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Passing arguments to URL object


How do I return multiple values from a function?How to know if an object has an attribute in PythonHow do I pass a variable by reference?“Least Astonishment” and the Mutable Default ArgumentDetermine the type of an object?Peak detection in a 2D arrayRun a Python script from another Python script, passing in argumentsHow does the @property decorator work?Embed youtube video in KivyWhy is “1000000000000000 in range(1000000000000001)” so fast in Python 3?






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2















Using the URL object in kivy, https://kivy.org/doc/stable/api-kivy.network.urlrequest.html, if I wanted to change the on_success function to take in another parameter, how would I pass the value to it?



def generate_images(sensor_id):
req = UrlRequest(URL, on_success=url_success)


And then in the on_success having something like this



def url_success(req, result, sensor_id):









share|improve this question






























    2















    Using the URL object in kivy, https://kivy.org/doc/stable/api-kivy.network.urlrequest.html, if I wanted to change the on_success function to take in another parameter, how would I pass the value to it?



    def generate_images(sensor_id):
    req = UrlRequest(URL, on_success=url_success)


    And then in the on_success having something like this



    def url_success(req, result, sensor_id):









    share|improve this question


























      2












      2








      2








      Using the URL object in kivy, https://kivy.org/doc/stable/api-kivy.network.urlrequest.html, if I wanted to change the on_success function to take in another parameter, how would I pass the value to it?



      def generate_images(sensor_id):
      req = UrlRequest(URL, on_success=url_success)


      And then in the on_success having something like this



      def url_success(req, result, sensor_id):









      share|improve this question














      Using the URL object in kivy, https://kivy.org/doc/stable/api-kivy.network.urlrequest.html, if I wanted to change the on_success function to take in another parameter, how would I pass the value to it?



      def generate_images(sensor_id):
      req = UrlRequest(URL, on_success=url_success)


      And then in the on_success having something like this



      def url_success(req, result, sensor_id):






      python kivy kivy-language






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 27 at 22:06









      Ferris ArmstrongFerris Armstrong

      132 bronze badges




      132 bronze badges

























          1 Answer
          1






          active

          oldest

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          0















          One solution is to use functools.partial():



          from functools import partial

          # ...

          def generate_images(sensor_id):
          req = UrlRequest(URL, on_success=partial(url_success, sensor_id))

          # ...

          def url_success(sensor_id, req, result):
          print(sensor_id, req, result)


          Another solution is to use a lambda functions:



          def generate_images(sensor_id):
          req = UrlRequest(URL, on_success= lambda req, result, sensor_id=sensor_id : url_success(req, result, sensor_id))





          share|improve this answer


























            Your Answer






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            1 Answer
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            active

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            active

            oldest

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            active

            oldest

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            0















            One solution is to use functools.partial():



            from functools import partial

            # ...

            def generate_images(sensor_id):
            req = UrlRequest(URL, on_success=partial(url_success, sensor_id))

            # ...

            def url_success(sensor_id, req, result):
            print(sensor_id, req, result)


            Another solution is to use a lambda functions:



            def generate_images(sensor_id):
            req = UrlRequest(URL, on_success= lambda req, result, sensor_id=sensor_id : url_success(req, result, sensor_id))





            share|improve this answer































              0















              One solution is to use functools.partial():



              from functools import partial

              # ...

              def generate_images(sensor_id):
              req = UrlRequest(URL, on_success=partial(url_success, sensor_id))

              # ...

              def url_success(sensor_id, req, result):
              print(sensor_id, req, result)


              Another solution is to use a lambda functions:



              def generate_images(sensor_id):
              req = UrlRequest(URL, on_success= lambda req, result, sensor_id=sensor_id : url_success(req, result, sensor_id))





              share|improve this answer





























                0














                0










                0









                One solution is to use functools.partial():



                from functools import partial

                # ...

                def generate_images(sensor_id):
                req = UrlRequest(URL, on_success=partial(url_success, sensor_id))

                # ...

                def url_success(sensor_id, req, result):
                print(sensor_id, req, result)


                Another solution is to use a lambda functions:



                def generate_images(sensor_id):
                req = UrlRequest(URL, on_success= lambda req, result, sensor_id=sensor_id : url_success(req, result, sensor_id))





                share|improve this answer















                One solution is to use functools.partial():



                from functools import partial

                # ...

                def generate_images(sensor_id):
                req = UrlRequest(URL, on_success=partial(url_success, sensor_id))

                # ...

                def url_success(sensor_id, req, result):
                print(sensor_id, req, result)


                Another solution is to use a lambda functions:



                def generate_images(sensor_id):
                req = UrlRequest(URL, on_success= lambda req, result, sensor_id=sensor_id : url_success(req, result, sensor_id))






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Mar 27 at 22:25

























                answered Mar 27 at 22:17









                eyllanesceyllanesc

                107k12 gold badges38 silver badges71 bronze badges




                107k12 gold badges38 silver badges71 bronze badges





















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