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dividing matrix into four sub-blocks
Does a finally block always get executed in Java?Fastest way to determine if an integer's square root is an integerHow do I read / convert an InputStream into a String in Java?What is the difference between a static and a non-static initialization code blockHow to reference sub-matrices within a matrixHow do I convert a String to an int in Java?Dealing with “Xerces hell” in Java/Maven?Find the largest-sum sub-matrixdivide matrix to blocks with parallel diagonal linesJava 8 Distinct by property
i want devide matrix into four sub-blocks equally by vertically and horizontallty in java (Here, we suppose that m and nare even numbers) .
for example we have matrix:
1 2 3 4 5 6
7 8 9 1 2 8
1 2 3 4 5 6
4 5 6 7 8 9
1 4 7 2 5 8
3 6 9 7 2 5
I want to display the last block that is:
7 8 9
2 5 8
7 2 5
how i can resolve this problem in java.
java
edited Mar 21 at 20:33
Sterling Archer
16.1k126191
asked Mar 21 at 17:23
rouinrouin
13
|
show 1 more comment
i want devide matrix into four sub-blocks equally by vertically and horizontallty in java (Here, we suppose that m and nare even numbers) .
for example we have matrix:
1 2 3 4 5 6
7 8 9 1 2 8
1 2 3 4 5 6
4 5 6 7 8 9
1 4 7 2 5 8
3 6 9 7 2 5
I want to display the last block that is:
7 8 9
2 5 8
7 2 5
how i can resolve this problem in java.
java
edited Mar 21 at 20:33
Sterling Archer
16.1k126191
asked Mar 21 at 17:23
rouinrouin
13
3
Iterate over the right part of the matrix. What did you try so far? Please show us your efforts
– MWB
Mar 21 at 17:28
how i can do this. can you help me?
– rouin
Mar 21 at 17:31
All you need is 4forloops. Begin with the top left corner.
– Arnaud Denoyelle
Mar 21 at 17:33
I'm thinking a nested for loop where i and j start at n/2 or m/2. You should try to implement this yourself and come back with the problems you face and ask a more specific question.
– Patrick
Mar 21 at 17:33
Help us helping you by at least throwing in some code you did yourself. We will not code this for you.
– NaeiKinDus
Mar 21 at 17:33
|
show 1 more comment
i want devide matrix into four sub-blocks equally by vertically and horizontallty in java (Here, we suppose that m and nare even numbers) .
for example we have matrix:
1 2 3 4 5 6
7 8 9 1 2 8
1 2 3 4 5 6
4 5 6 7 8 9
1 4 7 2 5 8
3 6 9 7 2 5
I want to display the last block that is:
7 8 9
2 5 8
7 2 5
how i can resolve this problem in java.
java
edited Mar 21 at 20:33
Sterling Archer
16.1k126191
asked Mar 21 at 17:23
rouinrouin
13
i want devide matrix into four sub-blocks equally by vertically and horizontallty in java (Here, we suppose that m and nare even numbers) .
for example we have matrix:
1 2 3 4 5 6
7 8 9 1 2 8
1 2 3 4 5 6
4 5 6 7 8 9
1 4 7 2 5 8
3 6 9 7 2 5
I want to display the last block that is:
7 8 9
2 5 8
7 2 5
how i can resolve this problem in java.
java
java
edited Mar 21 at 20:33
Sterling Archer
16.1k126191
asked Mar 21 at 17:23
rouinrouin
13
edited Mar 21 at 20:33
Sterling Archer
16.1k126191
asked Mar 21 at 17:23
rouinrouin
13
edited Mar 21 at 20:33
Sterling Archer
16.1k126191
edited Mar 21 at 20:33
Sterling Archer
16.1k126191
edited Mar 21 at 20:33
Sterling Archer
16.1k126191
16.1k126191
asked Mar 21 at 17:23
rouinrouin
13
asked Mar 21 at 17:23
rouinrouin
13
asked Mar 21 at 17:23
rouinrouin
13
13
3
Iterate over the right part of the matrix. What did you try so far? Please show us your efforts
– MWB
Mar 21 at 17:28
how i can do this. can you help me?
– rouin
Mar 21 at 17:31
All you need is 4forloops. Begin with the top left corner.
– Arnaud Denoyelle
Mar 21 at 17:33
I'm thinking a nested for loop where i and j start at n/2 or m/2. You should try to implement this yourself and come back with the problems you face and ask a more specific question.
– Patrick
Mar 21 at 17:33
Help us helping you by at least throwing in some code you did yourself. We will not code this for you.
– NaeiKinDus
Mar 21 at 17:33
|
show 1 more comment
3
Iterate over the right part of the matrix. What did you try so far? Please show us your efforts
– MWB
Mar 21 at 17:28
how i can do this. can you help me?
– rouin
Mar 21 at 17:31
All you need is 4forloops. Begin with the top left corner.
– Arnaud Denoyelle
Mar 21 at 17:33
I'm thinking a nested for loop where i and j start at n/2 or m/2. You should try to implement this yourself and come back with the problems you face and ask a more specific question.
– Patrick
Mar 21 at 17:33
Help us helping you by at least throwing in some code you did yourself. We will not code this for you.
– NaeiKinDus
Mar 21 at 17:33
3
3
Iterate over the right part of the matrix. What did you try so far? Please show us your efforts
– MWB
Mar 21 at 17:28
Iterate over the right part of the matrix. What did you try so far? Please show us your efforts
– MWB
Mar 21 at 17:28
how i can do this. can you help me?
– rouin
Mar 21 at 17:31
how i can do this. can you help me?
