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Convert a multi-line string into a javascript object

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;

1

I've my raw data that looks like this:

Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
x1000

I'd like to convert into a loopable object with keys and values something like:

var d = 
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
;

How can convert this to a javascript object? I'm thinking stringify may be a good starting point. FirstName have different values. They are just for the purpose of demonstration

javascript regex

share|improve this question

edited Mar 25 at 18:00

adiga

12.4k62745

asked Mar 22 at 5:36

EthanPrisonMikeEthanPrisonMike

136

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Use regex to extract data
  
  – Pranav C Balan
  Mar 22 at 5:39
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  maybe use regex to extract data and convert it to object like you want.
  
  – vibhor1997a
  Mar 22 at 5:39
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yea it's not JSON. above is it's format when pasted in too notepad
  
  – EthanPrisonMike
  Mar 22 at 5:40
  
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  Please post the actual data. You cannot have duplicate keys in an object. Are First Name etc just placeholders?
  
  – adiga
  Mar 22 at 5:40
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @EthanPrisonMike please use better sample data in your question, something that actually makes sense as a JS object. What is (Details-Details)? Is it literally that or something else?
  
  – Phil
  Mar 22 at 5:42
  
  

  
  
  
  

 | 
show 4 more comments

1

I've my raw data that looks like this:

Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
x1000

I'd like to convert into a loopable object with keys and values something like:

var d = 
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
;

How can convert this to a javascript object? I'm thinking stringify may be a good starting point. FirstName have different values. They are just for the purpose of demonstration

javascript regex

share|improve this question

edited Mar 25 at 18:00

adiga

12.4k62745

asked Mar 22 at 5:36

EthanPrisonMikeEthanPrisonMike

136

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Use regex to extract data
  
  – Pranav C Balan
  Mar 22 at 5:39
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  maybe use regex to extract data and convert it to object like you want.
  
  – vibhor1997a
  Mar 22 at 5:39
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yea it's not JSON. above is it's format when pasted in too notepad
  
  – EthanPrisonMike
  Mar 22 at 5:40
  
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  Please post the actual data. You cannot have duplicate keys in an object. Are First Name etc just placeholders?
  
  – adiga
  Mar 22 at 5:40
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @EthanPrisonMike please use better sample data in your question, something that actually makes sense as a JS object. What is (Details-Details)? Is it literally that or something else?
  
  – Phil
  Mar 22 at 5:42
  
  

  
  
  
  

 | 
show 4 more comments

I've my raw data that looks like this:

Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
x1000

I'd like to convert into a loopable object with keys and values something like:

var d = 
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
;

How can convert this to a javascript object? I'm thinking stringify may be a good starting point. FirstName have different values. They are just for the purpose of demonstration

javascript regex

share|improve this question

edited Mar 25 at 18:00

adiga

12.4k62745

asked Mar 22 at 5:36

EthanPrisonMikeEthanPrisonMike

136

Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
Last Name, First Name (Details-Details) #ID
x1000

var d = 
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
 "FirstName LastName": "#ID";
;

share|improve this question

edited Mar 25 at 18:00

adiga

12.4k62745

asked Mar 22 at 5:36

EthanPrisonMikeEthanPrisonMike

136

share|improve this question

edited Mar 25 at 18:00

adiga

12.4k62745

asked Mar 22 at 5:36

EthanPrisonMikeEthanPrisonMike

136

edited Mar 25 at 18:00

adiga

12.4k62745

edited Mar 25 at 18:00

adiga

12.4k62745

asked Mar 22 at 5:36

EthanPrisonMikeEthanPrisonMike

136

asked Mar 22 at 5:36

EthanPrisonMikeEthanPrisonMike

136

2 Answers
2

active

oldest

votes

1

• 
  split the string at n
  


• loop through each line using map
  


• Use match with the regex /(.*), (.*) (.*)s+(.*)/ to get first name, last name into capturing groups (demo)


• create an object from the array using reduce
  

let str =
`LastName1, FirstName1 (Details-Details) #ID1
LastName2, FirstName2 (Details-Details) #ID2
LastName3, FirstName3 (Details-Details) #ID3`

let output = str.split("n")
 .map(a => a.match(/(.*), (.*) (.*)s+(.*)/))
 .reduce((r, [, last, first, id]) => 
 r[`$first $last`] = id
 return r;
 ,)

console.log(output)

share|improve this answer

edited Mar 22 at 5:55

answered Mar 22 at 5:48

adigaadiga

12.4k62745

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  gonna give this a shot. some last names have commas so I'll have to edit out and reapply after conversion. I'll lyk
  
  – EthanPrisonMike
  Mar 22 at 5:55
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @EthanPrisonMike it doesn't matter if the last names have , regex101.com/r/rf7x7B/1
  
  – adiga
  Mar 22 at 6:02
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  lol i meant apostrophes.
  
