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refactor try-catch across class hierarchy

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1

Suppose you have this code:

class Base {
 void method() throws Exception 
 try 
 //Lots of code here
 catch (Exception e) 
 //handle it (very little code here)
 
 

class Derived extends Base {
 @Override
 void method() throws Exception 
 try 
 //Lots of code here (same code as in base class)
 catch (Exception e) 
 //handle it (very little code here; also same as base class)
 catch (Error e) 
 e.printStackTrace();
 System.exit(1);
 
 

So, as we can see, the methods are the same except the derived class has an extra catch clause. Is there a nice way to have a bit less duplicated code here?

java exception refactoring dry code-duplication

share|improve this question

asked Mar 28 at 0:41

Mark VYMark VY

73155 silver badges1919 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I suggest to put your code in try block inside another method and call it when you need to.
  
  – Jordan Motta
  Mar 28 at 0:54
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Hm... that works I suppose. Can't share the skeleton that way though. For instance, imagine that both methods have an identical finally block as well. (In the code that motivated this question, this is pretty much true: they have an almost identical finally block, with almost as much code as the try block.) I could make a method for that too I guess, but, but I'm not sure if there's QUITE enough code duplication for me to be sure this is worth the trouble.
  
  – Mark VY
  Mar 28 at 1:02
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  "The first rule of functions is that they should be small. The second rule of functions is that they should be smaller than that." (Martin, Clean Code, 2009, p 34). It is enough code to make into a method.
  
  – KevinO
  Mar 28 at 1:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  alright, alright, fair point
  
  – Mark VY
  Mar 28 at 14:30
  

  
  
  
  

add a comment | 

1

Suppose you have this code:

class Base {
 void method() throws Exception 
 try 
 //Lots of code here
 catch (Exception e) 
 //handle it (very little code here)
 
 

class Derived extends Base {
 @Override
 void method() throws Exception 
 try 
 //Lots of code here (same code as in base class)
 catch (Exception e) 
 //handle it (very little code here; also same as base class)
 catch (Error e) 
 e.printStackTrace();
 System.exit(1);
 
 

So, as we can see, the methods are the same except the derived class has an extra catch clause. Is there a nice way to have a bit less duplicated code here?

java exception refactoring dry code-duplication

share|improve this question

asked Mar 28 at 0:41

Mark VYMark VY

73155 silver badges1919 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I suggest to put your code in try block inside another method and call it when you need to.
  
  – Jordan Motta
  Mar 28 at 0:54
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Hm... that works I suppose. Can't share the skeleton that way though. For instance, imagine that both methods have an identical finally block as well. (In the code that motivated this question, this is pretty much true: they have an almost identical finally block, with almost as much code as the try block.) I could make a method for that too I guess, but, but I'm not sure if there's QUITE enough code duplication for me to be sure this is worth the trouble.
  
  – Mark VY
  Mar 28 at 1:02
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  "The first rule of functions is that they should be small. The second rule of functions is that they should be smaller than that." (Martin, Clean Code, 2009, p 34). It is enough code to make into a method.
  
  – KevinO
  Mar 28 at 1:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  alright, alright, fair point
  
  – Mark VY
  Mar 28 at 14:30
  

  
  
  
  

add a comment | 

Suppose you have this code:

class Base {
 void method() throws Exception 
 try 
 //Lots of code here
 catch (Exception e) 
 //handle it (very little code here)
 
 

class Derived extends Base {
 @Override
 void method() throws Exception 
 try 
 //Lots of code here (same code as in base class)
 catch (Exception e) 
 //handle it (very little code here; also same as base class)
 catch (Error e) 
 e.printStackTrace();
 System.exit(1);
 
 

So, as we can see, the methods are the same except the derived class has an extra catch clause. Is there a nice way to have a bit less duplicated code here?

java exception refactoring dry code-duplication

share|improve this question

asked Mar 28 at 0:41

Mark VYMark VY

73155 silver badges1919 bronze badges

class Base {
 void method() throws Exception 
 try 
 //Lots of code here
 catch (Exception e) 
 //handle it (very little code here)
 
 

class Derived extends Base {
 @Override
 void method() throws Exception 
 try 
 //Lots of code here (same code as in base class)
 catch (Exception e) 
 //handle it (very little code here; also same as base class)
 catch (Error e) 
 e.printStackTrace();
 System.exit(1);
 
 

share|improve this question

asked Mar 28 at 0:41

Mark VYMark VY

73155 silver badges1919 bronze badges

share|improve this question

asked Mar 28 at 0:41

Mark VYMark VY

73155 silver badges1919 bronze badges

asked Mar 28 at 0:41

Mark VYMark VY

73155 silver badges1919 bronze badges

asked Mar 28 at 0:41

Mark VYMark VY

73155 silver badges1919 bronze badges