Reused while loop only working for one selection boxEmulate a do-while loop in Python?How to POST empty <select .. multiple> HTML elements if empty?Syntax for a single-line Bash infinite while loopHow to style a <select> dropdown with only CSS?Set selected option of select boxHow do I make a placeholder for a 'select' box?$_POST is empty when submitting a value that was posted to the formHow to pass select box value to PHP variable on same page?Disable <select> option when selected in another <select> boxIssue filling selection box with PHP from database

Why does the U.S. military maintain their own weather satellites?

Is the net torque changed when a partner on a seesaw stands or hangs from her end instead of sitting?

Can you use Apple Care+ without any checks (bringing just MacBook)?

Can I leave a large suitcase at TPE during a 4-hour layover, and pick it up 4.5 days later when I come back to TPE on my way to Taipei downtown?

Sum and average calculator

How can I improve my formal definitions?

apt-file regex: find multiple packages at once using or

A word for the urge to do the opposite

Ideas behind the 8.Bd3 line in the 4.Ng5 Two Knights Defense

Can the inductive kick be discharged without a freewheeling diode, in this example?

Do universities maintain secret textbooks?

Fishing from underwater domes

How many possible file types in the output `ls -l` command?

Break down the phrase "shitsurei shinakereba naranaindesu"

What is this "opened" cube called?

Can a system of three stars exist?

How would a disabled person earn their living in a medieval-type town?

When you have to wait for a short time

How does the search space affect the speed of an ILP solver?

A vector is defined to have a magnitude and *a* direction, but the zero vector has no *single* direction. So, how is the zero vector a vector?

Can a human variant take proficiency in initiative?

how can reincarnation magic be limited to prevent overuse?

Confidence intervals for the mean of a sample of counts

Cheap oscilloscope showing 16 MHz square wave



Reused while loop only working for one selection box


Emulate a do-while loop in Python?How to POST empty <select .. multiple> HTML elements if empty?Syntax for a single-line Bash infinite while loopHow to style a <select> dropdown with only CSS?Set selected option of select boxHow do I make a placeholder for a 'select' box?$_POST is empty when submitting a value that was posted to the formHow to pass select box value to PHP variable on same page?Disable <select> option when selected in another <select> boxIssue filling selection box with PHP from database






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








0















I need to generate a list of teams from the cups selection box at the top of my page, this code allows me to run a while loop to generate the correct results for the first selection box, however, when i replicate the code in the second it shows no results?



 <form class="seed-form">
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
while ($team = mysqli_fetch_assoc($show_teams)) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
while ($team = mysqli_fetch_assoc($show_teams)) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>



<input type="submit" name="submit" value="Generate" class="submit">
<?php

if (isset($_POST['submit'])) //checking if submit button was clicked

include_once 'action/dbcon.php';

$cname = $_POST['cupname'];

if (empty($cname))
header("Location: tables.php?field=empty"); //return them if fields are empty
exit();
else
$sql = "SELECT * FROM teams WHERE cup_name='$cname'";
$show_teams = mysqli_query($conn, $sql);
$numberCheck = mysqli_num_rows($show_teams);

if ($numberCheck < 8)
header("Location: tables.php?tables=1"); //Take to cup page if there arent enough teams in the cup



?>









share|improve this question



















  • 1





    Warning: Your code is vulnerable to SQL Injection attacks. You should use parameterised queries and prepared statements to help prevent attackers from compromising your database by using malicious input values. bobby-tables.com gives an explanation of the risks, as well as some examples of how to write your queries safely using PHP / mysqli. Never insert unsanitised data directly into your SQL. The way your code is written now, someone could easily steal, incorrectly change, or even delete your data.

    – ADyson
    Mar 27 at 23:56

















0















I need to generate a list of teams from the cups selection box at the top of my page, this code allows me to run a while loop to generate the correct results for the first selection box, however, when i replicate the code in the second it shows no results?



 <form class="seed-form">
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
while ($team = mysqli_fetch_assoc($show_teams)) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
while ($team = mysqli_fetch_assoc($show_teams)) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>



<input type="submit" name="submit" value="Generate" class="submit">
<?php

if (isset($_POST['submit'])) //checking if submit button was clicked

include_once 'action/dbcon.php';

$cname = $_POST['cupname'];

if (empty($cname))
header("Location: tables.php?field=empty"); //return them if fields are empty
exit();
else
$sql = "SELECT * FROM teams WHERE cup_name='$cname'";
$show_teams = mysqli_query($conn, $sql);
$numberCheck = mysqli_num_rows($show_teams);

if ($numberCheck < 8)
header("Location: tables.php?tables=1"); //Take to cup page if there arent enough teams in the cup



?>









share|improve this question



















  • 1





    Warning: Your code is vulnerable to SQL Injection attacks. You should use parameterised queries and prepared statements to help prevent attackers from compromising your database by using malicious input values. bobby-tables.com gives an explanation of the risks, as well as some examples of how to write your queries safely using PHP / mysqli. Never insert unsanitised data directly into your SQL. The way your code is written now, someone could easily steal, incorrectly change, or even delete your data.

