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How to Change Color of Line graphs in Statsmodel Decomposition Plots


How can I do a line break (line continuation) in Python?How do you change the size of figures drawn with matplotlib?Plot two graphs in same plot in RHow to read a file line-by-line into a list?How to put the legend out of the plotHaving line color vary with data index for line graph in matplotlib?Plotting line(color, attribue defined) graph using pandasHow to change colors of points in Python's ggplotAnimated plot with different color for every data pointPandas Series not plotting to timeseries chart






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1















The default color of the seasonal decomposition graphs is a light blue.
1. How can you change the colors so that each of the lines is a different color?
2. If each plot can not have a separate color, how would I change all of the colors to say red?



I've tried adding arguments to decomposition.plot(color = 'red')
and searching the documentation for clues.



import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
# I want 7 days of 24 hours with 60 minutes each
periods = 7 * 24 * 60
tidx = pd.date_range('2016-07-01', periods=periods, freq='D')
np.random.seed([3,1415])

# This will pick a number of normally distributed random numbers
# where the number is specified by periods
data = np.random.randn(periods)

ts = pd.Series(data=data, index=tidx, name='TimeSeries')

decomposition = sm.tsa.seasonal_decompose(ts, model ='additive')
fig = decomposition.plot()
plt.show()


A decomposition plot in which each graph is a different color.
enter image description here










share|improve this question




























    1















    The default color of the seasonal decomposition graphs is a light blue.
    1. How can you change the colors so that each of the lines is a different color?
    2. If each plot can not have a separate color, how would I change all of the colors to say red?



    I've tried adding arguments to decomposition.plot(color = 'red')
    and searching the documentation for clues.



    import pandas as pd
    import numpy as np
    import matplotlib.pyplot as plt
    # I want 7 days of 24 hours with 60 minutes each
    periods = 7 * 24 * 60
    tidx = pd.date_range('2016-07-01', periods=periods, freq='D')
    np.random.seed([3,1415])

    # This will pick a number of normally distributed random numbers
    # where the number is specified by periods
    data = np.random.randn(periods)

    ts = pd.Series(data=data, index=tidx, name='TimeSeries')

    decomposition = sm.tsa.seasonal_decompose(ts, model ='additive')
    fig = decomposition.plot()
    plt.show()


    A decomposition plot in which each graph is a different color.
    enter image description here










    share|improve this question
























      1












      1








      1








      The default color of the seasonal decomposition graphs is a light blue.
      1. How can you change the colors so that each of the lines is a different color?
      2. If each plot can not have a separate color, how would I change all of the colors to say red?



      I've tried adding arguments to decomposition.plot(color = 'red')
      and searching the documentation for clues.



      import pandas as pd
      import numpy as np
      import matplotlib.pyplot as plt
      # I want 7 days of 24 hours with 60 minutes each
      periods = 7 * 24 * 60
      tidx = pd.date_range('2016-07-01', periods=periods, freq='D')
      np.random.seed([3,1415])

      # This will pick a number of normally distributed random numbers
      # where the number is specified by periods
      data = np.random.randn(periods)

      ts = pd.Series(data=data, index=tidx, name='TimeSeries')

      decomposition = sm.tsa.seasonal_decompose(ts, model ='additive')
      fig = decomposition.plot()
      plt.show()


      A decomposition plot in which each graph is a different color.
      enter image description here










      share|improve this question














      The default color of the seasonal decomposition graphs is a light blue.
      1. How can you change the colors so that each of the lines is a different color?
      2. If each plot can not have a separate color, how would I change all of the colors to say red?



      I've tried adding arguments to decomposition.plot(color = 'red')
      and searching the documentation for clues.



      import pandas as pd
      import numpy as np
      import matplotlib.pyplot as plt
      # I want 7 days of 24 hours with 60 minutes each
      periods = 7 * 24 * 60
      tidx = pd.date_range('2016-07-01', periods=periods, freq='D')
      np.random.seed([3,1415])

      # This will pick a number of normally distributed random numbers
      # where the number is specified by periods
      data = np.random.randn(periods)

      ts = pd.Series(data=data, index=tidx, name='TimeSeries')

      decomposition = sm.tsa.seasonal_decompose(ts, model ='additive')
      fig = decomposition.plot()
      plt.show()


      A decomposition plot in which each graph is a different color.
      enter image description here







      python plot statsmodels






      share|improve this question













      share|improve this question











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      asked Mar 26 at 4:48









      rer49rer49

      1088 bronze badges




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          1














          The decomposition object in the code you posted uses pandas in the plotting method. I don't see a way of passing colors directly to the plot method, and it doesn't take **kwargs.



