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How to split 1 key value into 2 keys values
How do JavaScript closures work?How do I check if an element is hidden in jQuery?How do I remove a property from a JavaScript object?How do I check if an array includes an object in JavaScript?How to append something to an array?How do I redirect to another webpage?Checking if a key exists in a JavaScript object?How to check whether a string contains a substring in JavaScript?How do I remove a particular element from an array in JavaScript?How to get all properties values of a Javascript Object (without knowing the keys)?
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I'm new to JavaScript. I have the following object:
let obj1 =
[
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
I want to split the longString key into 2 keys, and the value into 2 values.
Here is what I want to make:
let obj2 =
[
'id': 1,
'name': 'Joe',
'date': '2011-04-23T18:25:23.511Z'
,
'id': 2,
'name': 'Mary',
'date': '2010-04-23T18:25:23.511Z'
];
I've tried to do it in pieces, but I'm stuck with the first piece which is splitting the value of longString.
This works for string:
let v = 'Mary - 2010-04-23T18:25:23.511Z';
let w = v.split(' -', 1);
How do I make it work for an object? Or is there a totally different way to split property values? Also, do I need to write a loop to assign obj1 to obj2?
javascript arrays
edited Mar 22 at 19:12
adiga
13k62745
asked Mar 22 at 18:41
vt2424253vt2424253
47831127
add a comment |
I'm new to JavaScript. I have the following object:
let obj1 =
[
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
I want to split the longString key into 2 keys, and the value into 2 values.
Here is what I want to make:
let obj2 =
[
'id': 1,
'name': 'Joe',
'date': '2011-04-23T18:25:23.511Z'
,
'id': 2,
'name': 'Mary',
'date': '2010-04-23T18:25:23.511Z'
];
I've tried to do it in pieces, but I'm stuck with the first piece which is splitting the value of longString.
This works for string:
let v = 'Mary - 2010-04-23T18:25:23.511Z';
let w = v.split(' -', 1);
How do I make it work for an object? Or is there a totally different way to split property values? Also, do I need to write a loop to assign obj1 to obj2?
javascript arrays
edited Mar 22 at 19:12
adiga
13k62745
asked Mar 22 at 18:41
vt2424253vt2424253
47831127
FYI, JSON and JavaScript objects are two different things.
– Felix Kling
Mar 22 at 18:43
add a comment |
I'm new to JavaScript. I have the following object:
let obj1 =
[
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
I want to split the longString key into 2 keys, and the value into 2 values.
Here is what I want to make:
let obj2 =
[
'id': 1,
'name': 'Joe',
'date': '2011-04-23T18:25:23.511Z'
,
'id': 2,
'name': 'Mary',
'date': '2010-04-23T18:25:23.511Z'
];
I've tried to do it in pieces, but I'm stuck with the first piece which is splitting the value of longString.
This works for string:
let v = 'Mary - 2010-04-23T18:25:23.511Z';
let w = v.split(' -', 1);
How do I make it work for an object? Or is there a totally different way to split property values? Also, do I need to write a loop to assign obj1 to obj2?
javascript arrays
edited Mar 22 at 19:12
adiga
13k62745
asked Mar 22 at 18:41
vt2424253vt2424253
47831127
I'm new to JavaScript. I have the following object:
let obj1 =
[
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
I want to split the longString key into 2 keys, and the value into 2 values.
Here is what I want to make:
let obj2 =
[
'id': 1,
'name': 'Joe',
'date': '2011-04-23T18:25:23.511Z'
,
'id': 2,
'name': 'Mary',
'date': '2010-04-23T18:25:23.511Z'
];
I've tried to do it in pieces, but I'm stuck with the first piece which is splitting the value of longString.
This works for string:
let v = 'Mary - 2010-04-23T18:25:23.511Z';
let w = v.split(' -', 1);
How do I make it work for an object? Or is there a totally different way to split property values? Also, do I need to write a loop to assign obj1 to obj2?
javascript arrays
javascript arrays
edited Mar 22 at 19:12
adiga
13k62745
asked Mar 22 at 18:41
vt2424253vt2424253
47831127
edited Mar 22 at 19:12
adiga
13k62745
asked Mar 22 at 18:41
vt2424253vt2424253
47831127
edited Mar 22 at 19:12
adiga
13k62745
edited Mar 22 at 19:12
adiga
13k62745
edited Mar 22 at 19:12
adiga
13k62745
13k62745
asked Mar 22 at 18:41
vt2424253vt2424253
47831127
asked Mar 22 at 18:41
vt2424253vt2424253
47831127
asked Mar 22 at 18:41
vt2424253vt2424253
47831127
47831127
FYI, JSON and JavaScript objects are two different things.
