Calculate distance from current Latitude and Longitude with different Latitude and Longitude in one kilometer [closed] Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) The Ask Question Wizard is Live! Data science time! April 2019 and salary with experienceselect restaurant table entries within a certain distance from current location using phpFastest Way to Find Distance Between Two Lat/Long PointsMySQL: Large VARCHAR vs. TEXT?latitude/longitude find nearest latitude/longitude - complex sql or complex calculationSQL select only rows with max value on a columnCalculate distance given 2 points, latitude and longitudeRadius of 40 kilometers using latitude and longitudeReference - What does this error mean in PHP?Near by search in google maps using latitude and longitudemysql pdo distance longitude and latitudeMySQL filter data based on distance and calculate that distance
What's the point in a preamp?
What do you call the holes in a flute?
When communicating altitude with a '9' in it, should it be pronounced "nine hundred" or "niner hundred"?
What items from the Roman-age tech-level could be used to deter all creatures from entering a small area?
Need a suitable toxic chemical for a murder plot in my novel
What was the last x86 CPU that did not have the x87 floating-point unit built in?
Antler Helmet: Can it work?
Can a zero nonce be safely used with AES-GCM if the key is random and never used again?
Is drag coefficient lowest at zero angle of attack?
Blender game recording at the wrong time
Estimated State payment too big --> money back; + 2018 Tax Reform
Is there a service that would inform me whenever a new direct route is scheduled from a given airport?
Is it possible to ask for a hotel room without minibar/extra services?
What would be Julian Assange's expected punishment, on the current English criminal law?
Estimate capacitor parameters
90's book, teen horror
How can I make names more distinctive without making them longer?
What do you call a plan that's an alternative plan in case your initial plan fails?
How to market an anarchic city as a tourism spot to people living in civilized areas?
How is simplicity better than precision and clarity in prose?
Passing functions in C++
How many things? AとBがふたつ
Can I add database to AWS RDS MySQL without creating new instance?
Using "nakedly" instead of "with nothing on"
Calculate distance from current Latitude and Longitude with different Latitude and Longitude in one kilometer [closed]
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
The Ask Question Wizard is Live!
Data science time! April 2019 and salary with experienceselect restaurant table entries within a certain distance from current location using phpFastest Way to Find Distance Between Two Lat/Long PointsMySQL: Large VARCHAR vs. TEXT?latitude/longitude find nearest latitude/longitude - complex sql or complex calculationSQL select only rows with max value on a columnCalculate distance given 2 points, latitude and longitudeRadius of 40 kilometers using latitude and longitudeReference - What does this error mean in PHP?Near by search in google maps using latitude and longitudemysql pdo distance longitude and latitudeMySQL filter data based on distance and calculate that distance
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I have problem I think but I can not find the ideal solution. I am storing different restaurant locations latitude and longitude in Mysql table. I want to find a restaurant around 1 km radial distance from current location of user using latitude and longitude so how to do this. I have to show all restaurants which are in 1 km radius from user current location latitude and longitude.
php mysql
edited Mar 19 at 20:48
Cooper
8,6592830
asked Mar 19 at 20:30
Muhammad LuqmanMuhammad Luqman
43
closed as too broad by castis, Raymond Nijland, Alon Eitan, Strawberry, mickmackusa Mar 25 at 10:10
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
I have problem I think but I can not find the ideal solution. I am storing different restaurant locations latitude and longitude in Mysql table. I want to find a restaurant around 1 km radial distance from current location of user using latitude and longitude so how to do this. I have to show all restaurants which are in 1 km radius from user current location latitude and longitude.
php mysql
edited Mar 19 at 20:48
Cooper
8,6592830
asked Mar 19 at 20:30
Muhammad LuqmanMuhammad Luqman
43
closed as too broad by castis, Raymond Nijland, Alon Eitan, Strawberry, mickmackusa Mar 25 at 10:10
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
2
Possible duplicate of select restaurant table entries within a certain distance from current location using php
– tim
Mar 19 at 20:32
no it not solve my problem I need all restaurant which are under 1 km without duplicate
– Muhammad Luqman
Mar 19 at 20:43
2
Without table structure, example data, correct user case (you forgot to mention you needed unique restaurants within 1 km did you forget annymore?) and expected results we know even less then you, see Why should I provide an MCVE for what seems to me to be a very simple SQL query?, this question is unclear like it is and will be most likely voteclosed.