          A work around would be to call the pandas plotting code directly on the object:



          fig, axes = plt.subplots(4, 1, sharex=True)

          decomposition.observed.plot(ax=axes[0], legend=False, color='r')
          axes[0].set_ylabel('Observed')
          decomposition.trend.plot(ax=axes[1], legend=False, color='g')
          axes[1].set_ylabel('Trend')
          decomposition.seasonal.plot(ax=axes[2], legend=False)
          axes[2].set_ylabel('Seasonal')
          decomposition.resid.plot(ax=axes[3], legend=False, color='k')
          axes[3].set_ylabel('Residual')


          enter image description here






          share|improve this answer






















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            active

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            active

            oldest

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            1














            The decomposition object in the code you posted uses pandas in the plotting method. I don't see a way of passing colors directly to the plot method, and it doesn't take **kwargs.



            A work around would be to call the pandas plotting code directly on the object:



            fig, axes = plt.subplots(4, 1, sharex=True)

            decomposition.observed.plot(ax=axes[0], legend=False, color='r')
            axes[0].set_ylabel('Observed')
            decomposition.trend.plot(ax=axes[1], legend=False, color='g')
            axes[1].set_ylabel('Trend')
            decomposition.seasonal.plot(ax=axes[2], legend=False)
            axes[2].set_ylabel('Seasonal')
            decomposition.resid.plot(ax=axes[3], legend=False, color='k')
            axes[3].set_ylabel('Residual')


            enter image description here






            share|improve this answer



























              1














              The decomposition object in the code you posted uses pandas in the plotting method. I don't see a way of passing colors directly to the plot method, and it doesn't take **kwargs.



              A work around would be to call the pandas plotting code directly on the object:



              fig, axes = plt.subplots(4, 1, sharex=True)

              decomposition.observed.plot(ax=axes[0], legend=False, color='r')
              axes[0].set_ylabel('Observed')
              decomposition.trend.plot(ax=axes[1], legend=False, color='g')
              axes[1].set_ylabel('Trend')
              decomposition.seasonal.plot(ax=axes[2], legend=False)
              axes[2].set_ylabel('Seasonal')
              decomposition.resid.plot(ax=axes[3], legend=False, color='k')
              axes[3].set_ylabel('Residual')


              enter image description here






              share|improve this answer

























                1












                1








                1







                The decomposition object in the code you posted uses pandas in the plotting method. I don't see a way of passing colors directly to the plot method, and it doesn't take **kwargs.



                A work around would be to call the pandas plotting code directly on the object:



                fig, axes = plt.subplots(4, 1, sharex=True)

                decomposition.observed.plot(ax=axes[0], legend=False, color='r')
                axes[0].set_ylabel('Observed')
                decomposition.trend.plot(ax=axes[1], legend=False, color='g')
                axes[1].set_ylabel('Trend')
                decomposition.seasonal.plot(ax=axes[2], legend=False)
                axes[2].set_ylabel('Seasonal')
                decomposition.resid.plot(ax=axes[3], legend=False, color='k')
                axes[3].set_ylabel('Residual')


                enter image description here






                share|improve this answer













                The decomposition object in the code you posted uses pandas in the plotting method. I don't see a way of passing colors directly to the plot method, and it doesn't take **kwargs.



                A work around would be to call the pandas plotting code directly on the object:



                fig, axes = plt.subplots(4, 1, sharex=True)

                decomposition.observed.plot(ax=axes[0], legend=False, color='r')
                axes[0].set_ylabel('Observed')
                decomposition.trend.plot(ax=axes[1], legend=False, color='g')
                axes[1].set_ylabel('Trend')
                decomposition.seasonal.plot(ax=axes[2], legend=False)
                axes[2].set_ylabel('Seasonal')
                decomposition.resid.plot(ax=axes[3], legend=False, color='k')
                axes[3].set_ylabel('Residual')


                enter image description here







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 26 at 5:11









                johnchasejohnchase

                5,3851 gold badge21 silver badges37 bronze badges




                5,3851 gold badge21 silver badges37 bronze badges


















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