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Remove numbers that contains 8-10 digits at different places in a line

Regular expression to match a line that doesn't contain a wordConverting user input string to regular expressionRemoving empty lines in Notepad++Regex: Remove lines containingRegEx to extract the first 6 to 10 digit number, excluding 8 digit numbersRegex - searching for a certain number of digits in each lineR remove repeated digit sequencesRegex - Remove all but 2 digitsExpression to search for a 10 digit specific numberRemove a 4- to 6-digit number from an alphanumeric string

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0

I have a list of different items. Some of them have 8-10 digits in front of the name, some others have these 8-10 digits behind the name and some others again don't have these numbers in the name.

I have two expressions that I use to remove these digits, but I can not manage to combine them with | (or). They work each for themselves, but if I use the first expression first, then the second expression, I don't get the result I want to have.

I use these to expressions for now:

(?<=[d]8,10) (.*)
.*?(?=[d]8,10)

But if I use them both (first one and then the other), then some of the lines become totally empty.

How can I combine these to to do what I want, or if it's better, write a new expression that does what I want to do :)

List is like this:

12345678 Book
12345678 Book
Book 12345678
Book 12345678
Cabinet 120x30x145

Want this result:

Book
Book
Book
Book
Cabinet 120x30x145

regex

share|improve this question

edited Mar 23 at 11:08

revo

34.9k135289

asked Mar 23 at 10:49

user10094121user10094121

124

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  What regex flavor are you using (i.e. which tool) and how do you apply it? Just getting a regex to match does not remove text, so please make a Minimal, Complete, and Verifiable example to demonstrate.
  
  – Yunnosch
  Mar 23 at 10:56
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Why not replace bd8,10b with nothing?
  
  – Toto
  Mar 23 at 11:00
  

  
  
  
  

add a comment | 

0

I have a list of different items. Some of them have 8-10 digits in front of the name, some others have these 8-10 digits behind the name and some others again don't have these numbers in the name.

I have two expressions that I use to remove these digits, but I can not manage to combine them with | (or). They work each for themselves, but if I use the first expression first, then the second expression, I don't get the result I want to have.

I use these to expressions for now:

(?<=[d]8,10) (.*)
.*?(?=[d]8,10)

But if I use them both (first one and then the other), then some of the lines become totally empty.

How can I combine these to to do what I want, or if it's better, write a new expression that does what I want to do :)

List is like this:

12345678 Book
12345678 Book
Book 12345678
Book 12345678
Cabinet 120x30x145

Want this result:

Book
Book
Book
Book
Cabinet 120x30x145

regex

share|improve this question

edited Mar 23 at 11:08

revo

34.9k135289

asked Mar 23 at 10:49

user10094121user10094121

124

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  What regex flavor are you using (i.e. which tool) and how do you apply it? Just getting a regex to match does not remove text, so please make a Minimal, Complete, and Verifiable example to demonstrate.
  
  – Yunnosch
  Mar 23 at 10:56
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Why not replace bd8,10b with nothing?
  
  – Toto
  Mar 23 at 11:00
  

  
  
  
  

add a comment | 

I have a list of different items. Some of them have 8-10 digits in front of the name, some others have these 8-10 digits behind the name and some others again don't have these numbers in the name.

I have two expressions that I use to remove these digits, but I can not manage to combine them with | (or). They work each for themselves, but if I use the first expression first, then the second expression, I don't get the result I want to have.

I use these to expressions for now:

(?<=[d]8,10) (.*)
.*?(?=[d]8,10)

But if I use them both (first one and then the other), then some of the lines become totally empty.

How can I combine these to to do what I want, or if it's better, write a new expression that does what I want to do :)

List is like this:

12345678 Book
12345678 Book
Book 12345678
Book 12345678
Cabinet 120x30x145

Want this result:

Book
Book
Book
Book
Cabinet 120x30x145

regex

share|improve this question

edited Mar 23 at 11:08

revo

34.9k135289

asked Mar 23 at 10:49

user10094121user10094121

124

(?<=[d]8,10) (.*)
.*?(?=[d]8,10)

12345678 Book
12345678 Book
Book 12345678
Book 12345678
Cabinet 120x30x145

Book
Book
Book
Book
Cabinet 120x30x145

share|improve this question

edited Mar 23 at 11:08

revo

34.9k135289

asked Mar 23 at 10:49

user10094121user10094121

124

share|improve this question

edited Mar 23 at 11:08

revo

34.9k135289

asked Mar 23 at 10:49

user10094121user10094121

124

edited Mar 23 at 11:08

revo

34.9k135289

edited Mar 23 at 11:08

revo

34.9k135289

asked Mar 23 at 10:49

user10094121user10094121

124

asked Mar 23 at 10:49

user10094121user10094121

124

3 Answers
3

active

oldest

votes

1

Why not just use the following.
Check if there are 8 numbers in the beginning of the string, or at the end of it and remove them.

