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fs.FileRead -> TypeError [ERR_INVALID_ARG_TYPE]: The “path” argument must be one of type string, Buffer, or URL. Received type undefined
How to show data from mysql in nodejs with a refresh rate.aac extension audio files are played on IETemplate literal trapped in a string variableNode.js fs.stat [TypeError: path must be a string] on passing BufferJest TypeError: Path must be a string. Received undefinedExpress req.body not WorkingCannot find module var http = require('http'), https = require('https'), fs = require('fs')YouTube API Error, Node.jsElectron-packager - The “path” argument must be of type string. Received type undefinedNode JS Promise TypeError: Cannot read property 'then' of undefined
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
function openFileDialog()
dialog.showOpenDialog(win,
properties: ['openFile']
, filepath =>
if (filepath)
fs.writeFile('path.txt', filepath, function (err, data)
if (err) console.log(err);
);
scanFile(filepath)
)
function scanFile(filepath) filepath[0] == 'undefined') return;
console.log(filepath)
fs.readFile(filepath,"utf8", (err,data) => )
I tried to made electron music player app. As a first step is opening my file. When I open file, "TypeError [ERR_INVALID_ARG_TYPE]: The "path" argument must be one of type string, Buffer, or URL. Received type undefined" that error occured and error message showed that scanFile(filepath), fs.readFile(~~) caused error. How should I fix it?
javascript node.js electron fs
add a comment |
function openFileDialog()
dialog.showOpenDialog(win,
properties: ['openFile']
, filepath =>
if (filepath)
fs.writeFile('path.txt', filepath, function (err, data)
if (err) console.log(err);
);
scanFile(filepath)
)
function scanFile(filepath) filepath[0] == 'undefined') return;
console.log(filepath)
fs.readFile(filepath,"utf8", (err,data) => )
I tried to made electron music player app. As a first step is opening my file. When I open file, "TypeError [ERR_INVALID_ARG_TYPE]: The "path" argument must be one of type string, Buffer, or URL. Received type undefined" that error occured and error message showed that scanFile(filepath), fs.readFile(~~) caused error. How should I fix it?
javascript node.js electron fs
What does:console.log(filepath)
outputs? Because the error is clear, you're passing something that's not a string, buffer or URL.
– Marcos Casagrande
Mar 24 at 17:20
@MarcosCasagrande Ah That's just checking code. I forgot to erase. Thx :)
– SunBathe
Mar 25 at 3:01
add a comment |
function openFileDialog()
dialog.showOpenDialog(win,
properties: ['openFile']
, filepath =>
if (filepath)
fs.writeFile('path.txt', filepath, function (err, data)
if (err) console.log(err);
);
scanFile(filepath)
)
function scanFile(filepath) filepath[0] == 'undefined') return;
console.log(filepath)
fs.readFile(filepath,"utf8", (err,data) => )
I tried to made electron music player app. As a first step is opening my file. When I open file, "TypeError [ERR_INVALID_ARG_TYPE]: The "path" argument must be one of type string, Buffer, or URL. Received type undefined" that error occured and error message showed that scanFile(filepath), fs.readFile(~~) caused error. How should I fix it?
javascript node.js electron fs
function openFileDialog()
dialog.showOpenDialog(win,
properties: ['openFile']
, filepath =>
if (filepath)
fs.writeFile('path.txt', filepath, function (err, data)
if (err) console.log(err);
);
scanFile(filepath)
)
function scanFile(filepath) filepath[0] == 'undefined') return;
console.log(filepath)
fs.readFile(filepath,"utf8", (err,data) => )
I tried to made electron music player app. As a first step is opening my file. When I open file, "TypeError [ERR_INVALID_ARG_TYPE]: The "path" argument must be one of type string, Buffer, or URL. Received type undefined" that error occured and error message showed that scanFile(filepath), fs.readFile(~~) caused error. How should I fix it?
javascript node.js electron fs
javascript node.js electron fs
asked Mar 24 at 17:17
SunBatheSunBathe
2916
2916
What does:console.log(filepath)
outputs? Because the error is clear, you're passing something that's not a string, buffer or URL.
