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How to update multiple values in mysql based on another table using join



The 2019 Stack Overflow Developer Survey Results Are InAdd a column with a default value to an existing table in SQL ServerSQL update from one Table to another based on a ID matchCan I concatenate multiple MySQL rows into one field?How to get a list of MySQL user accountsHow can I do an UPDATE statement with JOIN in SQL?How do I UPDATE from a SELECT in SQL Server?Finding duplicate values in a SQL tableInsert into a MySQL table or update if existsHow to reset AUTO_INCREMENT in MySQL?How to import an SQL file using the command line in MySQL?



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0















I have two tables products and filters. My products table is like below:-



id name color_id size_id composition_id
1 Test Black 60x60 CM Cotton
2 Test2 Red 60X90 CM Acryllic


My filters table as below:-



id filter_name
1 Black
2 Red
22 60x60 CM
23 60X90 CM
61 Cotton
62 Acryllic


My Expected output like below:-



id name color_id size_id composition_id
1 Test 1 22 61
2 Test2 2 23 62


I have tried below query that is working for only color_id. Query is below:-



UPDATE products
INNER JOIN filters ON products.color_id = filters.filter_name
SET products.color_id = filters.id


I want to update all ' color_id,size_id,composition_id' in one update statement. May be we need to use Case Statements. Can anyone help?










share|improve this question




























    0















    I have two tables products and filters. My products table is like below:-



    id name color_id size_id composition_id
    1 Test Black 60x60 CM Cotton
    2 Test2 Red 60X90 CM Acryllic


    My filters table as below:-



    id filter_name
    1 Black
    2 Red
    22 60x60 CM
    23 60X90 CM
    61 Cotton
    62 Acryllic


    My Expected output like below:-



    id name color_id size_id composition_id
    1 Test 1 22 61
    2 Test2 2 23 62


    I have tried below query that is working for only color_id. Query is below:-



    UPDATE products
    INNER JOIN filters ON products.color_id = filters.filter_name
    SET products.color_id = filters.id


    I want to update all ' color_id,size_id,composition_id' in one update statement. May be we need to use Case Statements. Can anyone help?










    share|improve this question
























      0












      0








      0








      I have two tables products and filters. My products table is like below:-



      id name color_id size_id composition_id
      1 Test Black 60x60 CM Cotton
      2 Test2 Red 60X90 CM Acryllic


      My filters table as below:-



      id filter_name
      1 Black
      2 Red
      22 60x60 CM
      23 60X90 CM
      61 Cotton
      62 Acryllic


      My Expected output like below:-



      id name color_id size_id composition_id
      1 Test 1 22 61
      2 Test2 2 23 62


      I have tried below query that is working for only color_id. Query is below:-



      UPDATE products
      INNER JOIN filters ON products.color_id = filters.filter_name
      SET products.color_id = filters.id


      I want to update all ' color_id,size_id,composition_id' in one update statement. May be we need to use Case Statements. Can anyone help?










      share|improve this question














      I have two tables products and filters. My products table is like below:-



      id name color_id size_id composition_id
      1 Test Black 60x60 CM Cotton
      2 Test2 Red 60X90 CM Acryllic


      My filters table as below:-



      id filter_name
      1 Black
      2 Red
      22 60x60 CM
      23 60X90 CM
      61 Cotton
      62 Acryllic


      My Expected output like below:-



      id name color_id size_id composition_id
      1 Test 1 22 61
      2 Test2 2 23 62


      I have tried below query that is working for only color_id. Query is below:-



      UPDATE products
      INNER JOIN filters ON products.color_id = filters.filter_name
      SET products.color_id = filters.id


      I want to update all ' color_id,size_id,composition_id' in one update statement. May be we need to use Case Statements. Can anyone help?







      mysql sql






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 22 at 4:53









      kunalkunal

      12210




      12210






















          1 Answer
          1






          active

          oldest

          votes


















          2














          One way you can do this is with a set of correlated subqueries, one for each column that you need to look up. We use a COALESCE so that if the value is not found, we retain the previous value:



          UPDATE products p
          SET color_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.color_id), color_id),
          size_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.size_id), size_id),
          composition_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.composition_id), composition_id)


          Then you can SELECT * FROM products:



          id name color_id size_id composition_id
          1 Test 1 22 61
          2 Test2 2 23 62


          Demo on dbfiddle



          You can also achieve the same result with an UPDATE ... JOIN query, which might be more efficient:



          UPDATE products p
          LEFT JOIN filters f1 ON f1.filter_name = p.color_id
          LEFT JOIN filters f2 ON f2.filter_name = p.size_id
          LEFT JOIN filters f3 ON f3.filter_name = p.composition_id
          SET color_id = COALESCE(f1.id, color_id),
          size_id = COALESCE(f2.id, size_id),
          composition_id = COALESCE(f3.id, composition_id)


          Demo on dbfiddle






          share|improve this answer

























          • Your way is right but what if my 100 records are already updated and i again run this query... above 100 records will be empty .. Hope you understand

            – kunal
            Mar 22 at 5:07












          • @kunal I didn't realise you might run the query multiple times. I've updated it (and the demo) for that situation

            – Nick
            Mar 22 at 5:12











          • actually my client don't want to fill ids in column.. So my client gives csv sheet with names every week so i will update the sql query manually . Hope you understand

            – kunal
            Mar 22 at 5:15






          • 1





            @kunal no worries. Glad I could help.