– Raymond Nijland
Mar 19 at 21:20
I mean all the restaurant which are under 1km from user current location
– Muhammad Luqman
Mar 20 at 6:45
add a comment |
I have problem I think but I can not find the ideal solution. I am storing different restaurant locations latitude and longitude in Mysql table. I want to find a restaurant around 1 km radial distance from current location of user using latitude and longitude so how to do this. I have to show all restaurants which are in 1 km radius from user current location latitude and longitude.
php mysql
edited Mar 19 at 20:48
Cooper
8,6592830
asked Mar 19 at 20:30
Muhammad LuqmanMuhammad Luqman
43
I have problem I think but I can not find the ideal solution. I am storing different restaurant locations latitude and longitude in Mysql table. I want to find a restaurant around 1 km radial distance from current location of user using latitude and longitude so how to do this. I have to show all restaurants which are in 1 km radius from user current location latitude and longitude.
php mysql
php mysql
edited Mar 19 at 20:48
Cooper
8,6592830
asked Mar 19 at 20:30
Muhammad LuqmanMuhammad Luqman
43
edited Mar 19 at 20:48
Cooper
8,6592830
asked Mar 19 at 20:30
Muhammad LuqmanMuhammad Luqman
43
edited Mar 19 at 20:48
Cooper
8,6592830
edited Mar 19 at 20:48
Cooper
8,6592830
edited Mar 19 at 20:48
Cooper
8,6592830
8,6592830
asked Mar 19 at 20:30
Muhammad LuqmanMuhammad Luqman
43
asked Mar 19 at 20:30
Muhammad LuqmanMuhammad Luqman
43
asked Mar 19 at 20:30
Muhammad LuqmanMuhammad Luqman
43
43
closed as too broad by castis, Raymond Nijland, Alon Eitan, Strawberry, mickmackusa Mar 25 at 10:10
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as too broad by castis, Raymond Nijland, Alon Eitan, Strawberry, mickmackusa Mar 25 at 10:10
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
2
Possible duplicate of select restaurant table entries within a certain distance from current location using php
– tim
Mar 19 at 20:32
no it not solve my problem I need all restaurant which are under 1 km without duplicate
– Muhammad Luqman
Mar 19 at 20:43
2
Without table structure, example data, correct user case (you forgot to mention you needed unique restaurants within 1 km did you forget annymore?) and expected results we know even less then you, see Why should I provide an MCVE for what seems to me to be a very simple SQL query?, this question is unclear like it is and will be most likely voteclosed.
– Raymond Nijland
Mar 19 at 21:20
I mean all the restaurant which are under 1km from user current location
– Muhammad Luqman
Mar 20 at 6:45
add a comment |
2
Possible duplicate of select restaurant table entries within a certain distance from current location using php
– tim
Mar 19 at 20:32
no it not solve my problem I need all restaurant which are under 1 km without duplicate
– Muhammad Luqman
Mar 19 at 20:43
2
Without table structure, example data, correct user case (you forgot to mention you needed unique restaurants within 1 km did you forget annymore?) and expected results we know even less then you, see Why should I provide an MCVE for what seems to me to be a very simple SQL query?, this question is unclear like it is and will be most likely voteclosed.
