Compare two large tables by various attributes - PostgreSQLPostgreSQL “DESCRIBE TABLE”Show tables in PostgreSQLExport PostgreSQL table to CSV file with headingsModify OWNER on all tables simultaneously in PostgreSQLHow to import CSV file data into a PostgreSQL table?How can I drop all the tables in a PostgreSQL database?List tables in a PostgreSQL schemaDesigning a SQL schema for a combination of many-to-many relationship (variations of products)MYSQL select and ground by maxNeed efficient SQL on joining rowcount from a materialized view with another materialized view

Is floating in space similar to falling under gravity?

Can a Beholder use rays in melee range?

What are the problems in teaching guitar via Skype?

Apparent Ring of Craters on the Moon

Different PCB color ( is it different material? )

In what episode of TOS did a character on the bridge make a comment about raising one to some power?

How to prevent bad sectors?

Why do Russians call their women expensive ("дорогая")?

Terminology about G- simplicial complexes

Infinitely many hats

Is it ok to put a subplot to a story that is never meant to contribute to the development of the main plot?

Can't use numexpr in horizontal mode

Draw a checker pattern with a black X in the center

Were pen cap holes designed to prevent death by suffocation if swallowed?

Probability of fraction not being able to be simplified

The Passive Wisdom (Perception) score of my character on D&D Beyond seems too high

A Mathematical Discussion: Fill in the Blank

What caused the tendency for conservatives to not support climate change reform?

Restoring order in a deck of playing cards

How can I find where certain bash function is defined?

Is there an evolutionary advantage to having two heads?

What is the 中 in ダウンロード中?

Could IPv6 make NAT / port numbers redundant?

How to capture more stars?



Compare two large tables by various attributes - PostgreSQL


PostgreSQL “DESCRIBE TABLE”Show tables in PostgreSQLExport PostgreSQL table to CSV file with headingsModify OWNER on all tables simultaneously in PostgreSQLHow to import CSV file data into a PostgreSQL table?How can I drop all the tables in a PostgreSQL database?List tables in a PostgreSQL schemaDesigning a SQL schema for a combination of many-to-many relationship (variations of products)MYSQL select and ground by maxNeed efficient SQL on joining rowcount from a materialized view with another materialized view






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








1















I'm having trouble coming up with an efficient query that compares two tables with various attributes. This is for a report for an online retailer who has several hundred thousand SKUs available for sale. Each SKU is a variation of a "parent" product. They sell on various marketplaces and need to see if there are items that are not available for sale in various places.



There is a table with all parent products, and another table with all variations with their corresponding SKU. In a third table they have a complete list of each sku (variation) and it's corresponding marketplace where the combination of sku + marketplace is unique.



Database uses PostgreSQL



Table structures are as follows:



Product Table:



Products
id | parent_sku | vendor_id
-------------------------------
1 | ABC | 100
2 | DEF | 200
3 | XYZ | 100


Variation Table:



Variations
id | parent_id | sku
----------------------------
1 | 1 | ABC-1
2 | 1 | ABC-2
3 | 1 | ABC-3
4 | 2 | DEF-1
5 | 2 | DEF-2
6 | 3 | XYZ-1
7 | 3 | XYZ-2


Marketplace Table:



MarketplaceData
id | sku | marketplace | price
----------------------------
1 | ABC-1 | website1 | 99.99
2 | ABC-2 | website1 | 99.99
3 | ABC-3 | website1 | 89.99
4 | DEF-1 | website1 | 29.99
5 | DEF-2 | website1 | 29.99
6 | XYZ-1 | website1 | 39.99
7 | XYZ-2 | website1 | 39.99
8 | ABC-1 | website2 | 99.99
9 | ABC-2 | website2 | 99.99
10 | ABC-3 | website2 | 99.99
11 | DEF-1 | website2 | 29.99
12 | DEF-2 | website2 | 29.99
13 | XYZ-1 | website2 | 34.99
14 | XYZ-2 | website2 | 34.99


I have a working query, but it takes extremely long to execute and is very taxing.