– Marcos Casagrande
Mar 24 at 17:20
@MarcosCasagrande Ah That's just checking code. I forgot to erase. Thx :)
– SunBathe
Mar 25 at 3:01
add a comment |
What does:console.log(filepath)
outputs? Because the error is clear, you're passing something that's not a string, buffer or URL.
– Marcos Casagrande
Mar 24 at 17:20
@MarcosCasagrande Ah That's just checking code. I forgot to erase. Thx :)
– SunBathe
Mar 25 at 3:01
What does:
console.log(filepath)
outputs? Because the error is clear, you're passing something that's not a string, buffer or URL.– Marcos Casagrande
Mar 24 at 17:20
What does:
console.log(filepath)
outputs? Because the error is clear, you're passing something that's not a string, buffer or URL.– Marcos Casagrande
Mar 24 at 17:20
@MarcosCasagrande Ah That's just checking code. I forgot to erase. Thx :)
– SunBathe
Mar 25 at 3:01
@MarcosCasagrande Ah That's just checking code. I forgot to erase. Thx :)
– SunBathe
Mar 25 at 3:01
add a comment |
1 Answer
1
active
oldest
votes
The first line of scanFile
reads:
if(!filepath || filepath[0] == 'undefined') return;
This indicates to me that filepath
is an array, not a string (or Buffer or URL). Check the output of the console.log
statement to see if this is the case. Since the if
statement is checking for filepath[0]
, I'd start there and update the code to read fs.readFile(filepath[0],"utf8", (err,data) => {
, since the if
statement implies that filepath[0
] is the value you should be using
It worked what I thought. Thank you!
– SunBathe
Mar 25 at 3:05
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The first line of scanFile
reads:
if(!filepath || filepath[0] == 'undefined') return;
This indicates to me that filepath
is an array, not a string (or Buffer or URL). Check the output of the console.log
statement to see if this is the case. Since the if
statement is checking for filepath[0]
, I'd start there and update the code to read fs.readFile(filepath[0],"utf8", (err,data) => {
, since the if
statement implies that filepath[0
] is the value you should be using
It worked what I thought. Thank you!
– SunBathe
Mar 25 at 3:05
add a comment |
The first line of scanFile
reads:
if(!filepath || filepath[0] == 'undefined') return;
This indicates to me that filepath
is an array, not a string (or Buffer or URL). Check the output of the console.log
statement to see if this is the case. Since the if
statement is checking for filepath[0]
, I'd start there and update the code to read fs.readFile(filepath[0],"utf8", (err,data) => {
, since the if
statement implies that filepath[0
] is the value you should be using
It worked what I thought. Thank you!
– SunBathe
Mar 25 at 3:05
add a comment |
The first line of scanFile
reads:
if(!filepath || filepath[0] == 'undefined') return;
This indicates to me that filepath
is an array, not a string (or Buffer or URL). Check the output of the console.log
statement to see if this is the case. Since the if
statement is checking for filepath[0]
, I'd start there and update the code to read fs.readFile(filepath[0],"utf8", (err,data) => {
, since the if
statement implies that filepath[0
] is the value you should be using
The first line of scanFile
reads:
if(!filepath || filepath[0] == 'undefined') return;
This indicates to me that filepath
is an array, not a string (or Buffer or URL). Check the output of the console.log
statement to see if this is the case. Since the if
statement is checking for filepath[0]
, I'd start there and update the code to read fs.readFile(filepath[0],"utf8", (err,data) => {
, since the if
statement implies that filepath[0
] is the value you should be using
answered Mar 24 at 17:32
djherudjheru
2,02211113
2,02211113
It worked what I thought. Thank you!
– SunBathe
Mar 25 at 3:05
add a comment |
It worked what I thought. Thank you!
– SunBathe
Mar 25 at 3:05
It worked what I thought. Thank you!
– SunBathe
Mar 25 at 3:05
It worked what I thought. Thank you!
– SunBathe
Mar 25 at 3:05
add a comment |
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What does:
console.log(filepath)
outputs? Because the error is clear, you're passing something that's not a string, buffer or URL.– Marcos Casagrande
Mar 24 at 17:20
@MarcosCasagrande Ah That's just checking code. I forgot to erase. Thx :)
– SunBathe
Mar 25 at 3:01