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how to pass a list to a function without using move in mips


mips program that finds how many times a character appears in a specific stringMIPS subroutine passing parameters by referenceMars Mips , how to represent struct and listMIPS function with multiple argumentsHow to implement NOT operation in MIPS?Trouble with simple Mips functionMIPS - Moving graphsMove a graph within a certain range - MIPSMIPS swap functionC to MIPS - functions and arrays






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0















i want to pass a list to function in mips so that i can do soemthing to that lsit, but my assignment prohibit the move instruction,



tried to pass the address, but they all error



addi $fp, $sp, 0
addi $sp, $sp, -4

la $t0, thelist
sw $t0, ($sp)
jal bubblesort

bubblesort:
#call function
addi $sp, $sp, -8 #push 8 bytes to store $fp and $ra
sw $ra, 4($sp)
sw $fp, ($sp)

#copy $sp to $fp
addi $fp, $sp, 0

#allocate local variable
addi $sp, $sp, -16 #i, j, listaddress, size

#initialize i j n
lw $t0, 8($fp)
sw $t0, -12($fp) # listaddress
lw $t1, size
sw $0, -8($fp) #i = 0
sw $0, -4($fp) #j = 0

loop1:
#condition
lw $t0, -8($fp) #load i
lw $t1, size #the actual n
addi $t1, $t1, -1 #n = n - 1
beq $t0, $t1, end #if i == n-1, jump to end

loop2:
lw $t0, -4($fp) #load j
lw $t1, size #load n
addi $t1, $t1, -1 #n = n - 1
beq $t0, $t1, exit1 #if j == n-1, jump to exit1

#swap section
lw $t1, thelist #$t1 = list address
sll $t0, $t0, 2 #j = j*4
add $t3, $t1, $t0 #address of list[j]
lw $t4, ($t3) #list[j]
lw $t5, 4($t3) #list[j+1]
slt $t2, $t5, $t4
beq $t2, $0, exit2 #if list[j] < list[j+1], jump to loop2
#swap
add $t2, $t5, 0 #temp = list[j+1]
add $t5, $t4, 0 #list[j+1] = list[j]
add $t4, $t2, 0 #list[j] = temp

sw $t5, ($t3)
sw $t6, 4($t3)

lw $t0, -4($fp)
addi $t0, $t0, 1 #j = j+1
sw $t0, -4($fp)
j loop2

exit2:
lw $t0, -4($fp)
addi $t0, $t0, 1 #j = j+1
sw $t0, -4($fp)
j loop2

exit1:
lw $t0, -8($fp)
addi $t0, $t0, 1
sw $t0, -8($fp)
j loop1
end:
lw $v0, -12($fp)
addi $sp, $sp 12
lw $fp, ($sp)
lw $ra, 4($sp)
addi $sp, $sp, 8
jr $ra









share|improve this question
































    0















    i want to pass a list to function in mips so that i can do soemthing to that lsit, but my assignment prohibit the move instruction,



    tried to pass the address, but they all error



    addi $fp, $sp, 0
    addi $sp, $sp, -4

    la $t0, thelist
    sw $t0, ($sp)
    jal bubblesort

    bubblesort:
    #call function
    addi $sp, $sp, -8 #push 8 bytes to store $fp and $ra
    sw $ra, 4($sp)
    sw $fp, ($sp)

    #copy $sp to $fp
    addi $fp, $sp, 0

    #allocate local variable
    addi $sp, $sp, -16 #i, j, listaddress, size

    #initialize i j n
    lw $t0, 8($fp)
    sw $t0, -12($fp) # listaddress
    lw $t1, size
    sw $0, -8($fp) #i = 0
    sw $0, -4($fp) #j = 0

    loop1:
    #condition
    lw $t0, -8($fp) #load i
    lw $t1, size #the actual n
    addi $t1, $t1, -1 #n = n - 1
    beq $t0, $t1, end #if i == n-1, jump to end

    loop2:
    lw $t0, -4($fp) #load j
    lw $t1, size #load n
    addi $t1, $t1, -1 #n = n - 1
    beq $t0, $t1, exit1 #if j == n-1, jump to exit1

