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How to convert 'x' minute format to 'xx' in vb.net
Vb.net countdownWhat is a NullReferenceException, and how do I fix it?Convert Visual Basic 6.0 type to VB.NET 'Structure'How to run vb.net project in another pc?FTP upload ProgressBar in VB.NETVB.NET: Countdown the Time Selected from DatabaseVB.Net Formatting TimeSpan with .Net Framework 2.0Timer not working in VB.NET 2010Convert string from two textboxes to hh:mm vb.NETVb.net How to make your Application goes Sleep if not used 10 minutes or 15 minutes
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So, I'm making a VB.NET software, and want to show minute format as XX minute, e.g: "05 minute left" and not like this: "5 minute left." My code now like this:
min = DateTime.Now.ToString("mm") + NumericUpDown2.Value
I've tried with big "MM" letters but it's just another time format.
Is that a countdown application, and when I'm try to check the time failed.
If Date.Time.Minutes = min Than
Alarm.show
End If
vb.net
asked Mar 23 at 19:31
NightelsNightels
12
add a comment |
So, I'm making a VB.NET software, and want to show minute format as XX minute, e.g: "05 minute left" and not like this: "5 minute left." My code now like this:
min = DateTime.Now.ToString("mm") + NumericUpDown2.Value
I've tried with big "MM" letters but it's just another time format.
Is that a countdown application, and when I'm try to check the time failed.
If Date.Time.Minutes = min Than
Alarm.show
End If
vb.net
asked Mar 23 at 19:31
NightelsNightels
12
What type of variable ismin? Are you performing addition or concatenation? If addition: You cannot format the number before you display it.DateTime.Now.ToString("mm")will be converted back into an integer (integers have no format) before being added withNumericUpDown2.Value.
– Visual Vincent
Mar 23 at 20:08
3
Set Option Strict On. No matter what typeminis, the rest of the code is gluing a number to a string.
– Nat Pongjardenlarp
Mar 23 at 20:12
min is string and if i display text to any label and add NumericUpDown2.Value i get ineffectual numbers. e.g min = 10 and NumericUpDown2.Value = 15 i get this: 1015 :/
– Nightels
Mar 23 at 20:15
You are appending strings here! To get the integer values added, you should be using some parsing mechanism such asInteger.Parsehere. But first of all, set option strict on and the rest will become visible.
– preciousbetine
Mar 23 at 20:32
1
Please turn on Option Strict. This is a 2 part process. First for the current project - In Solution Explorer double click My Project. Choose Compile on the left. In the Option Strict drop-down select ON. Second for future projects - Go to the Tools Menu -> Options -> Projects and Solutions -> VB Defaults. In the Option Strict drop-down select ON. This will save you from bugs at runtime.
– Mary
Mar 23 at 20:33
add a comment |
So, I'm making a VB.NET software, and want to show minute format as XX minute, e.g: "05 minute left" and not like this: "5 minute left." My code now like this:
min = DateTime.Now.ToString("mm") + NumericUpDown2.Value
I've tried with big "MM" letters but it's just another time format.
Is that a countdown application, and when I'm try to check the time failed.
If Date.Time.Minutes = min Than
Alarm.show
End If
vb.net
asked Mar 23 at 19:31
NightelsNightels
12
So, I'm making a VB.NET software, and want to show minute format as XX minute, e.g: "05 minute left" and not like this: "5 minute left." My code now like this:
min = DateTime.Now.ToString("mm") + NumericUpDown2.Value
I've tried with big "MM" letters but it's just another time format.
Is that a countdown application, and when I'm try to check the time failed.
If Date.Time.Minutes = min Than
Alarm.show
End If
vb.net
vb.net
asked Mar 23 at 19:31
NightelsNightels
12
asked Mar 23 at 19:31
NightelsNightels
12
asked Mar 23 at 19:31
NightelsNightels
12
asked Mar 23 at 19:31
NightelsNightels
12
asked Mar 23 at 19:31
NightelsNightels
12
12
What type of variable ismin? Are you performing addition or concatenation? If addition: You cannot format the number before you display it.DateTime.Now.ToString("mm")will be converted back into an integer (integers have no format) before being added withNumericUpDown2.Value.
