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How do I prevent terminal from closing out out after git hook is called from bash script?

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0

I'm curious to learn and know why a terminal is crashing out. I have a bash function, gc_push_wh, that calls a git hook like so:

git_push_wh () 
 GIT_DIR_="$(git rev-parse --git-dir)"
 BRANCH="$(git rev-parse --symbolic --abbrev-ref $(git symbolic-ref HEAD))"

 git push "$@"

 POST_PUSH="$GIT_DIR_/../hooks/post-push"
 test $? -eq 0 && test -x "$POST_PUSH" &&
 exec "$POST_PUSH" "$BRANCH" "$@"

All this works fine. But when the hook terminates, the terminal closes out. Here is what's in the hook:

#!/usr/bin/env bash

ssh -t root@10.0.0.222 -p 30000 "cd ~/.dotfiles; git pull; lb;"

I have a git alias set up to run with this function like so:

git gcpush

When run with the git alias, the terminal does not close out.

IMPORTANT: I tried throwing a read command at the end of the hook but after I hit enter, the terminal still closes out.

bash git

share|improve this question

asked Mar 28 at 21:11

StevieDStevieD

1,10399 silver badges2020 bronze badges

add a comment
 | 

0

I'm curious to learn and know why a terminal is crashing out. I have a bash function, gc_push_wh, that calls a git hook like so:

git_push_wh () 
 GIT_DIR_="$(git rev-parse --git-dir)"
 BRANCH="$(git rev-parse --symbolic --abbrev-ref $(git symbolic-ref HEAD))"

 git push "$@"

 POST_PUSH="$GIT_DIR_/../hooks/post-push"
 test $? -eq 0 && test -x "$POST_PUSH" &&
 exec "$POST_PUSH" "$BRANCH" "$@"

All this works fine. But when the hook terminates, the terminal closes out. Here is what's in the hook:

#!/usr/bin/env bash

ssh -t root@10.0.0.222 -p 30000 "cd ~/.dotfiles; git pull; lb;"

I have a git alias set up to run with this function like so:

git gcpush

When run with the git alias, the terminal does not close out.

IMPORTANT: I tried throwing a read command at the end of the hook but after I hit enter, the terminal still closes out.

bash git

share|improve this question

asked Mar 28 at 21:11

StevieDStevieD

1,10399 silver badges2020 bronze badges

add a comment
 | 

I'm curious to learn and know why a terminal is crashing out. I have a bash function, gc_push_wh, that calls a git hook like so:

git_push_wh () 
 GIT_DIR_="$(git rev-parse --git-dir)"
 BRANCH="$(git rev-parse --symbolic --abbrev-ref $(git symbolic-ref HEAD))"

 git push "$@"

 POST_PUSH="$GIT_DIR_/../hooks/post-push"
 test $? -eq 0 && test -x "$POST_PUSH" &&
 exec "$POST_PUSH" "$BRANCH" "$@"

All this works fine. But when the hook terminates, the terminal closes out. Here is what's in the hook:

#!/usr/bin/env bash

ssh -t root@10.0.0.222 -p 30000 "cd ~/.dotfiles; git pull; lb;"

I have a git alias set up to run with this function like so:

git gcpush

When run with the git alias, the terminal does not close out.

IMPORTANT: I tried throwing a read command at the end of the hook but after I hit enter, the terminal still closes out.

bash git

share|improve this question

asked Mar 28 at 21:11

StevieDStevieD

1,10399 silver badges2020 bronze badges

git_push_wh () 
 GIT_DIR_="$(git rev-parse --git-dir)"
 BRANCH="$(git rev-parse --symbolic --abbrev-ref $(git symbolic-ref HEAD))"

 git push "$@"

 POST_PUSH="$GIT_DIR_/../hooks/post-push"
 test $? -eq 0 && test -x "$POST_PUSH" &&
 exec "$POST_PUSH" "$BRANCH" "$@"

