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Save string from firestore to variable
Stream builder from firestore to flutterUsing Stream Building with a specific Firestore documentFlutter FireStoreHow do you get the document id after adding document in Cloud Firestore in DartFlutter Firestore NoSuchMethodErrorFlutter/Dart: save data in different documents in firestoreFirestore snapshots.map(_transform) has no data in StreamBuilderFlutter: Firebase auth and Firestore snapshot streamHow to retrieve specific user details from firestore with flutterReading two streams from Cloud Firestore and merging the streams
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I am trying to get a value from firestore and save it to a variable in flutter. I tried using StreamBuilder, but since i am not building a widget it does not work.
To clarify my problem, I am trying to get a url from a firestore document and then open it when i press a button in the app.
I also tried to adapt code i found in another question, but that returns null.
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
var data;
docRef.get().then((datasnapshot)
data = datasnapshot.data['url'];
);
return data;
The collection is called information, the document pdf, and the field url
dart
flutter google-cloud-firestore asked Mar 28 at 18:18
Hannes HultergårdHannes Hultergård
426 bronze badges
add a comment
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I am trying to get a value from firestore and save it to a variable in flutter. I tried using StreamBuilder, but since i am not building a widget it does not work.
To clarify my problem, I am trying to get a url from a firestore document and then open it when i press a button in the app.
I also tried to adapt code i found in another question, but that returns null.
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
var data;
docRef.get().then((datasnapshot)
data = datasnapshot.data['url'];
);
return data;
The collection is called information, the document pdf, and the field url
dart
flutter google-cloud-firestore asked Mar 28 at 18:18
Hannes HultergårdHannes Hultergård
426 bronze badges
add a comment
|
I am trying to get a value from firestore and save it to a variable in flutter. I tried using StreamBuilder, but since i am not building a widget it does not work.
To clarify my problem, I am trying to get a url from a firestore document and then open it when i press a button in the app.
I also tried to adapt code i found in another question, but that returns null.
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
var data;
docRef.get().then((datasnapshot)
data = datasnapshot.data['url'];
);
return data;
The collection is called information, the document pdf, and the field url
dart
flutter google-cloud-firestore asked Mar 28 at 18:18
Hannes HultergårdHannes Hultergård
426 bronze badges
I am trying to get a value from firestore and save it to a variable in flutter. I tried using StreamBuilder, but since i am not building a widget it does not work.
To clarify my problem, I am trying to get a url from a firestore document and then open it when i press a button in the app.
I also tried to adapt code i found in another question, but that returns null.
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
var data;
docRef.get().then((datasnapshot)
data = datasnapshot.data['url'];
);
return data;
The collection is called information, the document pdf, and the field url
dart
flutter google-cloud-firestore dart
flutter google-cloud-firestore asked Mar 28 at 18:18
Hannes HultergårdHannes Hultergård
426 bronze badges
asked Mar 28 at 18:18
Hannes HultergårdHannes Hultergård
426 bronze badges
asked Mar 28 at 18:18
Hannes HultergårdHannes Hultergård
426 bronze badges
asked Mar 28 at 18:18
Hannes HultergårdHannes Hultergård
426 bronze badges
asked Mar 28 at 18:18
Hannes HultergårdHannes Hultergård
426 bronze badges
426 bronze badges
add a comment
|
add a comment
|
2 Answers
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oldest
votes
This method will return null because you are not waiting for the get() future to return before you return data. docRef.get() is a Future, so it will execute asychronously. Meanwhile, your program will move on to the next line, which is return data.
Something like this would do what you want I think:
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
return docRef.get().then((datasnapshot)
return datasnapshot.data['url'];
);
answered Mar 28 at 19:12
KrisKris
5233 silver badges10 bronze badges
add a comment
|
Since _getUrl is already marked as async you can also use await in its body to return the right value:
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
await datasnapshot = docRef.get();
let data = datasnapshot.data['url'];
return data;
answered Mar 28 at 19:53
Frank van PuffelenFrank van Puffelen
277k37 gold badges449 silver badges469 bronze badges
add a comment
|
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
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active
oldest
votes
This method will return null because you are not waiting for the get() future to return before you return data. docRef.get() is a Future, so it will execute asychronously. Meanwhile, your program will move on to the next line, which is return data.