    #swap section
    lw $t1, thelist #$t1 = list address
    sll $t0, $t0, 2 #j = j*4
    add $t3, $t1, $t0 #address of list[j]
    lw $t4, ($t3) #list[j]
    lw $t5, 4($t3) #list[j+1]
    slt $t2, $t5, $t4
    beq $t2, $0, exit2 #if list[j] < list[j+1], jump to loop2
    #swap
    add $t2, $t5, 0 #temp = list[j+1]
    add $t5, $t4, 0 #list[j+1] = list[j]
    add $t4, $t2, 0 #list[j] = temp

    sw $t5, ($t3)
    sw $t6, 4($t3)

    lw $t0, -4($fp)
    addi $t0, $t0, 1 #j = j+1
    sw $t0, -4($fp)
    j loop2

    exit2:
    lw $t0, -4($fp)
    addi $t0, $t0, 1 #j = j+1
    sw $t0, -4($fp)
    j loop2

    exit1:
    lw $t0, -8($fp)
    addi $t0, $t0, 1
    sw $t0, -8($fp)
    j loop1
    end:
    lw $v0, -12($fp)
    addi $sp, $sp 12
    lw $fp, ($sp)
    lw $ra, 4($sp)
    addi $sp, $sp, 8
    jr $ra









    share|improve this question




























      0












      0








      0








      i want to pass a list to function in mips so that i can do soemthing to that lsit, but my assignment prohibit the move instruction,



      tried to pass the address, but they all error



      addi $fp, $sp, 0
      addi $sp, $sp, -4

      la $t0, thelist
      sw $t0, ($sp)
      jal bubblesort

      bubblesort:
      #call function
      addi $sp, $sp, -8 #push 8 bytes to store $fp and $ra
      sw $ra, 4($sp)
      sw $fp, ($sp)

      #copy $sp to $fp
      addi $fp, $sp, 0

      #allocate local variable
      addi $sp, $sp, -16 #i, j, listaddress, size

      #initialize i j n
      lw $t0, 8($fp)
      sw $t0, -12($fp) # listaddress
      lw $t1, size
      sw $0, -8($fp) #i = 0
      sw $0, -4($fp) #j = 0

      loop1:
      #condition
      lw $t0, -8($fp) #load i
      lw $t1, size #the actual n
      addi $t1, $t1, -1 #n = n - 1
      beq $t0, $t1, end #if i == n-1, jump to end

      loop2:
      lw $t0, -4($fp) #load j
      lw $t1, size #load n
      addi $t1, $t1, -1 #n = n - 1
      beq $t0, $t1, exit1 #if j == n-1, jump to exit1

      #swap section
      lw $t1, thelist #$t1 = list address
      sll $t0, $t0, 2 #j = j*4
      add $t3, $t1, $t0 #address of list[j]
      lw $t4, ($t3) #list[j]
      lw $t5, 4($t3) #list[j+1]
      slt $t2, $t5, $t4
      beq $t2, $0, exit2 #if list[j] < list[j+1], jump to loop2
      #swap
      add $t2, $t5, 0 #temp = list[j+1]
      add $t5, $t4, 0 #list[j+1] = list[j]
      add $t4, $t2, 0 #list[j] = temp

      sw $t5, ($t3)
      sw $t6, 4($t3)

      lw $t0, -4($fp)
      addi $t0, $t0, 1 #j = j+1
      sw $t0, -4($fp)
      j loop2

      exit2:
      lw $t0, -4($fp)
      addi $t0, $t0, 1 #j = j+1
      sw $t0, -4($fp)
      j loop2

      exit1:
      lw $t0, -8($fp)
      addi $t0, $t0, 1
      sw $t0, -8($fp)
      j loop1
      end:
      lw $v0, -12($fp)
      addi $sp, $sp 12
      lw $fp, ($sp)
      lw $ra, 4($sp)
      addi $sp, $sp, 8
      jr $ra









      share|improve this question
















      i want to pass a list to function in mips so that i can do soemthing to that lsit, but my assignment prohibit the move instruction,



      tried to pass the address, but they all error



      addi $fp, $sp, 0
      addi $sp, $sp, -4

      la $t0, thelist
      sw $t0, ($sp)
      jal bubblesort

      bubblesort:
      #call function
      addi $sp, $sp, -8 #push 8 bytes to store $fp and $ra
      sw $ra, 4($sp)
      sw $fp, ($sp)