SELECT DISTINCT parent_id FROM Variations 
WHERE sku IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2'))
AND sku NOT IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4'))
LIMIT 20 OFFSET 0


Since each sku + marketplace dataset has close to 400,000 rows and the MarketplaceData table contains over 2 million rows, this query takes forever to execute.



In terms of indexing, the id column is the primary key for each. The Variations table has an index on sku (must be unique) and the MarketplaceData is indexed on sku + marketplace.



Ultimately, what I need is a list of unique parent_id's that meet the criteria.



Any help or guidance would be greatly appreciated.



Thanks!










share|improve this question




























    1















    I'm having trouble coming up with an efficient query that compares two tables with various attributes. This is for a report for an online retailer who has several hundred thousand SKUs available for sale. Each SKU is a variation of a "parent" product. They sell on various marketplaces and need to see if there are items that are not available for sale in various places.



    There is a table with all parent products, and another table with all variations with their corresponding SKU. In a third table they have a complete list of each sku (variation) and it's corresponding marketplace where the combination of sku + marketplace is unique.



    Database uses PostgreSQL



    Table structures are as follows:



    Product Table:



    Products
    id | parent_sku | vendor_id
    -------------------------------
    1 | ABC | 100
    2 | DEF | 200
    3 | XYZ | 100


    Variation Table:



    Variations
    id | parent_id | sku
    ----------------------------
    1 | 1 | ABC-1
    2 | 1 | ABC-2
    3 | 1 | ABC-3
    4 | 2 | DEF-1
    5 | 2 | DEF-2
    6 | 3 | XYZ-1
    7 | 3 | XYZ-2


    Marketplace Table:



    MarketplaceData
    id | sku | marketplace | price
    ----------------------------
    1 | ABC-1 | website1 | 99.99
    2 | ABC-2 | website1 | 99.99
    3 | ABC-3 | website1 | 89.99
    4 | DEF-1 | website1 | 29.99
    5 | DEF-2 | website1 | 29.99
    6 | XYZ-1 | website1 | 39.99
    7 | XYZ-2 | website1 | 39.99
    8 | ABC-1 | website2 | 99.99
    9 | ABC-2 | website2 | 99.99
    10 | ABC-3 | website2 | 99.99
    11 | DEF-1 | website2 | 29.99
    12 | DEF-2 | website2 | 29.99
    13 | XYZ-1 | website2 | 34.99
    14 | XYZ-2 | website2 | 34.99


    I have a working query, but it takes extremely long to execute and is very taxing.



    SELECT DISTINCT parent_id FROM Variations 
    WHERE sku IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2'))
    AND sku NOT IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4'))
    LIMIT 20 OFFSET 0


    Since each sku + marketplace dataset has close to 400,000 rows and the MarketplaceData table contains over 2 million rows, this query takes forever to execute.



    In terms of indexing, the id column is the primary key for each. The Variations table has an index on sku (must be unique) and the MarketplaceData is indexed on sku + marketplace.



    Ultimately, what I need is a list of unique parent_id's that meet the criteria.



    Any help or guidance would be greatly appreciated.



    Thanks!










    share|improve this question
























      1












      1








      1








      I'm having trouble coming up with an efficient query that compares two tables with various attributes. This is for a report for an online retailer who has several hundred thousand SKUs available for sale. Each SKU is a variation of a "parent" product. They sell on various marketplaces and need to see if there are items that are not available for sale in various places.



      There is a table with all parent products, and another table with all variations with their corresponding SKU. In a third table they have a complete list of each sku (variation) and it's corresponding marketplace where the combination of sku + marketplace is unique.



