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Why am I getting a response from the wrong API endpoint?

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0

I am following this tutorial initially I was trying to get a response using postman with the url

ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com/:8080

but it would not return a response, so then I tried without the / at the end and it returned what I wanted, why is this happening as my flask route clearly has a / in it

My flask app looks like this

from flask import Flask

application = Flask(__name__)

@application.route("/")
def hello():
 return "<h1 style='color:blue'>Hello There!</h1>"

if __name__ == '__main__':
 application.run(host="0.0.0.0", port="8080")

python flask

share|improve this question

asked Mar 21 at 15:26

Connor McCannConnor McCann

947

add a comment | 

0

I am following this tutorial initially I was trying to get a response using postman with the url

ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com/:8080

but it would not return a response, so then I tried without the / at the end and it returned what I wanted, why is this happening as my flask route clearly has a / in it

My flask app looks like this

from flask import Flask

application = Flask(__name__)

@application.route("/")
def hello():
 return "<h1 style='color:blue'>Hello There!</h1>"

if __name__ == '__main__':
 application.run(host="0.0.0.0", port="8080")

python flask

share|improve this question

asked Mar 21 at 15:26

Connor McCannConnor McCann

947

add a comment | 

I am following this tutorial initially I was trying to get a response using postman with the url

ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com/:8080

but it would not return a response, so then I tried without the / at the end and it returned what I wanted, why is this happening as my flask route clearly has a / in it

My flask app looks like this

from flask import Flask

application = Flask(__name__)

@application.route("/")
def hello():
 return "<h1 style='color:blue'>Hello There!</h1>"

if __name__ == '__main__':
 application.run(host="0.0.0.0", port="8080")

python flask

share|improve this question

asked Mar 21 at 15:26

Connor McCannConnor McCann

947

from flask import Flask

application = Flask(__name__)

@application.route("/")
def hello():
 return "<h1 style='color:blue'>Hello There!</h1>"

if __name__ == '__main__':
 application.run(host="0.0.0.0", port="8080")

share|improve this question

asked Mar 21 at 15:26

Connor McCannConnor McCann

947

share|improve this question

asked Mar 21 at 15:26

Connor McCannConnor McCann

947

asked Mar 21 at 15:26

Connor McCannConnor McCann

947

asked Mar 21 at 15:26

Connor McCannConnor McCann

947

2 Answers
2

active

oldest

votes

4

The order of the parts of a URL is important.

The URL

ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com/:8080

Is going to attempt port 80, and look for a path /:8080.

ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com:8080/

Will attempt port 8080 and look for a path /

share|improve this answer

edited Mar 21 at 15:46

answered Mar 21 at 15:31

Ian McLairdIan McLaird

4,96021630

add a comment | 

1

There are two different concepts that you are getting mixed up on here.

The line @application.route("/") defines the root of your site. That is the default entry point or path if you enter your site address in a browser without e.g /about at the end.

The address ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com:8080 is a combination of the web server address and port, separated by a colon. You will not get a response if you alter this address. You could add a "/" after the 8080 to get to a particular page.

share|improve this answer

answered Mar 21 at 15:32

NickNick

1,10911634

add a comment | 

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4

The order of the parts of a URL is important.

The URL

ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com/:8080

Is going to attempt port 80, and look for a path /:8080.

ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com:8080/

Will attempt port 8080 and look for a path /

share|improve this answer

edited Mar 21 at 15:46

answered Mar 21 at 15:31

Ian McLairdIan McLaird

4,96021630

add a comment | 

4

The order of the parts of a URL is important.

The URL

ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com/:8080

Is going to attempt port 80, and look for a path /:8080.

ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com:8080/

Will attempt port 8080 and look for a path /

share|improve this answer

edited Mar 21 at 15:46

answered Mar 21 at 15:31

Ian McLairdIan McLaird

4,96021630

add a comment | 

The order of the parts of a URL is important.

The URL

ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com/:8080

Is going to attempt port 80, and look for a path /:8080.

ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com:8080/

Will attempt port 8080 and look for a path /

share|improve this answer

edited Mar 21 at 15:46

answered Mar 21 at 15:31

Ian McLairdIan McLaird

4,96021630

share|improve this answer

edited Mar 21 at 15:46

answered Mar 21 at 15:31

Ian McLairdIan McLaird

4,96021630

answered Mar 21 at 15:31

Ian McLairdIan McLaird

4,96021630

answered Mar 21 at 15:31

Ian McLairdIan McLaird

4,96021630

1

There are two different concepts that you are getting mixed up on here.

The line @application.route("/") defines the root of your site. That is the default entry point or path if you enter your site address in a browser without e.g /about at the end.

The address ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com:8080 is a combination of the web server address and port, separated by a colon. You will not get a response if you alter this address. You could add a "/" after the 8080 to get to a particular page.

share|improve this answer

answered Mar 21 at 15:32

NickNick

1,10911634

add a comment | 

1

There are two different concepts that you are getting mixed up on here.

The line @application.route("/") defines the root of your site. That is the default entry point or path if you enter your site address in a browser without e.g /about at the end.

The address ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com:8080 is a combination of the web server address and port, separated by a colon. You will not get a response if you alter this address. You could add a "/" after the 8080 to get to a particular page.

share|improve this answer

answered Mar 21 at 15:32

NickNick

1,10911634

add a comment | 

There are two different concepts that you are getting mixed up on here.

The line @application.route("/") defines the root of your site. That is the default entry point or path if you enter your site address in a browser without e.g /about at the end.

The address ec2-x-x-xxx-xx.eu-west-2.compute.amazonaws.com:8080 is a combination of the web server address and port, separated by a colon. You will not get a response if you alter this address. You could add a "/" after the 8080 to get to a particular page.

share|improve this answer

answered Mar 21 at 15:32

NickNick

1,10911634

share|improve this answer

answered Mar 21 at 15:32

NickNick

1,10911634

answered Mar 21 at 15:32

NickNick

1,10911634

answered Mar 21 at 15:32

NickNick

1,10911634