How can I determine if ID's are grouped similarly? [duplicate]How can you compare two cluster groupings in terms of similarity or overlap in Python?Grouping functions (tapply, by, aggregate) and the *apply familyHow to make a great R reproducible exampleCluster analysis in R: determine the optimal number of clustersR data clustering using a pre-defined distance/similarity matrixclustering qualitative data in ROptimal grouping/clustering of items in groups with minimum sizeR Univariate Clustering by GroupCoding for two different clustering methodsHow can you compare two cluster groupings in terms of similarity or overlap in Python?Consecutive Across and Unique Number Within Group

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How can I determine if ID's are grouped similarly? [duplicate]


How can you compare two cluster groupings in terms of similarity or overlap in Python?Grouping functions (tapply, by, aggregate) and the *apply familyHow to make a great R reproducible exampleCluster analysis in R: determine the optimal number of clustersR data clustering using a pre-defined distance/similarity matrixclustering qualitative data in ROptimal grouping/clustering of items in groups with minimum sizeR Univariate Clustering by GroupCoding for two different clustering methodsHow can you compare two cluster groupings in terms of similarity or overlap in Python?Consecutive Across and Unique Number Within Group






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








-1
















This question already has an answer here:



  • How can you compare two cluster groupings in terms of similarity or overlap in Python?

    2 answers



I have applied two different clustering algorithms to my data, and I would like to express the commonality among the results of these.



The data is organized as;



  • "ID" = Identifier

  • "Group_1" = Results from first clustering algorithm

  • "Group_2" = Results from second clustering algorithm.

Group_1 is the output of a hierarchical clustering, which had the highest CVI at k = 5, and Group_2 is the output of k-means clustering, which had the highest CVI at k = 10.



I would like to determine the similarity of the results.



Here is the data, which I try to find the similarity of:



structure(list(ID = c(400100L, 400101L, 400106L, 442306L, 443110L, 
443300L, 443301L, 443302L, 443303L, 443304L, 443307L, 443309L,
443311L, 443312L, 443313L, 443314L, 443316L, 443317L, 443322L,
443324L, 443328L, 443329L, 443330L, 443331L, 443332L, 443333L,
443334L, 443339L, 443344L, 443345L, 443351L, 443365L, 443366L,
443371L, 443378L, 443382L, 443383L, 443388L, 443390L, 443392L,
443396L, 443398L, 443399L, 443506L, 443507L, 443511L, 443512L,
443514L, 443521L, 443522L, 443800L, 443802L, 443816L, 443817L,
443819L, 443820L, 443823L, 443825L, 443828L, 443829L, 443833L,
443842L, 443855L, 443859L, 443876L, 443877L, 443879L, 444101L,
444104L, 444202L, 444204L, 444207L, 444251L, 444305L, 444307L,
444309L, 444312L, 444314L, 444325L, 444327L, 444328L, 444334L,
444335L, 444339L, 444341L, 444346L, 444359L, 444501L, 444504L,
444508L, 444509L, 444511L, 444512L, 444514L, 444517L, 444520L,
444521L, 444547L, 444548L, 444554L, 445101L, 445106L, 445112L,
445113L, 445115L, 445120L, 445141L, 445302L, 445303L, 445304L,
445309L, 445312L, 445313L, 445315L, 445316L, 445318L, 445319L,
445322L, 445327L, 445330L, 445333L, 445404L, 445405L, 445409L,
445510L, 445522L, 445552L, 445560L, 451704L, 451705L, 452503L,
452514L), Group_1 = c(1L, 1L, 2L, 2L, 3L, 2L, 4L, 2L, 2L, 1L,
2L, 2L, 2L, 2L, 1L, 1L, 1L, 2L, 5L, 2L, 2L, 4L, 4L, 4L, 5L, 5L,
2L, 2L, 1L, 1L, 2L, 2L, 3L, 4L, 4L, 3L, 2L, 2L, 1L, 3L, 1L, 1L,
3L, 2L, 3L, 2L, 1L, 4L, 2L, 5L, 4L, 5L, 3L, 4L, 1L, 2L, 3L, 2L,
2L, 5L, 4L, 2L, 2L, 5L, 1L, 1L, 1L, 2L, 5L, 4L, 4L, 2L, 3L, 3L,
1L, 2L, 1L, 4L, 2L, 4L, 5L, 1L, 4L, 2L, 4L, 2L, 3L, 2L, 2L, 2L,
1L, 2L, 2L, 3L, 4L, 2L, 2L, 3L, 4L, 1L, 1L, 5L, 2L, 2L, 3L, 4L,
3L, 5L, 4L, 1L, 1L, 1L, 2L, 4L, 3L, 4L, 4L, 1L, 2L, 1L, 1L, 2L,
5L, 4L, 4L, 2L, 4L, 3L, 1L, 1L, 3L, 5L), Group_2 = c(7, 7, 7,
7, 8, 3, 3, 7, 3, 9, 6, 1, 7, 7, 10, 7, 4, 6, 7, 7, 6, 3, 3,
10, 7, 6, 1, 7, 9, 1, 6, 7, 3, 1, 5, 3, 7, 2, 5, 6, 5, 4, 6,
10, 1, 1, 1, 10, 1, 6, 7, 6, 6, 3, 7, 7, 6, 5, 7, 6, 9, 7, 8,
6, 3, 7, 9, 3, 7, 6, 6, 2, 6, 3, 3, 2, 7, 1, 6, 6, 6, 3, 6, 6,
3, 7, 7, 1, 3, 7, 3, 6, 8, 6, 3, 7, 6, 7, 7, 1, 3, 6, 7, 3, 7,
3, 7, 3, 3, 5, 5, 2, 6, 3, 1, 6, 7, 6, 7, 5, 2, 7, 6, 5, 7, 1,
8, 7, 3, 9, 7, 6)), row.names = c(NA, -132L), class = c("data.frame"))


