Styjun

English word for "product of tinkering"

Character descriptions

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0

I have several sub folders in a directory (dir.1 dir.2 dir.3 etc) containing files (p.dat and c.dat) from which I want to extract part of the content to a.dat. How can I adjust my directory path to read p.dat and c.dat in all the sub directories, serially?

I set dir=dir.* (where * indicate the series)

#!/bin/sh

for dir in `ls | grep dir`

do
 cd $dir
 sed -n '1p' p.dat | awk 'printf("%15.3f",(($2-$1)/2+$1)*10-200)' >> ../all.dat
 sed -n '2p' p.dat | awk 'printf("%15.3f",(($2-$1)/2+$1)*10-200)' >> ../all.dat
 outkey c.dat >> ../a.dat
 cd ..
done
sort all.dat -o temp.dat
mv temp.dat a.dat
#more a.dat

bash

share|improve this question

edited Mar 25 at 9:20

Dominique

2,81552147

asked Mar 24 at 17:15

geomarinegeomarine

63

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  for dir in dir*
  
  – Cyrus
  Mar 24 at 17:20
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  ...and all the bugs that shellcheck.net finds, which explicitly includes both quoting your expansion -- cd "$dir" is necessary to correctly handle directory names with characters in IFS or which could be parsed as globs -- and checking the exit status of cd (cd "$dir" || continue). Much more efficient, btw, to put >../all.dat on the same line immediately after the done; then everything in the loop appends to that file, opening it just once rather than re-opening it over and over.
  
  – Charles Duffy
  Mar 24 at 17:32
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @CharlesDuffy, thanks for your comment. Do you suggest cd "$dir" || continue to replace cd $dir; and >../all.dat immediately after done (same line)? when I tried this, this result shows 'cd: $dir: no such file or directory'.
  
  – geomarine
  Mar 24 at 18:12
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  That error message makes it look like you used the wrong kind of quotes. cd "$dir" || continue (the correct form) is not cd '$dir' || continue.
  
  – Charles Duffy
  Mar 24 at 18:14
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  It's not clear from your last comment how you applied Cyrus's advice. It should just be for dir in dir*; do, with no ls or grep anywhere. See Why you shouldn't parse the output of ls.
  
  – Charles Duffy
  Mar 24 at 18:15
  
  

  
  
  
  

 | 
show 7 more comments

0

I have several sub folders in a directory (dir.1 dir.2 dir.3 etc) containing files (p.dat and c.dat) from which I want to extract part of the content to a.dat. How can I adjust my directory path to read p.dat and c.dat in all the sub directories, serially?

I set dir=dir.* (where * indicate the series)

#!/bin/sh

for dir in `ls | grep dir`

do
 cd $dir
 sed -n '1p' p.dat | awk 'printf("%15.3f",(($2-$1)/2+$1)*10-200)' >> ../all.dat
 sed -n '2p' p.dat | awk 'printf("%15.3f",(($2-$1)/2+$1)*10-200)' >> ../all.dat
 outkey c.dat >> ../a.dat
 cd ..
done
sort all.dat -o temp.dat
mv temp.dat a.dat
#more a.dat

bash

share|improve this question

edited Mar 25 at 9:20

Dominique

2,81552147

asked Mar 24 at 17:15

geomarinegeomarine

63

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  for dir in dir*
  
  – Cyrus
  Mar 24 at 17:20
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  ...and all the bugs that shellcheck.net finds, which explicitly includes both quoting your expansion -- cd "$dir" is necessary to correctly handle directory names with characters in IFS or which could be parsed as globs -- and checking the exit status of cd (cd "$dir" || continue). Much more efficient, btw, to put >../all.dat on the same line immediately after the done; then everything in the loop appends to that file, opening it just once rather than re-opening it over and over.
  
  – Charles Duffy
  Mar 24 at 17:32
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @CharlesDuffy, thanks for your comment. Do you suggest cd "$dir" || continue to replace cd $dir; and >../all.dat immediately after done (same line)? when I tried this, this result shows 'cd: $dir: no such file or directory'.
  
  – geomarine
  Mar 24 at 18:12
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  That error message makes it look like you used the wrong kind of quotes. cd "$dir" || continue (the correct form) is not cd '$dir' || continue.
  
  – Charles Duffy
  Mar 24 at 18:14
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  It's not clear from your last comment how you applied Cyrus's advice. It should just be for dir in dir*; do, with no ls or grep anywhere. See Why you shouldn't parse the output of ls.
  
  – Charles Duffy
  Mar 24 at 18:15
  
  

  
  
  
  

 | 
show 7 more comments

I have several sub folders in a directory (dir.1 dir.2 dir.3 etc) containing files (p.dat and c.dat) from which I want to extract part of the content to a.dat. How can I adjust my directory path to read p.dat and c.dat in all the sub directories, serially?

I set dir=dir.* (where * indicate the series)

#!/bin/sh

for dir in `ls | grep dir`

do
 cd $dir
 sed -n '1p' p.dat | awk 'printf("%15.3f",(($2-$1)/2+$1)*10-200)' >> ../all.dat
 sed -n '2p' p.dat | awk 'printf("%15.3f",(($2-$1)/2+$1)*10-200)' >> ../all.dat
 outkey c.dat >> ../a.dat
 cd ..
done
sort all.dat -o temp.dat
mv temp.dat a.dat
#more a.dat

bash

share|improve this question

edited Mar 25 at 9:20

Dominique

2,81552147

asked Mar 24 at 17:15

geomarinegeomarine

63

#!/bin/sh

for dir in `ls | grep dir`

do
 cd $dir
 sed -n '1p' p.dat | awk 'printf("%15.3f",(($2-$1)/2+$1)*10-200)' >> ../all.dat
 sed -n '2p' p.dat | awk 'printf("%15.3f",(($2-$1)/2+$1)*10-200)' >> ../all.dat
 outkey c.dat >> ../a.dat
 cd ..
done
sort all.dat -o temp.dat
mv temp.dat a.dat
#more a.dat

share|improve this question

edited Mar 25 at 9:20

Dominique

2,81552147

asked Mar 24 at 17:15

geomarinegeomarine

63

share|improve this question

edited Mar 25 at 9:20

Dominique

2,81552147

asked Mar 24 at 17:15

geomarinegeomarine

63

edited Mar 25 at 9:20

Dominique

2,81552147

edited Mar 25 at 9:20

Dominique

2,81552147

asked Mar 24 at 17:15

geomarinegeomarine

63

asked Mar 24 at 17:15

geomarinegeomarine

63