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Remove multiple copies of folder that starts with same name using batch-file



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0















My DESKTOP contain copies of 'CEEMEA EMEA' folder i.e.



EMEA CEEMEA



EMEA CEEMEA - Copy



EMEA CEEMEA - Copy (2)



EMEA CEEMEA - Copy (3)



and so on



I want to delete all folders that starts with EMEA CEEMEA as file name using CMD or batch-file.



rd /s /q "%CD%NEW FOLDER*"


but above command not doing anything. how does it work?










share|improve this question






























    0















    My DESKTOP contain copies of 'CEEMEA EMEA' folder i.e.



    EMEA CEEMEA



    EMEA CEEMEA - Copy



    EMEA CEEMEA - Copy (2)



    EMEA CEEMEA - Copy (3)



    and so on



    I want to delete all folders that starts with EMEA CEEMEA as file name using CMD or batch-file.



    rd /s /q "%CD%NEW FOLDER*"


    but above command not doing anything. how does it work?










    share|improve this question


























      0












      0








      0








      My DESKTOP contain copies of 'CEEMEA EMEA' folder i.e.



      EMEA CEEMEA



      EMEA CEEMEA - Copy



      EMEA CEEMEA - Copy (2)



      EMEA CEEMEA - Copy (3)



      and so on



      I want to delete all folders that starts with EMEA CEEMEA as file name using CMD or batch-file.



      rd /s /q "%CD%NEW FOLDER*"


      but above command not doing anything. how does it work?










      share|improve this question
















      My DESKTOP contain copies of 'CEEMEA EMEA' folder i.e.



      EMEA CEEMEA



      EMEA CEEMEA - Copy



      EMEA CEEMEA - Copy (2)



      EMEA CEEMEA - Copy (3)



      and so on



      I want to delete all folders that starts with EMEA CEEMEA as file name using CMD or batch-file.



      rd /s /q "%CD%NEW FOLDER*"


      but above command not doing anything. how does it work?







      batch-file cmd directory






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 25 at 7:58







      Ibn e Ashiq

















      asked Mar 22 at 7:43









      Ibn e AshiqIbn e Ashiq

      3221620




      3221620






















          1 Answer
          1






          active

          oldest

          votes


















          1














          You can do this using a For loop with its /D option:



          For /D %A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%A"


          As you've updated your question to include batch-file, you'd change the command to this from one:



          For /D %%A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%%A"





          share|improve this answer




















          • 1





            I'd prefer that you first take a look at the usage information for both of the commands used. Open a Command Prompt window and enter For /?, and read its content, paying additional note to its /D option. Next repeat the process using RD /?. After you've read them, if you still have any questions pertaining to this particular line of code, post back, and we'll see if we can help explain. Essentially it looks for directories, matching the wilcarded fileset in parentheses, and outputs each match, one at a time , as the metavariable %A, which is subsequently used in the Do command, RD.

            – Compo
            Mar 23 at 16:52











          • actually I need to use this For /D %A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%A" in .bat file and it does nothing.. is there anything I could change ??

            – Ibn e Ashiq
            Mar 25 at 6:09







          • 1





            It all depends upon where your batch file is located or what your current working directory is at the time the line is ran. You stated My DESKTOP, so I provided, the location for that. One thing is for sure, you do not need the %CD% part, because any location which is not a fully qualified path will be taken as relative to the current directory.

            – Compo
            Mar 25 at 8:20












          • you are right about Desktop. Problem with my command was I did not use %% percentage, now For /D %%A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%%A" is working fine.

            – Ibn e Ashiq
            Mar 25 at 8:26











          • I updated my answer, when I noticed that you'd modified your question to include the batch file requirement.

            – Compo
            Mar 25 at 8:28











          Your Answer






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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          You can do this using a For loop with its /D option:



          For /D %A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%A"


          As you've updated your question to include batch-file, you'd change the command to this from one:



          For /D %%A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%%A"





          share|improve this answer




















          • 1





            I'd prefer that you first take a look at the usage information for both of the commands used. Open a Command Prompt window and enter For /?, and read its content, paying additional note to its /D option. Next repeat the process using RD /?. After you've read them, if you still have any questions pertaining to this particular line of code, post back, and we'll see if we can help explain. Essentially it looks for directories, matching the wilcarded fileset in parentheses, and outputs each match, one at a time , as the metavariable %A, which is subsequently used in the Do command, RD.