– Felix Kling
Mar 22 at 18:43
add a comment |
FYI, JSON and JavaScript objects are two different things.
– Felix Kling
Mar 22 at 18:43
FYI, JSON and JavaScript objects are two different things.
– Felix Kling
Mar 22 at 18:43
FYI, JSON and JavaScript objects are two different things.
– Felix Kling
Mar 22 at 18:43
add a comment |
3 Answers
3
active
oldest
votes
You could map over the array and split the longString for each object. Use destructuring to get the splits into name and date variables
let obj1 =
[
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const output = obj1.map(a =>
let [name, date] = a.longString.split(" - ");
return id: a.id, name, date
)
console.log(output)answered Mar 22 at 18:44
adigaadiga
13k62745
add a comment |
You can simply use map and s+-s+ pattern to split. second parameter of split is to specify the number of element we want in output
let obj1 =['id': 1,'longString': 'Joe - 2011-04-23T18:25:23.511Z', 'id': 2, 'longString': 'Mary - 2010-04-23T18:25:23.511Z'];
let op = obj1.map((id, longString) =>
let [name, date] = longString.split(/s+-s+/,2)
return id, name, date
)
console.log(op)answered Mar 22 at 18:44
Code ManiacCode Maniac
13.1k21034
add a comment |
let obj1 = [
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const res = obj1.map((
id,
longString
) => (
id,
name: longString.match(/w+/)[0],
date: longString.match(/d+.*/)[0],
))
console.log(res)answered Mar 22 at 19:32
G.azizG.aziz
1,158518
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You could map over the array and split the longString for each object. Use destructuring to get the splits into name and date variables
let obj1 =
[
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const output = obj1.map(a =>
let [name, date] = a.longString.split(" - ");
return id: a.id, name, date
)
console.log(output)answered Mar 22 at 18:44
adigaadiga
13k62745
add a comment |
You could map over the array and split the longString for each object. Use destructuring to get the splits into name and date variables
let obj1 =
[
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const output = obj1.map(a =>
let [name, date] = a.longString.split(" - ");
return id: a.id, name, date
)
console.log(output)answered Mar 22 at 18:44
adigaadiga
13k62745
add a comment |
You could map over the array and split the longString for each object. Use destructuring to get the splits into name and date variables
let obj1 =
[
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const output = obj1.map(a =>
let [name, date] = a.longString.split(" - ");
return id: a.id, name, date
)
console.log(output)answered Mar 22 at 18:44
adigaadiga
13k62745
You could map over the array and split the longString for each object. Use destructuring to get the splits into name and date variables
let obj1 =
[
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const output = obj1.map(a =>
let [name, date] = a.longString.split(" - ");
return id: a.id, name, date
)
console.log(output)let obj1 =
[
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const output = obj1.map(a =>
let [name, date] = a.longString.split(" - ");
return id: a.id, name, date
)
console.log(output)let obj1 =
[
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const output = obj1.map(a =>
let [name, date] = a.longString.split(" - ");
return id: a.id, name, date
)
console.log(output)answered Mar 22 at 18:44
adigaadiga
13k62745
edited Mar 22 at 19:12
answered Mar 22 at 18:44
adigaadiga
13k62745
answered Mar 22 at 18:44
adigaadiga
13k62745
answered Mar 22 at 18:44
adigaadiga
13k62745
13k62745
add a comment |
add a comment |
You can simply use map and s+-s+ pattern to split. second parameter of split is to specify the number of element we want in output
let obj1 =['id': 1,'longString': 'Joe - 2011-04-23T18:25:23.511Z', 'id': 2, 'longString': 'Mary - 2010-04-23T18:25:23.511Z'];
let op = obj1.map((id, longString) =>
let [name, date] = longString.split(/s+-s+/,2)
return id, name, date
)