  – EthanPrisonMike
  Mar 22 at 6:05
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @EthanPrisonMike that doesn't affect the regex as well. Try it on regex101
  
  – adiga
  Mar 22 at 6:06
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I'm using vs code. threw the apostrophe at the beginning of the object and end like you did and it's erroring out after the first line. error at the end of the first line is ("unterminated string literal") essentially the 2500 lines won't convert into a giant string. I should probably mention I'm trying to do all this in a js file as well
  
  – EthanPrisonMike
  Mar 22 at 6:19
  
  

  
  
  
  

 | 
show 5 more comments

0

You can use regex to extract the data, use RegExp#exec method to extract data using a regular expression.

var str = `Last Name1, First Name1 (Details-Details) j1
Last Name2, First Name2 (Details-Details) 32
Last Name3, First Name3 (Details-Details) 3
Last Nam4e, First Name4 (Details-Details) 4
Last Name5, First Name5 (Details-Details) 5
Last Name6, First Name6 (Details-Details) 6`


// pattern for matching the string
let reg = /([w ]+)bs?,s?([w ]+)bs*([^)]+)s*([wd]+)/g;

// variable for storing match
let m;

// object for the result
let res = ;

// iterate over the matches
while (m = reg.exec(str)) 
// define object property based on the match
 res[`$m[2] $m[1]`] = m[3];


console.log(res);

Regex explanation here.

share|improve this answer

edited Mar 22 at 6:01

answered Mar 22 at 5:49

Pranav C BalanPranav C Balan

90.2k1391118

add a comment | 

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1

• 
  split the string at n
  


• loop through each line using map
  


• Use match with the regex /(.*), (.*) (.*)s+(.*)/ to get first name, last name into capturing groups (demo)


• create an object from the array using reduce
  

let str =
`LastName1, FirstName1 (Details-Details) #ID1
LastName2, FirstName2 (Details-Details) #ID2
LastName3, FirstName3 (Details-Details) #ID3`

let output = str.split("n")
 .map(a => a.match(/(.*), (.*) (.*)s+(.*)/))
 .reduce((r, [, last, first, id]) => 
 r[`$first $last`] = id
 return r;
 ,)

console.log(output)

share|improve this answer

edited Mar 22 at 5:55

answered Mar 22 at 5:48

adigaadiga

12.4k62745

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  gonna give this a shot. some last names have commas so I'll have to edit out and reapply after conversion. I'll lyk
  
  – EthanPrisonMike
  Mar 22 at 5:55
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @EthanPrisonMike it doesn't matter if the last names have , regex101.com/r/rf7x7B/1
  
  – adiga
  Mar 22 at 6:02
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  lol i meant apostrophes.
  
  – EthanPrisonMike
  Mar 22 at 6:05
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @EthanPrisonMike that doesn't affect the regex as well. Try it on regex101
  
  – adiga
  Mar 22 at 6:06
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I'm using vs code. threw the apostrophe at the beginning of the object and end like you did and it's erroring out after the first line. error at the end of the first line is ("unterminated string literal") essentially the 2500 lines won't convert into a giant string. I should probably mention I'm trying to do all this in a js file as well
  
  – EthanPrisonMike
  Mar 22 at 6:19
  
  

  
  
  
  

 | 
show 5 more comments

1

• 
  split the string at n
  


• loop through each line using map
  


• Use match with the regex /(.*), (.*) (.*)s+(.*)/ to get first name, last name into capturing groups (demo)


• create an object from the array using reduce
  

let str =
`LastName1, FirstName1 (Details-Details) #ID1
LastName2, FirstName2 (Details-Details) #ID2
LastName3, FirstName3 (Details-Details) #ID3`

let output = str.split("n")
 .map(a => a.match(/(.*), (.*) (.*)s+(.*)/))
 .reduce((r, [, last, first, id]) => 
 r[`$first $last`] = id
 return r;
 ,)

console.log(output)

share|improve this answer

edited Mar 22 at 5:55

answered Mar 22 at 5:48

adigaadiga

12.4k62745

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  gonna give this a shot. some last names have commas so I'll have to edit out and reapply after conversion. I'll lyk
  
  – EthanPrisonMike
  Mar 22 at 5:55
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @EthanPrisonMike it doesn't matter if the last names have , regex101.com/r/rf7x7B/1
  
  – adiga
  Mar 22 at 6:02
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  lol i meant apostrophes.
  
