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Regex pattern for first name without whitespace or numbers

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-2

I have this regex pattern

/^[^-s][^0-9][a-zA-Zs-]+$/

I am a bit confused on why when I test it on https://www.regextester.com/
My pattern allows one single number to be added before the string. Meaning that if I type in '2Mantas' it will still accept it whereas '22Mantas' will fail the test. I do not want any numbers or whitespace to be allowed. Any ideas anyone?

regex

share|improve this question

asked Mar 28 at 20:07

Mantas StanionisMantas Stanionis

3055 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Please provide some sample inputs that should pass, and some that should fail.
  
  – esqew
  Mar 28 at 20:09
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  any string passes if you include one number before it '5steve' '2daniel' etc. but '22steve' would fail.
  
  – Mantas Stanionis
  Mar 28 at 20:11
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Yes, you've indicated that above. Can you provide some inputs that should and should not pass? For example, we can assume that 5steve and 2daniel should not pass, but can you give us an example for what should pass?
  
  – esqew
  Mar 28 at 20:12
  

  
  
  
  

add a comment
 | 

-2

I have this regex pattern

/^[^-s][^0-9][a-zA-Zs-]+$/

I am a bit confused on why when I test it on https://www.regextester.com/
My pattern allows one single number to be added before the string. Meaning that if I type in '2Mantas' it will still accept it whereas '22Mantas' will fail the test. I do not want any numbers or whitespace to be allowed. Any ideas anyone?

regex

share|improve this question

asked Mar 28 at 20:07

Mantas StanionisMantas Stanionis

3055 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Please provide some sample inputs that should pass, and some that should fail.
  
  – esqew
  Mar 28 at 20:09
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  any string passes if you include one number before it '5steve' '2daniel' etc. but '22steve' would fail.
  
  – Mantas Stanionis
  Mar 28 at 20:11
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Yes, you've indicated that above. Can you provide some inputs that should and should not pass? For example, we can assume that 5steve and 2daniel should not pass, but can you give us an example for what should pass?
  
  – esqew
  Mar 28 at 20:12
  

  
  
  
  

add a comment
 | 

I have this regex pattern

/^[^-s][^0-9][a-zA-Zs-]+$/

I am a bit confused on why when I test it on https://www.regextester.com/
My pattern allows one single number to be added before the string. Meaning that if I type in '2Mantas' it will still accept it whereas '22Mantas' will fail the test. I do not want any numbers or whitespace to be allowed. Any ideas anyone?

regex

share|improve this question

asked Mar 28 at 20:07

Mantas StanionisMantas Stanionis

3055 bronze badges

share|improve this question

asked Mar 28 at 20:07

Mantas StanionisMantas Stanionis

3055 bronze badges

share|improve this question

asked Mar 28 at 20:07

Mantas StanionisMantas Stanionis

3055 bronze badges

asked Mar 28 at 20:07

Mantas StanionisMantas Stanionis

3055 bronze badges

asked Mar 28 at 20:07

Mantas StanionisMantas Stanionis

3055 bronze badges

3 Answers
3

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0

You have two negation groups so it is saying the first character cannot be whitespace and the second character cannot be a number. If you put the whitespace and digit in the first brackets it will work as desired.

^[^-sd][a-zA-Zs-]+$

share|improve this answer

answered Mar 28 at 20:12

bwingbwing

47466 silver badges99 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  amazing. thank you for the explanation too!
  
  – Mantas Stanionis
  Mar 28 at 20:13
  

  
  
  
  

add a comment
 | 

0

The first two rules in your current regular expression break down to the following:

1. 
   ^[^s-] - the first character in the string should not be a whitespace or a hyphen. This explains why 2steve is accepted - 2 is not a whitespace or a hyphen character.


2. 
   [^0-9] - the second character in the strnig should not be a digit. This iexplains why 22steve is not accepted - the 2 in the second position is a digit, which violates this rule.

Assuming you don't want anything but capital and lowercase letters in your first name input, and the name shouldn't start with a whitespace or hyphen character, you can simplify to a subset of your current regular expression:

/^[A-Za-z][A-Za-z-s]+$/

^Regex101

share|improve this answer

edited Mar 28 at 20:13

answered Mar 28 at 20:11

esqewesqew

24k2121 gold badges7979 silver badges110110 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  if you add a single digit before the name it still passes on regextester.com
  
  – Mantas Stanionis
  Mar 28 at 20:12
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MantasStanionis - yes, you're correct, my mistake, I've updated my regex.
  
  – esqew
  Mar 28 at 20:14
  

  
  
  
  

add a comment
 | 

0

This should work

Get string, that starts with exactly one digit, and after this digits should be expression, that contains only strings (greedy)

^d1([a-zA-Z]+)

https://regex101.com/r/wtBwd7/1

share|improve this answer

answered Mar 28 at 20:18

Kamil NajaKamil Naja

2,49933 gold badges1414 silver badges2727 bronze badges

add a comment
 | 

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0

You have two negation groups so it is saying the first character cannot be whitespace and the second character cannot be a number. If you put the whitespace and digit in the first brackets it will work as desired.

^[^-sd][a-zA-Zs-]+$

share|improve this answer

answered Mar 28 at 20:12

bwingbwing

47466 silver badges99 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  amazing. thank you for the explanation too!
  
  – Mantas Stanionis
  Mar 28 at 20:13
  

  
  
  
  

add a comment
 | 

0

You have two negation groups so it is saying the first character cannot be whitespace and the second character cannot be a number. If you put the whitespace and digit in the first brackets it will work as desired.

^[^-sd][a-zA-Zs-]+$

share|improve this answer

answered Mar 28 at 20:12

bwingbwing

47466 silver badges99 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  amazing. thank you for the explanation too!
  
