Python scanner for the first free port in a rangePython Port ScannerPython Port Scanner 2.0Python Port Scanner 2.1Simple C Port ScannerIP Range Port ScannerIP Scanner via python socketsPython proxy checker/scannerThe start of a Python port scannerPython port scanner using multithreadingSimple port scanner in Python 3

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Python scanner for the first free port in a range


Python Port ScannerPython Port Scanner 2.0Python Port Scanner 2.1Simple C Port ScannerIP Range Port ScannerIP Scanner via python socketsPython proxy checker/scannerThe start of a Python port scannerPython port scanner using multithreadingSimple port scanner in Python 3






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








7












$begingroup$


I have a distributed application (YARN), which runs a WebApp.



This application use a default port to start (8008), before I start I need to check if port is in use.



A container may run in the same virtual machine, hence port may be in use.
(Max I have 4 containers in WebApp).



I created the following code which seem to work, but want to see if there are some clean ups/improvements suggested.



def port_in_use(port):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
result = sock.connect_ex(('127.0.0.1', port))
if result == 0:
return True
else:
return False


def start_dashboard():
base_port = os.getenv('DASHBOARD_PORT_ENV_VAR', 8008)
scan_ports = True
attempts = 0
max_attempts = 10
while(scan_ports and attempts <= max_attempts):
if port_in_use(base_port):
base_port += 1
attempts += 1
else:
scan_ports = False
if attempts == max_attempts:
raise IOError('Port in use')
dashboard.configure(port=base_port)
dashboard.launch()









share|improve this question











$endgroup$


















    7












    $begingroup$


    I have a distributed application (YARN), which runs a WebApp.



    This application use a default port to start (8008), before I start I need to check if port is in use.



    A container may run in the same virtual machine, hence port may be in use.
    (Max I have 4 containers in WebApp).



    I created the following code which seem to work, but want to see if there are some clean ups/improvements suggested.



    def port_in_use(port):
    sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    result = sock.connect_ex(('127.0.0.1', port))
    if result == 0:
    return True
    else:
    return False


    def start_dashboard():
    base_port = os.getenv('DASHBOARD_PORT_ENV_VAR', 8008)
    scan_ports = True
    attempts = 0
    max_attempts = 10
    while(scan_ports and attempts <= max_attempts):
    if port_in_use(base_port):
    base_port += 1
    attempts += 1
    else:
    scan_ports = False
    if attempts == max_attempts:
    raise IOError('Port in use')
    dashboard.configure(port=base_port)
    dashboard.launch()









    share|improve this question











    $endgroup$














      7












      7








      7


      1



      $begingroup$


      I have a distributed application (YARN), which runs a WebApp.



      This application use a default port to start (8008), before I start I need to check if port is in use.



      A container may run in the same virtual machine, hence port may be in use.
      (Max I have 4 containers in WebApp).



      I created the following code which seem to work, but want to see if there are some clean ups/improvements suggested.



      def port_in_use(port):
      sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
      result = sock.connect_ex(('127.0.0.1', port))
      if result == 0:
      return True
      else:
      return False


      def start_dashboard():
      base_port = os.getenv('DASHBOARD_PORT_ENV_VAR', 8008)
      scan_ports = True
      attempts = 0
      max_attempts = 10
      while(scan_ports and attempts <= max_attempts):
      if port_in_use(base_port):
      base_port += 1
      attempts += 1
      else:
      scan_ports = False
      if attempts == max_attempts:
      raise IOError('Port in use')
      dashboard.configure(port=base_port)
      dashboard.launch()









      share|improve this question











      $endgroup$




      I have a distributed application (YARN), which runs a WebApp.



      This application use a default port to start (8008), before I start I need to check if port is in use.



      A container may run in the same virtual machine, hence port may be in use.
      (Max I have 4 containers in WebApp).