    – ADyson
    Mar 27 at 23:56













0












0








0








I need to generate a list of teams from the cups selection box at the top of my page, this code allows me to run a while loop to generate the correct results for the first selection box, however, when i replicate the code in the second it shows no results?



 <form class="seed-form">
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
while ($team = mysqli_fetch_assoc($show_teams)) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
while ($team = mysqli_fetch_assoc($show_teams)) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>



<input type="submit" name="submit" value="Generate" class="submit">
<?php

if (isset($_POST['submit'])) //checking if submit button was clicked

include_once 'action/dbcon.php';

$cname = $_POST['cupname'];

if (empty($cname))
header("Location: tables.php?field=empty"); //return them if fields are empty
exit();
else
$sql = "SELECT * FROM teams WHERE cup_name='$cname'";
$show_teams = mysqli_query($conn, $sql);
$numberCheck = mysqli_num_rows($show_teams);

if ($numberCheck < 8)
header("Location: tables.php?tables=1"); //Take to cup page if there arent enough teams in the cup



?>









share|improve this question














I need to generate a list of teams from the cups selection box at the top of my page, this code allows me to run a while loop to generate the correct results for the first selection box, however, when i replicate the code in the second it shows no results?



 <form class="seed-form">
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
while ($team = mysqli_fetch_assoc($show_teams)) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
while ($team = mysqli_fetch_assoc($show_teams)) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>



<input type="submit" name="submit" value="Generate" class="submit">
<?php

if (isset($_POST['submit'])) //checking if submit button was clicked

include_once 'action/dbcon.php';

$cname = $_POST['cupname'];

if (empty($cname))
header("Location: tables.php?field=empty"); //return them if fields are empty
exit();
else
$sql = "SELECT * FROM teams WHERE cup_name='$cname'";
$show_teams = mysqli_query($conn, $sql);
$numberCheck = mysqli_num_rows($show_teams);

if ($numberCheck < 8)
header("Location: tables.php?tables=1"); //Take to cup page if there arent enough teams in the cup



?>






php html while-loop






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 27 at 23:53









Brad ArcherBrad Archer

164 bronze badges




164 bronze badges










  • 1





    Warning: Your code is vulnerable to SQL Injection attacks. You should use parameterised queries and prepared statements to help prevent attackers from compromising your database by using malicious input values. bobby-tables.com gives an explanation of the risks, as well as some examples of how to write your queries safely using PHP / mysqli. Never insert unsanitised data directly into your SQL. The way your code is written now, someone could easily steal, incorrectly change, or even delete your data.

    – ADyson
    Mar 27 at 23:56












  • 1





    Warning: Your code is vulnerable to SQL Injection attacks. You should use parameterised queries and prepared statements to help prevent attackers from compromising your database by using malicious input values. bobby-tables.com gives an explanation of the risks, as well as some examples of how to write your queries safely using PHP / mysqli. Never insert unsanitised data directly into your SQL. The way your code is written now, someone could easily steal, incorrectly change, or even delete your data.

    – ADyson
    Mar 27 at 23:56







1




1





Warning: Your code is vulnerable to SQL Injection attacks. You should use parameterised queries and prepared statements to help prevent attackers from compromising your database by using malicious input values. bobby-tables.com gives an explanation of the risks, as well as some examples of how to write your queries safely using PHP / mysqli. Never insert unsanitised data directly into your SQL. The way your code is written now, someone could easily steal, incorrectly change, or even delete your data.

– ADyson
Mar 27 at 23:56





Warning: Your code is vulnerable to SQL Injection attacks. You should use parameterised queries and prepared statements to help prevent attackers from compromising your database by using malicious input values. bobby-tables.com gives an explanation of the risks, as well as some examples of how to write your queries safely using PHP / mysqli. Never insert unsanitised data directly into your SQL. The way your code is written now, someone could easily steal, incorrectly change, or even delete your data.

