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How to unsubscribe from onSnaphot() in mobx-state-tree?


How to validate an email address in JavaScript?How do JavaScript closures work?How do I check if an element is hidden in jQuery?How do I remove a property from a JavaScript object?How do I redirect to another webpage?How do I include a JavaScript file in another JavaScript file?How to replace all occurrences of a string in JavaScriptHow to check whether a string contains a substring in JavaScript?How do I remove a particular element from an array in JavaScript?How do I return the response from an asynchronous call?













0















I'm using mobx-state-tree's onSnapshot() feature to listen to state changes, I then persist the state with every change in local storage. This is how I do it:



import onSnapshot from "mobx-state-tree";

onSnapshot(store, newSnapshot =>

saveLocalSnapshot(newSnapshot);

);


My question is, how do I unsubscribe from onSnapshot() when my app needs to stop persisting every snapshot?










share|improve this question






















  • As a work-around, I've wrapped the saveLocalSnapshot() call in an if statement, which checks a new property I added: store.shouldPersistSnapshots. This solves my problem but there has to be a more elegant way.

    – Lunster
    Mar 21 at 18:21
















0















I'm using mobx-state-tree's onSnapshot() feature to listen to state changes, I then persist the state with every change in local storage. This is how I do it:



import onSnapshot from "mobx-state-tree";

onSnapshot(store, newSnapshot =>

saveLocalSnapshot(newSnapshot);

);


My question is, how do I unsubscribe from onSnapshot() when my app needs to stop persisting every snapshot?










share|improve this question






















  • As a work-around, I've wrapped the saveLocalSnapshot() call in an if statement, which checks a new property I added: store.shouldPersistSnapshots. This solves my problem but there has to be a more elegant way.

    – Lunster
    Mar 21 at 18:21














0












0








0








I'm using mobx-state-tree's onSnapshot() feature to listen to state changes, I then persist the state with every change in local storage. This is how I do it:



import onSnapshot from "mobx-state-tree";

onSnapshot(store, newSnapshot =>

saveLocalSnapshot(newSnapshot);

);


My question is, how do I unsubscribe from onSnapshot() when my app needs to stop persisting every snapshot?










share|improve this question














I'm using mobx-state-tree's onSnapshot() feature to listen to state changes, I then persist the state with every change in local storage. This is how I do it:



import onSnapshot from "mobx-state-tree";

onSnapshot(store, newSnapshot =>

saveLocalSnapshot(newSnapshot);

);


My question is, how do I unsubscribe from onSnapshot() when my app needs to stop persisting every snapshot?







javascript reactjs mobx mobx-state-tree






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 21 at 15:22









LunsterLunster

699412




699412












  • As a work-around, I've wrapped the saveLocalSnapshot() call in an if statement, which checks a new property I added: store.shouldPersistSnapshots. This solves my problem but there has to be a more elegant way.

    – Lunster
    Mar 21 at 18:21


















  • As a work-around, I've wrapped the saveLocalSnapshot() call in an if statement, which checks a new property I added: store.shouldPersistSnapshots. This solves my problem but there has to be a more elegant way.

    – Lunster
    Mar 21 at 18:21

















As a work-around, I've wrapped the saveLocalSnapshot() call in an if statement, which checks a new property I added: store.shouldPersistSnapshots. This solves my problem but there has to be a more elegant way.

– Lunster
Mar 21 at 18:21






As a work-around, I've wrapped the saveLocalSnapshot() call in an if statement, which checks a new property I added: store.shouldPersistSnapshots. This solves my problem but there has to be a more elegant way.

– Lunster
Mar 21 at 18:21













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