            – Nick
            Mar 22 at 5:21






          • 1





            COALESCE looks at each of its arguments, starting from the left, and returns the first one that is not NULL. So for example, in the second query, if there is no match for color_id in filters, f1.id will be NULL and the COALESCE(f1.id, color_id) will return the original value of color_id

            – Nick
            Mar 22 at 5:25











          Your Answer






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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          One way you can do this is with a set of correlated subqueries, one for each column that you need to look up. We use a COALESCE so that if the value is not found, we retain the previous value:



          UPDATE products p
          SET color_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.color_id), color_id),
          size_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.size_id), size_id),
          composition_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.composition_id), composition_id)


          Then you can SELECT * FROM products:



          id name color_id size_id composition_id
          1 Test 1 22 61
          2 Test2 2 23 62


          Demo on dbfiddle



          You can also achieve the same result with an UPDATE ... JOIN query, which might be more efficient:



          UPDATE products p
          LEFT JOIN filters f1 ON f1.filter_name = p.color_id
          LEFT JOIN filters f2 ON f2.filter_name = p.size_id
          LEFT JOIN filters f3 ON f3.filter_name = p.composition_id
          SET color_id = COALESCE(f1.id, color_id),
          size_id = COALESCE(f2.id, size_id),
          composition_id = COALESCE(f3.id, composition_id)


          Demo on dbfiddle






          share|improve this answer

























          • Your way is right but what if my 100 records are already updated and i again run this query... above 100 records will be empty .. Hope you understand

            – kunal
            Mar 22 at 5:07












          • @kunal I didn't realise you might run the query multiple times. I've updated it (and the demo) for that situation

            – Nick
            Mar 22 at 5:12











          • actually my client don't want to fill ids in column.. So my client gives csv sheet with names every week so i will update the sql query manually . Hope you understand

            – kunal
            Mar 22 at 5:15






          • 1





            @kunal no worries. Glad I could help.

            – Nick
            Mar 22 at 5:21






          • 1





            COALESCE looks at each of its arguments, starting from the left, and returns the first one that is not NULL. So for example, in the second query, if there is no match for color_id in filters, f1.id will be NULL and the COALESCE(f1.id, color_id) will return the original value of color_id

            – Nick
            Mar 22 at 5:25















          2














          One way you can do this is with a set of correlated subqueries, one for each column that you need to look up. We use a COALESCE so that if the value is not found, we retain the previous value:



          UPDATE products p
          SET color_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.color_id), color_id),
          size_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.size_id), size_id),
          composition_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.composition_id), composition_id)


          Then you can SELECT * FROM products:



          id name color_id size_id composition_id
          1 Test 1 22 61
          2 Test2 2 23 62


          Demo on dbfiddle



          You can also achieve the same result with an UPDATE ... JOIN query, which might be more efficient:



          UPDATE products p
          LEFT JOIN filters f1 ON f1.filter_name = p.color_id
          LEFT JOIN filters f2 ON f2.filter_name = p.size_id
          LEFT JOIN filters f3 ON f3.filter_name = p.composition_id
          SET color_id = COALESCE(f1.id, color_id),
          size_id = COALESCE(f2.id, size_id),
          composition_id = COALESCE(f3.id, composition_id)


          Demo on dbfiddle






          share|improve this answer

























          • Your way is right but what if my 100 records are already updated and i again run this query... above 100 records will be empty .. Hope you understand

            – kunal
            Mar 22 at 5:07












          • @kunal I didn't realise you might run the query multiple times. I've updated it (and the demo) for that situation

            – Nick
            Mar 22 at 5:12











          • actually my client don't want to fill ids in column.. So my client gives csv sheet with names every week so i will update the sql query manually . Hope you understand

            – kunal
            Mar 22 at 5:15






          • 1





            @kunal no worries. Glad I could help.

            – Nick
            Mar 22 at 5:21






          • 1





            COALESCE looks at each of its arguments, starting from the left, and returns the first one that is not NULL. So for example, in the second query, if there is no match for color_id in filters, f1.id will be NULL and the COALESCE(f1.id, color_id) will return the original value of color_id

            – Nick
            Mar 22 at 5:25













          2












          2








          2







          One way you can do this is with a set of correlated subqueries, one for each column that you need to look up. We use a COALESCE so that if the value is not found, we retain the previous value:



          UPDATE products p
          SET color_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.color_id), color_id),
          size_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.size_id), size_id),
          composition_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.composition_id), composition_id)


          Then you can SELECT * FROM products:



          id name color_id size_id composition_id
          1 Test 1 22 61
          2 Test2 2 23 62


          Demo on dbfiddle



          You can also achieve the same result with an UPDATE ... JOIN query, which might be more efficient:



