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Remove multiple copies of folder that starts with same name using batch-file

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;

0

My DESKTOP contain copies of 'CEEMEA EMEA' folder i.e.

EMEA CEEMEA

EMEA CEEMEA - Copy

EMEA CEEMEA - Copy (2)

EMEA CEEMEA - Copy (3)

and so on

I want to delete all folders that starts with EMEA CEEMEA as file name using CMD or batch-file.

rd /s /q "%CD%NEW FOLDER*"

but above command not doing anything. how does it work?

batch-file cmd directory

share|improve this question

edited Mar 25 at 7:58

Ibn e Ashiq

asked Mar 22 at 7:43

Ibn e AshiqIbn e Ashiq

3221620

add a comment | 

0

My DESKTOP contain copies of 'CEEMEA EMEA' folder i.e.

EMEA CEEMEA

EMEA CEEMEA - Copy

EMEA CEEMEA - Copy (2)

EMEA CEEMEA - Copy (3)

and so on

I want to delete all folders that starts with EMEA CEEMEA as file name using CMD or batch-file.

rd /s /q "%CD%NEW FOLDER*"

but above command not doing anything. how does it work?

batch-file cmd directory

share|improve this question

edited Mar 25 at 7:58

Ibn e Ashiq

asked Mar 22 at 7:43

Ibn e AshiqIbn e Ashiq

3221620

add a comment | 

My DESKTOP contain copies of 'CEEMEA EMEA' folder i.e.

EMEA CEEMEA

EMEA CEEMEA - Copy

EMEA CEEMEA - Copy (2)

EMEA CEEMEA - Copy (3)

and so on

I want to delete all folders that starts with EMEA CEEMEA as file name using CMD or batch-file.

rd /s /q "%CD%NEW FOLDER*"

but above command not doing anything. how does it work?

batch-file cmd directory

share|improve this question

edited Mar 25 at 7:58

Ibn e Ashiq

asked Mar 22 at 7:43

Ibn e AshiqIbn e Ashiq

3221620

rd /s /q "%CD%NEW FOLDER*"

share|improve this question

edited Mar 25 at 7:58

Ibn e Ashiq

asked Mar 22 at 7:43

Ibn e AshiqIbn e Ashiq

3221620

share|improve this question

edited Mar 25 at 7:58

Ibn e Ashiq

asked Mar 22 at 7:43

Ibn e AshiqIbn e Ashiq

3221620

asked Mar 22 at 7:43

Ibn e AshiqIbn e Ashiq

3221620

asked Mar 22 at 7:43

Ibn e AshiqIbn e Ashiq

3221620

1 Answer
1

active

oldest

votes

1

You can do this using a For loop with its /D option:

For /D %A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%A"

As you've updated your question to include batch-file, you'd change the command to this from one:

For /D %%A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%%A"

share|improve this answer

edited Mar 25 at 8:26

answered Mar 22 at 19:32

CompoCompo

17.2k31027

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I'd prefer that you first take a look at the usage information for both of the commands used. Open a Command Prompt window and enter For /?, and read its content, paying additional note to its /D option. Next repeat the process using RD /?. After you've read them, if you still have any questions pertaining to this particular line of code, post back, and we'll see if we can help explain. Essentially it looks for directories, matching the wilcarded fileset in parentheses, and outputs each match, one at a time , as the metavariable %A, which is subsequently used in the Do command, RD.
  
  – Compo
  Mar 23 at 16:52
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  actually I need to use this For /D %A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%A" in .bat file and it does nothing.. is there anything I could change ??
  
  – Ibn e Ashiq
  Mar 25 at 6:09
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  It all depends upon where your batch file is located or what your current working directory is at the time the line is ran. You stated My DESKTOP, so I provided, the location for that. One thing is for sure, you do not need the %CD% part, because any location which is not a fully qualified path will be taken as relative to the current directory.
  
  – Compo
  Mar 25 at 8:20
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  you are right about Desktop. Problem with my command was I did not use %% percentage, now For /D %%A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%%A" is working fine.
  
  – Ibn e Ashiq
  Mar 25 at 8:26
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I updated my answer, when I noticed that you'd modified your question to include the batch file requirement.
  