– ADyson
Mar 27 at 23:56












1 Answer
1






active

oldest

votes


















0















The problem is that fetch_assoc() returns the next row in the resultset, unless there are no more left (in which case it returns NULL - see docs).



Your first while loop runs until there are no more results. Therefore when you start the second while loop, there are still...you guessed it: no more results. You already used them up. Therefore the first call to fetch_assoc() in the second loop returns NULL immediately, and so the loop condition is never met, and the loop never executes.



There are two different ways to solve this:



1) Reset the result pointer to the start of the resultset. Somewhere between the two loops, write



mysqli_data_seek($show_teams, 0);


See docs for more info.



2) Read all the data into a PHP array, which you can then loop through as many times as you like using foreach:



 <?php
$teams = array();
while ($team = mysqli_fetch_assoc($show_teams))
$teams[] = $team;

?>

<form class="seed-form">
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
foreach ($teams as $team) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?><!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
foreach ($teams as $team) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>





share|improve this answer

























  • Both methods are throwing Notice: Undefined variable: show_teams in C:xampphtdocsfriendlyfixturestables.php on line 96 and Warning: mysqli_data_seek() expects parameter 1 to be mysqli_result, null given in C:xampphtdocsfriendlyfixturestables.php on line 101

    – Brad Archer
    Mar 28 at 0:17












  • According to the code in your question, $show_teams is your query result object. So that's why I used that name. Maybe you changed it in the meantime or something?

    – ADyson
    Mar 28 at 0:18












  • none of the variable names were changed hence why im extremely confused, dont suppose you have any clue?

    – Brad Archer
    Mar 28 at 0:26











  • I can't see how you run the query and assign the result, so it's hard to be sure. Can you add that to the code in the question?

    – ADyson
    Mar 28 at 0:29











  • Not to worry, i placed the data seek elsewhere, now the variable is being recognised. However, i do also appreciate the array solution, thanks for the help!

    – Brad Archer
    Mar 28 at 0:35










Your Answer






StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55388200%2freused-while-loop-only-working-for-one-selection-box%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0















The problem is that fetch_assoc() returns the next row in the resultset, unless there are no more left (in which case it returns NULL - see docs).



Your first while loop runs until there are no more results. Therefore when you start the second while loop, there are still...you guessed it: no more results. You already used them up. Therefore the first call to fetch_assoc() in the second loop returns NULL immediately, and so the loop condition is never met, and the loop never executes.



There are two different ways to solve this:



1) Reset the result pointer to the start of the resultset. Somewhere between the two loops, write



mysqli_data_seek($show_teams, 0);


See docs for more info.



2) Read all the data into a PHP array, which you can then loop through as many times as you like using foreach:



 <?php
$teams = array();
while ($team = mysqli_fetch_assoc($show_teams))
$teams[] = $team;

?>

<form class="seed-form">
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
foreach ($teams as $team) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?><!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
foreach ($teams as $team) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>





share|improve this answer

























  • Both methods are throwing Notice: Undefined variable: show_teams in C:xampphtdocsfriendlyfixturestables.php on line 96 and Warning: mysqli_data_seek() expects parameter 1 to be mysqli_result, null given in C:xampphtdocsfriendlyfixturestables.php on line 101

    – Brad Archer
    Mar 28 at 0:17












  • According to the code in your question, $show_teams is your query result object. So that's why I used that name. Maybe you changed it in the meantime or something?

    – ADyson
    Mar 28 at 0:18












  • none of the variable names were changed hence why im extremely confused, dont suppose you have any clue?

    – Brad Archer
    Mar 28 at 0:26











  • I can't see how you run the query and assign the result, so it's hard to be sure. Can you add that to the code in the question?

    – ADyson
    Mar 28 at 0:29











  • Not to worry, i placed the data seek elsewhere, now the variable is being recognised. However, i do also appreciate the array solution, thanks for the help!

    – Brad Archer
    Mar 28 at 0:35















0















The problem is that fetch_assoc() returns the next row in the resultset, unless there are no more left (in which case it returns NULL - see docs).



Your first while loop runs until there are no more results. Therefore when you start the second while loop, there are still...you guessed it: no more results. You already used them up. Therefore the first call to fetch_assoc() in the second loop returns NULL immediately, and so the loop condition is never met, and the loop never executes.



There are two different ways to solve this:



1) Reset the result pointer to the start of the resultset. Somewhere between the two loops, write



mysqli_data_seek($show_teams, 0);


See docs for more info.



