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The sum of certain digits from an input number

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0

I've been trying to sum a certain digit from a number, for example

Number: 5
Input: 54365
Output: The sum of 5's is 10

Second example:

Number: 5
Input: 5437555
Output: The sum of 5's is 20

I've managed to separate the digits yet I couldn't find the condition to sum
a certain number (for instance number 5 like the examples).

I'd appreciate to hear your idea of doing it

public static void main(String[] args) 
 int sum = 0;
 int number = MyConsole.readInt("Enter a number:");
 while (number > 0) 
 if (number % 10 == 8) 
 sum += 8;
 else 
 number /= 10;
 
 
 System.out.println("The sum of 8's is:" + sum);
 

My way of separating the numbers.

Also i have a small program to get input instead of using scanner since we still haven't went through it in class.

java

share|improve this question

edited Mar 23 at 13:29

LppEdd

10.1k31749

asked Mar 23 at 11:14

Aviv David MalkaAviv David Malka

112

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  All inputs are in String format?
  
  – Nicholas K
  Mar 23 at 11:15
  

  
  
  
  


• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  
  Hi and welcome to Stackoverflow! Please provide what you have tried so far so we could help you.
  
  – Mustahsan
  Mar 23 at 11:15
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  If you could provide some code, it would be great :)
  
  – Yassin Hajaj
  Mar 23 at 11:16
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You haven't posted any single line of your code, so we can't tell you how to fix/improve it.
  
  – JB Nizet
  Mar 23 at 11:16
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Please read and follow How do I ask a good question? to get helped.
  
  – BionicCode
  Mar 23 at 11:19
  

  
  
  
  

 | 
show 4 more comments

0

I've been trying to sum a certain digit from a number, for example

Number: 5
Input: 54365
Output: The sum of 5's is 10

Second example:

Number: 5
Input: 5437555
Output: The sum of 5's is 20

I've managed to separate the digits yet I couldn't find the condition to sum
a certain number (for instance number 5 like the examples).

I'd appreciate to hear your idea of doing it

public static void main(String[] args) 
 int sum = 0;
 int number = MyConsole.readInt("Enter a number:");
 while (number > 0) 
 if (number % 10 == 8) 
 sum += 8;
 else 
 number /= 10;
 
 
 System.out.println("The sum of 8's is:" + sum);
 

My way of separating the numbers.

Also i have a small program to get input instead of using scanner since we still haven't went through it in class.

java

share|improve this question

edited Mar 23 at 13:29

LppEdd

10.1k31749

asked Mar 23 at 11:14

Aviv David MalkaAviv David Malka

112

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  All inputs are in String format?
  
  – Nicholas K
  Mar 23 at 11:15
  

  
  
  
  


• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  
  Hi and welcome to Stackoverflow! Please provide what you have tried so far so we could help you.
  
  – Mustahsan
  Mar 23 at 11:15
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  If you could provide some code, it would be great :)
  
  – Yassin Hajaj
  Mar 23 at 11:16
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You haven't posted any single line of your code, so we can't tell you how to fix/improve it.
  
  – JB Nizet
  Mar 23 at 11:16
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Please read and follow How do I ask a good question? to get helped.
  
  – BionicCode
  Mar 23 at 11:19
  

  
  
  
  

 | 
show 4 more comments

I've been trying to sum a certain digit from a number, for example

Number: 5
Input: 54365
Output: The sum of 5's is 10

Second example:

Number: 5
Input: 5437555
Output: The sum of 5's is 20

I've managed to separate the digits yet I couldn't find the condition to sum
a certain number (for instance number 5 like the examples).

I'd appreciate to hear your idea of doing it

public static void main(String[] args) 
 int sum = 0;
 int number = MyConsole.readInt("Enter a number:");
 while (number > 0) 
 if (number % 10 == 8) 
 sum += 8;
 else 
 number /= 10;
 
 
 System.out.println("The sum of 8's is:" + sum);
 

My way of separating the numbers.