I would like to know a percentage agreement between the two groups, however I cannot figure out how to calculate it.



Ultimately, I would like to arrive at something as:



ID's grouped together in both "Group_1" and "Group_2" divided by N



My assumption would then be that ID's grouped similarly by both algorithms are correctly labelled and I could redo the clustering with the remaining ID's.










share|improve this question















marked as duplicate by Anony-Mousse cluster-analysis
Users with the  cluster-analysis badge can single-handedly close cluster-analysis questions as duplicates and reopen them as needed.

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Mar 23 at 23:13


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
























    -1
















    This question already has an answer here:



    • How can you compare two cluster groupings in terms of similarity or overlap in Python?

      2 answers



    I have applied two different clustering algorithms to my data, and I would like to express the commonality among the results of these.



    The data is organized as;



    • "ID" = Identifier

    • "Group_1" = Results from first clustering algorithm

    • "Group_2" = Results from second clustering algorithm.

    Group_1 is the output of a hierarchical clustering, which had the highest CVI at k = 5, and Group_2 is the output of k-means clustering, which had the highest CVI at k = 10.



    I would like to determine the similarity of the results.



    Here is the data, which I try to find the similarity of:



    structure(list(ID = c(400100L, 400101L, 400106L, 442306L, 443110L, 
    443300L, 443301L, 443302L, 443303L, 443304L, 443307L, 443309L,
    443311L, 443312L, 443313L, 443314L, 443316L, 443317L, 443322L,
    443324L, 443328L, 443329L, 443330L, 443331L, 443332L, 443333L,
    443334L, 443339L, 443344L, 443345L, 443351L, 443365L, 443366L,
    443371L, 443378L, 443382L, 443383L, 443388L, 443390L, 443392L,
    443396L, 443398L, 443399L, 443506L, 443507L, 443511L, 443512L,
    443514L, 443521L, 443522L, 443800L, 443802L, 443816L, 443817L,
    443819L, 443820L, 443823L, 443825L, 443828L, 443829L, 443833L,
    443842L, 443855L, 443859L, 443876L, 443877L, 443879L, 444101L,
    444104L, 444202L, 444204L, 444207L, 444251L, 444305L, 444307L,
    444309L, 444312L, 444314L, 444325L, 444327L, 444328L, 444334L,
