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Getting an error decoding JSON, Swift 4.2


Safely turning a JSON string into an objectHow do I format a Microsoft JSON date?Can comments be used in JSON?How can I pretty-print JSON in a shell script?What is the correct JSON content type?Why does Google prepend while(1); to their JSON responses?Why can't Python parse this JSON data?How can I pretty-print JSON using JavaScript?Parse JSON in JavaScript?How do I POST JSON data with Curl from a terminal/commandline to Test Spring REST?






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margin-bottom:0;









-2

















I am getting an error when decoding JSON in swift 4.2




Expected to decode Array but found a dictionary instead.




My JSON Model:



public struct NewsSource: Equatable, Decodable 

public let id: String?
public let name: String?
public let sourceDescription: String?
public let url: URL?

enum CodingKeys: String, CodingKey
case id
case name
case sourceDescription = "description"
case url



public init(id: String,
name: String,
sourceDescription: String,
url: URL,
category: NewsCategory,
language: NewsLanguage,
country: NewsCountry)
self.id = id
self.name = name
self.sourceDescription = sourceDescription
self.url = url



How I fetch the JSON:



func fetchJSON() 

let urlString = "https://newsapi.org/v2/sources?apiKey=myAPIKey"

guard let url = URL(string: urlString) else return
URLSession.shared.dataTask(with: url) (data, _, err) in
DispatchQueue.main.async
if let err = err
print("Failed to get data from url:", err)
return


guard let data = data else return
print(data)
do

let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase

self.Sources = try decoder.decode([NewsSource].self, from: data)
self.tableView.reloadData()

catch let jsonErr
print("Failed to decode:", jsonErr)


.resume()










share|improve this question


































    -2

















    I am getting an error when decoding JSON in swift 4.2




    Expected to decode Array but found a dictionary instead.




    My JSON Model:



    public struct NewsSource: Equatable, Decodable 

    public let id: String?
    public let name: String?
    public let sourceDescription: String?
    public let url: URL?

    enum CodingKeys: String, CodingKey
    case id
    case name
    case sourceDescription = "description"
    case url



    public init(id: String,
    name: String,
    sourceDescription: String,
    url: URL,
    category: NewsCategory,
    language: NewsLanguage,
    country: NewsCountry)
    self.id = id
    self.name = name
    self.sourceDescription = sourceDescription
    self.url = url



    How I fetch the JSON:



    func fetchJSON() 

    let urlString = "https://newsapi.org/v2/sources?apiKey=myAPIKey"

    guard let url = URL(string: urlString) else return
    URLSession.shared.dataTask(with: url) (data, _, err) in
    DispatchQueue.main.async
    if let err = err
    print("Failed to get data from url:", err)
    return


    guard let data = data else return
    print(data)
    do

    let decoder = JSONDecoder()
    decoder.keyDecodingStrategy = .convertFromSnakeCase

    self.Sources = try decoder.decode([NewsSource].self, from: data)
    self.tableView.reloadData()

    catch let jsonErr
    print("Failed to decode:", jsonErr)


    .resume()










    share|improve this question






























      -2












      -2








      -2








      I am getting an error when decoding JSON in swift 4.2




      Expected to decode Array but found a dictionary instead.




      My JSON Model:



      public struct NewsSource: Equatable, Decodable 

      public let id: String?
      public let name: String?
      public let sourceDescription: String?
      public let url: URL?

      enum CodingKeys: String, CodingKey
      case id
      case name
      case sourceDescription = "description"
      case url



      public init(id: String,
      name: String,
      sourceDescription: String,
      url: URL,
      category: NewsCategory,
      language: NewsLanguage,
      country: NewsCountry)
      self.id = id
      self.name = name
      self.sourceDescription = sourceDescription
      self.url = url



      How I fetch the JSON:



      func fetchJSON() 

      let urlString = "https://newsapi.org/v2/sources?apiKey=myAPIKey"

      guard let url = URL(string: urlString) else return
      URLSession.shared.dataTask(with: url) (data, _, err) in
      DispatchQueue.main.async
      if let err = err
      print("Failed to get data from url:", err)
      return


      guard let data = data else return
      print(data)
      do

      let decoder = JSONDecoder()
      decoder.keyDecodingStrategy = .convertFromSnakeCase

      self.Sources = try decoder.decode([NewsSource].self, from: data)
      self.tableView.reloadData()

      catch let jsonErr
      print("Failed to decode:", jsonErr)


      .resume()










      share|improve this question

















      I am getting an error when decoding JSON in swift 4.2




      Expected to decode Array but found a dictionary instead.




