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How to plot only a specific DBSCAN label using matplotlib?


How do you change the size of figures drawn with matplotlib?Plotting time in Python with MatplotlibHow to put the legend out of the plotHow to create an HTML checkbox with a clickable labelSave plot to image file instead of displaying it using MatplotlibHow do I plot in real-time in a while loop using matplotlib?Setting different color for each series in scatter plot on matplotlibHow to make IPython notebook matplotlib plot inlineVarying cluster labels in DBSCANDBSCAN clustering plotting through ggplot2






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-1















I'm working with sckitlearn/matplotlib to clusterize and plot some data, with 3D projection. The code is working fine, but now I want to plot only a specific DBSCAN label.



I expect to plot individually the labels 0 or 1 or 2, so I can identify more easily the data in each cluster. How can I extract these values? Any ideas?










share|improve this question




























    -1















    I'm working with sckitlearn/matplotlib to clusterize and plot some data, with 3D projection. The code is working fine, but now I want to plot only a specific DBSCAN label.



    I expect to plot individually the labels 0 or 1 or 2, so I can identify more easily the data in each cluster. How can I extract these values? Any ideas?










    share|improve this question
























      -1












      -1








      -1








      I'm working with sckitlearn/matplotlib to clusterize and plot some data, with 3D projection. The code is working fine, but now I want to plot only a specific DBSCAN label.



      I expect to plot individually the labels 0 or 1 or 2, so I can identify more easily the data in each cluster. How can I extract these values? Any ideas?










      share|improve this question














      I'm working with sckitlearn/matplotlib to clusterize and plot some data, with 3D projection. The code is working fine, but now I want to plot only a specific DBSCAN label.



      I expect to plot individually the labels 0 or 1 or 2, so I can identify more easily the data in each cluster. How can I extract these values? Any ideas?







      python-2.7 matplotlib label dbscan






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 23 at 20:47









      Bruno SantosBruno Santos

      234




      234






















          1 Answer
          1






          active

          oldest

          votes


















          1














          Use array indexing.



          You can plot X[label == 1] easily.






          share|improve this answer























          • I'm plotting like: plt.scatter(X[:,0], X[:,1], X[:,2], c=db.labels_, cmap='rainbow') Altering to: plt.scatter(X[db.labels_ == 1], c=db.labels_, cmap='rainbow') or plt.scatter(X[db.labels_ == 1], X[db.labels_ == 1], X[db.labels_ == 1], c=db.labels_, cmap='rainbow') did not go well.

            – Bruno Santos
            Mar 24 at 14:01












          • Since X is 2d, you'll want a two dimensional index there, as before. Or you define subX=X[labels==1] and plot it as before.

            – Anony-Mousse
            Mar 24 at 14:36











          Your Answer






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          1 Answer
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          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          Use array indexing.



          You can plot X[label == 1] easily.






          share|improve this answer























          • I'm plotting like: plt.scatter(X[:,0], X[:,1], X[:,2], c=db.labels_, cmap='rainbow') Altering to: plt.scatter(X[db.labels_ == 1], c=db.labels_, cmap='rainbow') or plt.scatter(X[db.labels_ == 1], X[db.labels_ == 1], X[db.labels_ == 1], c=db.labels_, cmap='rainbow') did not go well.

            – Bruno Santos
            Mar 24 at 14:01












          • Since X is 2d, you'll want a two dimensional index there, as before. Or you define subX=X[labels==1] and plot it as before.

            – Anony-Mousse
            Mar 24 at 14:36















          1














          Use array indexing.



          You can plot X[label == 1] easily.






          share|improve this answer























          • I'm plotting like: plt.scatter(X[:,0], X[:,1], X[:,2], c=db.labels_, cmap='rainbow') Altering to: plt.scatter(X[db.labels_ == 1], c=db.labels_, cmap='rainbow') or plt.scatter(X[db.labels_ == 1], X[db.labels_ == 1], X[db.labels_ == 1], c=db.labels_, cmap='rainbow') did not go well.

            – Bruno Santos
            Mar 24 at 14:01












          • Since X is 2d, you'll want a two dimensional index there, as before. Or you define subX=X[labels==1] and plot it as before.

            – Anony-Mousse
            Mar 24 at 14:36













          1












          1








          1







          Use array indexing.



          You can plot X[label == 1] easily.






          share|improve this answer













          Use array indexing.



          You can plot X[label == 1] easily.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 23 at 23:06









          Anony-MousseAnony-Mousse

          60k799164




          60k799164












          • I'm plotting like: plt.scatter(X[:,0], X[:,1], X[:,2], c=db.labels_, cmap='rainbow') Altering to: plt.scatter(X[db.labels_ == 1], c=db.labels_, cmap='rainbow') or plt.scatter(X[db.labels_ == 1], X[db.labels_ == 1], X[db.labels_ == 1], c=db.labels_, cmap='rainbow') did not go well.

            – Bruno Santos
            Mar 24 at 14:01












          • Since X is 2d, you'll want a two dimensional index there, as before. Or you define subX=X[labels==1] and plot it as before.

            – Anony-Mousse
            Mar 24 at 14:36

















          • I'm plotting like: plt.scatter(X[:,0], X[:,1], X[:,2], c=db.labels_, cmap='rainbow') Altering to: plt.scatter(X[db.labels_ == 1], c=db.labels_, cmap='rainbow') or plt.scatter(X[db.labels_ == 1], X[db.labels_ == 1], X[db.labels_ == 1], c=db.labels_, cmap='rainbow') did not go well.

            – Bruno Santos
            Mar 24 at 14:01












          • Since X is 2d, you'll want a two dimensional index there, as before. Or you define subX=X[labels==1] and plot it as before.

            – Anony-Mousse
            Mar 24 at 14:36
















          I'm plotting like: plt.scatter(X[:,0], X[:,1], X[:,2], c=db.labels_, cmap='rainbow') Altering to: plt.scatter(X[db.labels_ == 1], c=db.labels_, cmap='rainbow') or plt.scatter(X[db.labels_ == 1], X[db.labels_ == 1], X[db.labels_ == 1], c=db.labels_, cmap='rainbow') did not go well.

          – Bruno Santos
          Mar 24 at 14:01






          I'm plotting like: plt.scatter(X[:,0], X[:,1], X[:,2], c=db.labels_, cmap='rainbow') Altering to: plt.scatter(X[db.labels_ == 1], c=db.labels_, cmap='rainbow') or plt.scatter(X[db.labels_ == 1], X[db.labels_ == 1], X[db.labels_ == 1], c=db.labels_, cmap='rainbow') did not go well.

          – Bruno Santos
          Mar 24 at 14:01














          Since X is 2d, you'll want a two dimensional index there, as before. Or you define subX=X[labels==1] and plot it as before.

          – Anony-Mousse
          Mar 24 at 14:36





          Since X is 2d, you'll want a two dimensional index there, as before. Or you define subX=X[labels==1] and plot it as before.

          – Anony-Mousse
          Mar 24 at 14:36



















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