    444335L, 444339L, 444341L, 444346L, 444359L, 444501L, 444504L,
    444508L, 444509L, 444511L, 444512L, 444514L, 444517L, 444520L,
    444521L, 444547L, 444548L, 444554L, 445101L, 445106L, 445112L,
    445113L, 445115L, 445120L, 445141L, 445302L, 445303L, 445304L,
    445309L, 445312L, 445313L, 445315L, 445316L, 445318L, 445319L,
    445322L, 445327L, 445330L, 445333L, 445404L, 445405L, 445409L,
    445510L, 445522L, 445552L, 445560L, 451704L, 451705L, 452503L,
    452514L), Group_1 = c(1L, 1L, 2L, 2L, 3L, 2L, 4L, 2L, 2L, 1L,
    2L, 2L, 2L, 2L, 1L, 1L, 1L, 2L, 5L, 2L, 2L, 4L, 4L, 4L, 5L, 5L,
    2L, 2L, 1L, 1L, 2L, 2L, 3L, 4L, 4L, 3L, 2L, 2L, 1L, 3L, 1L, 1L,
    3L, 2L, 3L, 2L, 1L, 4L, 2L, 5L, 4L, 5L, 3L, 4L, 1L, 2L, 3L, 2L,
    2L, 5L, 4L, 2L, 2L, 5L, 1L, 1L, 1L, 2L, 5L, 4L, 4L, 2L, 3L, 3L,
    1L, 2L, 1L, 4L, 2L, 4L, 5L, 1L, 4L, 2L, 4L, 2L, 3L, 2L, 2L, 2L,
    1L, 2L, 2L, 3L, 4L, 2L, 2L, 3L, 4L, 1L, 1L, 5L, 2L, 2L, 3L, 4L,
    3L, 5L, 4L, 1L, 1L, 1L, 2L, 4L, 3L, 4L, 4L, 1L, 2L, 1L, 1L, 2L,
    5L, 4L, 4L, 2L, 4L, 3L, 1L, 1L, 3L, 5L), Group_2 = c(7, 7, 7,
    7, 8, 3, 3, 7, 3, 9, 6, 1, 7, 7, 10, 7, 4, 6, 7, 7, 6, 3, 3,
    10, 7, 6, 1, 7, 9, 1, 6, 7, 3, 1, 5, 3, 7, 2, 5, 6, 5, 4, 6,
    10, 1, 1, 1, 10, 1, 6, 7, 6, 6, 3, 7, 7, 6, 5, 7, 6, 9, 7, 8,
    6, 3, 7, 9, 3, 7, 6, 6, 2, 6, 3, 3, 2, 7, 1, 6, 6, 6, 3, 6, 6,
    3, 7, 7, 1, 3, 7, 3, 6, 8, 6, 3, 7, 6, 7, 7, 1, 3, 6, 7, 3, 7,
    3, 7, 3, 3, 5, 5, 2, 6, 3, 1, 6, 7, 6, 7, 5, 2, 7, 6, 5, 7, 1,
    8, 7, 3, 9, 7, 6)), row.names = c(NA, -132L), class = c("data.frame"))


    I would like to know a percentage agreement between the two groups, however I cannot figure out how to calculate it.



    Ultimately, I would like to arrive at something as:



    ID's grouped together in both "Group_1" and "Group_2" divided by N



    My assumption would then be that ID's grouped similarly by both algorithms are correctly labelled and I could redo the clustering with the remaining ID's.










    share|improve this question















    marked as duplicate by Anony-Mousse cluster-analysis
    Users with the  cluster-analysis badge can single-handedly close cluster-analysis questions as duplicates and reopen them as needed.

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    Mar 23 at 23:13


    This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.




















