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fs.FileRead -> TypeError [ERR_INVALID_ARG_TYPE]: The “path” argument must be one of type string, Buffer, or URL. Received type undefined


How to show data from mysql in nodejs with a refresh rate.aac extension audio files are played on IETemplate literal trapped in a string variableNode.js fs.stat [TypeError: path must be a string] on passing BufferJest TypeError: Path must be a string. Received undefinedExpress req.body not WorkingCannot find module var http = require('http'), https = require('https'), fs = require('fs')YouTube API Error, Node.jsElectron-packager - The “path” argument must be of type string. Received type undefinedNode JS Promise TypeError: Cannot read property 'then' of undefined






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








0















function openFileDialog() 
dialog.showOpenDialog(win,
properties: ['openFile']
, filepath =>

if (filepath)
fs.writeFile('path.txt', filepath, function (err, data)
if (err) console.log(err);
);
scanFile(filepath)

)


function scanFile(filepath) filepath[0] == 'undefined') return;
console.log(filepath)
fs.readFile(filepath,"utf8", (err,data) => )



I tried to made electron music player app. As a first step is opening my file. When I open file, "TypeError [ERR_INVALID_ARG_TYPE]: The "path" argument must be one of type string, Buffer, or URL. Received type undefined" that error occured and error message showed that scanFile(filepath), fs.readFile(~~) caused error. How should I fix it?










share|improve this question






















  • What does: console.log(filepath) outputs? Because the error is clear, you're passing something that's not a string, buffer or URL.

    – Marcos Casagrande
    Mar 24 at 17:20











  • @MarcosCasagrande Ah That's just checking code. I forgot to erase. Thx :)

    – SunBathe
    Mar 25 at 3:01

















0















function openFileDialog() 
dialog.showOpenDialog(win,
properties: ['openFile']
, filepath =>

if (filepath)
fs.writeFile('path.txt', filepath, function (err, data)
if (err) console.log(err);
);
scanFile(filepath)

)


function scanFile(filepath) filepath[0] == 'undefined') return;
console.log(filepath)
fs.readFile(filepath,"utf8", (err,data) => )



I tried to made electron music player app. As a first step is opening my file. When I open file, "TypeError [ERR_INVALID_ARG_TYPE]: The "path" argument must be one of type string, Buffer, or URL. Received type undefined" that error occured and error message showed that scanFile(filepath), fs.readFile(~~) caused error. How should I fix it?










share|improve this question






















  • What does: console.log(filepath) outputs? Because the error is clear, you're passing something that's not a string, buffer or URL.

    – Marcos Casagrande
    Mar 24 at 17:20











  • @MarcosCasagrande Ah That's just checking code. I forgot to erase. Thx :)

    – SunBathe
    Mar 25 at 3:01













0












0








0








function openFileDialog() 
dialog.showOpenDialog(win,
properties: ['openFile']
, filepath =>

if (filepath)
fs.writeFile('path.txt', filepath, function (err, data)
if (err) console.log(err);
);
scanFile(filepath)

)


function scanFile(filepath) filepath[0] == 'undefined') return;
console.log(filepath)
fs.readFile(filepath,"utf8", (err,data) => )



I tried to made electron music player app. As a first step is opening my file. When I open file, "TypeError [ERR_INVALID_ARG_TYPE]: The "path" argument must be one of type string, Buffer, or URL. Received type undefined" that error occured and error message showed that scanFile(filepath), fs.readFile(~~) caused error. How should I fix it?










share|improve this question














function openFileDialog() 
dialog.showOpenDialog(win,
properties: ['openFile']
, filepath =>

if (filepath)
fs.writeFile('path.txt', filepath, function (err, data)
if (err) console.log(err);
);
scanFile(filepath)

)


function scanFile(filepath) filepath[0] == 'undefined') return;
console.log(filepath)
fs.readFile(filepath,"utf8", (err,data) => )



I tried to made electron music player app. As a first step is opening my file. When I open file, "TypeError [ERR_INVALID_ARG_TYPE]: The "path" argument must be one of type string, Buffer, or URL. Received type undefined" that error occured and error message showed that scanFile(filepath), fs.readFile(~~) caused error. How should I fix it?







javascript node.js electron fs






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 24 at 17:17









SunBatheSunBathe

2916




2916












  • What does: console.log(filepath) outputs? Because the error is clear, you're passing something that's not a string, buffer or URL.

