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Read variable line by line in shell (dash included)
Check if a directory exists in a shell scriptHow do I prompt for Yes/No/Cancel input in a Linux shell script?Shell command to sum integers, one per line?In the shell, what does “ 2>&1 ” mean?How to count all the lines of code in a directory recursively?How to declare and use boolean variables in shell script?How to concatenate string variables in BashDelete lines in a text file that contain a specific stringCheck existence of input argument in a Bash shell scriptHow to read a file into a variable in shell?
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i have a variable with stored logs. What i want is to read every line of the variable containing logs and keep that line or remove base on some filtering stuffs.
The problem is that my code is working on bash, but not working on dash.
this is my code:
filtered_logs=""
while IFS= read -r line
do
...(store line to $filterered_logs if it comes throught filter )
done <<< "$logs"
logs="$filtered_logs"
this code is working in bash. But ' done <<< "$logs" ' is not working in dash (since is default sh in ubuntu). It's a homework and i need, that it works on every shell possible.
What i tried was:
filtered_logs=""
echo "$logs" |
while IFS= read -r line
do
...(store line to $filterered_logs if it comes throught filter )
done
logs="$filtered_logs"
But if i store something in from while cycle to $filtered_logs, it's not working. And i can't access this while cycle with my debugger too. (I think that the whole while cycle is whole new process since i run it with |.
My question is how to make it works, please. Thank you
shell sh
asked Mar 24 at 2:07
RuuzaRuuza
32
add a comment |
i have a variable with stored logs. What i want is to read every line of the variable containing logs and keep that line or remove base on some filtering stuffs.
The problem is that my code is working on bash, but not working on dash.
this is my code:
filtered_logs=""
while IFS= read -r line
do
...(store line to $filterered_logs if it comes throught filter )
done <<< "$logs"
logs="$filtered_logs"
this code is working in bash. But ' done <<< "$logs" ' is not working in dash (since is default sh in ubuntu). It's a homework and i need, that it works on every shell possible.
What i tried was:
filtered_logs=""
echo "$logs" |
while IFS= read -r line
do
...(store line to $filterered_logs if it comes throught filter )
done
logs="$filtered_logs"
But if i store something in from while cycle to $filtered_logs, it's not working. And i can't access this while cycle with my debugger too. (I think that the whole while cycle is whole new process since i run it with |.
My question is how to make it works, please. Thank you
shell sh
asked Mar 24 at 2:07
RuuzaRuuza
32
man echo;man cat; google "shell input redirection"
– jhnc
Mar 24 at 2:34
Every shell possible seems a to an unlimited assignment. Do you need to use the while-construction or can you switch toawk,sedor another tool avoidingwhile(which has more problems like performance and skipping the last line when it is not ending with a newline) ?
– Walter A
Mar 24 at 11:16
yes, i can use both awk and sed. And it seems that other classmates used that. Sadly i didn't learned how to work with that, so i ended with this.
– Ruuza
Mar 24 at 12:16
add a comment |
i have a variable with stored logs. What i want is to read every line of the variable containing logs and keep that line or remove base on some filtering stuffs.
The problem is that my code is working on bash, but not working on dash.
this is my code:
filtered_logs=""
while IFS= read -r line
do
...(store line to $filterered_logs if it comes throught filter )
done <<< "$logs"
logs="$filtered_logs"
this code is working in bash. But ' done <<< "$logs" ' is not working in dash (since is default sh in ubuntu). It's a homework and i need, that it works on every shell possible.
What i tried was:
filtered_logs=""
echo "$logs" |
while IFS= read -r line
do
...(store line to $filterered_logs if it comes throught filter )
done
logs="$filtered_logs"
But if i store something in from while cycle to $filtered_logs, it's not working. And i can't access this while cycle with my debugger too. (I think that the whole while cycle is whole new process since i run it with |.
My question is how to make it works, please. Thank you
shell sh
asked Mar 24 at 2:07
RuuzaRuuza
32
i have a variable with stored logs. What i want is to read every line of the variable containing logs and keep that line or remove base on some filtering stuffs.