  – EthanPrisonMike
  Mar 22 at 6:05
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @EthanPrisonMike that doesn't affect the regex as well. Try it on regex101
  
  – adiga
  Mar 22 at 6:06
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I'm using vs code. threw the apostrophe at the beginning of the object and end like you did and it's erroring out after the first line. error at the end of the first line is ("unterminated string literal") essentially the 2500 lines won't convert into a giant string. I should probably mention I'm trying to do all this in a js file as well
  
  – EthanPrisonMike
  Mar 22 at 6:19
  
  

  
  
  
  

 | 
show 5 more comments

• 
  split the string at n
  


• loop through each line using map
  


• Use match with the regex /(.*), (.*) (.*)s+(.*)/ to get first name, last name into capturing groups (demo)


• create an object from the array using reduce
  

let str =
`LastName1, FirstName1 (Details-Details) #ID1
LastName2, FirstName2 (Details-Details) #ID2
LastName3, FirstName3 (Details-Details) #ID3`

let output = str.split("n")
 .map(a => a.match(/(.*), (.*) (.*)s+(.*)/))
 .reduce((r, [, last, first, id]) => 
 r[`$first $last`] = id
 return r;
 ,)

console.log(output)

share|improve this answer

edited Mar 22 at 5:55

answered Mar 22 at 5:48

adigaadiga

12.4k62745

let str =
`LastName1, FirstName1 (Details-Details) #ID1
LastName2, FirstName2 (Details-Details) #ID2
LastName3, FirstName3 (Details-Details) #ID3`

let output = str.split("n")
 .map(a => a.match(/(.*), (.*) (.*)s+(.*)/))
 .reduce((r, [, last, first, id]) => 
 r[`$first $last`] = id
 return r;
 ,)

console.log(output)

let str =
`LastName1, FirstName1 (Details-Details) #ID1
LastName2, FirstName2 (Details-Details) #ID2
LastName3, FirstName3 (Details-Details) #ID3`

let output = str.split("n")
 .map(a => a.match(/(.*), (.*) (.*)s+(.*)/))
 .reduce((r, [, last, first, id]) => 
 r[`$first $last`] = id
 return r;
 ,)

console.log(output)

let str =
`LastName1, FirstName1 (Details-Details) #ID1
LastName2, FirstName2 (Details-Details) #ID2
LastName3, FirstName3 (Details-Details) #ID3`

let output = str.split("n")
 .map(a => a.match(/(.*), (.*) (.*)s+(.*)/))
 .reduce((r, [, last, first, id]) => 
 r[`$first $last`] = id
 return r;
 ,)

console.log(output)

share|improve this answer

edited Mar 22 at 5:55

answered Mar 22 at 5:48

adigaadiga

12.4k62745

answered Mar 22 at 5:48

adigaadiga

12.4k62745

answered Mar 22 at 5:48

adigaadiga

12.4k62745

0

You can use regex to extract the data, use RegExp#exec method to extract data using a regular expression.

var str = `Last Name1, First Name1 (Details-Details) j1
Last Name2, First Name2 (Details-Details) 32
Last Name3, First Name3 (Details-Details) 3
Last Nam4e, First Name4 (Details-Details) 4
Last Name5, First Name5 (Details-Details) 5
Last Name6, First Name6 (Details-Details) 6`


// pattern for matching the string
let reg = /([w ]+)bs?,s?([w ]+)bs*([^)]+)s*([wd]+)/g;

// variable for storing match
let m;

// object for the result
let res = ;

// iterate over the matches
while (m = reg.exec(str)) 
// define object property based on the match
 res[`$m[2] $m[1]`] = m[3];


console.log(res);

Regex explanation here.

share|improve this answer

edited Mar 22 at 6:01

answered Mar 22 at 5:49

Pranav C BalanPranav C Balan

90.2k1391118

add a comment | 

0

You can use regex to extract the data, use RegExp#exec method to extract data using a regular expression.