      I created the following code which seem to work, but want to see if there are some clean ups/improvements suggested.



      def port_in_use(port):
      sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
      result = sock.connect_ex(('127.0.0.1', port))
      if result == 0:
      return True
      else:
      return False


      def start_dashboard():
      base_port = os.getenv('DASHBOARD_PORT_ENV_VAR', 8008)
      scan_ports = True
      attempts = 0
      max_attempts = 10
      while(scan_ports and attempts <= max_attempts):
      if port_in_use(base_port):
      base_port += 1
      attempts += 1
      else:
      scan_ports = False
      if attempts == max_attempts:
      raise IOError('Port in use')
      dashboard.configure(port=base_port)
      dashboard.launch()






      python python-3.x networking socket






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 23 at 13:52









      200_success

      132k20159426




      132k20159426










      asked Mar 23 at 7:09









      spicyramenspicyramen

      319312




      319312




















          1 Answer
          1






          active

          oldest

          votes


















          9












          $begingroup$

          Your code has some incorrect assumptions.



          • an application may listen on a specific address/port combination; 127.0.0.1:port can be available while *:port is not.


          • an application may bind a port without listening. Connects will fail, but so will your own bind.


          • a firewall or other mechanism can interfere with connections, generating false positives in your scan.


          The reliable approach is to bind the port, just as your dashboard will, and then release it.



          result = sock.bind(('', port))
          sock.close()



          You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard logic cleaner and get rid of boolean loop-terminator scan_ports. Just exit the loop by returning the answer.



          def next_free_port( port=1024, max_port=65535 ):
          sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
          while port <= max_port:
          try:
          sock.bind(('', port))
          sock.close()
          return port
          except OSError:
          port += 1
          raise IOError('no free ports')

          def start_dashboard():

          # pass optional second parameter "max_port" here, else scan until a free one is found
          port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )

          dashboard.configure(port=port)
          dashboard.launch()


          You can use netcat to make ports in-use for testing: nc -l -p 9999 will listen on port 9999; press control-C to end it.






          share|improve this answer











          $endgroup$












          • $begingroup$
            Thank you for the answer, check is local, so no firewall in place.
            $endgroup$
            – spicyramen
            Mar 23 at 17:42










          • $begingroup$
            I mean a host firewall, like iptables on Linux.
            $endgroup$
            – Oh My Goodness
            Mar 23 at 19:06











          • $begingroup$
            Sounds good, any recommendation for Python style? Thanks
            $endgroup$
            – spicyramen
            Mar 24 at 1:53






          • 1




            $begingroup$
            the code can be a little shorter and clearer; see edits for a fleshed-out example.
            $endgroup$
            – Oh My Goodness
            Mar 24 at 6:37






          • 1




            $begingroup$
            Thank you! Great sample
            $endgroup$
            – spicyramen
            Mar 24 at 8:37











          Your Answer






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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          9












          $begingroup$

          Your code has some incorrect assumptions.



          • an application may listen on a specific address/port combination; 127.0.0.1:port can be available while *:port is not.


          • an application may bind a port without listening. Connects will fail, but so will your own bind.


          • a firewall or other mechanism can interfere with connections, generating false positives in your scan.


          The reliable approach is to bind the port, just as your dashboard will, and then release it.



          result = sock.bind(('', port))
          sock.close()



          You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard logic cleaner and get rid of boolean loop-terminator scan_ports. Just exit the loop by returning the answer.



          def next_free_port( port=1024, max_port=65535 ):
          sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
          while port <= max_port:
          try:
          sock.bind(('', port))
          sock.close()
          return port
          except OSError:
          port += 1
          raise IOError('no free ports')

          def start_dashboard():

          # pass optional second parameter "max_port" here, else scan until a free one is found
          port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )

          dashboard.configure(port=port)
          dashboard.launch()


          You can use netcat to make ports in-use for testing: nc -l -p 9999 will listen on port 9999; press control-C to end it.






          share|improve this answer











          $endgroup$












          • $begingroup$
            Thank you for the answer, check is local, so no firewall in place.
            $endgroup$
            – spicyramen
            Mar 23 at 17:42