            – Compo
            Mar 23 at 16:52











          • actually I need to use this For /D %A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%A" in .bat file and it does nothing.. is there anything I could change ??

            – Ibn e Ashiq
            Mar 25 at 6:09







          • 1





            It all depends upon where your batch file is located or what your current working directory is at the time the line is ran. You stated My DESKTOP, so I provided, the location for that. One thing is for sure, you do not need the %CD% part, because any location which is not a fully qualified path will be taken as relative to the current directory.

            – Compo
            Mar 25 at 8:20












          • you are right about Desktop. Problem with my command was I did not use %% percentage, now For /D %%A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%%A" is working fine.

            – Ibn e Ashiq
            Mar 25 at 8:26











          • I updated my answer, when I noticed that you'd modified your question to include the batch file requirement.

            – Compo
            Mar 25 at 8:28















          1














          You can do this using a For loop with its /D option:



          For /D %A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%A"


          As you've updated your question to include batch-file, you'd change the command to this from one:



          For /D %%A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%%A"





          share|improve this answer




















          • 1





            I'd prefer that you first take a look at the usage information for both of the commands used. Open a Command Prompt window and enter For /?, and read its content, paying additional note to its /D option. Next repeat the process using RD /?. After you've read them, if you still have any questions pertaining to this particular line of code, post back, and we'll see if we can help explain. Essentially it looks for directories, matching the wilcarded fileset in parentheses, and outputs each match, one at a time , as the metavariable %A, which is subsequently used in the Do command, RD.

            – Compo
            Mar 23 at 16:52











          • actually I need to use this For /D %A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%A" in .bat file and it does nothing.. is there anything I could change ??

            – Ibn e Ashiq
            Mar 25 at 6:09







          • 1





            It all depends upon where your batch file is located or what your current working directory is at the time the line is ran. You stated My DESKTOP, so I provided, the location for that. One thing is for sure, you do not need the %CD% part, because any location which is not a fully qualified path will be taken as relative to the current directory.

            – Compo
            Mar 25 at 8:20












          • you are right about Desktop. Problem with my command was I did not use %% percentage, now For /D %%A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%%A" is working fine.

            – Ibn e Ashiq
            Mar 25 at 8:26











          • I updated my answer, when I noticed that you'd modified your question to include the batch file requirement.

            – Compo
            Mar 25 at 8:28













          1












          1








          1







          You can do this using a For loop with its /D option:



          For /D %A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%A"


          As you've updated your question to include batch-file, you'd change the command to this from one:



          For /D %%A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%%A"





          share|improve this answer















          You can do this using a For loop with its /D option:



          For /D %A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%A"


          As you've updated your question to include batch-file, you'd change the command to this from one:



          For /D %%A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%%A"






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 25 at 8:26

























          answered Mar 22 at 19:32









          CompoCompo

          17.2k31027




          17.2k31027







          • 1





            I'd prefer that you first take a look at the usage information for both of the commands used. Open a Command Prompt window and enter For /?, and read its content, paying additional note to its /D option. Next repeat the process using RD /?. After you've read them, if you still have any questions pertaining to this particular line of code, post back, and we'll see if we can help explain. Essentially it looks for directories, matching the wilcarded fileset in parentheses, and outputs each match, one at a time , as the metavariable %A, which is subsequently used in the Do command, RD.

            – Compo
            Mar 23 at 16:52











          • actually I need to use this For /D %A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%A" in .bat file and it does nothing.. is there anything I could change ??

            – Ibn e Ashiq
            Mar 25 at 6:09







          • 1





            It all depends upon where your batch file is located or what your current working directory is at the time the line is ran. You stated My DESKTOP, so I provided, the location for that. One thing is for sure, you do not need the %CD% part, because any location which is not a fully qualified path will be taken as relative to the current directory.

            – Compo
            Mar 25 at 8:20












          • you are right about Desktop. Problem with my command was I did not use %% percentage, now For /D %%A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%%A" is working fine.