– Raymond Nijland
Mar 19 at 21:20
I mean all the restaurant which are under 1km from user current location
– Muhammad Luqman
Mar 20 at 6:45
2
2
Possible duplicate of select restaurant table entries within a certain distance from current location using php
– tim
Mar 19 at 20:32
Possible duplicate of select restaurant table entries within a certain distance from current location using php
– tim
Mar 19 at 20:32
no it not solve my problem I need all restaurant which are under 1 km without duplicate
– Muhammad Luqman
Mar 19 at 20:43
no it not solve my problem I need all restaurant which are under 1 km without duplicate
– Muhammad Luqman
Mar 19 at 20:43
2
2
Without table structure, example data, correct user case (you forgot to mention you needed unique restaurants within 1 km did you forget annymore?) and expected results we know even less then you, see Why should I provide an MCVE for what seems to me to be a very simple SQL query?, this question is unclear like it is and will be most likely voteclosed.
– Raymond Nijland
Mar 19 at 21:20
Without table structure, example data, correct user case (you forgot to mention you needed unique restaurants within 1 km did you forget annymore?) and expected results we know even less then you, see Why should I provide an MCVE for what seems to me to be a very simple SQL query?, this question is unclear like it is and will be most likely voteclosed.
– Raymond Nijland
Mar 19 at 21:20
I mean all the restaurant which are under 1km from user current location
– Muhammad Luqman
Mar 20 at 6:45
I mean all the restaurant which are under 1km from user current location
– Muhammad Luqman
Mar 20 at 6:45
add a comment |
2 Answers
2
active
oldest
votes
This is the formula of distances using longitude and latitude
a = sin²(Δφ/2) + cos φ1 ⋅ cos φ2 ⋅ sin²(Δλ/2)
c = 2 * atan2( √a, √(1−a) )
d = R * c
//Where φ represent the latitudes, and λ represent the longitudes.
Reference: https://www.sisense.com/blog/latitude-longitude-distance-calculation-explained/
Also you can check this page for using javascript.
https://www.movable-type.co.uk/scripts/latlong.html
edited Mar 22 at 7:49
marc_s
585k13011261272
answered Mar 19 at 22:33
Ahmet UğurAhmet Uğur
17627
add a comment |
Remember that latitude and longitude originally are writed on degrees, I think you first need to know how much distance represents 1º, on some books and websites it says that 1º is about 111km depending how near is the spot from the equator line, so (more or less):
1º - 111km, also 1º equals 60'
then 1' should be 1.85km, and 1' equals 60"
then 1" is more or less 0.03km
so 32.4324" is about 1km
Now... basically you need to now the limits of a square based on the initial location, for this just add/substract 32.4324" to latitude and longitude, so give it a try.. lets go to las vegas (use google maps)
36.1699412,-115.1398296
This locations is on a sexagesimal notation son lets convert 32.4324".. its simply... just divide it on 3600 and that is 0.009009009, this is the value you must add/subtract to/from latitude/longitude
north bound, after add: 36.1789502
south bound, after substract: 36.1609322
east bound, after add: -115.1308206
west bound, after substract: -115.1488386
now on gmaps try to locate these bounds for ex (north bound: 36.1789502,-115.1398296) you will see is just above original location, you can also measure distance from original location up to 1km and that is more or less near to the north bound you just calculated.
so now, just query your database and filter it where latitude is between north bound(36.1609322) and south bound(36.1789502), and also longitude is between west bound(-115.1488386) and east bound(-115.1308206) and that should do the work. So the magic is just to add/substract 0.009009009 to any location point.
answered Mar 19 at 22:38
Jonnathan QJonnathan Q
25217
Why not just go with a the standard approach for calculating distance on a sphere
– Strawberry
Mar 20 at 0:41
@Strawberry i'm not sure about that, but anyways explain us how to solve the problem, just keep in mind the goal, it is to get a list of restaurants stored on database that are in 1km radius from an initial location.
