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Comparing TreeMap of ArrayLists
Create ArrayList from arrayWhen to use LinkedList over ArrayList in Java?How to get the last value of an ArrayListInitialization of an ArrayList in one lineComparing Java enum members: == or equals()?Sort ArrayList of custom Objects by propertyDifference between HashMap, LinkedHashMap and TreeMapConverting 'ArrayList<String> to 'String[]' in JavaConvert ArrayList<String> to String[] arrayhow to count an element in each index of Arraylist in c#
So I'm doing something kind of funky...
I have a a TreeMap of ArrayLists. <Integer, ArrayList<Integer>>
I need to compare the each ArrayList to see if there is a common element.
How would I do this?
Here is what I think in theory should work, but its no go.
for(int i = 1; i < treemap.size(); i++)
//cycle this users movies "j"
for(int j=2; j < currentArray.size(); j++)
compareArray = treemap.get(j);
//cylce next users movies "k"
for(int k=1; k<compareArray.size(); k++)
if(currentArray.get(i) == compareArray.get(k))
if (treemap.containsKey(i))
ArrayList<Integer> list3 = treemap.get(i);
list3.add(currentArray.get(j));
treemap2.remove(i);
treemap2.put(i, list3);
if (!treemap.containsKey(i))
ArrayList<Integer> list4 = new ArrayList<Integer>();
list4.add(currentArray.get(j));
treemap2.put(i, list4);
currentArray = treemap.get(i+1);
java arraylist treemap
add a comment |
So I'm doing something kind of funky...
I have a a TreeMap of ArrayLists. <Integer, ArrayList<Integer>>
I need to compare the each ArrayList to see if there is a common element.
How would I do this?
Here is what I think in theory should work, but its no go.
for(int i = 1; i < treemap.size(); i++)
//cycle this users movies "j"
for(int j=2; j < currentArray.size(); j++)
compareArray = treemap.get(j);
//cylce next users movies "k"
for(int k=1; k<compareArray.size(); k++)
if(currentArray.get(i) == compareArray.get(k))
if (treemap.containsKey(i))
ArrayList<Integer> list3 = treemap.get(i);
list3.add(currentArray.get(j));
treemap2.remove(i);
treemap2.put(i, list3);
if (!treemap.containsKey(i))
ArrayList<Integer> list4 = new ArrayList<Integer>();
list4.add(currentArray.get(j));
treemap2.put(i, list4);
currentArray = treemap.get(i+1);
java arraylist treemap
1
You have to first attempt something. If it doesn't work, then you post the code, error message, actual vs. expected behavior
– Juan Mendes
Mar 21 at 20:35
Yes, I'm aware to try something... But I can't begin to picture a starting point.
– Hooch
Mar 21 at 20:41
1
map.values() gets you all the ArrayList<Integer>'s. That's your starting point
– Not a JD
Mar 21 at 20:42
So I updated my post with what I believe should be working... I'd imagine it's something stupid, or maybe I just have a bad idea all around.
– Hooch
Mar 22 at 1:40
add a comment |
So I'm doing something kind of funky...
I have a a TreeMap of ArrayLists. <Integer, ArrayList<Integer>>
I need to compare the each ArrayList to see if there is a common element.
How would I do this?
Here is what I think in theory should work, but its no go.
for(int i = 1; i < treemap.size(); i++)
//cycle this users movies "j"
for(int j=2; j < currentArray.size(); j++)
compareArray = treemap.get(j);
//cylce next users movies "k"
for(int k=1; k<compareArray.size(); k++)
if(currentArray.get(i) == compareArray.get(k))
if (treemap.containsKey(i))
ArrayList<Integer> list3 = treemap.get(i);
list3.add(currentArray.get(j));
treemap2.remove(i);
treemap2.put(i, list3);
if (!treemap.containsKey(i))
ArrayList<Integer> list4 = new ArrayList<Integer>();
list4.add(currentArray.get(j));
treemap2.put(i, list4);
currentArray = treemap.get(i+1);
java arraylist treemap
So I'm doing something kind of funky...