      My JSON Model:



      public struct NewsSource: Equatable, Decodable 

      public let id: String?
      public let name: String?
      public let sourceDescription: String?
      public let url: URL?

      enum CodingKeys: String, CodingKey
      case id
      case name
      case sourceDescription = "description"
      case url



      public init(id: String,
      name: String,
      sourceDescription: String,
      url: URL,
      category: NewsCategory,
      language: NewsLanguage,
      country: NewsCountry)
      self.id = id
      self.name = name
      self.sourceDescription = sourceDescription
      self.url = url



      How I fetch the JSON:



      func fetchJSON() 

      let urlString = "https://newsapi.org/v2/sources?apiKey=myAPIKey"

      guard let url = URL(string: urlString) else return
      URLSession.shared.dataTask(with: url) (data, _, err) in
      DispatchQueue.main.async
      if let err = err
      print("Failed to get data from url:", err)
      return


      guard let data = data else return
      print(data)
      do

      let decoder = JSONDecoder()
      decoder.keyDecodingStrategy = .convertFromSnakeCase

      self.Sources = try decoder.decode([NewsSource].self, from: data)
      self.tableView.reloadData()

      catch let jsonErr
      print("Failed to decode:", jsonErr)


      .resume()







      ios json swift swift4.2 jsondecoder






      share|improve this question
















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 29 at 1:55









      Simply Ged

      3,6608 gold badges21 silver badges29 bronze badges




      3,6608 gold badges21 silver badges29 bronze badges










      asked Mar 28 at 21:40









      Mäsäm MähmôôdMäsäm Mähmôôd

      12 bronze badges




      12 bronze badges

























          2 Answers
          2






          active

          oldest

          votes


















          2


















          If you look at the JSON that is being returned it looks like this:



          {
          "status": "ok",
          "sources": [
          "id": "abc-news",
          "name": "ABC News",
          "description": "Your trusted source for breaking news, analysis, exclusive interviews, headlines, and videos at ABCNews.com.",
          "url": "https://abcnews.go.com",
          "category": "general",
          "language": "en",
          "country": "us"
          ,
          "id": "abc-news-au",
          "name": "ABC News (AU)",
          "description": "Australia's most trusted source of local, national and world news. Comprehensive, independent, in-depth analysis, the latest business, sport, weather and more.",
          "url": "http://www.abc.net.au/news",
          "category": "general",
          "language": "en",
          "country": "au"
          ,
          ...


          While there is an array of sources, the array is not the root. The root of the JSON is an object with a status string and and a sources array. This is why the decoder is failing.



          You need to define an additional struct to handle this:



          struct NewsResult 
          let status: String
          let sources: [NewsSource]



          Then you decode this object:



          let sourceResult = try decoder.decode(NewsResult.self, from: data)
          self.sources = sourceResult.sources





          share|improve this answer


























          • Thank you friend. made changes and now it's working.

            – Mäsäm Mähmôôd
            Mar 28 at 22:08


















          0


















          This should be your structure:



          struct NewsSource: Codable 
          let status: String
          let sources: [NewsSource]


          public struct NewsSource: Equatable, Decodable

          public let id: String?
          public let name: String?
          public let sourceDescription: String?
          public let url: URL?

          enum CodingKeys: String, CodingKey
          case id
          case name
          case sourceDescription = "description"
          case url



          public init(id: String,
          name: String,
          sourceDescription: String,
          url: URL,
          category: NewsCategory,
          language: NewsLanguage,
          country: NewsCountry)
          self.id = id
          self.name = name
          self.sourceDescription = sourceDescription
          self.url = url


          struct Source: Codable
          let id, name, description: String
          let url: String
          let category: Category
          let language, country: String


          enum Category: String, Codable
          case business = "business"
          case entertainment = "entertainment"
          case general = "general"
          case health = "health"
          case science = "science"
          case sports = "sports"
          case technology = "technology"



          And then to decode it:



          let decoder = JSONDecoder()
          decoder.keyDecodingStrategy = .convertFromSnakeCase
          let newsSource = try? decoder.decode(NewsSource.self, from: data)
          self.Sources = newsSource.sources
          self.tableView.reloadData()


          Hope this helps!






          share|improve this answer


























          • I have done the changes and its working now Thanks.

            – Mäsäm Mähmôôd
            Mar 28 at 22:07











          • Please mark the questions as correct.

            – OkiRules
            Mar 28 at 23:31











          • Also have a look at my edit on the question, I have hidden your API key so others can't use it and changed some spelling and grammar.