– Jonnathan Q
Mar 20 at 11:42
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
This is the formula of distances using longitude and latitude
a = sin²(Δφ/2) + cos φ1 ⋅ cos φ2 ⋅ sin²(Δλ/2)
c = 2 * atan2( √a, √(1−a) )
d = R * c
//Where φ represent the latitudes, and λ represent the longitudes.
Reference: https://www.sisense.com/blog/latitude-longitude-distance-calculation-explained/
Also you can check this page for using javascript.
https://www.movable-type.co.uk/scripts/latlong.html
edited Mar 22 at 7:49
marc_s
585k13011261272
answered Mar 19 at 22:33
Ahmet UğurAhmet Uğur
17627
add a comment |
This is the formula of distances using longitude and latitude
a = sin²(Δφ/2) + cos φ1 ⋅ cos φ2 ⋅ sin²(Δλ/2)
c = 2 * atan2( √a, √(1−a) )
d = R * c
//Where φ represent the latitudes, and λ represent the longitudes.
Reference: https://www.sisense.com/blog/latitude-longitude-distance-calculation-explained/
Also you can check this page for using javascript.
https://www.movable-type.co.uk/scripts/latlong.html
edited Mar 22 at 7:49
marc_s
585k13011261272
answered Mar 19 at 22:33
Ahmet UğurAhmet Uğur
17627
add a comment |
This is the formula of distances using longitude and latitude
a = sin²(Δφ/2) + cos φ1 ⋅ cos φ2 ⋅ sin²(Δλ/2)
c = 2 * atan2( √a, √(1−a) )
d = R * c
//Where φ represent the latitudes, and λ represent the longitudes.
Reference: https://www.sisense.com/blog/latitude-longitude-distance-calculation-explained/
Also you can check this page for using javascript.
https://www.movable-type.co.uk/scripts/latlong.html
edited Mar 22 at 7:49
marc_s
585k13011261272
answered Mar 19 at 22:33
Ahmet UğurAhmet Uğur
17627
This is the formula of distances using longitude and latitude
a = sin²(Δφ/2) + cos φ1 ⋅ cos φ2 ⋅ sin²(Δλ/2)
c = 2 * atan2( √a, √(1−a) )
d = R * c
//Where φ represent the latitudes, and λ represent the longitudes.
Reference: https://www.sisense.com/blog/latitude-longitude-distance-calculation-explained/
Also you can check this page for using javascript.
https://www.movable-type.co.uk/scripts/latlong.html
edited Mar 22 at 7:49
marc_s
585k13011261272
answered Mar 19 at 22:33
Ahmet UğurAhmet Uğur
17627
edited Mar 22 at 7:49
marc_s
585k13011261272
edited Mar 22 at 7:49
marc_s
585k13011261272
edited Mar 22 at 7:49
marc_s
585k13011261272
585k13011261272
answered Mar 19 at 22:33
Ahmet UğurAhmet Uğur
17627
answered Mar 19 at 22:33
Ahmet UğurAhmet Uğur
17627
answered Mar 19 at 22:33
Ahmet UğurAhmet Uğur
17627
17627
add a comment |
add a comment |
Remember that latitude and longitude originally are writed on degrees, I think you first need to know how much distance represents 1º, on some books and websites it says that 1º is about 111km depending how near is the spot from the equator line, so (more or less):
1º - 111km, also 1º equals 60'
then 1' should be 1.85km, and 1' equals 60"
then 1" is more or less 0.03km
so 32.4324" is about 1km
Now... basically you need to now the limits of a square based on the initial location, for this just add/substract 32.4324" to latitude and longitude, so give it a try.. lets go to las vegas (use google maps)
36.1699412,-115.1398296
This locations is on a sexagesimal notation son lets convert 32.4324".. its simply... just divide it on 3600 and that is 0.009009009, this is the value you must add/subtract to/from latitude/longitude
north bound, after add: 36.1789502
south bound, after substract: 36.1609322
east bound, after add: -115.1308206
west bound, after substract: -115.1488386
now on gmaps try to locate these bounds for ex (north bound: 36.1789502,-115.1398296) you will see is just above original location, you can also measure distance from original location up to 1km and that is more or less near to the north bound you just calculated.