          • $begingroup$
            I mean a host firewall, like iptables on Linux.
            $endgroup$
            – Oh My Goodness
            Mar 23 at 19:06











          • $begingroup$
            Sounds good, any recommendation for Python style? Thanks
            $endgroup$
            – spicyramen
            Mar 24 at 1:53






          • 1




            $begingroup$
            the code can be a little shorter and clearer; see edits for a fleshed-out example.
            $endgroup$
            – Oh My Goodness
            Mar 24 at 6:37






          • 1




            $begingroup$
            Thank you! Great sample
            $endgroup$
            – spicyramen
            Mar 24 at 8:37















          9












          $begingroup$

          Your code has some incorrect assumptions.



          • an application may listen on a specific address/port combination; 127.0.0.1:port can be available while *:port is not.


          • an application may bind a port without listening. Connects will fail, but so will your own bind.


          • a firewall or other mechanism can interfere with connections, generating false positives in your scan.


          The reliable approach is to bind the port, just as your dashboard will, and then release it.



          result = sock.bind(('', port))
          sock.close()



          You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard logic cleaner and get rid of boolean loop-terminator scan_ports. Just exit the loop by returning the answer.



          def next_free_port( port=1024, max_port=65535 ):
          sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
          while port <= max_port:
          try:
          sock.bind(('', port))
          sock.close()
          return port
          except OSError:
          port += 1
          raise IOError('no free ports')

          def start_dashboard():

          # pass optional second parameter "max_port" here, else scan until a free one is found
          port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )

          dashboard.configure(port=port)
          dashboard.launch()


          You can use netcat to make ports in-use for testing: nc -l -p 9999 will listen on port 9999; press control-C to end it.






          share|improve this answer











          $endgroup$












          • $begingroup$
            Thank you for the answer, check is local, so no firewall in place.
            $endgroup$
            – spicyramen
            Mar 23 at 17:42










          • $begingroup$
            I mean a host firewall, like iptables on Linux.
            $endgroup$
            – Oh My Goodness
            Mar 23 at 19:06











          • $begingroup$
            Sounds good, any recommendation for Python style? Thanks
            $endgroup$
            – spicyramen
            Mar 24 at 1:53






          • 1




            $begingroup$
            the code can be a little shorter and clearer; see edits for a fleshed-out example.
            $endgroup$
            – Oh My Goodness
            Mar 24 at 6:37






          • 1




            $begingroup$
            Thank you! Great sample
            $endgroup$
            – spicyramen
            Mar 24 at 8:37













          9












          9








          9





          $begingroup$

          Your code has some incorrect assumptions.



          • an application may listen on a specific address/port combination; 127.0.0.1:port can be available while *:port is not.


          • an application may bind a port without listening. Connects will fail, but so will your own bind.


          • a firewall or other mechanism can interfere with connections, generating false positives in your scan.


          The reliable approach is to bind the port, just as your dashboard will, and then release it.



          result = sock.bind(('', port))
          sock.close()



          You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard logic cleaner and get rid of boolean loop-terminator scan_ports. Just exit the loop by returning the answer.



          def next_free_port( port=1024, max_port=65535 ):
          sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
          while port <= max_port:
          try:
          sock.bind(('', port))
          sock.close()
          return port
          except OSError:
          port += 1
          raise IOError('no free ports')

          def start_dashboard():

          # pass optional second parameter "max_port" here, else scan until a free one is found
          port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )

          dashboard.configure(port=port)
          dashboard.launch()


          You can use netcat to make ports in-use for testing: nc -l -p 9999 will listen on port 9999; press control-C to end it.






          share|improve this answer











          $endgroup$



          Your code has some incorrect assumptions.



          • an application may listen on a specific address/port combination; 127.0.0.1:port can be available while *:port is not.


          • an application may bind a port without listening. Connects will fail, but so will your own bind.


          • a firewall or other mechanism can interfere with connections, generating false positives in your scan.