#!/usr/bin/env bash

ssh -t root@10.0.0.222 -p 30000 "cd ~/.dotfiles; git pull; lb;"

share|improve this question

asked Mar 28 at 21:11

StevieDStevieD

1,10399 silver badges2020 bronze badges

share|improve this question

asked Mar 28 at 21:11

StevieDStevieD

1,10399 silver badges2020 bronze badges

asked Mar 28 at 21:11

StevieDStevieD

1,10399 silver badges2020 bronze badges

asked Mar 28 at 21:11

StevieDStevieD

1,10399 silver badges2020 bronze badges

1 Answer
1

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oldest

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3

The exec command is replacing the currently running bash process's image with the image of a new bash process that will run the script in $POST_PUSH. Hence, the process will finish running when that script exits. It will never never come back to the bash process that you started with, as would have happened had the script been run in a subshell.

If you replace, the line

 exec "$POST_PUSH" "$BRANCH" "$@"

with

 "$POST_PUSH" "$BRANCH" "$@"

you will achieve what you wish to.

share|improve this answer

answered Mar 28 at 21:23

euphoria83euphoria83

7,4461616 gold badges5353 silver badges6767 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I just spotted this a few seconds ago myself. copy/paste programming is a huge time killer. Thanks!
  
  – StevieD
  Mar 28 at 21:27
  

  
  
  
  

add a comment
 | 

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3

The exec command is replacing the currently running bash process's image with the image of a new bash process that will run the script in $POST_PUSH. Hence, the process will finish running when that script exits. It will never never come back to the bash process that you started with, as would have happened had the script been run in a subshell.

If you replace, the line

 exec "$POST_PUSH" "$BRANCH" "$@"

with

 "$POST_PUSH" "$BRANCH" "$@"

you will achieve what you wish to.

share|improve this answer

answered Mar 28 at 21:23

euphoria83euphoria83

7,4461616 gold badges5353 silver badges6767 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I just spotted this a few seconds ago myself. copy/paste programming is a huge time killer. Thanks!
  
  – StevieD
  Mar 28 at 21:27
  

  
  
  
  

add a comment
 | 

3

The exec command is replacing the currently running bash process's image with the image of a new bash process that will run the script in $POST_PUSH. Hence, the process will finish running when that script exits. It will never never come back to the bash process that you started with, as would have happened had the script been run in a subshell.

If you replace, the line

 exec "$POST_PUSH" "$BRANCH" "$@"

with

 "$POST_PUSH" "$BRANCH" "$@"

you will achieve what you wish to.

share|improve this answer

answered Mar 28 at 21:23

euphoria83euphoria83

7,4461616 gold badges5353 silver badges6767 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I just spotted this a few seconds ago myself. copy/paste programming is a huge time killer. Thanks!
  
  – StevieD
  Mar 28 at 21:27
  

  
  
  
  

add a comment
 | 

The exec command is replacing the currently running bash process's image with the image of a new bash process that will run the script in $POST_PUSH. Hence, the process will finish running when that script exits. It will never never come back to the bash process that you started with, as would have happened had the script been run in a subshell.

If you replace, the line

 exec "$POST_PUSH" "$BRANCH" "$@"

with

 "$POST_PUSH" "$BRANCH" "$@"

you will achieve what you wish to.

share|improve this answer

answered Mar 28 at 21:23

euphoria83euphoria83

7,4461616 gold badges5353 silver badges6767 bronze badges

 exec "$POST_PUSH" "$BRANCH" "$@"

 "$POST_PUSH" "$BRANCH" "$@"

share|improve this answer

answered Mar 28 at 21:23

euphoria83euphoria83

7,4461616 gold badges5353 silver badges6767 bronze badges

answered Mar 28 at 21:23

euphoria83euphoria83

7,4461616 gold badges5353 silver badges6767 bronze badges

answered Mar 28 at 21:23

euphoria83euphoria83

7,4461616 gold badges5353 silver badges6767 bronze badges