The problem is that my code is working on bash, but not working on dash.
this is my code:
filtered_logs=""
while IFS= read -r line
do
...(store line to $filterered_logs if it comes throught filter )
done <<< "$logs"
logs="$filtered_logs"
this code is working in bash. But ' done <<< "$logs" ' is not working in dash (since is default sh in ubuntu). It's a homework and i need, that it works on every shell possible.
What i tried was:
filtered_logs=""
echo "$logs" |
while IFS= read -r line
do
...(store line to $filterered_logs if it comes throught filter )
done
logs="$filtered_logs"
But if i store something in from while cycle to $filtered_logs, it's not working. And i can't access this while cycle with my debugger too. (I think that the whole while cycle is whole new process since i run it with |.
My question is how to make it works, please. Thank you
shell sh
shell sh
asked Mar 24 at 2:07
RuuzaRuuza
32
asked Mar 24 at 2:07
RuuzaRuuza
32
asked Mar 24 at 2:07
RuuzaRuuza
32
asked Mar 24 at 2:07
RuuzaRuuza
32
asked Mar 24 at 2:07
RuuzaRuuza
32
32
man echo;man cat; google "shell input redirection"
– jhnc
Mar 24 at 2:34
Every shell possible seems a to an unlimited assignment. Do you need to use the while-construction or can you switch toawk,sedor another tool avoidingwhile(which has more problems like performance and skipping the last line when it is not ending with a newline) ?
– Walter A
Mar 24 at 11:16
yes, i can use both awk and sed. And it seems that other classmates used that. Sadly i didn't learned how to work with that, so i ended with this.
– Ruuza
Mar 24 at 12:16
add a comment |
man echo;man cat; google "shell input redirection"
– jhnc
Mar 24 at 2:34
Every shell possible seems a to an unlimited assignment. Do you need to use the while-construction or can you switch toawk,sedor another tool avoidingwhile(which has more problems like performance and skipping the last line when it is not ending with a newline) ?
– Walter A
Mar 24 at 11:16
yes, i can use both awk and sed. And it seems that other classmates used that. Sadly i didn't learned how to work with that, so i ended with this.
– Ruuza
Mar 24 at 12:16
man echo ; man cat ; google "shell input redirection"– jhnc
Mar 24 at 2:34
man echo ; man cat ; google "shell input redirection"– jhnc
Mar 24 at 2:34
Every shell possible seems a to an unlimited assignment. Do you need to use the while-construction or can you switch to
awk, sed or another tool avoiding while (which has more problems like performance and skipping the last line when it is not ending with a newline) ?– Walter A
Mar 24 at 11:16
Every shell possible seems a to an unlimited assignment. Do you need to use the while-construction or can you switch to
awk, sed or another tool avoiding while (which has more problems like performance and skipping the last line when it is not ending with a newline) ?– Walter A
Mar 24 at 11:16
yes, i can use both awk and sed. And it seems that other classmates used that. Sadly i didn't learned how to work with that, so i ended with this.
– Ruuza
Mar 24 at 12:16
yes, i can use both awk and sed. And it seems that other classmates used that. Sadly i didn't learned how to work with that, so i ended with this.
– Ruuza
Mar 24 at 12:16
add a comment |
1 Answer
1
active
oldest
votes
It's easy to use clean posix api in your case:
logs=$(
printf "%s" "$logs" |
while IFS= read -r line
do
echo "store this to logs"
done
)
answered Mar 24 at 3:23
Kamil CukKamil Cuk
15.3k2633
printf "%s" "$(echo "$logs" | tail -3)"will show that the last newline is missing.
– Walter A
Mar 24 at 10:24
Thank you so much, it works!. Yes, the last line is missing. I append a newline to variable as workaround. Do you know about better solution?
– Ruuza
Mar 24 at 14:08
Justprintf "%sn" "$logs"orwhile ....; do ... done <<<"$logs".
– Kamil Cuk
Mar 24 at 20:42
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
It's easy to use clean posix api in your case:
logs=$(
printf "%s" "$logs" |
while IFS= read -r line
do
echo "store this to logs"
done
)
answered Mar 24 at 3:23
Kamil CukKamil Cuk
15.3k2633
printf "%s" "$(echo "$logs" | tail -3)"will show that the last newline is missing.