Something like this would do what you want I think:
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
return docRef.get().then((datasnapshot)
return datasnapshot.data['url'];
);
answered Mar 28 at 19:12
KrisKris
5233 silver badges10 bronze badges
add a comment
|
This method will return null because you are not waiting for the get() future to return before you return data. docRef.get() is a Future, so it will execute asychronously. Meanwhile, your program will move on to the next line, which is return data.
Something like this would do what you want I think:
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
return docRef.get().then((datasnapshot)
return datasnapshot.data['url'];
);
answered Mar 28 at 19:12
KrisKris
5233 silver badges10 bronze badges
add a comment
|
This method will return null because you are not waiting for the get() future to return before you return data. docRef.get() is a Future, so it will execute asychronously. Meanwhile, your program will move on to the next line, which is return data.
Something like this would do what you want I think:
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
return docRef.get().then((datasnapshot)
return datasnapshot.data['url'];
);
answered Mar 28 at 19:12
KrisKris
5233 silver badges10 bronze badges
This method will return null because you are not waiting for the get() future to return before you return data. docRef.get() is a Future, so it will execute asychronously. Meanwhile, your program will move on to the next line, which is return data.
Something like this would do what you want I think:
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
return docRef.get().then((datasnapshot)
return datasnapshot.data['url'];
);
answered Mar 28 at 19:12
KrisKris
5233 silver badges10 bronze badges
answered Mar 28 at 19:12
KrisKris
5233 silver badges10 bronze badges
answered Mar 28 at 19:12
KrisKris
5233 silver badges10 bronze badges
answered Mar 28 at 19:12
KrisKris
5233 silver badges10 bronze badges
5233 silver badges10 bronze badges
add a comment
|
add a comment
|
Since _getUrl is already marked as async you can also use await in its body to return the right value:
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
await datasnapshot = docRef.get();
let data = datasnapshot.data['url'];
return data;
answered Mar 28 at 19:53
Frank van PuffelenFrank van Puffelen
277k37 gold badges449 silver badges469 bronze badges
add a comment
|
Since _getUrl is already marked as async you can also use await in its body to return the right value:
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
await datasnapshot = docRef.get();
let data = datasnapshot.data['url'];
return data;
answered Mar 28 at 19:53
Frank van PuffelenFrank van Puffelen
277k37 gold badges449 silver badges469 bronze badges
add a comment
|
Since _getUrl is already marked as async you can also use await in its body to return the right value:
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
await datasnapshot = docRef.get();
let data = datasnapshot.data['url'];
return data;
answered Mar 28 at 19:53
Frank van PuffelenFrank van Puffelen
277k37 gold badges449 silver badges469 bronze badges
Since _getUrl is already marked as async you can also use await in its body to return the right value:
Future _getUrl() async
DocumentReference docRef = Firestore.instance.collection('information').document('pdf');
await datasnapshot = docRef.get();
let data = datasnapshot.data['url'];
return data;
answered Mar 28 at 19:53
Frank van PuffelenFrank van Puffelen
277k37 gold badges449 silver badges469 bronze badges
answered Mar 28 at 19:53
Frank van PuffelenFrank van Puffelen
277k37 gold badges449 silver badges469 bronze badges
answered Mar 28 at 19:53
Frank van PuffelenFrank van Puffelen
277k37 gold badges449 silver badges469 bronze badges
answered Mar 28 at 19:53
Frank van PuffelenFrank van Puffelen
277k37 gold badges449 silver badges469 bronze badges
277k37 gold badges449 silver badges469 bronze badges
add a comment
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add a comment
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