var str = `Last Name1, First Name1 (Details-Details) j1
Last Name2, First Name2 (Details-Details) 32
Last Name3, First Name3 (Details-Details) 3
Last Nam4e, First Name4 (Details-Details) 4
Last Name5, First Name5 (Details-Details) 5
Last Name6, First Name6 (Details-Details) 6`


// pattern for matching the string
let reg = /([w ]+)bs?,s?([w ]+)bs*([^)]+)s*([wd]+)/g;

// variable for storing match
let m;

// object for the result
let res = ;

// iterate over the matches
while (m = reg.exec(str)) 
// define object property based on the match
 res[`$m[2] $m[1]`] = m[3];


console.log(res);

Regex explanation here.

share|improve this answer

edited Mar 22 at 6:01

answered Mar 22 at 5:49

Pranav C BalanPranav C Balan

90.2k1391118

add a comment | 

You can use regex to extract the data, use RegExp#exec method to extract data using a regular expression.

var str = `Last Name1, First Name1 (Details-Details) j1
Last Name2, First Name2 (Details-Details) 32
Last Name3, First Name3 (Details-Details) 3
Last Nam4e, First Name4 (Details-Details) 4
Last Name5, First Name5 (Details-Details) 5
Last Name6, First Name6 (Details-Details) 6`


// pattern for matching the string
let reg = /([w ]+)bs?,s?([w ]+)bs*([^)]+)s*([wd]+)/g;

// variable for storing match
let m;

// object for the result
let res = ;

// iterate over the matches
while (m = reg.exec(str)) 
// define object property based on the match
 res[`$m[2] $m[1]`] = m[3];


console.log(res);

Regex explanation here.

share|improve this answer

edited Mar 22 at 6:01

answered Mar 22 at 5:49

Pranav C BalanPranav C Balan

90.2k1391118

var str = `Last Name1, First Name1 (Details-Details) j1
Last Name2, First Name2 (Details-Details) 32
Last Name3, First Name3 (Details-Details) 3
Last Nam4e, First Name4 (Details-Details) 4
Last Name5, First Name5 (Details-Details) 5
Last Name6, First Name6 (Details-Details) 6`


// pattern for matching the string
let reg = /([w ]+)bs?,s?([w ]+)bs*([^)]+)s*([wd]+)/g;

// variable for storing match
let m;

// object for the result
let res = ;

// iterate over the matches
while (m = reg.exec(str)) 
// define object property based on the match
 res[`$m[2] $m[1]`] = m[3];


console.log(res);

var str = `Last Name1, First Name1 (Details-Details) j1
Last Name2, First Name2 (Details-Details) 32
Last Name3, First Name3 (Details-Details) 3
Last Nam4e, First Name4 (Details-Details) 4
Last Name5, First Name5 (Details-Details) 5
Last Name6, First Name6 (Details-Details) 6`


// pattern for matching the string
let reg = /([w ]+)bs?,s?([w ]+)bs*([^)]+)s*([wd]+)/g;

// variable for storing match
let m;

// object for the result
let res = ;

// iterate over the matches
while (m = reg.exec(str)) 
// define object property based on the match
 res[`$m[2] $m[1]`] = m[3];


console.log(res);

var str = `Last Name1, First Name1 (Details-Details) j1
Last Name2, First Name2 (Details-Details) 32
Last Name3, First Name3 (Details-Details) 3
Last Nam4e, First Name4 (Details-Details) 4
Last Name5, First Name5 (Details-Details) 5
Last Name6, First Name6 (Details-Details) 6`


// pattern for matching the string
let reg = /([w ]+)bs?,s?([w ]+)bs*([^)]+)s*([wd]+)/g;

// variable for storing match
let m;

// object for the result
let res = ;

// iterate over the matches
while (m = reg.exec(str)) 
// define object property based on the match
 res[`$m[2] $m[1]`] = m[3];


console.log(res);

share|improve this answer

edited Mar 22 at 6:01

answered Mar 22 at 5:49

Pranav C BalanPranav C Balan

90.2k1391118

answered Mar 22 at 5:49

Pranav C BalanPranav C Balan

90.2k1391118

answered Mar 22 at 5:49

Pranav C BalanPranav C Balan

90.2k1391118