      Database uses PostgreSQL



      Table structures are as follows:



      Product Table:



      Products
      id | parent_sku | vendor_id
      -------------------------------
      1 | ABC | 100
      2 | DEF | 200
      3 | XYZ | 100


      Variation Table:



      Variations
      id | parent_id | sku
      ----------------------------
      1 | 1 | ABC-1
      2 | 1 | ABC-2
      3 | 1 | ABC-3
      4 | 2 | DEF-1
      5 | 2 | DEF-2
      6 | 3 | XYZ-1
      7 | 3 | XYZ-2


      Marketplace Table:



      MarketplaceData
      id | sku | marketplace | price
      ----------------------------
      1 | ABC-1 | website1 | 99.99
      2 | ABC-2 | website1 | 99.99
      3 | ABC-3 | website1 | 89.99
      4 | DEF-1 | website1 | 29.99
      5 | DEF-2 | website1 | 29.99
      6 | XYZ-1 | website1 | 39.99
      7 | XYZ-2 | website1 | 39.99
      8 | ABC-1 | website2 | 99.99
      9 | ABC-2 | website2 | 99.99
      10 | ABC-3 | website2 | 99.99
      11 | DEF-1 | website2 | 29.99
      12 | DEF-2 | website2 | 29.99
      13 | XYZ-1 | website2 | 34.99
      14 | XYZ-2 | website2 | 34.99


      I have a working query, but it takes extremely long to execute and is very taxing.



      SELECT DISTINCT parent_id FROM Variations 
      WHERE sku IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2'))
      AND sku NOT IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4'))
      LIMIT 20 OFFSET 0


      Since each sku + marketplace dataset has close to 400,000 rows and the MarketplaceData table contains over 2 million rows, this query takes forever to execute.



      In terms of indexing, the id column is the primary key for each. The Variations table has an index on sku (must be unique) and the MarketplaceData is indexed on sku + marketplace.



      Ultimately, what I need is a list of unique parent_id's that meet the criteria.



      Any help or guidance would be greatly appreciated.



      Thanks!










      share|improve this question














      I'm having trouble coming up with an efficient query that compares two tables with various attributes. This is for a report for an online retailer who has several hundred thousand SKUs available for sale. Each SKU is a variation of a "parent" product. They sell on various marketplaces and need to see if there are items that are not available for sale in various places.



      There is a table with all parent products, and another table with all variations with their corresponding SKU. In a third table they have a complete list of each sku (variation) and it's corresponding marketplace where the combination of sku + marketplace is unique.



      Database uses PostgreSQL



      Table structures are as follows:



      Product Table:



      Products
      id | parent_sku | vendor_id
      -------------------------------
      1 | ABC | 100
      2 | DEF | 200
      3 | XYZ | 100


      Variation Table:



      Variations
      id | parent_id | sku
      ----------------------------
      1 | 1 | ABC-1
      2 | 1 | ABC-2
      3 | 1 | ABC-3
      4 | 2 | DEF-1
      5 | 2 | DEF-2
      6 | 3 | XYZ-1
      7 | 3 | XYZ-2


      Marketplace Table:



      MarketplaceData
      id | sku | marketplace | price
      ----------------------------
      1 | ABC-1 | website1 | 99.99
      2 | ABC-2 | website1 | 99.99
      3 | ABC-3 | website1 | 89.99
      4 | DEF-1 | website1 | 29.99
      5 | DEF-2 | website1 | 29.99
      6 | XYZ-1 | website1 | 39.99
      7 | XYZ-2 | website1 | 39.99
      8 | ABC-1 | website2 | 99.99
      9 | ABC-2 | website2 | 99.99
      10 | ABC-3 | website2 | 99.99
      11 | DEF-1 | website2 | 29.99
      12 | DEF-2 | website2 | 29.99
      13 | XYZ-1 | website2 | 34.99
      14 | XYZ-2 | website2 | 34.99


      I have a working query, but it takes extremely long to execute and is very taxing.



      SELECT DISTINCT parent_id FROM Variations 
      WHERE sku IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2'))
      AND sku NOT IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4'))
      LIMIT 20 OFFSET 0


      Since each sku + marketplace dataset has close to 400,000 rows and the MarketplaceData table contains over 2 million rows, this query takes forever to execute.



      In terms of indexing, the id column is the primary key for each. The Variations table has an index on sku (must be unique) and the MarketplaceData is indexed on sku + marketplace.



      Ultimately, what I need is a list of unique parent_id's that meet the criteria.



      Any help or guidance would be greatly appreciated.



