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PHP: How to set the value of a variable through another variable?

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3

I have a variable that calls an item, but what I have to display is the description of his category. So the structure I figured out is something like this willing that writing $item1 in $var1 it displays "Bla Bla Bla" (the value of $cat1):

$var1 = $item1;
$item1 = $cat1;
$cat1 = 'Bla Bla Bla';

Believe or not it doesn't work :-)
I am a novice with php, sorry to ask stupid questions! And thank you so much to help!

php

share|improve this question

edited Mar 28 at 22:56

Nik

1,27011 gold badge77 silver badges1717 bronze badges

asked Mar 28 at 22:10

FoorioFoorio

1822 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Hi, not sure exectly what you are trying to achieve
  
  – RiggsFolly
  Mar 28 at 22:11
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  are you maybe trying something like $var1->cat1 ? just guessing here
  
  – jonathan Heindl
  Mar 28 at 22:13
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes and my english does not help (I am Italian)... indeed I would like to write <?php echo $var1; ?> in my page and display "Bla Bla Bla" but I need to use those 3 variables
  
  – Foorio
  Mar 28 at 22:14
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  why do you need 3 variables ?
  
  – jonathan Heindl
  Mar 28 at 22:15
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Because it is the product, the category and the family... so when I set the product I need also to display the Family Description
  
  – Foorio
  Mar 28 at 22:16
  

  
  
  
  

 | 
show 5 more comments

3

I have a variable that calls an item, but what I have to display is the description of his category. So the structure I figured out is something like this willing that writing $item1 in $var1 it displays "Bla Bla Bla" (the value of $cat1):

$var1 = $item1;
$item1 = $cat1;
$cat1 = 'Bla Bla Bla';

Believe or not it doesn't work :-)
I am a novice with php, sorry to ask stupid questions! And thank you so much to help!

php

share|improve this question

edited Mar 28 at 22:56

Nik

1,27011 gold badge77 silver badges1717 bronze badges

asked Mar 28 at 22:10

FoorioFoorio

1822 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Hi, not sure exectly what you are trying to achieve
  
  – RiggsFolly
  Mar 28 at 22:11
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  are you maybe trying something like $var1->cat1 ? just guessing here
  
  – jonathan Heindl
  Mar 28 at 22:13
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes and my english does not help (I am Italian)... indeed I would like to write <?php echo $var1; ?> in my page and display "Bla Bla Bla" but I need to use those 3 variables
  
  – Foorio
  Mar 28 at 22:14
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  why do you need 3 variables ?
  
  – jonathan Heindl
  Mar 28 at 22:15
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Because it is the product, the category and the family... so when I set the product I need also to display the Family Description
  
  – Foorio
  Mar 28 at 22:16
  

  
  
  
  

 | 
show 5 more comments

I have a variable that calls an item, but what I have to display is the description of his category. So the structure I figured out is something like this willing that writing $item1 in $var1 it displays "Bla Bla Bla" (the value of $cat1):

$var1 = $item1;
$item1 = $cat1;
$cat1 = 'Bla Bla Bla';

Believe or not it doesn't work :-)
I am a novice with php, sorry to ask stupid questions! And thank you so much to help!

php

share|improve this question

edited Mar 28 at 22:56

Nik

1,27011 gold badge77 silver badges1717 bronze badges

asked Mar 28 at 22:10

FoorioFoorio

1822 bronze badges

$var1 = $item1;
$item1 = $cat1;
$cat1 = 'Bla Bla Bla';

share|improve this question

edited Mar 28 at 22:56

Nik

1,27011 gold badge77 silver badges1717 bronze badges

asked Mar 28 at 22:10

FoorioFoorio

1822 bronze badges

share|improve this question

edited Mar 28 at 22:56

Nik

1,27011 gold badge77 silver badges1717 bronze badges

asked Mar 28 at 22:10

FoorioFoorio

1822 bronze badges

edited Mar 28 at 22:56

Nik

1,27011 gold badge77 silver badges1717 bronze badges

edited Mar 28 at 22:56

Nik

1,27011 gold badge77 silver badges1717 bronze badges

asked Mar 28 at 22:10

FoorioFoorio

1822 bronze badges

asked Mar 28 at 22:10

FoorioFoorio

1822 bronze badges

1 Answer
1

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oldest

votes

4

assignation of values in most common programm languajes is up to down (cascade programming style)

$var1 = $item1; <--- at this point $item1 is "empty" or null
$item1 = $cat1; <--- at this point $cat1 is empty too
$cat1 = 'Bla Bla Bla'; <--- here $cat1 take value 'Bla Bla Bla' 

so, you have to invert order of assignation like this:

$cat1 = 'Bla Bla Bla';
$item1 = $cat1;
$var1 = $item1;

the output show 'Bla Bla Bla' for $cat1 $item1 and $var1
hope this help.

share|improve this answer

edited Mar 29 at 2:00

Alireza Zojaji

55811 gold badge77 silver badges2626 bronze badges

answered Mar 28 at 22:24

Sebastian P.Sebastian P.