      -1












      -1








      -1









      This question already has an answer here:



      • How can you compare two cluster groupings in terms of similarity or overlap in Python?

        2 answers



      I have applied two different clustering algorithms to my data, and I would like to express the commonality among the results of these.



      The data is organized as;



      • "ID" = Identifier

      • "Group_1" = Results from first clustering algorithm

      • "Group_2" = Results from second clustering algorithm.

      Group_1 is the output of a hierarchical clustering, which had the highest CVI at k = 5, and Group_2 is the output of k-means clustering, which had the highest CVI at k = 10.



      I would like to determine the similarity of the results.



      Here is the data, which I try to find the similarity of:



      structure(list(ID = c(400100L, 400101L, 400106L, 442306L, 443110L, 
      443300L, 443301L, 443302L, 443303L, 443304L, 443307L, 443309L,
      443311L, 443312L, 443313L, 443314L, 443316L, 443317L, 443322L,
      443324L, 443328L, 443329L, 443330L, 443331L, 443332L, 443333L,
      443334L, 443339L, 443344L, 443345L, 443351L, 443365L, 443366L,
      443371L, 443378L, 443382L, 443383L, 443388L, 443390L, 443392L,
      443396L, 443398L, 443399L, 443506L, 443507L, 443511L, 443512L,
      443514L, 443521L, 443522L, 443800L, 443802L, 443816L, 443817L,
      443819L, 443820L, 443823L, 443825L, 443828L, 443829L, 443833L,
      443842L, 443855L, 443859L, 443876L, 443877L, 443879L, 444101L,
      444104L, 444202L, 444204L, 444207L, 444251L, 444305L, 444307L,
      444309L, 444312L, 444314L, 444325L, 444327L, 444328L, 444334L,
      444335L, 444339L, 444341L, 444346L, 444359L, 444501L, 444504L,
      444508L, 444509L, 444511L, 444512L, 444514L, 444517L, 444520L,
      444521L, 444547L, 444548L, 444554L, 445101L, 445106L, 445112L,
      445113L, 445115L, 445120L, 445141L, 445302L, 445303L, 445304L,
      445309L, 445312L, 445313L, 445315L, 445316L, 445318L, 445319L,
      445322L, 445327L, 445330L, 445333L, 445404L, 445405L, 445409L,
      445510L, 445522L, 445552L, 445560L, 451704L, 451705L, 452503L,
      452514L), Group_1 = c(1L, 1L, 2L, 2L, 3L, 2L, 4L, 2L, 2L, 1L,
      2L, 2L, 2L, 2L, 1L, 1L, 1L, 2L, 5L, 2L, 2L, 4L, 4L, 4L, 5L, 5L,
      2L, 2L, 1L, 1L, 2L, 2L, 3L, 4L, 4L, 3L, 2L, 2L, 1L, 3L, 1L, 1L,
      3L, 2L, 3L, 2L, 1L, 4L, 2L, 5L, 4L, 5L, 3L, 4L, 1L, 2L, 3L, 2L,
      2L, 5L, 4L, 2L, 2L, 5L, 1L, 1L, 1L, 2L, 5L, 4L, 4L, 2L, 3L, 3L,
      1L, 2L, 1L, 4L, 2L, 4L, 5L, 1L, 4L, 2L, 4L, 2L, 3L, 2L, 2L, 2L,
      1L, 2L, 2L, 3L, 4L, 2L, 2L, 3L, 4L, 1L, 1L, 5L, 2L, 2L, 3L, 4L,
      3L, 5L, 4L, 1L, 1L, 1L, 2L, 4L, 3L, 4L, 4L, 1L, 2L, 1L, 1L, 2L,
      5L, 4L, 4L, 2L, 4L, 3L, 1L, 1L, 3L, 5L), Group_2 = c(7, 7, 7,
      7, 8, 3, 3, 7, 3, 9, 6, 1, 7, 7, 10, 7, 4, 6, 7, 7, 6, 3, 3,
      10, 7, 6, 1, 7, 9, 1, 6, 7, 3, 1, 5, 3, 7, 2, 5, 6, 5, 4, 6,
      10, 1, 1, 1, 10, 1, 6, 7, 6, 6, 3, 7, 7, 6, 5, 7, 6, 9, 7, 8,
      6, 3, 7, 9, 3, 7, 6, 6, 2, 6, 3, 3, 2, 7, 1, 6, 6, 6, 3, 6, 6,
      3, 7, 7, 1, 3, 7, 3, 6, 8, 6, 3, 7, 6, 7, 7, 1, 3, 6, 7, 3, 7,
      3, 7, 3, 3, 5, 5, 2, 6, 3, 1, 6, 7, 6, 7, 5, 2, 7, 6, 5, 7, 1,
      8, 7, 3, 9, 7, 6)), row.names = c(NA, -132L), class = c("data.frame"))