2) Read all the data into a PHP array, which you can then loop through as many times as you like using foreach:



 <?php
$teams = array();
while ($team = mysqli_fetch_assoc($show_teams))
$teams[] = $team;

?>

<form class="seed-form">
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
foreach ($teams as $team) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?><!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
foreach ($teams as $team) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>





share|improve this answer

























  • Both methods are throwing Notice: Undefined variable: show_teams in C:xampphtdocsfriendlyfixturestables.php on line 96 and Warning: mysqli_data_seek() expects parameter 1 to be mysqli_result, null given in C:xampphtdocsfriendlyfixturestables.php on line 101

    – Brad Archer
    Mar 28 at 0:17












  • According to the code in your question, $show_teams is your query result object. So that's why I used that name. Maybe you changed it in the meantime or something?

    – ADyson
    Mar 28 at 0:18












  • none of the variable names were changed hence why im extremely confused, dont suppose you have any clue?

    – Brad Archer
    Mar 28 at 0:26











  • I can't see how you run the query and assign the result, so it's hard to be sure. Can you add that to the code in the question?

    – ADyson
    Mar 28 at 0:29











  • Not to worry, i placed the data seek elsewhere, now the variable is being recognised. However, i do also appreciate the array solution, thanks for the help!

    – Brad Archer
    Mar 28 at 0:35













0














0










0









The problem is that fetch_assoc() returns the next row in the resultset, unless there are no more left (in which case it returns NULL - see docs).



Your first while loop runs until there are no more results. Therefore when you start the second while loop, there are still...you guessed it: no more results. You already used them up. Therefore the first call to fetch_assoc() in the second loop returns NULL immediately, and so the loop condition is never met, and the loop never executes.



There are two different ways to solve this:



1) Reset the result pointer to the start of the resultset. Somewhere between the two loops, write



mysqli_data_seek($show_teams, 0);


See docs for more info.



2) Read all the data into a PHP array, which you can then loop through as many times as you like using foreach:



 <?php
$teams = array();
while ($team = mysqli_fetch_assoc($show_teams))
$teams[] = $team;

?>

<form class="seed-form">
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
foreach ($teams as $team) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?><!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
foreach ($teams as $team) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>





share|improve this answer













The problem is that fetch_assoc() returns the next row in the resultset, unless there are no more left (in which case it returns NULL - see docs).



Your first while loop runs until there are no more results. Therefore when you start the second while loop, there are still...you guessed it: no more results. You already used them up. Therefore the first call to fetch_assoc() in the second loop returns NULL immediately, and so the loop condition is never met, and the loop never executes.



There are two different ways to solve this:



1) Reset the result pointer to the start of the resultset. Somewhere between the two loops, write



mysqli_data_seek($show_teams, 0);


See docs for more info.



2) Read all the data into a PHP array, which you can then loop through as many times as you like using foreach:



 <?php
$teams = array();
while ($team = mysqli_fetch_assoc($show_teams))
$teams[] = $team;

?>

<form class="seed-form">
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
foreach ($teams as $team) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?><!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>
<select name="team" required>
<option value='Holder' disabled selected>Select Team</option> <!--Placeholder for Select-->
<?php
foreach ($teams as $team) ?>
<option value="<?php echo $team["team_id"]; ?>"><?php echo $team["team_name"]; ?></option>
<?php ?> <!--FILLS SELECT BOX WITH TEAMS FROM THAT CUP-->
</select>






share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 28 at 0:03









ADysonADyson

29.3k12 gold badges28 silver badges46 bronze badges




29.3k12 gold badges28 silver badges46 bronze badges















  • Both methods are throwing Notice: Undefined variable: show_teams in C:xampphtdocsfriendlyfixturestables.php on line 96 and Warning: mysqli_data_seek() expects parameter 1 to be mysqli_result, null given in C:xampphtdocsfriendlyfixturestables.php on line 101

    – Brad Archer
    Mar 28 at 0:17












  • According to the code in your question, $show_teams is your query result object. So that's why I used that name. Maybe you changed it in the meantime or something?

    – ADyson
    Mar 28 at 0:18












  • none of the variable names were changed hence why im extremely confused, dont suppose you have any clue?

    – Brad Archer
    Mar 28 at 0:26











  • I can't see how you run the query and assign the result, so it's hard to be sure. Can you add that to the code in the question?

    – ADyson
    Mar 28 at 0:29











  • Not to worry, i placed the data seek elsewhere, now the variable is being recognised. However, i do also appreciate the array solution, thanks for the help!