so now, just query your database and filter it where latitude is between north bound(36.1609322) and south bound(36.1789502), and also longitude is between west bound(-115.1488386) and east bound(-115.1308206) and that should do the work. So the magic is just to add/substract 0.009009009 to any location point.
answered Mar 19 at 22:38
Jonnathan QJonnathan Q
25217
Why not just go with a the standard approach for calculating distance on a sphere
– Strawberry
Mar 20 at 0:41
@Strawberry i'm not sure about that, but anyways explain us how to solve the problem, just keep in mind the goal, it is to get a list of restaurants stored on database that are in 1km radius from an initial location.
– Jonnathan Q
Mar 20 at 11:42
add a comment |
Remember that latitude and longitude originally are writed on degrees, I think you first need to know how much distance represents 1º, on some books and websites it says that 1º is about 111km depending how near is the spot from the equator line, so (more or less):
1º - 111km, also 1º equals 60'
then 1' should be 1.85km, and 1' equals 60"
then 1" is more or less 0.03km
so 32.4324" is about 1km
Now... basically you need to now the limits of a square based on the initial location, for this just add/substract 32.4324" to latitude and longitude, so give it a try.. lets go to las vegas (use google maps)
36.1699412,-115.1398296
This locations is on a sexagesimal notation son lets convert 32.4324".. its simply... just divide it on 3600 and that is 0.009009009, this is the value you must add/subtract to/from latitude/longitude
north bound, after add: 36.1789502
south bound, after substract: 36.1609322
east bound, after add: -115.1308206
west bound, after substract: -115.1488386
now on gmaps try to locate these bounds for ex (north bound: 36.1789502,-115.1398296) you will see is just above original location, you can also measure distance from original location up to 1km and that is more or less near to the north bound you just calculated.
so now, just query your database and filter it where latitude is between north bound(36.1609322) and south bound(36.1789502), and also longitude is between west bound(-115.1488386) and east bound(-115.1308206) and that should do the work. So the magic is just to add/substract 0.009009009 to any location point.
answered Mar 19 at 22:38
Jonnathan QJonnathan Q
25217
Why not just go with a the standard approach for calculating distance on a sphere
– Strawberry
Mar 20 at 0:41
@Strawberry i'm not sure about that, but anyways explain us how to solve the problem, just keep in mind the goal, it is to get a list of restaurants stored on database that are in 1km radius from an initial location.
– Jonnathan Q
Mar 20 at 11:42
add a comment |
Remember that latitude and longitude originally are writed on degrees, I think you first need to know how much distance represents 1º, on some books and websites it says that 1º is about 111km depending how near is the spot from the equator line, so (more or less):
1º - 111km, also 1º equals 60'
then 1' should be 1.85km, and 1' equals 60"
then 1" is more or less 0.03km
so 32.4324" is about 1km
Now... basically you need to now the limits of a square based on the initial location, for this just add/substract 32.4324" to latitude and longitude, so give it a try.. lets go to las vegas (use google maps)
36.1699412,-115.1398296
This locations is on a sexagesimal notation son lets convert 32.4324".. its simply... just divide it on 3600 and that is 0.009009009, this is the value you must add/subtract to/from latitude/longitude
north bound, after add: 36.1789502
south bound, after substract: 36.1609322
east bound, after add: -115.1308206
west bound, after substract: -115.1488386
now on gmaps try to locate these bounds for ex (north bound: 36.1789502,-115.1398296) you will see is just above original location, you can also measure distance from original location up to 1km and that is more or less near to the north bound you just calculated.
so now, just query your database and filter it where latitude is between north bound(36.1609322) and south bound(36.1789502), and also longitude is between west bound(-115.1488386) and east bound(-115.1308206) and that should do the work. So the magic is just to add/substract 0.009009009 to any location point.