– rouin
Mar 21 at 17:31
All you need is 4
for loops. Begin with the top left corner.– Arnaud Denoyelle
Mar 21 at 17:33
All you need is 4
for loops. Begin with the top left corner.– Arnaud Denoyelle
Mar 21 at 17:33
I'm thinking a nested for loop where i and j start at n/2 or m/2. You should try to implement this yourself and come back with the problems you face and ask a more specific question.
– Patrick
Mar 21 at 17:33
I'm thinking a nested for loop where i and j start at n/2 or m/2. You should try to implement this yourself and come back with the problems you face and ask a more specific question.
– Patrick
Mar 21 at 17:33
Help us helping you by at least throwing in some code you did yourself. We will not code this for you.
– NaeiKinDus
Mar 21 at 17:33
Help us helping you by at least throwing in some code you did yourself. We will not code this for you.
– NaeiKinDus
Mar 21 at 17:33
|
show 1 more comment
1 Answer
1
active
oldest
votes
Iterate over the lower-right part of the matrix. Here is an example for a square matrix. I am sure you will be able to make it more generic for non-square quadrants or to get other quadrants than the lower-right one.
public int[][] getQuadrantOfSquareMatrix(int[][] matrix)
int newDimension = matrix.length / 2;
int[][] toReturn = new int[newDimension][newDimension];
for (int i = 0; i < newDimension; i++)
for (int j = 0; j < newDimension; j++)
toReturn[i][j] = matrix[i + newDimension][j + newDimension];
return toReturn;
answered Mar 21 at 17:36
MWBMWB
8761819
You can’t assume that the matrix is square, only that both dimensions are even.
– Joakim Danielson
Mar 21 at 20:38
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
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oldest
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active
oldest
votes
Iterate over the lower-right part of the matrix. Here is an example for a square matrix. I am sure you will be able to make it more generic for non-square quadrants or to get other quadrants than the lower-right one.
public int[][] getQuadrantOfSquareMatrix(int[][] matrix)
int newDimension = matrix.length / 2;
int[][] toReturn = new int[newDimension][newDimension];
for (int i = 0; i < newDimension; i++)
for (int j = 0; j < newDimension; j++)
toReturn[i][j] = matrix[i + newDimension][j + newDimension];
return toReturn;
answered Mar 21 at 17:36
MWBMWB
8761819
You can’t assume that the matrix is square, only that both dimensions are even.
– Joakim Danielson
Mar 21 at 20:38
add a comment |
Iterate over the lower-right part of the matrix. Here is an example for a square matrix. I am sure you will be able to make it more generic for non-square quadrants or to get other quadrants than the lower-right one.
public int[][] getQuadrantOfSquareMatrix(int[][] matrix)
int newDimension = matrix.length / 2;
int[][] toReturn = new int[newDimension][newDimension];
for (int i = 0; i < newDimension; i++)
for (int j = 0; j < newDimension; j++)
toReturn[i][j] = matrix[i + newDimension][j + newDimension];
return toReturn;
answered Mar 21 at 17:36
MWBMWB
8761819
You can’t assume that the matrix is square, only that both dimensions are even.
– Joakim Danielson
Mar 21 at 20:38
add a comment |
Iterate over the lower-right part of the matrix. Here is an example for a square matrix. I am sure you will be able to make it more generic for non-square quadrants or to get other quadrants than the lower-right one.
public int[][] getQuadrantOfSquareMatrix(int[][] matrix)
int newDimension = matrix.length / 2;
int[][] toReturn = new int[newDimension][newDimension];
for (int i = 0; i < newDimension; i++)
for (int j = 0; j < newDimension; j++)
toReturn[i][j] = matrix[i + newDimension][j + newDimension];
return toReturn;
answered Mar 21 at 17:36
MWBMWB
8761819
Iterate over the lower-right part of the matrix. Here is an example for a square matrix. I am sure you will be able to make it more generic for non-square quadrants or to get other quadrants than the lower-right one.
public int[][] getQuadrantOfSquareMatrix(int[][] matrix)
int newDimension = matrix.length / 2;
int[][] toReturn = new int[newDimension][newDimension];
for (int i = 0; i < newDimension; i++)
for (int j = 0; j < newDimension; j++)
toReturn[i][j] = matrix[i + newDimension][j + newDimension];
return toReturn;
answered Mar 21 at 17:36
MWBMWB
8761819
answered Mar 21 at 17:36
MWBMWB
8761819
answered Mar 21 at 17:36
MWBMWB
8761819
answered Mar 21 at 17:36
MWBMWB
8761819
8761819
You can’t assume that the matrix is square, only that both dimensions are even.
– Joakim Danielson
Mar 21 at 20:38
add a comment |
You can’t assume that the matrix is square, only that both dimensions are even.
– Joakim Danielson
Mar 21 at 20:38
You can’t assume that the matrix is square, only that both dimensions are even.
– Joakim Danielson
Mar 21 at 20:38
You can’t assume that the matrix is square, only that both dimensions are even.
– Joakim Danielson
Mar 21 at 20:38
add a comment |
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3
Iterate over the right part of the matrix. What did you try so far? Please show us your efforts
– MWB
Mar 21 at 17:28
how i can do this. can you help me?
– rouin
Mar 21 at 17:31
All you need is 4
forloops. Begin with the top left corner.– Arnaud Denoyelle
Mar 21 at 17:33
I'm thinking a nested for loop where i and j start at n/2 or m/2. You should try to implement this yourself and come back with the problems you face and ask a more specific question.
– Patrick
Mar 21 at 17:33
Help us helping you by at least throwing in some code you did yourself. We will not code this for you.
– NaeiKinDus
Mar 21 at 17:33