  – Compo
  Mar 25 at 8:28
  

  
  
  
  

add a comment | 

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1

You can do this using a For loop with its /D option:

For /D %A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%A"

As you've updated your question to include batch-file, you'd change the command to this from one:

For /D %%A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%%A"

share|improve this answer

edited Mar 25 at 8:26

answered Mar 22 at 19:32

CompoCompo

17.2k31027

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I'd prefer that you first take a look at the usage information for both of the commands used. Open a Command Prompt window and enter For /?, and read its content, paying additional note to its /D option. Next repeat the process using RD /?. After you've read them, if you still have any questions pertaining to this particular line of code, post back, and we'll see if we can help explain. Essentially it looks for directories, matching the wilcarded fileset in parentheses, and outputs each match, one at a time , as the metavariable %A, which is subsequently used in the Do command, RD.
  
  – Compo
  Mar 23 at 16:52
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  actually I need to use this For /D %A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%A" in .bat file and it does nothing.. is there anything I could change ??
  
  – Ibn e Ashiq
  Mar 25 at 6:09
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  It all depends upon where your batch file is located or what your current working directory is at the time the line is ran. You stated My DESKTOP, so I provided, the location for that. One thing is for sure, you do not need the %CD% part, because any location which is not a fully qualified path will be taken as relative to the current directory.
  
  – Compo
  Mar 25 at 8:20
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  you are right about Desktop. Problem with my command was I did not use %% percentage, now For /D %%A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%%A" is working fine.
  
  – Ibn e Ashiq
  Mar 25 at 8:26
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I updated my answer, when I noticed that you'd modified your question to include the batch file requirement.
  
  – Compo
  Mar 25 at 8:28
  

  
  
  
  

add a comment | 

1

You can do this using a For loop with its /D option:

For /D %A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%A"

As you've updated your question to include batch-file, you'd change the command to this from one:

For /D %%A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%%A"

share|improve this answer

edited Mar 25 at 8:26

answered Mar 22 at 19:32

CompoCompo

17.2k31027

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I'd prefer that you first take a look at the usage information for both of the commands used. Open a Command Prompt window and enter For /?, and read its content, paying additional note to its /D option. Next repeat the process using RD /?. After you've read them, if you still have any questions pertaining to this particular line of code, post back, and we'll see if we can help explain. Essentially it looks for directories, matching the wilcarded fileset in parentheses, and outputs each match, one at a time , as the metavariable %A, which is subsequently used in the Do command, RD.
  
  – Compo
  Mar 23 at 16:52
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  actually I need to use this For /D %A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%A" in .bat file and it does nothing.. is there anything I could change ??
  
  – Ibn e Ashiq
  Mar 25 at 6:09
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  It all depends upon where your batch file is located or what your current working directory is at the time the line is ran. You stated My DESKTOP, so I provided, the location for that. One thing is for sure, you do not need the %CD% part, because any location which is not a fully qualified path will be taken as relative to the current directory.
  
  – Compo
  Mar 25 at 8:20
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  you are right about Desktop. Problem with my command was I did not use %% percentage, now For /D %%A In ("%CD%EMEA CEEMEA*")Do @RD/S/Q "%%A" is working fine.
  
  – Ibn e Ashiq
  Mar 25 at 8:26
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I updated my answer, when I noticed that you'd modified your question to include the batch file requirement.
  
  – Compo
  Mar 25 at 8:28
  

  
  
  
  

add a comment | 

You can do this using a For loop with its /D option:

For /D %A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%A"

As you've updated your question to include batch-file, you'd change the command to this from one:

For /D %%A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%%A"

share|improve this answer

edited Mar 25 at 8:26

answered Mar 22 at 19:32

CompoCompo

17.2k31027

For /D %A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%A"

For /D %%A In ("%UserProfile%DesktopEMEA CEEMEA*")Do @RD/S/Q "%%A"

share|improve this answer

edited Mar 25 at 8:26

answered Mar 22 at 19:32

CompoCompo

17.2k31027

answered Mar 22 at 19:32

CompoCompo

17.2k31027

answered Mar 22 at 19:32

CompoCompo

17.2k31027