            – Ibn e Ashiq
            Mar 25 at 8:26











          • I updated my answer, when I noticed that you'd modified your question to include the batch file requirement.

            – Compo
            Mar 25 at 8:28












          • 1





            I'd prefer that you first take a look at the usage information for both of the commands used. Open a Command Prompt window and enter For /?, and read its content, paying additional note to its /D option. Next repeat the process using RD /?. After you've read them, if you still have any questions pertaining to this particular line of code, post back, and we'll see if we can help explain. Essentially it looks for directories, matching the wilcarded fileset in parentheses, and outputs each match, one at a time , as the metavariable %A, which is subsequently used in the Do command, RD.

            – Compo
            Mar 23 at 16:52











          • actually I need to use this For /D %A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%A" in .bat file and it does nothing.. is there anything I could change ??

            – Ibn e Ashiq
            Mar 25 at 6:09







          • 1





            It all depends upon where your batch file is located or what your current working directory is at the time the line is ran. You stated My DESKTOP, so I provided, the location for that. One thing is for sure, you do not need the %CD% part, because any location which is not a fully qualified path will be taken as relative to the current directory.

            – Compo
            Mar 25 at 8:20












          • you are right about Desktop. Problem with my command was I did not use %% percentage, now For /D %%A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%%A" is working fine.

            – Ibn e Ashiq
            Mar 25 at 8:26











          • I updated my answer, when I noticed that you'd modified your question to include the batch file requirement.

            – Compo
            Mar 25 at 8:28







          1




          1





          I'd prefer that you first take a look at the usage information for both of the commands used. Open a Command Prompt window and enter For /?, and read its content, paying additional note to its /D option. Next repeat the process using RD /?. After you've read them, if you still have any questions pertaining to this particular line of code, post back, and we'll see if we can help explain. Essentially it looks for directories, matching the wilcarded fileset in parentheses, and outputs each match, one at a time , as the metavariable %A, which is subsequently used in the Do command, RD.

          – Compo
          Mar 23 at 16:52





          I'd prefer that you first take a look at the usage information for both of the commands used. Open a Command Prompt window and enter For /?, and read its content, paying additional note to its /D option. Next repeat the process using RD /?. After you've read them, if you still have any questions pertaining to this particular line of code, post back, and we'll see if we can help explain. Essentially it looks for directories, matching the wilcarded fileset in parentheses, and outputs each match, one at a time , as the metavariable %A, which is subsequently used in the Do command, RD.

          – Compo
          Mar 23 at 16:52













          actually I need to use this For /D %A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%A" in .bat file and it does nothing.. is there anything I could change ??

          – Ibn e Ashiq
          Mar 25 at 6:09






          actually I need to use this For /D %A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%A" in .bat file and it does nothing.. is there anything I could change ??

          – Ibn e Ashiq
          Mar 25 at 6:09





          1




          1





          It all depends upon where your batch file is located or what your current working directory is at the time the line is ran. You stated My DESKTOP, so I provided, the location for that. One thing is for sure, you do not need the %CD% part, because any location which is not a fully qualified path will be taken as relative to the current directory.

          – Compo
          Mar 25 at 8:20






          It all depends upon where your batch file is located or what your current working directory is at the time the line is ran. You stated My DESKTOP, so I provided, the location for that. One thing is for sure, you do not need the %CD% part, because any location which is not a fully qualified path will be taken as relative to the current directory.

          – Compo
          Mar 25 at 8:20














          you are right about Desktop. Problem with my command was I did not use %% percentage, now For /D %%A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%%A" is working fine.

          – Ibn e Ashiq
          Mar 25 at 8:26





          you are right about Desktop. Problem with my command was I did not use %% percentage, now For /D %%A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%%A" is working fine.

          – Ibn e Ashiq
          Mar 25 at 8:26













          I updated my answer, when I noticed that you'd modified your question to include the batch file requirement.

          – Compo
          Mar 25 at 8:28





          I updated my answer, when I noticed that you'd modified your question to include the batch file requirement.

          – Compo
          Mar 25 at 8:28



















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