            – OkiRules
            Mar 28 at 23:37











          • thank you for the changes you have made.

            – Mäsäm Mähmôôd
            Mar 31 at 18:02












          Your Answer






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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2


















          If you look at the JSON that is being returned it looks like this:



          {
          "status": "ok",
          "sources": [
          "id": "abc-news",
          "name": "ABC News",
          "description": "Your trusted source for breaking news, analysis, exclusive interviews, headlines, and videos at ABCNews.com.",
          "url": "https://abcnews.go.com",
          "category": "general",
          "language": "en",
          "country": "us"
          ,
          "id": "abc-news-au",
          "name": "ABC News (AU)",
          "description": "Australia's most trusted source of local, national and world news. Comprehensive, independent, in-depth analysis, the latest business, sport, weather and more.",
          "url": "http://www.abc.net.au/news",
          "category": "general",
          "language": "en",
          "country": "au"
          ,
          ...


          While there is an array of sources, the array is not the root. The root of the JSON is an object with a status string and and a sources array. This is why the decoder is failing.



          You need to define an additional struct to handle this:



          struct NewsResult 
          let status: String
          let sources: [NewsSource]



          Then you decode this object:



          let sourceResult = try decoder.decode(NewsResult.self, from: data)
          self.sources = sourceResult.sources





          share|improve this answer


























          • Thank you friend. made changes and now it's working.

            – Mäsäm Mähmôôd
            Mar 28 at 22:08















          2


















          If you look at the JSON that is being returned it looks like this:



          {
          "status": "ok",
          "sources": [
          "id": "abc-news",
          "name": "ABC News",
          "description": "Your trusted source for breaking news, analysis, exclusive interviews, headlines, and videos at ABCNews.com.",
          "url": "https://abcnews.go.com",
          "category": "general",
          "language": "en",
          "country": "us"
          ,
          "id": "abc-news-au",
          "name": "ABC News (AU)",
          "description": "Australia's most trusted source of local, national and world news. Comprehensive, independent, in-depth analysis, the latest business, sport, weather and more.",
          "url": "http://www.abc.net.au/news",
          "category": "general",
          "language": "en",
          "country": "au"
          ,
          ...


          While there is an array of sources, the array is not the root. The root of the JSON is an object with a status string and and a sources array. This is why the decoder is failing.



          You need to define an additional struct to handle this:



          struct NewsResult 
          let status: String
          let sources: [NewsSource]



          Then you decode this object:



          let sourceResult = try decoder.decode(NewsResult.self, from: data)
          self.sources = sourceResult.sources





          share|improve this answer


























          • Thank you friend. made changes and now it's working.

            – Mäsäm Mähmôôd
            Mar 28 at 22:08













          2














          2










          2









          If you look at the JSON that is being returned it looks like this:



          {
          "status": "ok",
          "sources": [
          "id": "abc-news",
          "name": "ABC News",
          "description": "Your trusted source for breaking news, analysis, exclusive interviews, headlines, and videos at ABCNews.com.",
          "url": "https://abcnews.go.com",
          "category": "general",
          "language": "en",
          "country": "us"
          ,
          "id": "abc-news-au",
          "name": "ABC News (AU)",
          "description": "Australia's most trusted source of local, national and world news. Comprehensive, independent, in-depth analysis, the latest business, sport, weather and more.",
          "url": "http://www.abc.net.au/news",
          "category": "general",
          "language": "en",
          "country": "au"
          ,
          ...


          While there is an array of sources, the array is not the root. The root of the JSON is an object with a status string and and a sources array. This is why the decoder is failing.



          You need to define an additional struct to handle this:



          struct NewsResult 
          let status: String
          let sources: [NewsSource]



          Then you decode this object:



          let sourceResult = try decoder.decode(NewsResult.self, from: data)
          self.sources = sourceResult.sources





          share|improve this answer














          If you look at the JSON that is being returned it looks like this:



          {
          "status": "ok",
          "sources": [
          "id": "abc-news",
          "name": "ABC News",
          "description": "Your trusted source for breaking news, analysis, exclusive interviews, headlines, and videos at ABCNews.com.",
          "url": "https://abcnews.go.com",
          "category": "general",
          "language": "en",
          "country": "us"
          ,
          "id": "abc-news-au",
          "name": "ABC News (AU)",
          "description": "Australia's most trusted source of local, national and world news. Comprehensive, independent, in-depth analysis, the latest business, sport, weather and more.",
          "url": "http://www.abc.net.au/news",
          "category": "general",
          "language": "en",
          "country": "au"
          ,
          ...


