efg";
const obj = Object.keys(obj_)
 .filter(k => k.startsWith('clist_'))
 .reduce((a, c) => (a[c.match(/d+/g)] = obj_[c], a), );
 
console.log(obj);

share|improve this answer

answered Mar 28 at 15:10

Yosvel QuinteroYosvel Quintero

12.9k44 gold badges2727 silver badges3131 bronze badges

add a comment
 | 

0

You can do:

const obj_ = "clist_1": "abc","clist_2": "def","branch_1": "efg";
const obj = Object.keys(obj_)
 .filter(k => k.startsWith('clist_'))
 .reduce((a, c) => (a[c.match(/d+/g)] = obj_[c], a), );
 
console.log(obj);

share|improve this answer

answered Mar 28 at 15:10

Yosvel QuinteroYosvel Quintero

12.9k44 gold badges2727 silver badges3131 bronze badges

add a comment
 | 

You can do:

const obj_ = "clist_1": "abc","clist_2": "def","branch_1": "efg";
const obj = Object.keys(obj_)
 .filter(k => k.startsWith('clist_'))
 .reduce((a, c) => (a[c.match(/d+/g)] = obj_[c], a), );
 
console.log(obj);

share|improve this answer

answered Mar 28 at 15:10

Yosvel QuinteroYosvel Quintero

12.9k44 gold badges2727 silver badges3131 bronze badges

const obj_ = "clist_1": "abc","clist_2": "def","branch_1": "efg";
const obj = Object.keys(obj_)
 .filter(k => k.startsWith('clist_'))
 .reduce((a, c) => (a[c.match(/d+/g)] = obj_[c], a), );
 
console.log(obj);

const obj_ = "clist_1": "abc","clist_2": "def","branch_1": "efg";
const obj = Object.keys(obj_)
 .filter(k => k.startsWith('clist_'))
 .reduce((a, c) => (a[c.match(/d+/g)] = obj_[c], a), );
 
console.log(obj);

const obj_ = "clist_1": "abc","clist_2": "def","branch_1": "efg";
const obj = Object.keys(obj_)
 .filter(k => k.startsWith('clist_'))
 .reduce((a, c) => (a[c.match(/d+/g)] = obj_[c], a), );
 
console.log(obj);

share|improve this answer

answered Mar 28 at 15:10

Yosvel QuinteroYosvel Quintero

12.9k44 gold badges2727 silver badges3131 bronze badges

answered Mar 28 at 15:10

Yosvel QuinteroYosvel Quintero

12.9k44 gold badges2727 silver badges3131 bronze badges

answered Mar 28 at 15:10

Yosvel QuinteroYosvel Quintero

12.9k44 gold badges2727 silver badges3131 bronze badges