      Thanks!







      sql postgresql






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 24 at 8:58









      potorikpotorik

      335




      335






















          3 Answers
          3






          active

          oldest

          votes


















          1














          instead of IN and NOT In you could use INNER JOIN and LEFT JOIN with checking for null



          SELECT DISTINCT v.parent_id 
          FROM Variations v
          INNER JOIN (
          SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2')
          ) t1 on t1.sku = v.sku
          LEFT JOIN (
          SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4')
          ) t2 On t2.sku = v.sku
          WHERE t2.sku is null





          share|improve this answer






























            0














            Why if you only use a single subquery?



            SELECT DISTINCT parent_id 
            FROM Variations
            WHERE sku IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2')
            except
            SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4'))
            LIMIT 20 OFFSET 0





            share|improve this answer






























              0














              How about a simple aggregation to get the skus?



              select mpd.sku
              from MarketplaceData mpd
              where mpd.marketplace in ('website1', 'website2', 'website3', 'website4')
              group by mpd.sku
              having count(*) filter (where mpd.marketplace in ('website1', 'website2')) > 0 and
              count(*) filter (where mpd.marketplace in ('website3', 'website4')) = 0;


              Then to get the parent ids:



              select distinct v.parent_id
              from variations v join
              (select mpd.sku
              from MarketplaceData mpd
              where mpd.marketplace in ('website1', 'website2', 'website3', 'website4')
              group by mpd.sku
              having count(*) filter (where mpd.marketplace in ('website1', 'website2')) > 0 and
              count(*) filter (where mpd.marketplace in ('website3', 'website4')) = 0
              ) m
              on m.sku = v.sku;





              share|improve this answer























                Your Answer






                StackExchange.ifUsing("editor", function ()
                StackExchange.using("externalEditor", function ()
                StackExchange.using("snippets", function ()
                StackExchange.snippets.init();
                );
                );
                , "code-snippets");

                StackExchange.ready(function()
                var channelOptions =
                tags: "".split(" "),
                id: "1"
                ;
                initTagRenderer("".split(" "), "".split(" "), channelOptions);

                StackExchange.using("externalEditor", function()
                // Have to fire editor after snippets, if snippets enabled
                if (StackExchange.settings.snippets.snippetsEnabled)
                StackExchange.using("snippets", function()
                createEditor();
                );

                else
                createEditor();

                );

                function createEditor()
                StackExchange.prepareEditor(
                heartbeatType: 'answer',
                autoActivateHeartbeat: false,
                convertImagesToLinks: true,
                noModals: true,
                showLowRepImageUploadWarning: true,
                reputationToPostImages: 10,
                bindNavPrevention: true,
                postfix: "",
                imageUploader:
                brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
                contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
                allowUrls: true
                ,
                onDemand: true,
                discardSelector: ".discard-answer"
                ,immediatelyShowMarkdownHelp:true
                );



                );













                draft saved

                draft discarded


















                StackExchange.ready(
                function ()
                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55322146%2fcompare-two-large-tables-by-various-attributes-postgresql%23new-answer', 'question_page');

                );

                Post as a guest















                Required, but never shown

























                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                1














                instead of IN and NOT In you could use INNER JOIN and LEFT JOIN with checking for null



                SELECT DISTINCT v.parent_id 
                FROM Variations v
                INNER JOIN (
                SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2')
                ) t1 on t1.sku = v.sku
                LEFT JOIN (
                SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4')
                ) t2 On t2.sku = v.sku
                WHERE t2.sku is null





                share|improve this answer



























                  1














                  instead of IN and NOT In you could use INNER JOIN and LEFT JOIN with checking for null



                  SELECT DISTINCT v.parent_id 
                  FROM Variations v
                  INNER JOIN (
                  SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2')
                  ) t1 on t1.sku = v.sku
                  LEFT JOIN (
                  SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4')
                  ) t2 On t2.sku = v.sku
                  WHERE t2.sku is null





                  share|improve this answer

























                    1












                    1








                    1







                    instead of IN and NOT In you could use INNER JOIN and LEFT JOIN with checking for null



