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Even after converting my file as factor why does my output give factor(0) 30956 Levels?
Why are these numbers not equal?Numeric comparison difficulty in RHow to create a stratified sample by state in RConverting Data factors to DateError in predict.lm in R: factor as.factor(daily) has new level 2For all levels of a factor, return all levels of another factor from same dataframe - using dplyr ? rFactoring data in RR confusionMatrix() & Table() give the Error in sort.list(y) : 'x' must be atomic for 'sort.list' Have you called 'sort' on a list?error in running factor() on a column of a data frameconverting POSIXct back to factorConverting list to factor in RSort.list/unlist in Kripp.Alpha
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I am new to R and working on the below dataset:
I have a file called zippopinc
Repex:
head(zippopinc)
Year Zip Total_Population Median_Income City State
1 1 2017 ZCTA5 00601 17599 11757 Adjuntas PR
2 2 2017 ZCTA5 00602 39209 16190 Aguada PR
3 3 2017 ZCTA5 00603 50135 16645 Aguadilla PR
4 4 2017 ZCTA5 00606 6304 13387 Maricao PR
5 5 2017 ZCTA5 00610 27590 18741 Anasco PR
6 6 2017 ZCTA5 00612 62566 17744 Arecibo PR
Poptoincomeratio
1.4968955
2.4218036
3.0120156
0.4709046
1.4721733
3.5260370
poptoincomeratio is basically Total_Population/Median_Income
My objective is to find which zip code has the highest Poptoincomeratio:
My input:
max(sapply(zippopinc$Poptoincomeratio, max))
Output:
4.454182
So I tried,
zippopinc$Zip[demograph_ratio$Poptoincomeratio == 4.454182]
But this gave me:
factor(0)
30956 Levels
I then tried to convert zipopinc as a factor but got the below error:
> as.factor(zippopinc)
Error in sort.list(y) : 'x' must be atomic for 'sort.list'
Have you called 'sort' on a list?
How can I fix this?
r dplyr
edited Mar 23 at 7:53
Z.Lin
14.6k32345
asked Mar 23 at 2:18
KidCodeKidCode
504
add a comment |
I am new to R and working on the below dataset:
I have a file called zippopinc
Repex:
head(zippopinc)
Year Zip Total_Population Median_Income City State
1 1 2017 ZCTA5 00601 17599 11757 Adjuntas PR
2 2 2017 ZCTA5 00602 39209 16190 Aguada PR
3 3 2017 ZCTA5 00603 50135 16645 Aguadilla PR
4 4 2017 ZCTA5 00606 6304 13387 Maricao PR
5 5 2017 ZCTA5 00610 27590 18741 Anasco PR
6 6 2017 ZCTA5 00612 62566 17744 Arecibo PR
Poptoincomeratio
1.4968955
2.4218036
3.0120156
0.4709046
1.4721733
3.5260370
poptoincomeratio is basically Total_Population/Median_Income
My objective is to find which zip code has the highest Poptoincomeratio:
My input:
max(sapply(zippopinc$Poptoincomeratio, max))
Output:
4.454182
So I tried,
zippopinc$Zip[demograph_ratio$Poptoincomeratio == 4.454182]
But this gave me:
factor(0)
30956 Levels
I then tried to convert zipopinc as a factor but got the below error:
> as.factor(zippopinc)
Error in sort.list(y) : 'x' must be atomic for 'sort.list'
Have you called 'sort' on a list?
How can I fix this?
r dplyr
edited Mar 23 at 7:53
Z.Lin
14.6k32345
asked Mar 23 at 2:18
KidCodeKidCode
504
add a comment |
I am new to R and working on the below dataset:
I have a file called zippopinc
Repex:
head(zippopinc)
Year Zip Total_Population Median_Income City State
1 1 2017 ZCTA5 00601 17599 11757 Adjuntas PR
2 2 2017 ZCTA5 00602 39209 16190 Aguada PR
3 3 2017 ZCTA5 00603 50135 16645 Aguadilla PR
4 4 2017 ZCTA5 00606 6304 13387 Maricao PR
5 5 2017 ZCTA5 00610 27590 18741 Anasco PR
6 6 2017 ZCTA5 00612 62566 17744 Arecibo PR
Poptoincomeratio
1.4968955
2.4218036
3.0120156
0.4709046
1.4721733
3.5260370
poptoincomeratio is basically Total_Population/Median_Income
My objective is to find which zip code has the highest Poptoincomeratio:
My input:
max(sapply(zippopinc$Poptoincomeratio, max))
Output:
4.454182
So I tried,
zippopinc$Zip[demograph_ratio$Poptoincomeratio == 4.454182]
But this gave me:
factor(0)
30956 Levels
I then tried to convert zipopinc as a factor but got the below error:
> as.factor(zippopinc)
Error in sort.list(y) : 'x' must be atomic for 'sort.list'
Have you called 'sort' on a list?