Also i have a small program to get input instead of using scanner since we still haven't went through it in class.

java

share|improve this question

edited Mar 23 at 13:29

LppEdd

10.1k31749

asked Mar 23 at 11:14

Aviv David MalkaAviv David Malka

112

Number: 5
Input: 54365
Output: The sum of 5's is 10

Number: 5
Input: 5437555
Output: The sum of 5's is 20

public static void main(String[] args) 
 int sum = 0;
 int number = MyConsole.readInt("Enter a number:");
 while (number > 0) 
 if (number % 10 == 8) 
 sum += 8;
 else 
 number /= 10;
 
 
 System.out.println("The sum of 8's is:" + sum);
 

share|improve this question

edited Mar 23 at 13:29

LppEdd

10.1k31749

asked Mar 23 at 11:14

Aviv David MalkaAviv David Malka

112

share|improve this question

edited Mar 23 at 13:29

LppEdd

10.1k31749

asked Mar 23 at 11:14

Aviv David MalkaAviv David Malka

112

edited Mar 23 at 13:29

LppEdd

10.1k31749

edited Mar 23 at 13:29

LppEdd

10.1k31749

asked Mar 23 at 11:14

Aviv David MalkaAviv David Malka

112

asked Mar 23 at 11:14

Aviv David MalkaAviv David Malka

112

1 Answer
1

active

oldest

votes

1

Your requirement seems reasonably clear to me.
Given a number

final int number = 5;

And a starting number

final int input = 54365;

The easiest way is to convert that number to a String

final int inputStr = String.valueOf(input);

Then, you can filter each char for it, and sum them

final int sum =
 inputStr.chars() // Get a Stream of ints, which represent the characters
 .map(Character::getNumericValue) // Convert a char to its numeric representation
 .filter(i -> i == number) // Filter for the designated number
 .sum(); // Sum all the filtered integers

Output: 10

---

Using the same approach, but with an old-style for loop

final int input = 54365;
final int inputStr = String.valueOf(input);
final int number = 5;
int sum = 0;

for (final char c : inputStr.toCharArray()) 
 final int n = Character.getNumericValue(c);

 if (n == number) 
 sum += number;
 

---

Your solution can work

int number = 5;
int input = 543655;
int sum = 0;

while (input > 0) 
 if (input % 10 == number) 
 sum += number;
 

 input /= 10;

share|improve this answer

edited Mar 23 at 12:40

answered Mar 23 at 11:25

LppEddLppEdd

10.1k31749

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I am a rookie in computer programming, I was a bit ashamed to post my code here.
  
  – Aviv David Malka
  Mar 23 at 11:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @AvivDavidMalka do this, post the code you tried. Don't worry about it. We all were rookies. So that we can remove that "put on hold" thing.
  
  – LppEdd
  Mar 23 at 11:31
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  i was wondering if this could have been done by using while/for loops
  
  – Aviv David Malka
  Mar 23 at 11:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @AvivDavidMalka see updated answer. Is that acceptable?
  
  – LppEdd
  Mar 23 at 11:54
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Thanks a lot @LppEdd learnt a great deal^^
  
  – Aviv David Malka
  Mar 23 at 12:52
  

  
  
  
  

 | 
show 5 more comments

Your Answer

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1

Your requirement seems reasonably clear to me.
Given a number

final int number = 5;

And a starting number

final int input = 54365;

The easiest way is to convert that number to a String

final int inputStr = String.valueOf(input);

Then, you can filter each char for it, and sum them

final int sum =
 inputStr.chars() // Get a Stream of ints, which represent the characters
 .map(Character::getNumericValue) // Convert a char to its numeric representation
 .filter(i -> i == number) // Filter for the designated number
 .sum(); // Sum all the filtered integers

Output: 10

---

Using the same approach, but with an old-style for loop

final int input = 54365;
final int inputStr = String.valueOf(input);
final int number = 5;
int sum = 0;

for (final char c : inputStr.toCharArray()) 
 final int n = Character.getNumericValue(c);

 if (n == number) 
 sum += number;
 

---

Your solution can work

int number = 5;
int input = 543655;
int sum = 0;

while (input > 0) 
 if (input % 10 == number) 
 sum += number;
 

 input /= 10;

share|improve this answer

edited Mar 23 at 12:40

answered Mar 23 at 11:25

LppEddLppEdd

10.1k31749

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I am a rookie in computer programming, I was a bit ashamed to post my code here.
  
  – Aviv David Malka
  Mar 23 at 11:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @AvivDavidMalka do this, post the code you tried. Don't worry about it. We all were rookies. So that we can remove that "put on hold" thing.
  
  – LppEdd
  Mar 23 at 11:31
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  i was wondering if this could have been done by using while/for loops
  
  – Aviv David Malka
  Mar 23 at 11:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @AvivDavidMalka see updated answer. Is that acceptable?
  