      I would like to know a percentage agreement between the two groups, however I cannot figure out how to calculate it.



      Ultimately, I would like to arrive at something as:



      ID's grouped together in both "Group_1" and "Group_2" divided by N



      My assumption would then be that ID's grouped similarly by both algorithms are correctly labelled and I could redo the clustering with the remaining ID's.










      share|improve this question

















      This question already has an answer here:



      • How can you compare two cluster groupings in terms of similarity or overlap in Python?

        2 answers



      I have applied two different clustering algorithms to my data, and I would like to express the commonality among the results of these.



      The data is organized as;



      • "ID" = Identifier

      • "Group_1" = Results from first clustering algorithm

      • "Group_2" = Results from second clustering algorithm.

      Group_1 is the output of a hierarchical clustering, which had the highest CVI at k = 5, and Group_2 is the output of k-means clustering, which had the highest CVI at k = 10.



      I would like to determine the similarity of the results.



      Here is the data, which I try to find the similarity of:



      structure(list(ID = c(400100L, 400101L, 400106L, 442306L, 443110L, 
      443300L, 443301L, 443302L, 443303L, 443304L, 443307L, 443309L,
      443311L, 443312L, 443313L, 443314L, 443316L, 443317L, 443322L,
      443324L, 443328L, 443329L, 443330L, 443331L, 443332L, 443333L,
      443334L, 443339L, 443344L, 443345L, 443351L, 443365L, 443366L,
      443371L, 443378L, 443382L, 443383L, 443388L, 443390L, 443392L,
      443396L, 443398L, 443399L, 443506L, 443507L, 443511L, 443512L,
      443514L, 443521L, 443522L, 443800L, 443802L, 443816L, 443817L,
      443819L, 443820L, 443823L, 443825L, 443828L, 443829L, 443833L,
      443842L, 443855L, 443859L, 443876L, 443877L, 443879L, 444101L,
      444104L, 444202L, 444204L, 444207L, 444251L, 444305L, 444307L,
      444309L, 444312L, 444314L, 444325L, 444327L, 444328L, 444334L,
      444335L, 444339L, 444341L, 444346L, 444359L, 444501L, 444504L,
      444508L, 444509L, 444511L, 444512L, 444514L, 444517L, 444520L,
      444521L, 444547L, 444548L, 444554L, 445101L, 445106L, 445112L,
      445113L, 445115L, 445120L, 445141L, 445302L, 445303L, 445304L,
      445309L, 445312L, 445313L, 445315L, 445316L, 445318L, 445319L,
      445322L, 445327L, 445330L, 445333L, 445404L, 445405L, 445409L,
      445510L, 445522L, 445552L, 445560L, 451704L, 451705L, 452503L,
      452514L), Group_1 = c(1L, 1L, 2L, 2L, 3L, 2L, 4L, 2L, 2L, 1L,
      2L, 2L, 2L, 2L, 1L, 1L, 1L, 2L, 5L, 2L, 2L, 4L, 4L, 4L, 5L, 5L,
      2L, 2L, 1L, 1L, 2L, 2L, 3L, 4L, 4L, 3L, 2L, 2L, 1L, 3L, 1L, 1L,
      3L, 2L, 3L, 2L, 1L, 4L, 2L, 5L, 4L, 5L, 3L, 4L, 1L, 2L, 3L, 2L,
      2L, 5L, 4L, 2L, 2L, 5L, 1L, 1L, 1L, 2L, 5L, 4L, 4L, 2L, 3L, 3L,
      1L, 2L, 1L, 4L, 2L, 4L, 5L, 1L, 4L, 2L, 4L, 2L, 3L, 2L, 2L, 2L,
      1L, 2L, 2L, 3L, 4L, 2L, 2L, 3L, 4L, 1L, 1L, 5L, 2L, 2L, 3L, 4L,
      3L, 5L, 4L, 1L, 1L, 1L, 2L, 4L, 3L, 4L, 4L, 1L, 2L, 1L, 1L, 2L,
      5L, 4L, 4L, 2L, 4L, 3L, 1L, 1L, 3L, 5L), Group_2 = c(7, 7, 7,
      7, 8, 3, 3, 7, 3, 9, 6, 1, 7, 7, 10, 7, 4, 6, 7, 7, 6, 3, 3,
      10, 7, 6, 1, 7, 9, 1, 6, 7, 3, 1, 5, 3, 7, 2, 5, 6, 5, 4, 6,
      10, 1, 1, 1, 10, 1, 6, 7, 6, 6, 3, 7, 7, 6, 5, 7, 6, 9, 7, 8,
      6, 3, 7, 9, 3, 7, 6, 6, 2, 6, 3, 3, 2, 7, 1, 6, 6, 6, 3, 6, 6,
      3, 7, 7, 1, 3, 7, 3, 6, 8, 6, 3, 7, 6, 7, 7, 1, 3, 6, 7, 3, 7,
      3, 7, 3, 3, 5, 5, 2, 6, 3, 1, 6, 7, 6, 7, 5, 2, 7, 6, 5, 7, 1,
      8, 7, 3, 9, 7, 6)), row.names = c(NA, -132L), class = c("data.frame"))