answered Mar 19 at 22:38
Jonnathan QJonnathan Q
25217
Remember that latitude and longitude originally are writed on degrees, I think you first need to know how much distance represents 1º, on some books and websites it says that 1º is about 111km depending how near is the spot from the equator line, so (more or less):
1º - 111km, also 1º equals 60'
then 1' should be 1.85km, and 1' equals 60"
then 1" is more or less 0.03km
so 32.4324" is about 1km
Now... basically you need to now the limits of a square based on the initial location, for this just add/substract 32.4324" to latitude and longitude, so give it a try.. lets go to las vegas (use google maps)
36.1699412,-115.1398296
This locations is on a sexagesimal notation son lets convert 32.4324".. its simply... just divide it on 3600 and that is 0.009009009, this is the value you must add/subtract to/from latitude/longitude
north bound, after add: 36.1789502
south bound, after substract: 36.1609322
east bound, after add: -115.1308206
west bound, after substract: -115.1488386
now on gmaps try to locate these bounds for ex (north bound: 36.1789502,-115.1398296) you will see is just above original location, you can also measure distance from original location up to 1km and that is more or less near to the north bound you just calculated.
so now, just query your database and filter it where latitude is between north bound(36.1609322) and south bound(36.1789502), and also longitude is between west bound(-115.1488386) and east bound(-115.1308206) and that should do the work. So the magic is just to add/substract 0.009009009 to any location point.
answered Mar 19 at 22:38
Jonnathan QJonnathan Q
25217
edited Mar 20 at 11:47
answered Mar 19 at 22:38
Jonnathan QJonnathan Q
25217
answered Mar 19 at 22:38
Jonnathan QJonnathan Q
25217
answered Mar 19 at 22:38
Jonnathan QJonnathan Q
25217
25217
Why not just go with a the standard approach for calculating distance on a sphere
– Strawberry
Mar 20 at 0:41
@Strawberry i'm not sure about that, but anyways explain us how to solve the problem, just keep in mind the goal, it is to get a list of restaurants stored on database that are in 1km radius from an initial location.
– Jonnathan Q
Mar 20 at 11:42
add a comment |
Why not just go with a the standard approach for calculating distance on a sphere
– Strawberry
Mar 20 at 0:41
@Strawberry i'm not sure about that, but anyways explain us how to solve the problem, just keep in mind the goal, it is to get a list of restaurants stored on database that are in 1km radius from an initial location.
– Jonnathan Q
Mar 20 at 11:42
Why not just go with a the standard approach for calculating distance on a sphere
– Strawberry
Mar 20 at 0:41
Why not just go with a the standard approach for calculating distance on a sphere
– Strawberry
Mar 20 at 0:41
@Strawberry i'm not sure about that, but anyways explain us how to solve the problem, just keep in mind the goal, it is to get a list of restaurants stored on database that are in 1km radius from an initial location.
– Jonnathan Q
Mar 20 at 11:42
@Strawberry i'm not sure about that, but anyways explain us how to solve the problem, just keep in mind the goal, it is to get a list of restaurants stored on database that are in 1km radius from an initial location.
– Jonnathan Q
Mar 20 at 11:42
add a comment |
2
Possible duplicate of select restaurant table entries within a certain distance from current location using php
– tim
Mar 19 at 20:32
no it not solve my problem I need all restaurant which are under 1 km without duplicate
– Muhammad Luqman
Mar 19 at 20:43
2
Without table structure, example data, correct user case (you forgot to mention you needed unique restaurants within 1 km did you forget annymore?) and expected results we know even less then you, see Why should I provide an MCVE for what seems to me to be a very simple SQL query?, this question is unclear like it is and will be most likely voteclosed.
– Raymond Nijland
Mar 19 at 21:20
I mean all the restaurant which are under 1km from user current location
– Muhammad Luqman
Mar 20 at 6:45