  – LppEdd
  Mar 23 at 11:54
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Thanks a lot @LppEdd learnt a great deal^^
  
  – Aviv David Malka
  Mar 23 at 12:52
  

  
  
  
  

 | 
show 5 more comments

1

Your requirement seems reasonably clear to me.
Given a number

final int number = 5;

And a starting number

final int input = 54365;

The easiest way is to convert that number to a String

final int inputStr = String.valueOf(input);

Then, you can filter each char for it, and sum them

final int sum =
 inputStr.chars() // Get a Stream of ints, which represent the characters
 .map(Character::getNumericValue) // Convert a char to its numeric representation
 .filter(i -> i == number) // Filter for the designated number
 .sum(); // Sum all the filtered integers

Output: 10

---

Using the same approach, but with an old-style for loop

final int input = 54365;
final int inputStr = String.valueOf(input);
final int number = 5;
int sum = 0;

for (final char c : inputStr.toCharArray()) 
 final int n = Character.getNumericValue(c);

 if (n == number) 
 sum += number;
 

---

Your solution can work

int number = 5;
int input = 543655;
int sum = 0;

while (input > 0) 
 if (input % 10 == number) 
 sum += number;
 

 input /= 10;

share|improve this answer

edited Mar 23 at 12:40

answered Mar 23 at 11:25

LppEddLppEdd

10.1k31749

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I am a rookie in computer programming, I was a bit ashamed to post my code here.
  
  – Aviv David Malka
  Mar 23 at 11:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @AvivDavidMalka do this, post the code you tried. Don't worry about it. We all were rookies. So that we can remove that "put on hold" thing.
  
  – LppEdd
  Mar 23 at 11:31
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  i was wondering if this could have been done by using while/for loops
  
  – Aviv David Malka
  Mar 23 at 11:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @AvivDavidMalka see updated answer. Is that acceptable?
  
  – LppEdd
  Mar 23 at 11:54
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Thanks a lot @LppEdd learnt a great deal^^
  
  – Aviv David Malka
  Mar 23 at 12:52
  

  
  
  
  

 | 
show 5 more comments

Your requirement seems reasonably clear to me.
Given a number

final int number = 5;

And a starting number

final int input = 54365;

The easiest way is to convert that number to a String

final int inputStr = String.valueOf(input);

Then, you can filter each char for it, and sum them

final int sum =
 inputStr.chars() // Get a Stream of ints, which represent the characters
 .map(Character::getNumericValue) // Convert a char to its numeric representation
 .filter(i -> i == number) // Filter for the designated number
 .sum(); // Sum all the filtered integers

Output: 10

---

Using the same approach, but with an old-style for loop

final int input = 54365;
final int inputStr = String.valueOf(input);
final int number = 5;
int sum = 0;

for (final char c : inputStr.toCharArray()) 
 final int n = Character.getNumericValue(c);

 if (n == number) 
 sum += number;
 

---

Your solution can work

int number = 5;
int input = 543655;
int sum = 0;

while (input > 0) 
 if (input % 10 == number) 
 sum += number;
 

 input /= 10;

share|improve this answer

edited Mar 23 at 12:40

answered Mar 23 at 11:25

LppEddLppEdd

10.1k31749

final int number = 5;

final int input = 54365;

final int inputStr = String.valueOf(input);

final int sum =
 inputStr.chars() // Get a Stream of ints, which represent the characters
 .map(Character::getNumericValue) // Convert a char to its numeric representation
 .filter(i -> i == number) // Filter for the designated number
 .sum(); // Sum all the filtered integers

final int input = 54365;
final int inputStr = String.valueOf(input);
final int number = 5;
int sum = 0;

for (final char c : inputStr.toCharArray()) 
 final int n = Character.getNumericValue(c);

 if (n == number) 
 sum += number;
 

int number = 5;
int input = 543655;
int sum = 0;

while (input > 0) 
 if (input % 10 == number) 
 sum += number;
 

 input /= 10;

share|improve this answer

edited Mar 23 at 12:40

answered Mar 23 at 11:25

LppEddLppEdd

10.1k31749

answered Mar 23 at 11:25

LppEddLppEdd

10.1k31749

answered Mar 23 at 11:25

LppEddLppEdd

10.1k31749