          The reliable approach is to bind the port, just as your dashboard will, and then release it.



          result = sock.bind(('', port))
          sock.close()



          You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard logic cleaner and get rid of boolean loop-terminator scan_ports. Just exit the loop by returning the answer.



          def next_free_port( port=1024, max_port=65535 ):
          sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
          while port <= max_port:
          try:
          sock.bind(('', port))
          sock.close()
          return port
          except OSError:
          port += 1
          raise IOError('no free ports')

          def start_dashboard():

          # pass optional second parameter "max_port" here, else scan until a free one is found
          port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )

          dashboard.configure(port=port)
          dashboard.launch()


          You can use netcat to make ports in-use for testing: nc -l -p 9999 will listen on port 9999; press control-C to end it.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 24 at 7:23

























          answered Mar 23 at 8:49









          Oh My GoodnessOh My Goodness

          2,791316




          2,791316











          • $begingroup$
            Thank you for the answer, check is local, so no firewall in place.
            $endgroup$
            – spicyramen
            Mar 23 at 17:42










          • $begingroup$
            I mean a host firewall, like iptables on Linux.
            $endgroup$
            – Oh My Goodness
            Mar 23 at 19:06











          • $begingroup$
            Sounds good, any recommendation for Python style? Thanks
            $endgroup$
            – spicyramen
            Mar 24 at 1:53






          • 1




            $begingroup$
            the code can be a little shorter and clearer; see edits for a fleshed-out example.
            $endgroup$
            – Oh My Goodness
            Mar 24 at 6:37






          • 1




            $begingroup$
            Thank you! Great sample
            $endgroup$
            – spicyramen
            Mar 24 at 8:37
















          • $begingroup$
            Thank you for the answer, check is local, so no firewall in place.
            $endgroup$
            – spicyramen
            Mar 23 at 17:42










          • $begingroup$
            I mean a host firewall, like iptables on Linux.
            $endgroup$
            – Oh My Goodness
            Mar 23 at 19:06











          • $begingroup$
            Sounds good, any recommendation for Python style? Thanks
            $endgroup$
            – spicyramen
            Mar 24 at 1:53






          • 1




            $begingroup$
            the code can be a little shorter and clearer; see edits for a fleshed-out example.
            $endgroup$
            – Oh My Goodness
            Mar 24 at 6:37






          • 1




            $begingroup$
            Thank you! Great sample
            $endgroup$
            – spicyramen
            Mar 24 at 8:37















          $begingroup$
          Thank you for the answer, check is local, so no firewall in place.
          $endgroup$
          – spicyramen
          Mar 23 at 17:42




          $begingroup$
          Thank you for the answer, check is local, so no firewall in place.
          $endgroup$
          – spicyramen
          Mar 23 at 17:42












          $begingroup$
          I mean a host firewall, like iptables on Linux.
          $endgroup$
          – Oh My Goodness
          Mar 23 at 19:06





          $begingroup$
          I mean a host firewall, like iptables on Linux.
          $endgroup$
          – Oh My Goodness
          Mar 23 at 19:06













          $begingroup$
          Sounds good, any recommendation for Python style? Thanks
          $endgroup$
          – spicyramen
          Mar 24 at 1:53




          $begingroup$
          Sounds good, any recommendation for Python style? Thanks
          $endgroup$
          – spicyramen
          Mar 24 at 1:53




          1




          1




          $begingroup$
          the code can be a little shorter and clearer; see edits for a fleshed-out example.
          $endgroup$
          – Oh My Goodness
          Mar 24 at 6:37




          $begingroup$
          the code can be a little shorter and clearer; see edits for a fleshed-out example.
          $endgroup$
          – Oh My Goodness
          Mar 24 at 6:37




          1




          1




          $begingroup$
          Thank you! Great sample
          $endgroup$
          – spicyramen
          Mar 24 at 8:37




          $begingroup$
          Thank you! Great sample
          $endgroup$
          – spicyramen
          Mar 24 at 8:37

















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