          While there is an array of sources, the array is not the root. The root of the JSON is an object with a status string and and a sources array. This is why the decoder is failing.



          You need to define an additional struct to handle this:



          struct NewsResult 
          let status: String
          let sources: [NewsSource]



          Then you decode this object:



          let sourceResult = try decoder.decode(NewsResult.self, from: data)
          self.sources = sourceResult.sources






          share|improve this answer













          share|improve this answer




          share|improve this answer










          answered Mar 28 at 21:49









          Paulw11Paulw11

          75.3k10 gold badges100 silver badges117 bronze badges




          75.3k10 gold badges100 silver badges117 bronze badges















          • Thank you friend. made changes and now it's working.

            – Mäsäm Mähmôôd
            Mar 28 at 22:08

















          • Thank you friend. made changes and now it's working.

            – Mäsäm Mähmôôd
            Mar 28 at 22:08
















          Thank you friend. made changes and now it's working.

          – Mäsäm Mähmôôd
          Mar 28 at 22:08





          Thank you friend. made changes and now it's working.

          – Mäsäm Mähmôôd
          Mar 28 at 22:08













          0


















          This should be your structure:



          struct NewsSource: Codable 
          let status: String
          let sources: [NewsSource]


          public struct NewsSource: Equatable, Decodable

          public let id: String?
          public let name: String?
          public let sourceDescription: String?
          public let url: URL?

          enum CodingKeys: String, CodingKey
          case id
          case name
          case sourceDescription = "description"
          case url



          public init(id: String,
          name: String,
          sourceDescription: String,
          url: URL,
          category: NewsCategory,
          language: NewsLanguage,
          country: NewsCountry)
          self.id = id
          self.name = name
          self.sourceDescription = sourceDescription
          self.url = url


          struct Source: Codable
          let id, name, description: String
          let url: String
          let category: Category
          let language, country: String


          enum Category: String, Codable
          case business = "business"
          case entertainment = "entertainment"
          case general = "general"
          case health = "health"
          case science = "science"
          case sports = "sports"
          case technology = "technology"



          And then to decode it:



          let decoder = JSONDecoder()
          decoder.keyDecodingStrategy = .convertFromSnakeCase
          let newsSource = try? decoder.decode(NewsSource.self, from: data)
          self.Sources = newsSource.sources
          self.tableView.reloadData()


          Hope this helps!






          share|improve this answer


























          • I have done the changes and its working now Thanks.

            – Mäsäm Mähmôôd
            Mar 28 at 22:07











          • Please mark the questions as correct.

            – OkiRules
            Mar 28 at 23:31











          • Also have a look at my edit on the question, I have hidden your API key so others can't use it and changed some spelling and grammar.

            – OkiRules
            Mar 28 at 23:37











          • thank you for the changes you have made.

            – Mäsäm Mähmôôd
            Mar 31 at 18:02















          0


















          This should be your structure:



          struct NewsSource: Codable 
          let status: String
          let sources: [NewsSource]


          public struct NewsSource: Equatable, Decodable

          public let id: String?
          public let name: String?
          public let sourceDescription: String?
          public let url: URL?

          enum CodingKeys: String, CodingKey
          case id
          case name
          case sourceDescription = "description"
          case url



          public init(id: String,
          name: String,
          sourceDescription: String,
          url: URL,
          category: NewsCategory,
          language: NewsLanguage,
          country: NewsCountry)
          self.id = id
          self.name = name
          self.sourceDescription = sourceDescription
          self.url = url


          struct Source: Codable
          let id, name, description: String
          let url: String
          let category: Category
          let language, country: String


          enum Category: String, Codable
          case business = "business"
          case entertainment = "entertainment"
          case general = "general"
          case health = "health"
          case science = "science"
          case sports = "sports"
          case technology = "technology"



          And then to decode it:



          let decoder = JSONDecoder()
          decoder.keyDecodingStrategy = .convertFromSnakeCase
          let newsSource = try? decoder.decode(NewsSource.self, from: data)
          self.Sources = newsSource.sources
          self.tableView.reloadData()


          Hope this helps!






          share|improve this answer


























          • I have done the changes and its working now Thanks.

            – Mäsäm Mähmôôd
            Mar 28 at 22:07











          • Please mark the questions as correct.

            – OkiRules
            Mar 28 at 23:31











          • Also have a look at my edit on the question, I have hidden your API key so others can't use it and changed some spelling and grammar.

            – OkiRules
            Mar 28 at 23:37











          • thank you for the changes you have made.