                    SELECT DISTINCT v.parent_id 
                    FROM Variations v
                    INNER JOIN (
                    SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2')
                    ) t1 on t1.sku = v.sku
                    LEFT JOIN (
                    SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4')
                    ) t2 On t2.sku = v.sku
                    WHERE t2.sku is null





                    share|improve this answer













                    instead of IN and NOT In you could use INNER JOIN and LEFT JOIN with checking for null



                    SELECT DISTINCT v.parent_id 
                    FROM Variations v
                    INNER JOIN (
                    SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2')
                    ) t1 on t1.sku = v.sku
                    LEFT JOIN (
                    SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4')
                    ) t2 On t2.sku = v.sku
                    WHERE t2.sku is null






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Mar 24 at 9:12









                    scaisEdgescaisEdge

                    102k105472




                    102k105472























                        0














                        Why if you only use a single subquery?



                        SELECT DISTINCT parent_id 
                        FROM Variations
                        WHERE sku IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2')
                        except
                        SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4'))
                        LIMIT 20 OFFSET 0





                        share|improve this answer



























                          0














                          Why if you only use a single subquery?



                          SELECT DISTINCT parent_id 
                          FROM Variations
                          WHERE sku IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2')
                          except
                          SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4'))
                          LIMIT 20 OFFSET 0





                          share|improve this answer

























                            0












                            0








                            0







                            Why if you only use a single subquery?



                            SELECT DISTINCT parent_id 
                            FROM Variations
                            WHERE sku IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2')
                            except
                            SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4'))
                            LIMIT 20 OFFSET 0





                            share|improve this answer













                            Why if you only use a single subquery?



                            SELECT DISTINCT parent_id 
                            FROM Variations
                            WHERE sku IN (SELECT sku FROM MarketplaceData WHERE marketplace IN ('website1','website2')
                            except
                            SELECT sku FROM MarketplaceData WHERE marketplace IN ('website3','website4'))
                            LIMIT 20 OFFSET 0






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Mar 24 at 9:52









                            a_horse_with_no_namea_horse_with_no_name

                            314k47480584




                            314k47480584





















                                0














                                How about a simple aggregation to get the skus?



                                select mpd.sku
                                from MarketplaceData mpd
                                where mpd.marketplace in ('website1', 'website2', 'website3', 'website4')
                                group by mpd.sku
                                having count(*) filter (where mpd.marketplace in ('website1', 'website2')) > 0 and
                                count(*) filter (where mpd.marketplace in ('website3', 'website4')) = 0;


                                Then to get the parent ids:



                                select distinct v.parent_id
                                from variations v join
                                (select mpd.sku
                                from MarketplaceData mpd
                                where mpd.marketplace in ('website1', 'website2', 'website3', 'website4')
                                group by mpd.sku
                                having count(*) filter (where mpd.marketplace in ('website1', 'website2')) > 0 and
                                count(*) filter (where mpd.marketplace in ('website3', 'website4')) = 0
                                ) m
                                on m.sku = v.sku;





                                share|improve this answer



























                                  0














                                  How about a simple aggregation to get the skus?



                                  select mpd.sku
                                  from MarketplaceData mpd
                                  where mpd.marketplace in ('website1', 'website2', 'website3', 'website4')
                                  group by mpd.sku
                                  having count(*) filter (where mpd.marketplace in ('website1', 'website2')) > 0 and
                                  count(*) filter (where mpd.marketplace in ('website3', 'website4')) = 0;


                                  Then to get the parent ids:



                                  select distinct v.parent_id
                                  from variations v join
                                  (select mpd.sku
                                  from MarketplaceData mpd
                                  where mpd.marketplace in ('website1', 'website2', 'website3', 'website4')
                                  group by mpd.sku
                                  having count(*) filter (where mpd.marketplace in ('website1', 'website2')) > 0 and
                                  count(*) filter (where mpd.marketplace in ('website3', 'website4')) = 0
                                  ) m
                                  on m.sku = v.sku;





                                  share|improve this answer

























                                    0












                                    0








                                    0







                                    How about a simple aggregation to get the skus?



