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Replacing the date in a csv file with mm-yyyy
How to replace a character by a newline in VimCompare two dates with JavaScriptHow to check whether an object is a date?How to replace all occurrences of a string?How can I replace a newline (n) using sed?Detecting an “invalid date” Date instance in JavaScriptYYYY-MM-DD format date in shell scriptHow do I get the current date in JavaScript?How to format a JavaScript dateJavascript add leading zeroes to date
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I have a csv file consisting of one column of dates. The date format is dd.mm.yyyy. How can I use sed to replace the date with the mm-yy format? That is, to replace the date with mm-yyyy, which is a text and dropping the day in the date. An example of the input csv file is:
11.12.2018
21.01.2019
07.02.2019
29.03.2019
01.04.2019
I would like the output to be:
12-18
01-19
02-19
03-19
04-19
date sed replace
add a comment |
I have a csv file consisting of one column of dates. The date format is dd.mm.yyyy. How can I use sed to replace the date with the mm-yy format? That is, to replace the date with mm-yyyy, which is a text and dropping the day in the date. An example of the input csv file is:
11.12.2018
21.01.2019
07.02.2019
29.03.2019
01.04.2019
I would like the output to be:
12-18
01-19
02-19
03-19
04-19
date sed replace
Please take a look at How to create a Minimal, Complete, and Verifiable example. Please add sample input and your desired output for that sample input to your question.
– Cyrus
Mar 26 at 18:35
add a comment |
I have a csv file consisting of one column of dates. The date format is dd.mm.yyyy. How can I use sed to replace the date with the mm-yy format? That is, to replace the date with mm-yyyy, which is a text and dropping the day in the date. An example of the input csv file is:
11.12.2018
21.01.2019
07.02.2019
29.03.2019
01.04.2019
I would like the output to be:
12-18
01-19
02-19
03-19
04-19
date sed replace
I have a csv file consisting of one column of dates. The date format is dd.mm.yyyy. How can I use sed to replace the date with the mm-yy format? That is, to replace the date with mm-yyyy, which is a text and dropping the day in the date. An example of the input csv file is:
11.12.2018
21.01.2019
07.02.2019
29.03.2019
01.04.2019
I would like the output to be:
12-18
01-19
02-19
03-19
04-19
date sed replace
date sed replace
edited Mar 26 at 18:57
Reza
asked Mar 26 at 17:32
RezaReza
1486 bronze badges
1486 bronze badges
Please take a look at How to create a Minimal, Complete, and Verifiable example. Please add sample input and your desired output for that sample input to your question.
– Cyrus
Mar 26 at 18:35
add a comment |
Please take a look at How to create a Minimal, Complete, and Verifiable example. Please add sample input and your desired output for that sample input to your question.
– Cyrus
Mar 26 at 18:35
Please take a look at How to create a Minimal, Complete, and Verifiable example. Please add sample input and your desired output for that sample input to your question.
– Cyrus
Mar 26 at 18:35
Please take a look at How to create a Minimal, Complete, and Verifiable example. Please add sample input and your desired output for that sample input to your question.
– Cyrus
Mar 26 at 18:35
add a comment |
1 Answer
1
active
oldest
votes
With GNU sed:
sed -r 's/...(..)...(..)/1-2/' file
-r: use extended regular expressions in the script.
Output:
12-18
01-19
02-19
03-19
04-19
See: The Stack Overflow Regular Expressions FAQ
I get the following error message: sed: illegal option -- r usage: sed script [-Ealn] [-i extension] [file ...] sed [-Ealn] [-i extension] [-e script] ... [-f script_file] ... [file ...]
– Reza
Mar 26 at 19:33
You don't use GNU sed. Try to replace-rwith-E.
– Cyrus
Mar 27 at 5:08
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
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active
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votes
With GNU sed:
sed -r 's/...(..)...(..)/1-2/' file
-r: use extended regular expressions in the script.
Output:
12-18
01-19
02-19
03-19
04-19
See: The Stack Overflow Regular Expressions FAQ
I get the following error message: sed: illegal option -- r usage: sed script [-Ealn] [-i extension] [file ...] sed [-Ealn] [-i extension] [-e script] ... [-f script_file] ... [file ...]
– Reza
Mar 26 at 19:33
You don't use GNU sed. Try to replace-rwith-E.
– Cyrus
Mar 27 at 5:08
add a comment |
With GNU sed:
sed -r 's/...(..)...(..)/1-2/' file
-r: use extended regular expressions in the script.
Output:
12-18
01-19
02-19
03-19
04-19
See: The Stack Overflow Regular Expressions FAQ
I get the following error message: sed: illegal option -- r usage: sed script [-Ealn] [-i extension] [file ...] sed [-Ealn] [-i extension] [-e script] ... [-f script_file] ... [file ...]
– Reza
Mar 26 at 19:33
You don't use GNU sed. Try to replace-rwith-E.
– Cyrus
Mar 27 at 5:08
add a comment |
With GNU sed:
sed -r 's/...(..)...(..)/1-2/' file
-r: use extended regular expressions in the script.
Output:
12-18
01-19
02-19
03-19
04-19
See: The Stack Overflow Regular Expressions FAQ
With GNU sed:
sed -r 's/...(..)...(..)/1-2/' file
-r: use extended regular expressions in the script.
Output:
12-18
01-19
02-19
03-19
04-19
See: The Stack Overflow Regular Expressions FAQ
answered Mar 26 at 19:19
CyrusCyrus
50.4k5 gold badges41 silver badges84 bronze badges
50.4k5 gold badges41 silver badges84 bronze badges
I get the following error message: sed: illegal option -- r usage: sed script [-Ealn] [-i extension] [file ...] sed [-Ealn] [-i extension] [-e script] ... [-f script_file] ... [file ...]
– Reza
Mar 26 at 19:33
You don't use GNU sed. Try to replace-rwith-E.
– Cyrus
Mar 27 at 5:08
add a comment |
I get the following error message: sed: illegal option -- r usage: sed script [-Ealn] [-i extension] [file ...] sed [-Ealn] [-i extension] [-e script] ... [-f script_file] ... [file ...]
– Reza
Mar 26 at 19:33
You don't use GNU sed. Try to replace-rwith-E.
– Cyrus
Mar 27 at 5:08
I get the following error message: sed: illegal option -- r usage: sed script [-Ealn] [-i extension] [file ...] sed [-Ealn] [-i extension] [-e script] ... [-f script_file] ... [file ...]
– Reza
Mar 26 at 19:33
I get the following error message: sed: illegal option -- r usage: sed script [-Ealn] [-i extension] [file ...] sed [-Ealn] [-i extension] [-e script] ... [-f script_file] ... [file ...]
– Reza
Mar 26 at 19:33
You don't use GNU sed. Try to replace
-r with -E.– Cyrus
Mar 27 at 5:08
You don't use GNU sed. Try to replace
-r with -E.– Cyrus
Mar 27 at 5:08
add a comment |
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Please take a look at How to create a Minimal, Complete, and Verifiable example. Please add sample input and your desired output for that sample input to your question.
– Cyrus
Mar 26 at 18:35