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Passing arguments to URL object
How do I return multiple values from a function?How to know if an object has an attribute in PythonHow do I pass a variable by reference?“Least Astonishment” and the Mutable Default ArgumentDetermine the type of an object?Peak detection in a 2D arrayRun a Python script from another Python script, passing in argumentsHow does the @property decorator work?Embed youtube video in KivyWhy is “1000000000000000 in range(1000000000000001)” so fast in Python 3?
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Using the URL object in kivy, https://kivy.org/doc/stable/api-kivy.network.urlrequest.html, if I wanted to change the on_success function to take in another parameter, how would I pass the value to it?
def generate_images(sensor_id):
req = UrlRequest(URL, on_success=url_success)
And then in the on_success having something like this
def url_success(req, result, sensor_id):
python kivy kivy-language
add a comment |
Using the URL object in kivy, https://kivy.org/doc/stable/api-kivy.network.urlrequest.html, if I wanted to change the on_success function to take in another parameter, how would I pass the value to it?
def generate_images(sensor_id):
req = UrlRequest(URL, on_success=url_success)
And then in the on_success having something like this
def url_success(req, result, sensor_id):
python kivy kivy-language
add a comment |
Using the URL object in kivy, https://kivy.org/doc/stable/api-kivy.network.urlrequest.html, if I wanted to change the on_success function to take in another parameter, how would I pass the value to it?
def generate_images(sensor_id):
req = UrlRequest(URL, on_success=url_success)
And then in the on_success having something like this
def url_success(req, result, sensor_id):
python kivy kivy-language
Using the URL object in kivy, https://kivy.org/doc/stable/api-kivy.network.urlrequest.html, if I wanted to change the on_success function to take in another parameter, how would I pass the value to it?
def generate_images(sensor_id):
req = UrlRequest(URL, on_success=url_success)
And then in the on_success having something like this
def url_success(req, result, sensor_id):
python kivy kivy-language
python kivy kivy-language
asked Mar 27 at 22:06
Ferris ArmstrongFerris Armstrong
132 bronze badges
132 bronze badges
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1 Answer
1
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oldest
votes
One solution is to use functools.partial()
:
from functools import partial
# ...
def generate_images(sensor_id):
req = UrlRequest(URL, on_success=partial(url_success, sensor_id))
# ...
def url_success(sensor_id, req, result):
print(sensor_id, req, result)
Another solution is to use a lambda
functions:
def generate_images(sensor_id):
req = UrlRequest(URL, on_success= lambda req, result, sensor_id=sensor_id : url_success(req, result, sensor_id))
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
One solution is to use functools.partial()
:
from functools import partial
# ...
def generate_images(sensor_id):
req = UrlRequest(URL, on_success=partial(url_success, sensor_id))
# ...
def url_success(sensor_id, req, result):
print(sensor_id, req, result)
Another solution is to use a lambda
functions:
def generate_images(sensor_id):
req = UrlRequest(URL, on_success= lambda req, result, sensor_id=sensor_id : url_success(req, result, sensor_id))
add a comment |
One solution is to use functools.partial()
:
from functools import partial
# ...
def generate_images(sensor_id):
req = UrlRequest(URL, on_success=partial(url_success, sensor_id))
# ...
def url_success(sensor_id, req, result):
print(sensor_id, req, result)
Another solution is to use a lambda
functions:
def generate_images(sensor_id):
req = UrlRequest(URL, on_success= lambda req, result, sensor_id=sensor_id : url_success(req, result, sensor_id))
add a comment |
One solution is to use functools.partial()
:
from functools import partial
# ...
def generate_images(sensor_id):
req = UrlRequest(URL, on_success=partial(url_success, sensor_id))
# ...
def url_success(sensor_id, req, result):
print(sensor_id, req, result)
Another solution is to use a lambda
functions:
def generate_images(sensor_id):
req = UrlRequest(URL, on_success= lambda req, result, sensor_id=sensor_id : url_success(req, result, sensor_id))
One solution is to use functools.partial()
:
from functools import partial
# ...
def generate_images(sensor_id):
req = UrlRequest(URL, on_success=partial(url_success, sensor_id))
# ...
def url_success(sensor_id, req, result):
print(sensor_id, req, result)
Another solution is to use a lambda
functions:
def generate_images(sensor_id):
req = UrlRequest(URL, on_success= lambda req, result, sensor_id=sensor_id : url_success(req, result, sensor_id))
edited Mar 27 at 22:25
answered Mar 27 at 22:17
eyllanesceyllanesc
107k12 gold badges38 silver badges71 bronze badges
107k12 gold badges38 silver badges71 bronze badges
add a comment |
add a comment |
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