      I would like to know a percentage agreement between the two groups, however I cannot figure out how to calculate it.



      Ultimately, I would like to arrive at something as:



      ID's grouped together in both "Group_1" and "Group_2" divided by N



      My assumption would then be that ID's grouped similarly by both algorithms are correctly labelled and I could redo the clustering with the remaining ID's.





      This question already has an answer here:



      • How can you compare two cluster groupings in terms of similarity or overlap in Python?

        2 answers







      r cluster-analysis similarity






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 23 at 20:56









      markus

      16.8k21439




      16.8k21439










      asked Mar 23 at 20:46









      JPMJPM

      43




      43




      marked as duplicate by Anony-Mousse cluster-analysis
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          1 Answer
          1






          active

          oldest

          votes


















          0














          Standard clustering evaluation measures such as



          • adjusted Rand index (ARI)

          • Normalized mutual information (NMI)

          can be used to evaluate the similarity of two clusterings. It's easy to see that they are symmetric.






          share|improve this answer























          • Maybe, I was not clear in my description. One thing, is that I want to determine the symmetry between the groupings - and here you are right. I could use one of the above. However, this does not help me in determining the IDs, which have been clustered similarly by both the first and second method, and thus does not help me in establishing the certainty of the clusters.

            – JPM
            Mar 24 at 12:55











          • If you study these measures, you'll see that clustering is predicting whether two objects are in the same cluster, or in different clusters. So the level you'll need to argue is on pairs of objects, not single IDs.

            – Anony-Mousse
            Mar 24 at 14:35

















          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          Standard clustering evaluation measures such as



          • adjusted Rand index (ARI)

          • Normalized mutual information (NMI)

          can be used to evaluate the similarity of two clusterings. It's easy to see that they are symmetric.






          share|improve this answer























          • Maybe, I was not clear in my description. One thing, is that I want to determine the symmetry between the groupings - and here you are right. I could use one of the above. However, this does not help me in determining the IDs, which have been clustered similarly by both the first and second method, and thus does not help me in establishing the certainty of the clusters.