(^d8,10s*|s*d8,10$)

It gives the wanted behaviour

share|improve this answer

answered Mar 23 at 11:03

Yassin HajajYassin Hajaj

14.8k73062

add a comment | 

1

Instead of only matching everything but a number containing
8-10 digits + adjacent spaces, use a regex to substitute
such a number (also + adjacent spaces) with an empty string.

To match, use the following regex:

*d8,10 *

That is:

• 
  * - a space and an asterix - a sequence of spaces (may be empty),


• 
  d8,10 - a sequence of 8 to 10 digits,


• 
  * - another sequence of spaces (may be empty).

The replacement string is (as I said) empty. Of course, you should use
g (global) option.

Note that you can not use s instead of the space, as s matches also
CR and LF and we don't want this.

For a working example see https://regex101.com/r/1hsGzT/1

share|improve this answer

edited Mar 23 at 12:08

The fourth bird

28.3k91631

answered Mar 23 at 11:11

Valdi_BoValdi_Bo

5,8502916

add a comment | 

0

You need to use b meta sequence boundary:

/b[0-9s]8,10b/g;

var str = `12345678 Book
12345678 Book
Book 12345678
Book 12345678
Cabinet 120x30x145`;

var rgx = /b[0-9s]8,10b/g;

var res = str.replace(rgx, `n`)

console.log(res);

share|improve this answer

answered Mar 23 at 11:07

zer00nezer00ne

26.3k32547

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This will remove 123 456
  
  – Toto
  Mar 23 at 11:31
  

  
  
  
  

add a comment | 

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1

Why not just use the following.
Check if there are 8 numbers in the beginning of the string, or at the end of it and remove them.

(^d8,10s*|s*d8,10$)

It gives the wanted behaviour

share|improve this answer

answered Mar 23 at 11:03

Yassin HajajYassin Hajaj

14.8k73062

add a comment | 

1

Why not just use the following.
Check if there are 8 numbers in the beginning of the string, or at the end of it and remove them.

(^d8,10s*|s*d8,10$)

It gives the wanted behaviour

share|improve this answer

answered Mar 23 at 11:03

Yassin HajajYassin Hajaj

14.8k73062

add a comment | 

Why not just use the following.
Check if there are 8 numbers in the beginning of the string, or at the end of it and remove them.

(^d8,10s*|s*d8,10$)

It gives the wanted behaviour

share|improve this answer

answered Mar 23 at 11:03

Yassin HajajYassin Hajaj

14.8k73062

share|improve this answer

answered Mar 23 at 11:03

Yassin HajajYassin Hajaj

14.8k73062

answered Mar 23 at 11:03

Yassin HajajYassin Hajaj

14.8k73062

answered Mar 23 at 11:03

Yassin HajajYassin Hajaj

14.8k73062

1

Instead of only matching everything but a number containing
8-10 digits + adjacent spaces, use a regex to substitute
such a number (also + adjacent spaces) with an empty string.

To match, use the following regex:

*d8,10 *

That is:

• 
  * - a space and an asterix - a sequence of spaces (may be empty),


• 
  d8,10 - a sequence of 8 to 10 digits,


• 
  * - another sequence of spaces (may be empty).

The replacement string is (as I said) empty. Of course, you should use
g (global) option.

Note that you can not use s instead of the space, as s matches also
CR and LF and we don't want this.

For a working example see https://regex101.com/r/1hsGzT/1

share|improve this answer

edited Mar 23 at 12:08

The fourth bird

28.3k91631

answered Mar 23 at 11:11

Valdi_BoValdi_Bo

5,8502916

add a comment | 

1

Instead of only matching everything but a number containing
8-10 digits + adjacent spaces, use a regex to substitute
such a number (also + adjacent spaces) with an empty string.