                                    select mpd.sku
                                    from MarketplaceData mpd
                                    where mpd.marketplace in ('website1', 'website2', 'website3', 'website4')
                                    group by mpd.sku
                                    having count(*) filter (where mpd.marketplace in ('website1', 'website2')) > 0 and
                                    count(*) filter (where mpd.marketplace in ('website3', 'website4')) = 0;


                                    Then to get the parent ids:



                                    select distinct v.parent_id
                                    from variations v join
                                    (select mpd.sku
                                    from MarketplaceData mpd
                                    where mpd.marketplace in ('website1', 'website2', 'website3', 'website4')
                                    group by mpd.sku
                                    having count(*) filter (where mpd.marketplace in ('website1', 'website2')) > 0 and
                                    count(*) filter (where mpd.marketplace in ('website3', 'website4')) = 0
                                    ) m
                                    on m.sku = v.sku;





                                    share|improve this answer













                                    How about a simple aggregation to get the skus?



                                    select mpd.sku
                                    from MarketplaceData mpd
                                    where mpd.marketplace in ('website1', 'website2', 'website3', 'website4')
                                    group by mpd.sku
                                    having count(*) filter (where mpd.marketplace in ('website1', 'website2')) > 0 and
                                    count(*) filter (where mpd.marketplace in ('website3', 'website4')) = 0;


                                    Then to get the parent ids:



                                    select distinct v.parent_id
                                    from variations v join
                                    (select mpd.sku
                                    from MarketplaceData mpd
                                    where mpd.marketplace in ('website1', 'website2', 'website3', 'website4')
                                    group by mpd.sku
                                    having count(*) filter (where mpd.marketplace in ('website1', 'website2')) > 0 and
                                    count(*) filter (where mpd.marketplace in ('website3', 'website4')) = 0
                                    ) m
                                    on m.sku = v.sku;






                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered Mar 24 at 12:36









                                    Gordon LinoffGordon Linoff

                                    814k37327435




                                    814k37327435



























                                        draft saved

                                        draft discarded
















































                                        Thanks for contributing an answer to Stack Overflow!


                                        • Please be sure to answer the question. Provide details and share your research!

                                        But avoid


                                        • Asking for help, clarification, or responding to other answers.

                                        • Making statements based on opinion; back them up with references or personal experience.

                                        To learn more, see our tips on writing great answers.




                                        draft saved


                                        draft discarded














                                        StackExchange.ready(
                                        function ()
                                        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55322146%2fcompare-two-large-tables-by-various-attributes-postgresql%23new-answer', 'question_page');

                                        );

                                        Post as a guest















                                        Required, but never shown





















































                                        Required, but never shown














                                        Required, but never shown












                                        Required, but never shown







                                        Required, but never shown

































                                        Required, but never shown














                                        Required, but never shown












                                        Required, but never shown







                                        Required, but never shown







                                        Popular posts from this blog

                                        Kamusi Yaliyomo Aina za kamusi | Muundo wa kamusi | Faida za kamusi | Dhima ya picha katika kamusi | Marejeo | Tazama pia | Viungo vya nje | UrambazajiKuhusu kamusiGo-SwahiliWiki-KamusiKamusi ya Kiswahili na Kiingerezakuihariri na kuongeza habari

                                        SQL error code 1064 with creating Laravel foreign keysForeign key constraints: When to use ON UPDATE and ON DELETEDropping column with foreign key Laravel error: General error: 1025 Error on renameLaravel SQL Can't create tableLaravel Migration foreign key errorLaravel php artisan migrate:refresh giving a syntax errorSQLSTATE[42S01]: Base table or view already exists or Base table or view already exists: 1050 Tableerror in migrating laravel file to xampp serverSyntax error or access violation: 1064:syntax to use near 'unsigned not null, modelName varchar(191) not null, title varchar(191) not nLaravel cannot create new table field in mysqlLaravel 5.7:Last migration creates table but is not registered in the migration table

                                        은진 송씨 목차 역사 본관 분파 인물 조선 왕실과의 인척 관계 집성촌 항렬자 인구 같이 보기 각주 둘러보기 메뉴은진 송씨세종실록 149권, 지리지 충청도 공주목 은진현