I have a a TreeMap of ArrayLists. <Integer, ArrayList<Integer>>
I need to compare the each ArrayList to see if there is a common element.
How would I do this?
Here is what I think in theory should work, but its no go.
for(int i = 1; i < treemap.size(); i++)
//cycle this users movies "j"
for(int j=2; j < currentArray.size(); j++)
compareArray = treemap.get(j);
//cylce next users movies "k"
for(int k=1; k<compareArray.size(); k++)
if(currentArray.get(i) == compareArray.get(k))
if (treemap.containsKey(i))
ArrayList<Integer> list3 = treemap.get(i);
list3.add(currentArray.get(j));
treemap2.remove(i);
treemap2.put(i, list3);
if (!treemap.containsKey(i))
ArrayList<Integer> list4 = new ArrayList<Integer>();
list4.add(currentArray.get(j));
treemap2.put(i, list4);
currentArray = treemap.get(i+1);
java arraylist treemap
java arraylist treemap
edited Mar 22 at 1:39
Hooch
asked Mar 21 at 20:32
HoochHooch
257
257
1
You have to first attempt something. If it doesn't work, then you post the code, error message, actual vs. expected behavior
– Juan Mendes
Mar 21 at 20:35
Yes, I'm aware to try something... But I can't begin to picture a starting point.
– Hooch
Mar 21 at 20:41
1
map.values() gets you all the ArrayList<Integer>'s. That's your starting point
– Not a JD
Mar 21 at 20:42
So I updated my post with what I believe should be working... I'd imagine it's something stupid, or maybe I just have a bad idea all around.
– Hooch
Mar 22 at 1:40
add a comment |
1
You have to first attempt something. If it doesn't work, then you post the code, error message, actual vs. expected behavior
– Juan Mendes
Mar 21 at 20:35
Yes, I'm aware to try something... But I can't begin to picture a starting point.
– Hooch
Mar 21 at 20:41
1
map.values() gets you all the ArrayList<Integer>'s. That's your starting point
– Not a JD
Mar 21 at 20:42
So I updated my post with what I believe should be working... I'd imagine it's something stupid, or maybe I just have a bad idea all around.
– Hooch
Mar 22 at 1:40
1
1
You have to first attempt something. If it doesn't work, then you post the code, error message, actual vs. expected behavior
– Juan Mendes
Mar 21 at 20:35
You have to first attempt something. If it doesn't work, then you post the code, error message, actual vs. expected behavior
– Juan Mendes
Mar 21 at 20:35
Yes, I'm aware to try something... But I can't begin to picture a starting point.
– Hooch
Mar 21 at 20:41
Yes, I'm aware to try something... But I can't begin to picture a starting point.
– Hooch
Mar 21 at 20:41
1
1
map.values() gets you all the ArrayList<Integer>'s. That's your starting point
– Not a JD
Mar 21 at 20:42
map.values() gets you all the ArrayList<Integer>'s. That's your starting point
– Not a JD
Mar 21 at 20:42
So I updated my post with what I believe should be working... I'd imagine it's something stupid, or maybe I just have a bad idea all around.
– Hooch
Mar 22 at 1:40
So I updated my post with what I believe should be working... I'd imagine it's something stupid, or maybe I just have a bad idea all around.
– Hooch
Mar 22 at 1:40
add a comment |
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1
You have to first attempt something. If it doesn't work, then you post the code, error message, actual vs. expected behavior
– Juan Mendes
Mar 21 at 20:35
Yes, I'm aware to try something... But I can't begin to picture a starting point.
– Hooch
Mar 21 at 20:41
1
map.values() gets you all the ArrayList<Integer>'s. That's your starting point
– Not a JD
Mar 21 at 20:42
So I updated my post with what I believe should be working... I'd imagine it's something stupid, or maybe I just have a bad idea all around.
– Hooch
Mar 22 at 1:40