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How to search for a value in array of objects and get it in Laravel?

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0

How to search an array of objects and get a specific value if exists, and if not, take something else in Laravel 5.8?

Collection
 #items: array:3[
 0 = Object
 attributes[
 "id" => 1
 "name" => 'google'
 "url" => 'https://google.com/'
 ]
 
 1 = Object
 2 = Object
 ]

So out of this how to check if in this array there is an attribute url that has google.com in it? If something like this does not exists than get something else?

Is it possible to do this without looping?

php arrays laravel

share|improve this question

edited Mar 22 at 11:25

Tridev Shrestha

301217

asked Mar 22 at 8:36

Emmanuel-AbEmmanuel-Ab

368

add a comment | 

0

How to search an array of objects and get a specific value if exists, and if not, take something else in Laravel 5.8?

Collection
 #items: array:3[
 0 = Object
 attributes[
 "id" => 1
 "name" => 'google'
 "url" => 'https://google.com/'
 ]
 
 1 = Object
 2 = Object
 ]

So out of this how to check if in this array there is an attribute url that has google.com in it? If something like this does not exists than get something else?

Is it possible to do this without looping?

php arrays laravel

share|improve this question

edited Mar 22 at 11:25

Tridev Shrestha

301217

asked Mar 22 at 8:36

Emmanuel-AbEmmanuel-Ab

368

add a comment | 

How to search an array of objects and get a specific value if exists, and if not, take something else in Laravel 5.8?

Collection
 #items: array:3[
 0 = Object
 attributes[
 "id" => 1
 "name" => 'google'
 "url" => 'https://google.com/'
 ]
 
 1 = Object
 2 = Object
 ]

So out of this how to check if in this array there is an attribute url that has google.com in it? If something like this does not exists than get something else?

Is it possible to do this without looping?

php arrays laravel

share|improve this question

edited Mar 22 at 11:25

Tridev Shrestha

301217

asked Mar 22 at 8:36

Emmanuel-AbEmmanuel-Ab

368

Collection
 #items: array:3[
 0 = Object
 attributes[
 "id" => 1
 "name" => 'google'
 "url" => 'https://google.com/'
 ]
 
 1 = Object
 2 = Object
 ]

share|improve this question

edited Mar 22 at 11:25

Tridev Shrestha

301217

asked Mar 22 at 8:36

Emmanuel-AbEmmanuel-Ab

368

share|improve this question

edited Mar 22 at 11:25

Tridev Shrestha

301217

asked Mar 22 at 8:36

Emmanuel-AbEmmanuel-Ab

368

edited Mar 22 at 11:25

Tridev Shrestha

301217

edited Mar 22 at 11:25

Tridev Shrestha

301217

asked Mar 22 at 8:36

Emmanuel-AbEmmanuel-Ab

368

asked Mar 22 at 8:36

Emmanuel-AbEmmanuel-Ab

368

1 Answer
1

active

oldest

votes

3

Assuming the collection variable is $sites, you should be able to use the ->contains() closure to check if any of the $sites contains the google url:

$hasGoogle = $sites->contains(function ($site, $key) 
 return $site->url == 'https://google.com';
);

if ($hasGoogle) 
 // do something
 else 
 // do something else

A boolean is returned from the ->contains() method.

share|improve this answer

edited Mar 22 at 14:17

answered Mar 22 at 9:41

thisiskelvinthisiskelvin

2,275414

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Thank you! This is awesome. :)
  
  – Emmanuel-Ab
  Mar 22 at 9:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Emmanuel-Ab You are welcome.
  
  – thisiskelvin
  Mar 22 at 9:59
  

  
  
  
  

add a comment | 

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3

Assuming the collection variable is $sites, you should be able to use the ->contains() closure to check if any of the $sites contains the google url:

$hasGoogle = $sites->contains(function ($site, $key) 
 return $site->url == 'https://google.com';
);

if ($hasGoogle) 
 // do something
 else 
 // do something else

A boolean is returned from the ->contains() method.

share|improve this answer

edited Mar 22 at 14:17

answered Mar 22 at 9:41

thisiskelvinthisiskelvin

2,275414

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Thank you! This is awesome. :)
  
  – Emmanuel-Ab
  Mar 22 at 9:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Emmanuel-Ab You are welcome.
  
  – thisiskelvin
  Mar 22 at 9:59
  

  
  
  
  

add a comment | 

3

Assuming the collection variable is $sites, you should be able to use the ->contains() closure to check if any of the $sites contains the google url:

$hasGoogle = $sites->contains(function ($site, $key) 
 return $site->url == 'https://google.com';
);

if ($hasGoogle) 
 // do something
 else 
 // do something else

A boolean is returned from the ->contains() method.

share|improve this answer

edited Mar 22 at 14:17

answered Mar 22 at 9:41

thisiskelvinthisiskelvin

2,275414

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Thank you! This is awesome. :)
  
  – Emmanuel-Ab
  Mar 22 at 9:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Emmanuel-Ab You are welcome.
  
  – thisiskelvin
  Mar 22 at 9:59
  

  
  
  
  

add a comment | 

Assuming the collection variable is $sites, you should be able to use the ->contains() closure to check if any of the $sites contains the google url:

$hasGoogle = $sites->contains(function ($site, $key) 
 return $site->url == 'https://google.com';
);

if ($hasGoogle) 
 // do something
 else 
 // do something else

A boolean is returned from the ->contains() method.

share|improve this answer

edited Mar 22 at 14:17

answered Mar 22 at 9:41

thisiskelvinthisiskelvin

2,275414

$hasGoogle = $sites->contains(function ($site, $key) 
 return $site->url == 'https://google.com';
);

if ($hasGoogle) 
 // do something
 else 
 // do something else

share|improve this answer

edited Mar 22 at 14:17

answered Mar 22 at 9:41

thisiskelvinthisiskelvin

2,275414

answered Mar 22 at 9:41

thisiskelvinthisiskelvin

2,275414

answered Mar 22 at 9:41

thisiskelvinthisiskelvin

2,275414