      #copy $sp to $fp
      addi $fp, $sp, 0

      #allocate local variable
      addi $sp, $sp, -16 #i, j, listaddress, size

      #initialize i j n
      lw $t0, 8($fp)
      sw $t0, -12($fp) # listaddress
      lw $t1, size
      sw $0, -8($fp) #i = 0
      sw $0, -4($fp) #j = 0

      loop1:
      #condition
      lw $t0, -8($fp) #load i
      lw $t1, size #the actual n
      addi $t1, $t1, -1 #n = n - 1
      beq $t0, $t1, end #if i == n-1, jump to end

      loop2:
      lw $t0, -4($fp) #load j
      lw $t1, size #load n
      addi $t1, $t1, -1 #n = n - 1
      beq $t0, $t1, exit1 #if j == n-1, jump to exit1

      #swap section
      lw $t1, thelist #$t1 = list address
      sll $t0, $t0, 2 #j = j*4
      add $t3, $t1, $t0 #address of list[j]
      lw $t4, ($t3) #list[j]
      lw $t5, 4($t3) #list[j+1]
      slt $t2, $t5, $t4
      beq $t2, $0, exit2 #if list[j] < list[j+1], jump to loop2
      #swap
      add $t2, $t5, 0 #temp = list[j+1]
      add $t5, $t4, 0 #list[j+1] = list[j]
      add $t4, $t2, 0 #list[j] = temp

      sw $t5, ($t3)
      sw $t6, 4($t3)

      lw $t0, -4($fp)
      addi $t0, $t0, 1 #j = j+1
      sw $t0, -4($fp)
      j loop2

      exit2:
      lw $t0, -4($fp)
      addi $t0, $t0, 1 #j = j+1
      sw $t0, -4($fp)
      j loop2

      exit1:
      lw $t0, -8($fp)
      addi $t0, $t0, 1
      sw $t0, -8($fp)
      j loop1
      end:
      lw $v0, -12($fp)
      addi $sp, $sp 12
      lw $fp, ($sp)
      lw $ra, 4($sp)
      addi $sp, $sp, 8
      jr $ra






      mips32






      share|improve this question















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      share|improve this question




      share|improve this question








      edited Mar 27 at 6:06









      Stefan Becker

      4,5913 gold badges11 silver badges25 bronze badges




      4,5913 gold badges11 silver badges25 bronze badges










      asked Mar 27 at 5:26









      LeslieLeslie

      1




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          0














          You actually can access $t registers inside your functions. There is no need to store it on the stack before. If you load your list to $t10 for example, you can easily access it inside of your function. Also: Instead of move, you can always use add. I can't run your code, since it is not a complete example. How is your list stored?






          share|improve this answer


























            Your Answer






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            1 Answer
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            You actually can access $t registers inside your functions. There is no need to store it on the stack before. If you load your list to $t10 for example, you can easily access it inside of your function. Also: Instead of move, you can always use add. I can't run your code, since it is not a complete example. How is your list stored?






            share|improve this answer































              0














              You actually can access $t registers inside your functions. There is no need to store it on the stack before. If you load your list to $t10 for example, you can easily access it inside of your function. Also: Instead of move, you can always use add. I can't run your code, since it is not a complete example. How is your list stored?






              share|improve this answer





























                0












                0








                0







                You actually can access $t registers inside your functions. There is no need to store it on the stack before. If you load your list to $t10 for example, you can easily access it inside of your function. Also: Instead of move, you can always use add. I can't run your code, since it is not a complete example. How is your list stored?






                share|improve this answer















                You actually can access $t registers inside your functions. There is no need to store it on the stack before. If you load your list to $t10 for example, you can easily access it inside of your function. Also: Instead of move, you can always use add. I can't run your code, since it is not a complete example. How is your list stored?







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Mar 28 at 21:40

























                answered Mar 28 at 21:35









                KruspeKruspe

                268 bronze badges




                268 bronze badges



















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