How can I fix this?
r dplyr
edited Mar 23 at 7:53
Z.Lin
14.6k32345
asked Mar 23 at 2:18
KidCodeKidCode
504
I am new to R and working on the below dataset:
I have a file called zippopinc
Repex:
head(zippopinc)
Year Zip Total_Population Median_Income City State
1 1 2017 ZCTA5 00601 17599 11757 Adjuntas PR
2 2 2017 ZCTA5 00602 39209 16190 Aguada PR
3 3 2017 ZCTA5 00603 50135 16645 Aguadilla PR
4 4 2017 ZCTA5 00606 6304 13387 Maricao PR
5 5 2017 ZCTA5 00610 27590 18741 Anasco PR
6 6 2017 ZCTA5 00612 62566 17744 Arecibo PR
Poptoincomeratio
1.4968955
2.4218036
3.0120156
0.4709046
1.4721733
3.5260370
poptoincomeratio is basically Total_Population/Median_Income
My objective is to find which zip code has the highest Poptoincomeratio:
My input:
max(sapply(zippopinc$Poptoincomeratio, max))
Output:
4.454182
So I tried,
zippopinc$Zip[demograph_ratio$Poptoincomeratio == 4.454182]
But this gave me:
factor(0)
30956 Levels
I then tried to convert zipopinc as a factor but got the below error:
> as.factor(zippopinc)
Error in sort.list(y) : 'x' must be atomic for 'sort.list'
Have you called 'sort' on a list?
How can I fix this?
r dplyr
r dplyr
edited Mar 23 at 7:53
Z.Lin
14.6k32345
asked Mar 23 at 2:18
KidCodeKidCode
504
edited Mar 23 at 7:53
Z.Lin
14.6k32345
asked Mar 23 at 2:18
KidCodeKidCode
504
edited Mar 23 at 7:53
Z.Lin
14.6k32345
edited Mar 23 at 7:53
Z.Lin
14.6k32345
edited Mar 23 at 7:53
Z.Lin
14.6k32345
14.6k32345
asked Mar 23 at 2:18
KidCodeKidCode
504
asked Mar 23 at 2:18
KidCodeKidCode
504
asked Mar 23 at 2:18
KidCodeKidCode
504
504
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
If you want to find which zip code has the highest Poptoincomeratio do :
zippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]
The reason why it doesn't yield you any output with current approach is because there are some limitations in comparing floating point values. Read more here
- Numeric comparison difficulty in R
- Why are these numbers not equal?
Even for the shared example, we can see that 3.5260370 is the highest value in Poptoincomeratio column but when we compare the values we get
zippopinc$Poptoincomeratio == 3.5260370
#[1] FALSE FALSE FALSE FALSE FALSE FALSE
but if you use which.max it returns the highest Zip value
zippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]
#[1] 612
answered Mar 23 at 2:31
Ronak ShahRonak Shah
51.9k104371
Thanks.This is just a reproducible example and not the entire dataset, that is why you dont see 4.454182 @Ronak Shah. I mentioned #Repex.
– KidCode
Mar 23 at 2:41
@KidCode I know. Can you runzippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]on your real data and compare the answer?
– Ronak Shah
Mar 23 at 2:41
Yes, I got it and marked your answer correct. :) thanks
– KidCode
Mar 23 at 2:43
add a comment |
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votes
If you want to find which zip code has the highest Poptoincomeratio do :
zippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]
The reason why it doesn't yield you any output with current approach is because there are some limitations in comparing floating point values. Read more here
- Numeric comparison difficulty in R
- Why are these numbers not equal?
Even for the shared example, we can see that 3.5260370 is the highest value in Poptoincomeratio column but when we compare the values we get
zippopinc$Poptoincomeratio == 3.5260370
#[1] FALSE FALSE FALSE FALSE FALSE FALSE
but if you use which.max it returns the highest Zip value
zippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]
#[1] 612
answered Mar 23 at 2:31
Ronak ShahRonak Shah
51.9k104371
Thanks.This is just a reproducible example and not the entire dataset, that is why you dont see 4.454182 @Ronak Shah. I mentioned #Repex.
– KidCode
Mar 23 at 2:41
@KidCode I know. Can you runzippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]on your real data and compare the answer?
