Styjun

Arrays:

 array1 = [id:1, name:"raju",id:2, name:"ravi",id:4, name:"john",id:6, name:"jack"];
 array2= [id:1, degree:"b.com",id:3, degree:"b.a",id:4, degree:"c.a",id:5, degree:"horticulture"];
 array3= [id:1, age:20,id:3, age:21,id:6, age:27,id:7, age:25];

Required result is:

resultarray = [
 id:1, name: "raju", degree:"b.com",age:20,
 id:2, name: "ravi",
 id:3, degree:"b.a", age:21,
 id:4, name:"john", degree:"c.a",
 id:5, degree:"horticulture",
 id:6, name:"jack", age:27,
 id:7, age:25
 ] 

i have tried different functions and tried for two arrays but not able to merge the object which doesnt have id to compare..

You can use reduce and destructuring

Here idea is

• First merge all the arrays in one array.


• Now using reduce we create id as key in op object


• If id key is already there we merge the inp and op[inp.id]
  


• If id is not there we create a new key with value inp
  

let array1 = [id:1, name:"raju",id:2, name:"ravi",id:4, name:"john",id:6, name:"jack"];
let array2= [id:1, degree:"b.com",id:3, degree:"b.a",id:4, degree:"c.a",id:5, degree:"horticulture"];
let array3= [id:1, age:20,id:3, age:21,id:6, age:27,id:7, age:25];

let temp = [...array1,...array2,...array3]

let op = temp.reduce((op,inp)=>,)

console.log(Object.values(op))

a possible solution:

let array1 = [id:1, name:"raju",id:2, name:"ravi",id:4, name:"john",id:6, name:"jack"];
let array2= [id:1, degree:"b.com",id:3, degree:"b.a",id:4, degree:"c.a",id:5, degree:"horticulture"];
let array3= [id:1, age:20,id:3, age:21,id:6, age:27,id:7, age:25];

let resp = [].concat(array1, array2, array3).reduce((acc, ele) => 
 let obj = acc.find(x => x.id === ele.id);
 return obj ? (Object.keys(ele).forEach(x => obj[x] = ele[x]), acc) : acc.concat(ele);
 , [])
 
console.log(resp)

There will be better solutions than this, but this is what I've tried:

Merging the 3 arrays into one :

let array = [...array1, ...array2, ...array3]

Looping through the items and then putting the values to "object"

let object = 
array.forEach((item) => 
 object[item.id] = ...object[item.id],...item)

Final solution

result = Object.values(object)

object variable will contain

object = '1': id: 1, age: 20, name: 'raju', degree: 'b.com' ,
 '2': id: 2, name: 'ravi' ,
 '3': id: 3, age: 21, degree: 'b.a' ,
 '4': id: 4, degree: 'c.a', name: 'john' ,
 '5': id: 5, degree: 'horticulture' ,
 '6': id: 6, age: 27, name: 'jack' ,
 '7': id: 7, age: 25 

result variable will contain

result = [ id: 1, age: 20, name: 'raju', degree: 'b.com' ,
 id: 2, name: 'ravi' ,
 id: 3, age: 21, degree: 'b.a' ,
 id: 4, degree: 'c.a', name: 'john' ,
 id: 5, degree: 'horticulture' ,
 id: 6, age: 27, name: 'jack' ,
 id: 7, age: 25 ]