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Easy way to allow options only when other is present using CommandLineParserLibrary
When to use struct?Is there a way of setting a property once only in C#Implementing INotifyPropertyChanged - does a better way exist?SqlException from Entity Framework - New transaction is not allowed because there are other threads running in the sessionHow do I remedy the “The breakpoint will not currently be hit. No symbols have been loaded for this document.” warning?Why are C# 4 optional parameters defined on interface not enforced on implementing class?Why must we define both == and != in C#?Do HttpClient and HttpClientHandler have to be disposed?Why not inherit from List<T>?Restrict values of C# command-line-parser options to Integers
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I am trying to implement logic using this library:
I have the verb write, and options by this scheme:
write (-md [-p|-s] [-t]) | (-txt [-v]) - where '|' - means or (only -p OR -s is accepted (but not necessary as shown by '[]') when using -md)
Is there easy way to implement this? or should I split this to separate verbs?
c# command-line-parser
asked Mar 25 at 14:02
Borys FursovBorys Fursov
13313 bronze badges
add a comment |
I am trying to implement logic using this library:
I have the verb write, and options by this scheme:
write (-md [-p|-s] [-t]) | (-txt [-v]) - where '|' - means or (only -p OR -s is accepted (but not necessary as shown by '[]') when using -md)
Is there easy way to implement this? or should I split this to separate verbs?
c# command-line-parser
asked Mar 25 at 14:02
Borys FursovBorys Fursov
13313 bronze badges
add a comment |
I am trying to implement logic using this library:
I have the verb write, and options by this scheme:
write (-md [-p|-s] [-t]) | (-txt [-v]) - where '|' - means or (only -p OR -s is accepted (but not necessary as shown by '[]') when using -md)
Is there easy way to implement this? or should I split this to separate verbs?
c# command-line-parser
asked Mar 25 at 14:02
Borys FursovBorys Fursov
13313 bronze badges
I am trying to implement logic using this library:
I have the verb write, and options by this scheme:
write (-md [-p|-s] [-t]) | (-txt [-v]) - where '|' - means or (only -p OR -s is accepted (but not necessary as shown by '[]') when using -md)
Is there easy way to implement this? or should I split this to separate verbs?
c# command-line-parser
c# command-line-parser
asked Mar 25 at 14:02
Borys FursovBorys Fursov
13313 bronze badges
asked Mar 25 at 14:02
Borys FursovBorys Fursov
13313 bronze badges
asked Mar 25 at 14:02
Borys FursovBorys Fursov
13313 bronze badges
asked Mar 25 at 14:02
Borys FursovBorys Fursov
13313 bronze badges
asked Mar 25 at 14:02
Borys FursovBorys Fursov
13313 bronze badges
13313 bronze badges
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Sorry for answering own question but it would be helpful to someone else (source):
You can use use SetName argument while declaring OptionAttribute:
internal class Options
[Option("username", SetName = "auth")]
public string Username get; set;
[Option("password", SetName = "auth")]
public string Password get; set;
[Option("guestaccess", SetName = "guest")]
public bool GuestAccess get; set;
Now username and password can be used together, but guestaccess is alone within "guest" set, so it can not be used with options from other sets.
answered Mar 25 at 14:40
Borys FursovBorys Fursov
13313 bronze badges
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Sorry for answering own question but it would be helpful to someone else (source):
You can use use SetName argument while declaring OptionAttribute:
internal class Options
[Option("username", SetName = "auth")]
public string Username get; set;
[Option("password", SetName = "auth")]
public string Password get; set;
[Option("guestaccess", SetName = "guest")]
public bool GuestAccess get; set;
Now username and password can be used together, but guestaccess is alone within "guest" set, so it can not be used with options from other sets.
answered Mar 25 at 14:40
Borys FursovBorys Fursov
13313 bronze badges
add a comment |
Sorry for answering own question but it would be helpful to someone else (source):
You can use use SetName argument while declaring OptionAttribute:
internal class Options
[Option("username", SetName = "auth")]
public string Username get; set;
[Option("password", SetName = "auth")]
public string Password get; set;
[Option("guestaccess", SetName = "guest")]
public bool GuestAccess get; set;
Now username and password can be used together, but guestaccess is alone within "guest" set, so it can not be used with options from other sets.
answered Mar 25 at 14:40
Borys FursovBorys Fursov
13313 bronze badges
add a comment |
Sorry for answering own question but it would be helpful to someone else (source):
You can use use SetName argument while declaring OptionAttribute:
internal class Options
[Option("username", SetName = "auth")]
public string Username get; set;
[Option("password", SetName = "auth")]
public string Password get; set;
[Option("guestaccess", SetName = "guest")]
public bool GuestAccess get; set;
Now username and password can be used together, but guestaccess is alone within "guest" set, so it can not be used with options from other sets.
answered Mar 25 at 14:40
Borys FursovBorys Fursov
13313 bronze badges
Sorry for answering own question but it would be helpful to someone else (source):
You can use use SetName argument while declaring OptionAttribute:
internal class Options
[Option("username", SetName = "auth")]
public string Username get; set;
[Option("password", SetName = "auth")]
public string Password get; set;
[Option("guestaccess", SetName = "guest")]
public bool GuestAccess get; set;
Now username and password can be used together, but guestaccess is alone within "guest" set, so it can not be used with options from other sets.
answered Mar 25 at 14:40
Borys FursovBorys Fursov
13313 bronze badges
answered Mar 25 at 14:40
Borys FursovBorys Fursov
13313 bronze badges
answered Mar 25 at 14:40
Borys FursovBorys Fursov
13313 bronze badges
answered Mar 25 at 14:40
Borys FursovBorys Fursov
13313 bronze badges
13313 bronze badges
add a comment |
add a comment |
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