    – Marcos Casagrande
    Mar 24 at 17:20











  • @MarcosCasagrande Ah That's just checking code. I forgot to erase. Thx :)

    – SunBathe
    Mar 25 at 3:01

















  • What does: console.log(filepath) outputs? Because the error is clear, you're passing something that's not a string, buffer or URL.

    – Marcos Casagrande
    Mar 24 at 17:20











  • @MarcosCasagrande Ah That's just checking code. I forgot to erase. Thx :)

    – SunBathe
    Mar 25 at 3:01
















What does: console.log(filepath) outputs? Because the error is clear, you're passing something that's not a string, buffer or URL.

– Marcos Casagrande
Mar 24 at 17:20





What does: console.log(filepath) outputs? Because the error is clear, you're passing something that's not a string, buffer or URL.

– Marcos Casagrande
Mar 24 at 17:20













@MarcosCasagrande Ah That's just checking code. I forgot to erase. Thx :)

– SunBathe
Mar 25 at 3:01





@MarcosCasagrande Ah That's just checking code. I forgot to erase. Thx :)

– SunBathe
Mar 25 at 3:01












1 Answer
1






active

oldest

votes


















1














The first line of scanFile reads:



if(!filepath || filepath[0] == 'undefined') return;



This indicates to me that filepath is an array, not a string (or Buffer or URL). Check the output of the console.log statement to see if this is the case. Since the if statement is checking for filepath[0], I'd start there and update the code to read fs.readFile(filepath[0],"utf8", (err,data) => {, since the if statement implies that filepath[0] is the value you should be using






share|improve this answer























  • It worked what I thought. Thank you!

    – SunBathe
    Mar 25 at 3:05











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1 Answer
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active

oldest

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active

oldest

votes









1














The first line of scanFile reads:



if(!filepath || filepath[0] == 'undefined') return;



This indicates to me that filepath is an array, not a string (or Buffer or URL). Check the output of the console.log statement to see if this is the case. Since the if statement is checking for filepath[0], I'd start there and update the code to read fs.readFile(filepath[0],"utf8", (err,data) => {, since the if statement implies that filepath[0] is the value you should be using






share|improve this answer























  • It worked what I thought. Thank you!

    – SunBathe
    Mar 25 at 3:05















1














The first line of scanFile reads:



if(!filepath || filepath[0] == 'undefined') return;



This indicates to me that filepath is an array, not a string (or Buffer or URL). Check the output of the console.log statement to see if this is the case. Since the if statement is checking for filepath[0], I'd start there and update the code to read fs.readFile(filepath[0],"utf8", (err,data) => {, since the if statement implies that filepath[0] is the value you should be using






share|improve this answer























  • It worked what I thought. Thank you!

    – SunBathe
    Mar 25 at 3:05













1












1








1







The first line of scanFile reads:



if(!filepath || filepath[0] == 'undefined') return;



This indicates to me that filepath is an array, not a string (or Buffer or URL). Check the output of the console.log statement to see if this is the case. Since the if statement is checking for filepath[0], I'd start there and update the code to read fs.readFile(filepath[0],"utf8", (err,data) => {, since the if statement implies that filepath[0] is the value you should be using






share|improve this answer













The first line of scanFile reads:



if(!filepath || filepath[0] == 'undefined') return;



This indicates to me that filepath is an array, not a string (or Buffer or URL). Check the output of the console.log statement to see if this is the case. Since the if statement is checking for filepath[0], I'd start there and update the code to read fs.readFile(filepath[0],"utf8", (err,data) => {, since the if statement implies that filepath[0] is the value you should be using







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 24 at 17:32









djherudjheru

2,02211113




2,02211113












  • It worked what I thought. Thank you!

    – SunBathe
    Mar 25 at 3:05

















  • It worked what I thought. Thank you!

    – SunBathe
    Mar 25 at 3:05
















It worked what I thought. Thank you!

– SunBathe
Mar 25 at 3:05





It worked what I thought. Thank you!

– SunBathe
Mar 25 at 3:05



















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