To match, use the following regex:

*d8,10 *

That is:

• 
  * - a space and an asterix - a sequence of spaces (may be empty),


• 
  d8,10 - a sequence of 8 to 10 digits,


• 
  * - another sequence of spaces (may be empty).

The replacement string is (as I said) empty. Of course, you should use
g (global) option.

Note that you can not use s instead of the space, as s matches also
CR and LF and we don't want this.

For a working example see https://regex101.com/r/1hsGzT/1

share|improve this answer

edited Mar 23 at 12:08

The fourth bird

28.3k91631

answered Mar 23 at 11:11

Valdi_BoValdi_Bo

5,8502916

add a comment | 

Instead of only matching everything but a number containing
8-10 digits + adjacent spaces, use a regex to substitute
such a number (also + adjacent spaces) with an empty string.

To match, use the following regex:

*d8,10 *

That is:

• 
  * - a space and an asterix - a sequence of spaces (may be empty),


• 
  d8,10 - a sequence of 8 to 10 digits,


• 
  * - another sequence of spaces (may be empty).

The replacement string is (as I said) empty. Of course, you should use
g (global) option.

Note that you can not use s instead of the space, as s matches also
CR and LF and we don't want this.

For a working example see https://regex101.com/r/1hsGzT/1

share|improve this answer

edited Mar 23 at 12:08

The fourth bird

28.3k91631

answered Mar 23 at 11:11

Valdi_BoValdi_Bo

5,8502916

*d8,10 *

share|improve this answer

edited Mar 23 at 12:08

The fourth bird

28.3k91631

answered Mar 23 at 11:11

Valdi_BoValdi_Bo

5,8502916

edited Mar 23 at 12:08

The fourth bird

28.3k91631

edited Mar 23 at 12:08

The fourth bird

28.3k91631

answered Mar 23 at 11:11

Valdi_BoValdi_Bo

5,8502916

answered Mar 23 at 11:11

Valdi_BoValdi_Bo

5,8502916

0

You need to use b meta sequence boundary:

/b[0-9s]8,10b/g;

var str = `12345678 Book
12345678 Book
Book 12345678
Book 12345678
Cabinet 120x30x145`;

var rgx = /b[0-9s]8,10b/g;

var res = str.replace(rgx, `n`)

console.log(res);

share|improve this answer

answered Mar 23 at 11:07

zer00nezer00ne

26.3k32547

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This will remove 123 456
  
  – Toto
  Mar 23 at 11:31
  

  
  
  
  

add a comment | 

0

You need to use b meta sequence boundary:

/b[0-9s]8,10b/g;

var str = `12345678 Book
12345678 Book
Book 12345678
Book 12345678
Cabinet 120x30x145`;

var rgx = /b[0-9s]8,10b/g;

var res = str.replace(rgx, `n`)

console.log(res);

share|improve this answer

answered Mar 23 at 11:07

zer00nezer00ne

26.3k32547

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This will remove 123 456
  
  – Toto
  Mar 23 at 11:31
  

  
  
  
  

add a comment | 

You need to use b meta sequence boundary:

/b[0-9s]8,10b/g;

var str = `12345678 Book
12345678 Book
Book 12345678
Book 12345678
Cabinet 120x30x145`;

var rgx = /b[0-9s]8,10b/g;

var res = str.replace(rgx, `n`)

console.log(res);

share|improve this answer

answered Mar 23 at 11:07

zer00nezer00ne

26.3k32547

var str = `12345678 Book
12345678 Book
Book 12345678
Book 12345678
Cabinet 120x30x145`;

var rgx = /b[0-9s]8,10b/g;

var res = str.replace(rgx, `n`)

console.log(res);

var str = `12345678 Book
12345678 Book
Book 12345678
Book 12345678
Cabinet 120x30x145`;

var rgx = /b[0-9s]8,10b/g;

var res = str.replace(rgx, `n`)

console.log(res);

var str = `12345678 Book
12345678 Book
Book 12345678
Book 12345678
Cabinet 120x30x145`;

var rgx = /b[0-9s]8,10b/g;

var res = str.replace(rgx, `n`)

console.log(res);

share|improve this answer

answered Mar 23 at 11:07

zer00nezer00ne

26.3k32547

answered Mar 23 at 11:07

zer00nezer00ne

26.3k32547

answered Mar 23 at 11:07

zer00nezer00ne

26.3k32547