7611 bronze badge

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That's great, thank you!
  
  – Foorio
  Mar 28 at 22:28
  

  
  
  
  

add a comment
 | 

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4

assignation of values in most common programm languajes is up to down (cascade programming style)

$var1 = $item1; <--- at this point $item1 is "empty" or null
$item1 = $cat1; <--- at this point $cat1 is empty too
$cat1 = 'Bla Bla Bla'; <--- here $cat1 take value 'Bla Bla Bla' 

so, you have to invert order of assignation like this:

$cat1 = 'Bla Bla Bla';
$item1 = $cat1;
$var1 = $item1;

the output show 'Bla Bla Bla' for $cat1 $item1 and $var1
hope this help.

share|improve this answer

edited Mar 29 at 2:00

Alireza Zojaji

55811 gold badge77 silver badges2626 bronze badges

answered Mar 28 at 22:24

Sebastian P.Sebastian P.

7611 bronze badge

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That's great, thank you!
  
  – Foorio
  Mar 28 at 22:28
  

  
  
  
  

add a comment
 | 

4

assignation of values in most common programm languajes is up to down (cascade programming style)

$var1 = $item1; <--- at this point $item1 is "empty" or null
$item1 = $cat1; <--- at this point $cat1 is empty too
$cat1 = 'Bla Bla Bla'; <--- here $cat1 take value 'Bla Bla Bla' 

so, you have to invert order of assignation like this:

$cat1 = 'Bla Bla Bla';
$item1 = $cat1;
$var1 = $item1;

the output show 'Bla Bla Bla' for $cat1 $item1 and $var1
hope this help.

share|improve this answer

edited Mar 29 at 2:00

Alireza Zojaji

55811 gold badge77 silver badges2626 bronze badges

answered Mar 28 at 22:24

Sebastian P.Sebastian P.

7611 bronze badge

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That's great, thank you!
  
  – Foorio
  Mar 28 at 22:28
  

  
  
  
  

add a comment
 | 

assignation of values in most common programm languajes is up to down (cascade programming style)

$var1 = $item1; <--- at this point $item1 is "empty" or null
$item1 = $cat1; <--- at this point $cat1 is empty too
$cat1 = 'Bla Bla Bla'; <--- here $cat1 take value 'Bla Bla Bla' 

so, you have to invert order of assignation like this:

$cat1 = 'Bla Bla Bla';
$item1 = $cat1;
$var1 = $item1;

the output show 'Bla Bla Bla' for $cat1 $item1 and $var1
hope this help.

share|improve this answer

edited Mar 29 at 2:00

Alireza Zojaji

55811 gold badge77 silver badges2626 bronze badges

answered Mar 28 at 22:24

Sebastian P.Sebastian P.

7611 bronze badge

$var1 = $item1; <--- at this point $item1 is "empty" or null
$item1 = $cat1; <--- at this point $cat1 is empty too
$cat1 = 'Bla Bla Bla'; <--- here $cat1 take value 'Bla Bla Bla' 

$cat1 = 'Bla Bla Bla';
$item1 = $cat1;
$var1 = $item1;

share|improve this answer

edited Mar 29 at 2:00

Alireza Zojaji

55811 gold badge77 silver badges2626 bronze badges

answered Mar 28 at 22:24

Sebastian P.Sebastian P.

7611 bronze badge

edited Mar 29 at 2:00

Alireza Zojaji

55811 gold badge77 silver badges2626 bronze badges

edited Mar 29 at 2:00

Alireza Zojaji

55811 gold badge77 silver badges2626 bronze badges

answered Mar 28 at 22:24

Sebastian P.Sebastian P.

7611 bronze badge

answered Mar 28 at 22:24

Sebastian P.Sebastian P.

7611 bronze badge