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How to print the full source code of URL? - in this particular case it prints only fraction

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-1

I have already retrieved source codes from some sites for my app and have used the function:

let usedURLString = "my http link"



guard let usedURL = URL(string: usedURLString) else 
 // if URL is not valid:
 print("Error: (usedURLString) doesn't seem to be a valid URL")
 return 
do 
 // getting the HTML sourcecode

 let sourceCodeHTML = try String(contentsOf: usedURL, encoding: String.Encoding.windowsCP1254)

 print(sourceCodeHTML)
 catch 
 print("there was an error: (error)")

Now I am struggling with the problem that I can't retrieve the full source code from a site that says it needs "This page needs javascript to run". When using the function above it prints only a small and weird fraction of html string. Can anyone help me with the issue? I have searched in many places but haven't found any solution to the issue.

ios swift

share|improve this question

asked Mar 26 at 19:44

Timothy StokarskiTimothy Stokarski

1

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  Well, for one thing, String(contentsOf: usedURL) is absolutely not the correct way to fetch the HTML from a web page. You are networking, use URLSession. That's what it's for.
  
  – matt
  Mar 26 at 19:48
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Could you please provide the link from which you want to retrieve the source code? I delete encoding: String.Encoding.windowsCP1254 and it works for me to retrieve something. Maybe you could change the String.Encoding type.
  
  – Yaming Lin
  Mar 26 at 20:09
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I have already tried changing the encoding type with no success. here is the link: olx.pl/nieruchomosci/mieszkania/sprzedaz/…
  
  – Timothy Stokarski
  Mar 26 at 21:00
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I tried your code and it works well for me. I did get the source HTML code. Could you please show your error message?
  
  – Yaming Lin
  Mar 27 at 1:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  There is no error, yet although the console prints source HTML code it is only a fraction of it. If I open source code via chrome on my computer it shows the full, very long code that I need. That is the whole issue
  
  – Timothy Stokarski
  Mar 27 at 9:26
  

  
  
  
  

add a comment | 

-1

I have already retrieved source codes from some sites for my app and have used the function:

let usedURLString = "my http link"



guard let usedURL = URL(string: usedURLString) else 
 // if URL is not valid:
 print("Error: (usedURLString) doesn't seem to be a valid URL")
 return 
do 
 // getting the HTML sourcecode

 let sourceCodeHTML = try String(contentsOf: usedURL, encoding: String.Encoding.windowsCP1254)

 print(sourceCodeHTML)
 catch 
 print("there was an error: (error)")

Now I am struggling with the problem that I can't retrieve the full source code from a site that says it needs "This page needs javascript to run". When using the function above it prints only a small and weird fraction of html string. Can anyone help me with the issue? I have searched in many places but haven't found any solution to the issue.

ios swift

share|improve this question

asked Mar 26 at 19:44

Timothy StokarskiTimothy Stokarski

1

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  Well, for one thing, String(contentsOf: usedURL) is absolutely not the correct way to fetch the HTML from a web page. You are networking, use URLSession. That's what it's for.
  
  – matt
  Mar 26 at 19:48
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Could you please provide the link from which you want to retrieve the source code? I delete encoding: String.Encoding.windowsCP1254 and it works for me to retrieve something. Maybe you could change the String.Encoding type.
  
  – Yaming Lin
  Mar 26 at 20:09
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I have already tried changing the encoding type with no success. here is the link: olx.pl/nieruchomosci/mieszkania/sprzedaz/…
  
  – Timothy Stokarski
  Mar 26 at 21:00
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I tried your code and it works well for me. I did get the source HTML code. Could you please show your error message?
  