          UPDATE products p
          LEFT JOIN filters f1 ON f1.filter_name = p.color_id
          LEFT JOIN filters f2 ON f2.filter_name = p.size_id
          LEFT JOIN filters f3 ON f3.filter_name = p.composition_id
          SET color_id = COALESCE(f1.id, color_id),
          size_id = COALESCE(f2.id, size_id),
          composition_id = COALESCE(f3.id, composition_id)


          Demo on dbfiddle






          share|improve this answer















          One way you can do this is with a set of correlated subqueries, one for each column that you need to look up. We use a COALESCE so that if the value is not found, we retain the previous value:



          UPDATE products p
          SET color_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.color_id), color_id),
          size_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.size_id), size_id),
          composition_id = COALESCE((SELECT id FROM filters WHERE filter_name = p.composition_id), composition_id)


          Then you can SELECT * FROM products:



          id name color_id size_id composition_id
          1 Test 1 22 61
          2 Test2 2 23 62


          Demo on dbfiddle



          You can also achieve the same result with an UPDATE ... JOIN query, which might be more efficient:



          UPDATE products p
          LEFT JOIN filters f1 ON f1.filter_name = p.color_id
          LEFT JOIN filters f2 ON f2.filter_name = p.size_id
          LEFT JOIN filters f3 ON f3.filter_name = p.composition_id
          SET color_id = COALESCE(f1.id, color_id),
          size_id = COALESCE(f2.id, size_id),
          composition_id = COALESCE(f3.id, composition_id)


          Demo on dbfiddle







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 22 at 5:11

























          answered Mar 22 at 5:05









          NickNick

          39.4k132443




          39.4k132443












          • Your way is right but what if my 100 records are already updated and i again run this query... above 100 records will be empty .. Hope you understand

            – kunal
            Mar 22 at 5:07












          • @kunal I didn't realise you might run the query multiple times. I've updated it (and the demo) for that situation

            – Nick
            Mar 22 at 5:12











          • actually my client don't want to fill ids in column.. So my client gives csv sheet with names every week so i will update the sql query manually . Hope you understand

            – kunal
            Mar 22 at 5:15






          • 1





            @kunal no worries. Glad I could help.

            – Nick
            Mar 22 at 5:21






          • 1





            COALESCE looks at each of its arguments, starting from the left, and returns the first one that is not NULL. So for example, in the second query, if there is no match for color_id in filters, f1.id will be NULL and the COALESCE(f1.id, color_id) will return the original value of color_id

            – Nick
            Mar 22 at 5:25

















          • Your way is right but what if my 100 records are already updated and i again run this query... above 100 records will be empty .. Hope you understand

            – kunal
            Mar 22 at 5:07












          • @kunal I didn't realise you might run the query multiple times. I've updated it (and the demo) for that situation

            – Nick
            Mar 22 at 5:12











          • actually my client don't want to fill ids in column.. So my client gives csv sheet with names every week so i will update the sql query manually . Hope you understand

            – kunal
            Mar 22 at 5:15






          • 1





            @kunal no worries. Glad I could help.

            – Nick
            Mar 22 at 5:21






          • 1





            COALESCE looks at each of its arguments, starting from the left, and returns the first one that is not NULL. So for example, in the second query, if there is no match for color_id in filters, f1.id will be NULL and the COALESCE(f1.id, color_id) will return the original value of color_id

            – Nick
            Mar 22 at 5:25
















          Your way is right but what if my 100 records are already updated and i again run this query... above 100 records will be empty .. Hope you understand

          – kunal
          Mar 22 at 5:07






          Your way is right but what if my 100 records are already updated and i again run this query... above 100 records will be empty .. Hope you understand

          – kunal
          Mar 22 at 5:07














          @kunal I didn't realise you might run the query multiple times. I've updated it (and the demo) for that situation

          – Nick
          Mar 22 at 5:12





          @kunal I didn't realise you might run the query multiple times. I've updated it (and the demo) for that situation

          – Nick
          Mar 22 at 5:12













          actually my client don't want to fill ids in column.. So my client gives csv sheet with names every week so i will update the sql query manually . Hope you understand

          – kunal
          Mar 22 at 5:15





          actually my client don't want to fill ids in column.. So my client gives csv sheet with names every week so i will update the sql query manually . Hope you understand

          – kunal
          Mar 22 at 5:15




          1




          1





          @kunal no worries. Glad I could help.

          – Nick
          Mar 22 at 5:21





          @kunal no worries. Glad I could help.

          – Nick
          Mar 22 at 5:21




          1




          1





          COALESCE looks at each of its arguments, starting from the left, and returns the first one that is not NULL. So for example, in the second query, if there is no match for color_id in filters, f1.id will be NULL and the COALESCE(f1.id, color_id) will return the original value of color_id

          – Nick
          Mar 22 at 5:25





          COALESCE looks at each of its arguments, starting from the left, and returns the first one that is not NULL. So for example, in the second query, if there is no match for color_id in filters, f1.id will be NULL and the COALESCE(f1.id, color_id) will return the original value of color_id

          – Nick
          Mar 22 at 5:25



















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