    – Brad Archer
    Mar 28 at 0:35

















  • Both methods are throwing Notice: Undefined variable: show_teams in C:xampphtdocsfriendlyfixturestables.php on line 96 and Warning: mysqli_data_seek() expects parameter 1 to be mysqli_result, null given in C:xampphtdocsfriendlyfixturestables.php on line 101

    – Brad Archer
    Mar 28 at 0:17












  • According to the code in your question, $show_teams is your query result object. So that's why I used that name. Maybe you changed it in the meantime or something?

    – ADyson
    Mar 28 at 0:18












  • none of the variable names were changed hence why im extremely confused, dont suppose you have any clue?

    – Brad Archer
    Mar 28 at 0:26











  • I can't see how you run the query and assign the result, so it's hard to be sure. Can you add that to the code in the question?

    – ADyson
    Mar 28 at 0:29











  • Not to worry, i placed the data seek elsewhere, now the variable is being recognised. However, i do also appreciate the array solution, thanks for the help!

    – Brad Archer
    Mar 28 at 0:35
















Both methods are throwing Notice: Undefined variable: show_teams in C:xampphtdocsfriendlyfixturestables.php on line 96 and Warning: mysqli_data_seek() expects parameter 1 to be mysqli_result, null given in C:xampphtdocsfriendlyfixturestables.php on line 101

– Brad Archer
Mar 28 at 0:17






Both methods are throwing Notice: Undefined variable: show_teams in C:xampphtdocsfriendlyfixturestables.php on line 96 and Warning: mysqli_data_seek() expects parameter 1 to be mysqli_result, null given in C:xampphtdocsfriendlyfixturestables.php on line 101

– Brad Archer
Mar 28 at 0:17














According to the code in your question, $show_teams is your query result object. So that's why I used that name. Maybe you changed it in the meantime or something?

– ADyson
Mar 28 at 0:18






According to the code in your question, $show_teams is your query result object. So that's why I used that name. Maybe you changed it in the meantime or something?

– ADyson
Mar 28 at 0:18














none of the variable names were changed hence why im extremely confused, dont suppose you have any clue?

– Brad Archer
Mar 28 at 0:26





none of the variable names were changed hence why im extremely confused, dont suppose you have any clue?

– Brad Archer
Mar 28 at 0:26













I can't see how you run the query and assign the result, so it's hard to be sure. Can you add that to the code in the question?

– ADyson
Mar 28 at 0:29





I can't see how you run the query and assign the result, so it's hard to be sure. Can you add that to the code in the question?

– ADyson
Mar 28 at 0:29













Not to worry, i placed the data seek elsewhere, now the variable is being recognised. However, i do also appreciate the array solution, thanks for the help!

– Brad Archer
Mar 28 at 0:35





Not to worry, i placed the data seek elsewhere, now the variable is being recognised. However, i do also appreciate the array solution, thanks for the help!

– Brad Archer
Mar 28 at 0:35








Got a question that you can’t ask on public Stack Overflow? Learn more about sharing private information with Stack Overflow for Teams.







Got a question that you can’t ask on public Stack Overflow? Learn more about sharing private information with Stack Overflow for Teams.



















draft saved

draft discarded
















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55388200%2freused-while-loop-only-working-for-one-selection-box%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Kamusi Yaliyomo Aina za kamusi | Muundo wa kamusi | Faida za kamusi | Dhima ya picha katika kamusi | Marejeo | Tazama pia | Viungo vya nje | UrambazajiKuhusu kamusiGo-SwahiliWiki-KamusiKamusi ya Kiswahili na Kiingerezakuihariri na kuongeza habari

SQL error code 1064 with creating Laravel foreign keysForeign key constraints: When to use ON UPDATE and ON DELETEDropping column with foreign key Laravel error: General error: 1025 Error on renameLaravel SQL Can't create tableLaravel Migration foreign key errorLaravel php artisan migrate:refresh giving a syntax errorSQLSTATE[42S01]: Base table or view already exists or Base table or view already exists: 1050 Tableerror in migrating laravel file to xampp serverSyntax error or access violation: 1064:syntax to use near 'unsigned not null, modelName varchar(191) not null, title varchar(191) not nLaravel cannot create new table field in mysqlLaravel 5.7:Last migration creates table but is not registered in the migration table

은진 송씨 목차 역사 본관 분파 인물 조선 왕실과의 인척 관계 집성촌 항렬자 인구 같이 보기 각주 둘러보기 메뉴은진 송씨세종실록 149권, 지리지 충청도 공주목 은진현