  – Mantas Stanionis
  Mar 28 at 20:13
  

  
  
  
  

add a comment
 | 

You have two negation groups so it is saying the first character cannot be whitespace and the second character cannot be a number. If you put the whitespace and digit in the first brackets it will work as desired.

^[^-sd][a-zA-Zs-]+$

share|improve this answer

answered Mar 28 at 20:12

bwingbwing

47466 silver badges99 bronze badges

^[^-sd][a-zA-Zs-]+$

share|improve this answer

answered Mar 28 at 20:12

bwingbwing

47466 silver badges99 bronze badges

answered Mar 28 at 20:12

bwingbwing

47466 silver badges99 bronze badges

answered Mar 28 at 20:12

bwingbwing

47466 silver badges99 bronze badges

0

The first two rules in your current regular expression break down to the following:

1. 
   ^[^s-] - the first character in the string should not be a whitespace or a hyphen. This explains why 2steve is accepted - 2 is not a whitespace or a hyphen character.


2. 
   [^0-9] - the second character in the strnig should not be a digit. This iexplains why 22steve is not accepted - the 2 in the second position is a digit, which violates this rule.

Assuming you don't want anything but capital and lowercase letters in your first name input, and the name shouldn't start with a whitespace or hyphen character, you can simplify to a subset of your current regular expression:

/^[A-Za-z][A-Za-z-s]+$/

^Regex101

share|improve this answer

edited Mar 28 at 20:13

answered Mar 28 at 20:11

esqewesqew

24k2121 gold badges7979 silver badges110110 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  if you add a single digit before the name it still passes on regextester.com
  
  – Mantas Stanionis
  Mar 28 at 20:12
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MantasStanionis - yes, you're correct, my mistake, I've updated my regex.
  
  – esqew
  Mar 28 at 20:14
  

  
  
  
  

add a comment
 | 

0

The first two rules in your current regular expression break down to the following:

1. 
   ^[^s-] - the first character in the string should not be a whitespace or a hyphen. This explains why 2steve is accepted - 2 is not a whitespace or a hyphen character.


2. 
   [^0-9] - the second character in the strnig should not be a digit. This iexplains why 22steve is not accepted - the 2 in the second position is a digit, which violates this rule.

Assuming you don't want anything but capital and lowercase letters in your first name input, and the name shouldn't start with a whitespace or hyphen character, you can simplify to a subset of your current regular expression:

/^[A-Za-z][A-Za-z-s]+$/

^Regex101

share|improve this answer

edited Mar 28 at 20:13

answered Mar 28 at 20:11

esqewesqew

24k2121 gold badges7979 silver badges110110 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  if you add a single digit before the name it still passes on regextester.com
  
  – Mantas Stanionis
  Mar 28 at 20:12
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MantasStanionis - yes, you're correct, my mistake, I've updated my regex.
  
  – esqew
  Mar 28 at 20:14
  

  
  
  
  

add a comment
 | 

The first two rules in your current regular expression break down to the following:

1. 
   ^[^s-] - the first character in the string should not be a whitespace or a hyphen. This explains why 2steve is accepted - 2 is not a whitespace or a hyphen character.


2. 
   [^0-9] - the second character in the strnig should not be a digit. This iexplains why 22steve is not accepted - the 2 in the second position is a digit, which violates this rule.

Assuming you don't want anything but capital and lowercase letters in your first name input, and the name shouldn't start with a whitespace or hyphen character, you can simplify to a subset of your current regular expression:

/^[A-Za-z][A-Za-z-s]+$/

^Regex101

share|improve this answer

edited Mar 28 at 20:13

answered Mar 28 at 20:11

esqewesqew

24k2121 gold badges7979 silver badges110110 bronze badges

/^[A-Za-z][A-Za-z-s]+$/

share|improve this answer

edited Mar 28 at 20:13

answered Mar 28 at 20:11

esqewesqew

24k2121 gold badges7979 silver badges110110 bronze badges

answered Mar 28 at 20:11

esqewesqew

24k2121 gold badges7979 silver badges110110 bronze badges

answered Mar 28 at 20:11

esqewesqew

24k2121 gold badges7979 silver badges110110 bronze badges

0

This should work

Get string, that starts with exactly one digit, and after this digits should be expression, that contains only strings (greedy)

^d1([a-zA-Z]+)

https://regex101.com/r/wtBwd7/1

share|improve this answer

answered Mar 28 at 20:18

Kamil NajaKamil Naja

2,49933 gold badges1414 silver badges2727 bronze badges

add a comment
 | 

0

This should work

Get string, that starts with exactly one digit, and after this digits should be expression, that contains only strings (greedy)

^d1([a-zA-Z]+)

https://regex101.com/r/wtBwd7/1

share|improve this answer

answered Mar 28 at 20:18

Kamil NajaKamil Naja

2,49933 gold badges1414 silver badges2727 bronze badges

add a comment
 | 

This should work

Get string, that starts with exactly one digit, and after this digits should be expression, that contains only strings (greedy)

^d1([a-zA-Z]+)

https://regex101.com/r/wtBwd7/1

share|improve this answer

answered Mar 28 at 20:18

Kamil NajaKamil Naja

2,49933 gold badges1414 silver badges2727 bronze badges

^d1([a-zA-Z]+)

share|improve this answer

answered Mar 28 at 20:18

Kamil NajaKamil Naja

2,49933 gold badges1414 silver badges2727 bronze badges

answered Mar 28 at 20:18

Kamil NajaKamil Naja

2,49933 gold badges1414 silver badges2727 bronze badges

answered Mar 28 at 20:18

Kamil NajaKamil Naja

2,49933 gold badges1414 silver badges2727 bronze badges