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vis.js removing whole graph when deleting single node

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I'm trying to delete a node from a vis.js graph. When the function is applied, instead of the node and its outgoing edges being deleted the entire graph gets erased. I want the changes to be kept intact when the page gets refreshed. The calls related to this are deleteNode (in index.html) and app.delete (in index.js).

index.html:

var deleteNode = function(data, callback)
 $.ajax(
 method: "delete",
 url: "/api/node",
 data: node: data.nodes[0] ,
 success: function(result)
 callback(result);
 
 )
;

index.js:

app.delete("/api/node", function(req, res)
 var deleteNode = req.body.node;
 var deleteResult = 
 nodes:[],
 edges: []
 ;

 var updatedNodes = _.filter(data.nodes, function(node)
 var keep = (node.id !== deleteNode);
 if(!keep)
 deleteResult.nodes.push(node);
 
 return keep;
 );

 var updatedEdges = _.filter(data.edges, function(edge)
 var keep = (edge.from !== deleteNode) );

 data.nodes = updatedNodes;
 data.edges = updatedEdges;

 res.send(deleteResult).end();
);

javascript jquery ajax api vis.js

share|improve this question

edited Mar 28 at 2:19

ottomeister

3,45722 gold badges1515 silver badges2121 bronze badges

asked Mar 28 at 0:10

Julian LanksteadJulian Lankstead

1

add a comment | 

0

I'm trying to delete a node from a vis.js graph. When the function is applied, instead of the node and its outgoing edges being deleted the entire graph gets erased. I want the changes to be kept intact when the page gets refreshed. The calls related to this are deleteNode (in index.html) and app.delete (in index.js).

index.html:

var deleteNode = function(data, callback)
 $.ajax(
 method: "delete",
 url: "/api/node",
 data: node: data.nodes[0] ,
 success: function(result)
 callback(result);
 
 )
;

index.js:

app.delete("/api/node", function(req, res)
 var deleteNode = req.body.node;
 var deleteResult = 
 nodes:[],
 edges: []
 ;

 var updatedNodes = _.filter(data.nodes, function(node)
 var keep = (node.id !== deleteNode);
 if(!keep)
 deleteResult.nodes.push(node);
 
 return keep;
 );

 var updatedEdges = _.filter(data.edges, function(edge)
 var keep = (edge.from !== deleteNode) );

 data.nodes = updatedNodes;
 data.edges = updatedEdges;

 res.send(deleteResult).end();
);

javascript jquery ajax api vis.js

share|improve this question

edited Mar 28 at 2:19

ottomeister

3,45722 gold badges1515 silver badges2121 bronze badges

asked Mar 28 at 0:10

Julian LanksteadJulian Lankstead

1

add a comment | 

I'm trying to delete a node from a vis.js graph. When the function is applied, instead of the node and its outgoing edges being deleted the entire graph gets erased. I want the changes to be kept intact when the page gets refreshed. The calls related to this are deleteNode (in index.html) and app.delete (in index.js).

index.html:

var deleteNode = function(data, callback)
 $.ajax(
 method: "delete",
 url: "/api/node",
 data: node: data.nodes[0] ,
 success: function(result)
 callback(result);
 
 )
;

index.js:

app.delete("/api/node", function(req, res)
 var deleteNode = req.body.node;
 var deleteResult = 
 nodes:[],
 edges: []
 ;

 var updatedNodes = _.filter(data.nodes, function(node)
 var keep = (node.id !== deleteNode);
 if(!keep)
 deleteResult.nodes.push(node);
 
 return keep;
 );

 var updatedEdges = _.filter(data.edges, function(edge)
 var keep = (edge.from !== deleteNode) );

 data.nodes = updatedNodes;
 data.edges = updatedEdges;

 res.send(deleteResult).end();
);

javascript jquery ajax api vis.js

share|improve this question

edited Mar 28 at 2:19

ottomeister

3,45722 gold badges1515 silver badges2121 bronze badges

asked Mar 28 at 0:10

Julian LanksteadJulian Lankstead

1

var deleteNode = function(data, callback)
 $.ajax(
 method: "delete",
 url: "/api/node",
 data: node: data.nodes[0] ,
 success: function(result)
 callback(result);
 
 )
;

app.delete("/api/node", function(req, res)
 var deleteNode = req.body.node;
 var deleteResult = 
 nodes:[],
 edges: []
 ;

 var updatedNodes = _.filter(data.nodes, function(node)
 var keep = (node.id !== deleteNode);
 if(!keep)
 deleteResult.nodes.push(node);
 
 return keep;
 );

 var updatedEdges = _.filter(data.edges, function(edge)
 var keep = (edge.from !== deleteNode) );

 data.nodes = updatedNodes;
 data.edges = updatedEdges;

 res.send(deleteResult).end();
);

share|improve this question

edited Mar 28 at 2:19

ottomeister

3,45722 gold badges1515 silver badges2121 bronze badges

asked Mar 28 at 0:10

Julian LanksteadJulian Lankstead

1

share|improve this question

edited Mar 28 at 2:19

ottomeister

3,45722 gold badges1515 silver badges2121 bronze badges

asked Mar 28 at 0:10

Julian LanksteadJulian Lankstead

1

edited Mar 28 at 2:19

ottomeister

3,45722 gold badges1515 silver badges2121 bronze badges

edited Mar 28 at 2:19

ottomeister

3,45722 gold badges1515 silver badges2121 bronze badges

asked Mar 28 at 0:10

Julian LanksteadJulian Lankstead

1

asked Mar 28 at 0:10

Julian LanksteadJulian Lankstead

1

1 Answer
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0

Are you sure that your logic is correct? That is the first thing I would check here. In particular, I see that your 'delete' method seems to be returning the 'deleteResult' variable, which is going to have probably all the nodes that you deleted as a consequence of the API call. Perhaps you wanted to return the 'data' variable instead?

share|improve this answer

answered Mar 28 at 17:34

pgoldweicpgoldweic

24211 silver badge77 bronze badges

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0

Are you sure that your logic is correct? That is the first thing I would check here. In particular, I see that your 'delete' method seems to be returning the 'deleteResult' variable, which is going to have probably all the nodes that you deleted as a consequence of the API call. Perhaps you wanted to return the 'data' variable instead?

share|improve this answer

answered Mar 28 at 17:34

pgoldweicpgoldweic

24211 silver badge77 bronze badges

add a comment | 

0

Are you sure that your logic is correct? That is the first thing I would check here. In particular, I see that your 'delete' method seems to be returning the 'deleteResult' variable, which is going to have probably all the nodes that you deleted as a consequence of the API call. Perhaps you wanted to return the 'data' variable instead?

share|improve this answer

answered Mar 28 at 17:34

pgoldweicpgoldweic

24211 silver badge77 bronze badges

add a comment | 

Are you sure that your logic is correct? That is the first thing I would check here. In particular, I see that your 'delete' method seems to be returning the 'deleteResult' variable, which is going to have probably all the nodes that you deleted as a consequence of the API call. Perhaps you wanted to return the 'data' variable instead?

share|improve this answer

answered Mar 28 at 17:34

pgoldweicpgoldweic

24211 silver badge77 bronze badges

share|improve this answer

answered Mar 28 at 17:34

pgoldweicpgoldweic

24211 silver badge77 bronze badges

answered Mar 28 at 17:34

pgoldweicpgoldweic

24211 silver badge77 bronze badges

answered Mar 28 at 17:34

pgoldweicpgoldweic

24211 silver badge77 bronze badges