            – Mäsäm Mähmôôd
            Mar 31 at 18:02













          0














          0










          0









          This should be your structure:



          struct NewsSource: Codable 
          let status: String
          let sources: [NewsSource]


          public struct NewsSource: Equatable, Decodable

          public let id: String?
          public let name: String?
          public let sourceDescription: String?
          public let url: URL?

          enum CodingKeys: String, CodingKey
          case id
          case name
          case sourceDescription = "description"
          case url



          public init(id: String,
          name: String,
          sourceDescription: String,
          url: URL,
          category: NewsCategory,
          language: NewsLanguage,
          country: NewsCountry)
          self.id = id
          self.name = name
          self.sourceDescription = sourceDescription
          self.url = url


          struct Source: Codable
          let id, name, description: String
          let url: String
          let category: Category
          let language, country: String


          enum Category: String, Codable
          case business = "business"
          case entertainment = "entertainment"
          case general = "general"
          case health = "health"
          case science = "science"
          case sports = "sports"
          case technology = "technology"



          And then to decode it:



          let decoder = JSONDecoder()
          decoder.keyDecodingStrategy = .convertFromSnakeCase
          let newsSource = try? decoder.decode(NewsSource.self, from: data)
          self.Sources = newsSource.sources
          self.tableView.reloadData()


          Hope this helps!






          share|improve this answer














          This should be your structure:



          struct NewsSource: Codable 
          let status: String
          let sources: [NewsSource]


          public struct NewsSource: Equatable, Decodable

          public let id: String?
          public let name: String?
          public let sourceDescription: String?
          public let url: URL?

          enum CodingKeys: String, CodingKey
          case id
          case name
          case sourceDescription = "description"
          case url



          public init(id: String,
          name: String,
          sourceDescription: String,
          url: URL,
          category: NewsCategory,
          language: NewsLanguage,
          country: NewsCountry)
          self.id = id
          self.name = name
          self.sourceDescription = sourceDescription
          self.url = url


          struct Source: Codable
          let id, name, description: String
          let url: String
          let category: Category
          let language, country: String


          enum Category: String, Codable
          case business = "business"
          case entertainment = "entertainment"
          case general = "general"
          case health = "health"
          case science = "science"
          case sports = "sports"
          case technology = "technology"



          And then to decode it:



          let decoder = JSONDecoder()
          decoder.keyDecodingStrategy = .convertFromSnakeCase
          let newsSource = try? decoder.decode(NewsSource.self, from: data)
          self.Sources = newsSource.sources
          self.tableView.reloadData()


          Hope this helps!







          share|improve this answer













          share|improve this answer




          share|improve this answer










          answered Mar 28 at 21:56









          OkiRulesOkiRules

          2462 silver badges13 bronze badges




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          • I have done the changes and its working now Thanks.

            – Mäsäm Mähmôôd
            Mar 28 at 22:07











          • Please mark the questions as correct.

            – OkiRules
            Mar 28 at 23:31











          • Also have a look at my edit on the question, I have hidden your API key so others can't use it and changed some spelling and grammar.

            – OkiRules
            Mar 28 at 23:37











          • thank you for the changes you have made.

            – Mäsäm Mähmôôd
            Mar 31 at 18:02

















          • I have done the changes and its working now Thanks.

            – Mäsäm Mähmôôd
            Mar 28 at 22:07











          • Please mark the questions as correct.

            – OkiRules
            Mar 28 at 23:31











          • Also have a look at my edit on the question, I have hidden your API key so others can't use it and changed some spelling and grammar.

            – OkiRules
            Mar 28 at 23:37











          • thank you for the changes you have made.

            – Mäsäm Mähmôôd
            Mar 31 at 18:02
















          I have done the changes and its working now Thanks.

          – Mäsäm Mähmôôd
          Mar 28 at 22:07





          I have done the changes and its working now Thanks.

          – Mäsäm Mähmôôd
          Mar 28 at 22:07













          Please mark the questions as correct.

          – OkiRules
          Mar 28 at 23:31





          Please mark the questions as correct.

          – OkiRules
          Mar 28 at 23:31













          Also have a look at my edit on the question, I have hidden your API key so others can't use it and changed some spelling and grammar.

          – OkiRules
          Mar 28 at 23:37





          Also have a look at my edit on the question, I have hidden your API key so others can't use it and changed some spelling and grammar.

          – OkiRules
          Mar 28 at 23:37













          thank you for the changes you have made.

          – Mäsäm Mähmôôd
          Mar 31 at 18:02





          thank you for the changes you have made.

          – Mäsäm Mähmôôd
          Mar 31 at 18:02


















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