– Ronak Shah
Mar 23 at 2:41
Yes, I got it and marked your answer correct. :) thanks
– KidCode
Mar 23 at 2:43
add a comment |
If you want to find which zip code has the highest Poptoincomeratio do :
zippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]
The reason why it doesn't yield you any output with current approach is because there are some limitations in comparing floating point values. Read more here
- Numeric comparison difficulty in R
- Why are these numbers not equal?
Even for the shared example, we can see that 3.5260370 is the highest value in Poptoincomeratio column but when we compare the values we get
zippopinc$Poptoincomeratio == 3.5260370
#[1] FALSE FALSE FALSE FALSE FALSE FALSE
but if you use which.max it returns the highest Zip value
zippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]
#[1] 612
answered Mar 23 at 2:31
Ronak ShahRonak Shah
51.9k104371
Thanks.This is just a reproducible example and not the entire dataset, that is why you dont see 4.454182 @Ronak Shah. I mentioned #Repex.
– KidCode
Mar 23 at 2:41
@KidCode I know. Can you runzippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]on your real data and compare the answer?
– Ronak Shah
Mar 23 at 2:41
Yes, I got it and marked your answer correct. :) thanks
– KidCode
Mar 23 at 2:43
add a comment |
If you want to find which zip code has the highest Poptoincomeratio do :
zippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]
The reason why it doesn't yield you any output with current approach is because there are some limitations in comparing floating point values. Read more here
- Numeric comparison difficulty in R
- Why are these numbers not equal?
Even for the shared example, we can see that 3.5260370 is the highest value in Poptoincomeratio column but when we compare the values we get
zippopinc$Poptoincomeratio == 3.5260370
#[1] FALSE FALSE FALSE FALSE FALSE FALSE
but if you use which.max it returns the highest Zip value
zippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]
#[1] 612
answered Mar 23 at 2:31
Ronak ShahRonak Shah
51.9k104371
If you want to find which zip code has the highest Poptoincomeratio do :
zippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]
The reason why it doesn't yield you any output with current approach is because there are some limitations in comparing floating point values. Read more here
- Numeric comparison difficulty in R
- Why are these numbers not equal?
Even for the shared example, we can see that 3.5260370 is the highest value in Poptoincomeratio column but when we compare the values we get
zippopinc$Poptoincomeratio == 3.5260370
#[1] FALSE FALSE FALSE FALSE FALSE FALSE
but if you use which.max it returns the highest Zip value
zippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]
#[1] 612
answered Mar 23 at 2:31
Ronak ShahRonak Shah
51.9k104371
edited Mar 23 at 2:38
answered Mar 23 at 2:31
Ronak ShahRonak Shah
51.9k104371
answered Mar 23 at 2:31
Ronak ShahRonak Shah
51.9k104371
answered Mar 23 at 2:31
Ronak ShahRonak Shah
51.9k104371
51.9k104371
Thanks.This is just a reproducible example and not the entire dataset, that is why you dont see 4.454182 @Ronak Shah. I mentioned #Repex.
– KidCode
Mar 23 at 2:41
@KidCode I know. Can you runzippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]on your real data and compare the answer?
– Ronak Shah
Mar 23 at 2:41
Yes, I got it and marked your answer correct. :) thanks
– KidCode
Mar 23 at 2:43
add a comment |
Thanks.This is just a reproducible example and not the entire dataset, that is why you dont see 4.454182 @Ronak Shah. I mentioned #Repex.
– KidCode
Mar 23 at 2:41
@KidCode I know. Can you runzippopinc$Zip[which.max(zippopinc$Poptoincomeratio)]on your real data and compare the answer?
– Ronak Shah
Mar 23 at 2:41
Yes, I got it and marked your answer correct. :) thanks
– KidCode
Mar 23 at 2:43
Thanks.This is just a reproducible example and not the entire dataset, that is why you dont see 4.454182 @Ronak Shah. I mentioned #Repex.
– KidCode
Mar 23 at 2:41
Thanks.This is just a reproducible example and not the entire dataset, that is why you dont see 4.454182 @Ronak Shah. I mentioned #Repex.
– KidCode
Mar 23 at 2:41
@KidCode I know. Can you run
zippopinc$Zip[which.max(zippopinc$Poptoincomeratio)] on your real data and compare the answer?– Ronak Shah
Mar 23 at 2:41
@KidCode I know. Can you run
zippopinc$Zip[which.max(zippopinc$Poptoincomeratio)] on your real data and compare the answer?– Ronak Shah
Mar 23 at 2:41
Yes, I got it and marked your answer correct. :) thanks
– KidCode
Mar 23 at 2:43
Yes, I got it and marked your answer correct. :) thanks
– KidCode
Mar 23 at 2:43
add a comment |
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