  – Yaming Lin
  Mar 27 at 1:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  There is no error, yet although the console prints source HTML code it is only a fraction of it. If I open source code via chrome on my computer it shows the full, very long code that I need. That is the whole issue
  
  – Timothy Stokarski
  Mar 27 at 9:26
  

  
  
  
  

add a comment | 

I have already retrieved source codes from some sites for my app and have used the function:

let usedURLString = "my http link"



guard let usedURL = URL(string: usedURLString) else 
 // if URL is not valid:
 print("Error: (usedURLString) doesn't seem to be a valid URL")
 return 
do 
 // getting the HTML sourcecode

 let sourceCodeHTML = try String(contentsOf: usedURL, encoding: String.Encoding.windowsCP1254)

 print(sourceCodeHTML)
 catch 
 print("there was an error: (error)")

Now I am struggling with the problem that I can't retrieve the full source code from a site that says it needs "This page needs javascript to run". When using the function above it prints only a small and weird fraction of html string. Can anyone help me with the issue? I have searched in many places but haven't found any solution to the issue.

ios swift

share|improve this question

asked Mar 26 at 19:44

Timothy StokarskiTimothy Stokarski

1

let usedURLString = "my http link"



guard let usedURL = URL(string: usedURLString) else 
 // if URL is not valid:
 print("Error: (usedURLString) doesn't seem to be a valid URL")
 return 
do 
 // getting the HTML sourcecode

 let sourceCodeHTML = try String(contentsOf: usedURL, encoding: String.Encoding.windowsCP1254)

 print(sourceCodeHTML)
 catch 
 print("there was an error: (error)")

share|improve this question

asked Mar 26 at 19:44

Timothy StokarskiTimothy Stokarski

1

share|improve this question

asked Mar 26 at 19:44

Timothy StokarskiTimothy Stokarski

1

asked Mar 26 at 19:44

Timothy StokarskiTimothy Stokarski

1

asked Mar 26 at 19:44

Timothy StokarskiTimothy Stokarski

1

1 Answer
1

active

oldest

votes

0

Try this:

let usedURLString = "my http link"
if let url = URL(string: usedURLString) 
 do 
 let contents = try String(contentsOfURL: myURL, encoding: NSUTF8StringEncoding)
 print(contents)
 catch 
 // contents could not be loaded
 
 else 
 // the URL was bad!

share|improve this answer

answered Mar 26 at 20:03

Joshua CleetusJoshua Cleetus

18611 silver badge99 bronze badges

add a comment | 

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0

Try this:

let usedURLString = "my http link"
if let url = URL(string: usedURLString) 
 do 
 let contents = try String(contentsOfURL: myURL, encoding: NSUTF8StringEncoding)
 print(contents)
 catch 
 // contents could not be loaded
 
 else 
 // the URL was bad!

share|improve this answer

answered Mar 26 at 20:03

Joshua CleetusJoshua Cleetus

18611 silver badge99 bronze badges

add a comment | 

0

Try this:

let usedURLString = "my http link"
if let url = URL(string: usedURLString) 
 do 
 let contents = try String(contentsOfURL: myURL, encoding: NSUTF8StringEncoding)
 print(contents)
 catch 
 // contents could not be loaded
 
 else 
 // the URL was bad!

share|improve this answer

answered Mar 26 at 20:03

Joshua CleetusJoshua Cleetus

18611 silver badge99 bronze badges

add a comment | 

Try this:

let usedURLString = "my http link"
if let url = URL(string: usedURLString) 
 do 
 let contents = try String(contentsOfURL: myURL, encoding: NSUTF8StringEncoding)
 print(contents)
 catch 
 // contents could not be loaded
 
 else 
 // the URL was bad!

share|improve this answer

answered Mar 26 at 20:03

Joshua CleetusJoshua Cleetus

18611 silver badge99 bronze badges

let usedURLString = "my http link"
if let url = URL(string: usedURLString) 
 do 
 let contents = try String(contentsOfURL: myURL, encoding: NSUTF8StringEncoding)
 print(contents)
 catch 
 // contents could not be loaded
 
 else 
 // the URL was bad!

share|improve this answer

answered Mar 26 at 20:03

Joshua CleetusJoshua Cleetus

18611 silver badge99 bronze badges

answered Mar 26 at 20:03

Joshua CleetusJoshua Cleetus

18611 silver badge99 bronze badges

answered Mar 26 at 20:03

Joshua CleetusJoshua Cleetus

18611 silver badge99 bronze badges