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Abaqus C++ API syntax

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2

I am new to Abaqus C++ API and have question about the syntax.

db_Odb& odb = openOdb("file.odb");
odb_Step& step = odb.steps()["Step-1"];

odb_Instance& instance = 
 odb.rootAssembly().instances()["PART-1-1"];

There are several instances that the syntax is something like odb.steps()["Step-1"].

My question is in odb.steps()["Step-1"]:

• is odb an object?


• is steps() a method of the object?


• what is steps()["str"]? I did not see that in regular C++ syntax.

c++ abaqus finite-element-analysis

share|improve this question

asked Mar 26 at 18:40

dfrw4r3dfrw4r3

1533 bronze badges

add a comment | 

2

I am new to Abaqus C++ API and have question about the syntax.

db_Odb& odb = openOdb("file.odb");
odb_Step& step = odb.steps()["Step-1"];

odb_Instance& instance = 
 odb.rootAssembly().instances()["PART-1-1"];

There are several instances that the syntax is something like odb.steps()["Step-1"].

My question is in odb.steps()["Step-1"]:

• is odb an object?


• is steps() a method of the object?


• what is steps()["str"]? I did not see that in regular C++ syntax.

c++ abaqus finite-element-analysis

share|improve this question

asked Mar 26 at 18:40

dfrw4r3dfrw4r3

1533 bronze badges

add a comment | 

I am new to Abaqus C++ API and have question about the syntax.

db_Odb& odb = openOdb("file.odb");
odb_Step& step = odb.steps()["Step-1"];

odb_Instance& instance = 
 odb.rootAssembly().instances()["PART-1-1"];

There are several instances that the syntax is something like odb.steps()["Step-1"].

My question is in odb.steps()["Step-1"]:

• is odb an object?


• is steps() a method of the object?


• what is steps()["str"]? I did not see that in regular C++ syntax.

c++ abaqus finite-element-analysis

share|improve this question

asked Mar 26 at 18:40

dfrw4r3dfrw4r3

1533 bronze badges

db_Odb& odb = openOdb("file.odb");
odb_Step& step = odb.steps()["Step-1"];

odb_Instance& instance = 
 odb.rootAssembly().instances()["PART-1-1"];

share|improve this question

asked Mar 26 at 18:40

dfrw4r3dfrw4r3

1533 bronze badges

share|improve this question

asked Mar 26 at 18:40

dfrw4r3dfrw4r3

1533 bronze badges

asked Mar 26 at 18:40

dfrw4r3dfrw4r3

1533 bronze badges

asked Mar 26 at 18:40

dfrw4r3dfrw4r3

1533 bronze badges

1 Answer
1

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0

To answer your questions: Yes, yes, and index operator. It is all standard C++ syntax.

Without knowing the library in question at all, the class might look something like this:

class db_Odb

public:
 std::unordered_map< std::string, odb_Step >& steps();
 // ...
;

So odb.steps() returns an indexable object (here I've used a hash map), and then we look up the key in it by appending ["Step-1"], which calls the map's index operator and returns a reference to a single odb_Step instance in that map.

share|improve this answer

edited Mar 26 at 19:01

answered Mar 26 at 18:46

metalmetal

3,7692323 silver badges3939 bronze badges

add a comment | 

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0

To answer your questions: Yes, yes, and index operator. It is all standard C++ syntax.

Without knowing the library in question at all, the class might look something like this:

class db_Odb

public:
 std::unordered_map< std::string, odb_Step >& steps();
 // ...
;

So odb.steps() returns an indexable object (here I've used a hash map), and then we look up the key in it by appending ["Step-1"], which calls the map's index operator and returns a reference to a single odb_Step instance in that map.

share|improve this answer

edited Mar 26 at 19:01

answered Mar 26 at 18:46

metalmetal

3,7692323 silver badges3939 bronze badges

add a comment | 

0

To answer your questions: Yes, yes, and index operator. It is all standard C++ syntax.

Without knowing the library in question at all, the class might look something like this:

class db_Odb

public:
 std::unordered_map< std::string, odb_Step >& steps();
 // ...
;

So odb.steps() returns an indexable object (here I've used a hash map), and then we look up the key in it by appending ["Step-1"], which calls the map's index operator and returns a reference to a single odb_Step instance in that map.

share|improve this answer

edited Mar 26 at 19:01

answered Mar 26 at 18:46

metalmetal

3,7692323 silver badges3939 bronze badges

add a comment | 

To answer your questions: Yes, yes, and index operator. It is all standard C++ syntax.

Without knowing the library in question at all, the class might look something like this:

class db_Odb

public:
 std::unordered_map< std::string, odb_Step >& steps();
 // ...
;

So odb.steps() returns an indexable object (here I've used a hash map), and then we look up the key in it by appending ["Step-1"], which calls the map's index operator and returns a reference to a single odb_Step instance in that map.

share|improve this answer

edited Mar 26 at 19:01

answered Mar 26 at 18:46

metalmetal

3,7692323 silver badges3939 bronze badges

class db_Odb

public:
 std::unordered_map< std::string, odb_Step >& steps();
 // ...
;

share|improve this answer

edited Mar 26 at 19:01

answered Mar 26 at 18:46

metalmetal

3,7692323 silver badges3939 bronze badges

answered Mar 26 at 18:46

metalmetal

3,7692323 silver badges3939 bronze badges

answered Mar 26 at 18:46

metalmetal

3,7692323 silver badges3939 bronze badges