console.log(op)answered Mar 22 at 18:44
Code ManiacCode Maniac
13.1k21034
add a comment |
You can simply use map and s+-s+ pattern to split. second parameter of split is to specify the number of element we want in output
let obj1 =['id': 1,'longString': 'Joe - 2011-04-23T18:25:23.511Z', 'id': 2, 'longString': 'Mary - 2010-04-23T18:25:23.511Z'];
let op = obj1.map((id, longString) =>
let [name, date] = longString.split(/s+-s+/,2)
return id, name, date
)
console.log(op)answered Mar 22 at 18:44
Code ManiacCode Maniac
13.1k21034
add a comment |
You can simply use map and s+-s+ pattern to split. second parameter of split is to specify the number of element we want in output
let obj1 =['id': 1,'longString': 'Joe - 2011-04-23T18:25:23.511Z', 'id': 2, 'longString': 'Mary - 2010-04-23T18:25:23.511Z'];
let op = obj1.map((id, longString) =>
let [name, date] = longString.split(/s+-s+/,2)
return id, name, date
)
console.log(op)answered Mar 22 at 18:44
Code ManiacCode Maniac
13.1k21034
You can simply use map and s+-s+ pattern to split. second parameter of split is to specify the number of element we want in output
let obj1 =['id': 1,'longString': 'Joe - 2011-04-23T18:25:23.511Z', 'id': 2, 'longString': 'Mary - 2010-04-23T18:25:23.511Z'];
let op = obj1.map((id, longString) =>
let [name, date] = longString.split(/s+-s+/,2)
return id, name, date
)
console.log(op)let obj1 =['id': 1,'longString': 'Joe - 2011-04-23T18:25:23.511Z', 'id': 2, 'longString': 'Mary - 2010-04-23T18:25:23.511Z'];
let op = obj1.map((id, longString) =>
let [name, date] = longString.split(/s+-s+/,2)
return id, name, date
)
console.log(op)let obj1 =['id': 1,'longString': 'Joe - 2011-04-23T18:25:23.511Z', 'id': 2, 'longString': 'Mary - 2010-04-23T18:25:23.511Z'];
let op = obj1.map((id, longString) =>
let [name, date] = longString.split(/s+-s+/,2)
return id, name, date
)
console.log(op)answered Mar 22 at 18:44
Code ManiacCode Maniac
13.1k21034
answered Mar 22 at 18:44
Code ManiacCode Maniac
13.1k21034
answered Mar 22 at 18:44
Code ManiacCode Maniac
13.1k21034
answered Mar 22 at 18:44
Code ManiacCode Maniac
13.1k21034
13.1k21034
add a comment |
add a comment |
let obj1 = [
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const res = obj1.map((
id,
longString
) => (
id,
name: longString.match(/w+/)[0],
date: longString.match(/d+.*/)[0],
))
console.log(res)answered Mar 22 at 19:32
G.azizG.aziz
1,158518
add a comment |
let obj1 = [
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const res = obj1.map((
id,
longString
) => (
id,
name: longString.match(/w+/)[0],
date: longString.match(/d+.*/)[0],
))
console.log(res)answered Mar 22 at 19:32
G.azizG.aziz
1,158518
add a comment |
let obj1 = [
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const res = obj1.map((
id,
longString
) => (
id,
name: longString.match(/w+/)[0],
date: longString.match(/d+.*/)[0],
))
console.log(res)answered Mar 22 at 19:32
G.azizG.aziz
1,158518
let obj1 = [
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const res = obj1.map((
id,
longString
) => (
id,
name: longString.match(/w+/)[0],
date: longString.match(/d+.*/)[0],
))
console.log(res)let obj1 = [
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const res = obj1.map((
id,
longString
) => (
id,
name: longString.match(/w+/)[0],
date: longString.match(/d+.*/)[0],
))
console.log(res)let obj1 = [
'id': 1,
'longString': 'Joe - 2011-04-23T18:25:23.511Z'
,
'id': 2,
'longString': 'Mary - 2010-04-23T18:25:23.511Z'
];
const res = obj1.map((
id,
longString
) => (
id,
name: longString.match(/w+/)[0],
date: longString.match(/d+.*/)[0],
))
console.log(res)answered Mar 22 at 19:32
G.azizG.aziz
1,158518
edited Mar 22 at 19:41
answered Mar 22 at 19:32
G.azizG.aziz
1,158518
answered Mar 22 at 19:32
G.azizG.aziz
1,158518
answered Mar 22 at 19:32
G.azizG.aziz
1,158518
1,158518
add a comment |
add a comment |
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FYI, JSON and JavaScript objects are two different things.
– Felix Kling
Mar 22 at 18:43