– Walter A
Mar 24 at 10:24
Thank you so much, it works!. Yes, the last line is missing. I append a newline to variable as workaround. Do you know about better solution?
– Ruuza
Mar 24 at 14:08
Justprintf "%sn" "$logs"orwhile ....; do ... done <<<"$logs".
– Kamil Cuk
Mar 24 at 20:42
add a comment |
It's easy to use clean posix api in your case:
logs=$(
printf "%s" "$logs" |
while IFS= read -r line
do
echo "store this to logs"
done
)
answered Mar 24 at 3:23
Kamil CukKamil Cuk
15.3k2633
printf "%s" "$(echo "$logs" | tail -3)"will show that the last newline is missing.
– Walter A
Mar 24 at 10:24
Thank you so much, it works!. Yes, the last line is missing. I append a newline to variable as workaround. Do you know about better solution?
– Ruuza
Mar 24 at 14:08
Justprintf "%sn" "$logs"orwhile ....; do ... done <<<"$logs".
– Kamil Cuk
Mar 24 at 20:42
add a comment |
It's easy to use clean posix api in your case:
logs=$(
printf "%s" "$logs" |
while IFS= read -r line
do
echo "store this to logs"
done
)
answered Mar 24 at 3:23
Kamil CukKamil Cuk
15.3k2633
It's easy to use clean posix api in your case:
logs=$(
printf "%s" "$logs" |
while IFS= read -r line
do
echo "store this to logs"
done
)
answered Mar 24 at 3:23
Kamil CukKamil Cuk
15.3k2633
answered Mar 24 at 3:23
Kamil CukKamil Cuk
15.3k2633
answered Mar 24 at 3:23
Kamil CukKamil Cuk
15.3k2633
answered Mar 24 at 3:23
Kamil CukKamil Cuk
15.3k2633
15.3k2633
printf "%s" "$(echo "$logs" | tail -3)"will show that the last newline is missing.
– Walter A
Mar 24 at 10:24
Thank you so much, it works!. Yes, the last line is missing. I append a newline to variable as workaround. Do you know about better solution?
– Ruuza
Mar 24 at 14:08
Justprintf "%sn" "$logs"orwhile ....; do ... done <<<"$logs".
– Kamil Cuk
Mar 24 at 20:42
add a comment |
printf "%s" "$(echo "$logs" | tail -3)"will show that the last newline is missing.
– Walter A
Mar 24 at 10:24
Thank you so much, it works!. Yes, the last line is missing. I append a newline to variable as workaround. Do you know about better solution?
– Ruuza
Mar 24 at 14:08
Justprintf "%sn" "$logs"orwhile ....; do ... done <<<"$logs".
– Kamil Cuk
Mar 24 at 20:42
printf "%s" "$(echo "$logs" | tail -3)" will show that the last newline is missing.– Walter A
Mar 24 at 10:24
printf "%s" "$(echo "$logs" | tail -3)" will show that the last newline is missing.– Walter A
Mar 24 at 10:24
Thank you so much, it works!. Yes, the last line is missing. I append a newline to variable as workaround. Do you know about better solution?
– Ruuza
Mar 24 at 14:08
Thank you so much, it works!. Yes, the last line is missing. I append a newline to variable as workaround. Do you know about better solution?
– Ruuza
Mar 24 at 14:08
Just
printf "%sn" "$logs" or while ....; do ... done <<<"$logs".– Kamil Cuk
Mar 24 at 20:42
Just
printf "%sn" "$logs" or while ....; do ... done <<<"$logs".– Kamil Cuk
Mar 24 at 20:42
add a comment |
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man echo;man cat; google "shell input redirection"– jhnc
Mar 24 at 2:34
Every shell possible seems a to an unlimited assignment. Do you need to use the while-construction or can you switch to
awk,sedor another tool avoidingwhile(which has more problems like performance and skipping the last line when it is not ending with a newline) ?– Walter A
Mar 24 at 11:16
yes, i can use both awk and sed. And it seems that other classmates used that. Sadly i didn't learned how to work with that, so i ended with this.
– Ruuza
Mar 24 at 12:16