            – JPM
            Mar 24 at 12:55











          • If you study these measures, you'll see that clustering is predicting whether two objects are in the same cluster, or in different clusters. So the level you'll need to argue is on pairs of objects, not single IDs.

            – Anony-Mousse
            Mar 24 at 14:35















          0














          Standard clustering evaluation measures such as



          • adjusted Rand index (ARI)

          • Normalized mutual information (NMI)

          can be used to evaluate the similarity of two clusterings. It's easy to see that they are symmetric.






          share|improve this answer























          • Maybe, I was not clear in my description. One thing, is that I want to determine the symmetry between the groupings - and here you are right. I could use one of the above. However, this does not help me in determining the IDs, which have been clustered similarly by both the first and second method, and thus does not help me in establishing the certainty of the clusters.

            – JPM
            Mar 24 at 12:55











          • If you study these measures, you'll see that clustering is predicting whether two objects are in the same cluster, or in different clusters. So the level you'll need to argue is on pairs of objects, not single IDs.

            – Anony-Mousse
            Mar 24 at 14:35













          0












          0








          0







          Standard clustering evaluation measures such as



          • adjusted Rand index (ARI)

          • Normalized mutual information (NMI)

          can be used to evaluate the similarity of two clusterings. It's easy to see that they are symmetric.






          share|improve this answer













          Standard clustering evaluation measures such as



          • adjusted Rand index (ARI)

          • Normalized mutual information (NMI)

          can be used to evaluate the similarity of two clusterings. It's easy to see that they are symmetric.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 23 at 23:11









          Anony-MousseAnony-Mousse

          60k799164




          60k799164












          • Maybe, I was not clear in my description. One thing, is that I want to determine the symmetry between the groupings - and here you are right. I could use one of the above. However, this does not help me in determining the IDs, which have been clustered similarly by both the first and second method, and thus does not help me in establishing the certainty of the clusters.

            – JPM
            Mar 24 at 12:55











          • If you study these measures, you'll see that clustering is predicting whether two objects are in the same cluster, or in different clusters. So the level you'll need to argue is on pairs of objects, not single IDs.

            – Anony-Mousse
            Mar 24 at 14:35

















          • Maybe, I was not clear in my description. One thing, is that I want to determine the symmetry between the groupings - and here you are right. I could use one of the above. However, this does not help me in determining the IDs, which have been clustered similarly by both the first and second method, and thus does not help me in establishing the certainty of the clusters.

            – JPM
            Mar 24 at 12:55











          • If you study these measures, you'll see that clustering is predicting whether two objects are in the same cluster, or in different clusters. So the level you'll need to argue is on pairs of objects, not single IDs.

            – Anony-Mousse
            Mar 24 at 14:35
















          Maybe, I was not clear in my description. One thing, is that I want to determine the symmetry between the groupings - and here you are right. I could use one of the above. However, this does not help me in determining the IDs, which have been clustered similarly by both the first and second method, and thus does not help me in establishing the certainty of the clusters.

          – JPM
          Mar 24 at 12:55





          Maybe, I was not clear in my description. One thing, is that I want to determine the symmetry between the groupings - and here you are right. I could use one of the above. However, this does not help me in determining the IDs, which have been clustered similarly by both the first and second method, and thus does not help me in establishing the certainty of the clusters.

          – JPM
          Mar 24 at 12:55













          If you study these measures, you'll see that clustering is predicting whether two objects are in the same cluster, or in different clusters. So the level you'll need to argue is on pairs of objects, not single IDs.

          – Anony-Mousse
          Mar 24 at 14:35





          If you study these measures, you'll see that clustering is predicting whether two objects are in the same cluster, or in different clusters. So the level you'll need to argue is on pairs of objects, not single IDs.

          – Anony-Mousse
          Mar 24 at 14:35





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