– Visual Vincent
Mar 23 at 20:08
3
Set Option Strict On. No matter what typeminis, the rest of the code is gluing a number to a string.
– Nat Pongjardenlarp
Mar 23 at 20:12
min is string and if i display text to any label and add NumericUpDown2.Value i get ineffectual numbers. e.g min = 10 and NumericUpDown2.Value = 15 i get this: 1015 :/
– Nightels
Mar 23 at 20:15
You are appending strings here! To get the integer values added, you should be using some parsing mechanism such asInteger.Parsehere. But first of all, set option strict on and the rest will become visible.
– preciousbetine
Mar 23 at 20:32
1
Please turn on Option Strict. This is a 2 part process. First for the current project - In Solution Explorer double click My Project. Choose Compile on the left. In the Option Strict drop-down select ON. Second for future projects - Go to the Tools Menu -> Options -> Projects and Solutions -> VB Defaults. In the Option Strict drop-down select ON. This will save you from bugs at runtime.
– Mary
Mar 23 at 20:33
add a comment |
What type of variable ismin? Are you performing addition or concatenation? If addition: You cannot format the number before you display it.DateTime.Now.ToString("mm")will be converted back into an integer (integers have no format) before being added withNumericUpDown2.Value.
– Visual Vincent
Mar 23 at 20:08
3
Set Option Strict On. No matter what typeminis, the rest of the code is gluing a number to a string.
– Nat Pongjardenlarp
Mar 23 at 20:12
min is string and if i display text to any label and add NumericUpDown2.Value i get ineffectual numbers. e.g min = 10 and NumericUpDown2.Value = 15 i get this: 1015 :/
– Nightels
Mar 23 at 20:15
You are appending strings here! To get the integer values added, you should be using some parsing mechanism such asInteger.Parsehere. But first of all, set option strict on and the rest will become visible.
– preciousbetine
Mar 23 at 20:32
1
Please turn on Option Strict. This is a 2 part process. First for the current project - In Solution Explorer double click My Project. Choose Compile on the left. In the Option Strict drop-down select ON. Second for future projects - Go to the Tools Menu -> Options -> Projects and Solutions -> VB Defaults. In the Option Strict drop-down select ON. This will save you from bugs at runtime.
– Mary
Mar 23 at 20:33
What type of variable is
min? Are you performing addition or concatenation? If addition: You cannot format the number before you display it. DateTime.Now.ToString("mm") will be converted back into an integer (integers have no format) before being added with NumericUpDown2.Value.– Visual Vincent
Mar 23 at 20:08
What type of variable is
min? Are you performing addition or concatenation? If addition: You cannot format the number before you display it. DateTime.Now.ToString("mm") will be converted back into an integer (integers have no format) before being added with NumericUpDown2.Value.– Visual Vincent
Mar 23 at 20:08
3
3
Set Option Strict On. No matter what type
min is, the rest of the code is gluing a number to a string.– Nat Pongjardenlarp
Mar 23 at 20:12
Set Option Strict On. No matter what type
min is, the rest of the code is gluing a number to a string.– Nat Pongjardenlarp
Mar 23 at 20:12
min is string and if i display text to any label and add NumericUpDown2.Value i get ineffectual numbers. e.g min = 10 and NumericUpDown2.Value = 15 i get this: 1015 :/
– Nightels
Mar 23 at 20:15
min is string and if i display text to any label and add NumericUpDown2.Value i get ineffectual numbers. e.g min = 10 and NumericUpDown2.Value = 15 i get this: 1015 :/
– Nightels
Mar 23 at 20:15
You are appending strings here! To get the integer values added, you should be using some parsing mechanism such as
Integer.Parse here. But first of all, set option strict on and the rest will become visible.– preciousbetine
Mar 23 at 20:32
You are appending strings here! To get the integer values added, you should be using some parsing mechanism such as
Integer.Parse here. But first of all, set option strict on and the rest will become visible.– preciousbetine
Mar 23 at 20:32
1
1
Please turn on Option Strict. This is a 2 part process. First for the current project - In Solution Explorer double click My Project. Choose Compile on the left. In the Option Strict drop-down select ON. Second for future projects - Go to the Tools Menu -> Options -> Projects and Solutions -> VB Defaults. In the Option Strict drop-down select ON. This will save you from bugs at runtime.
– Mary
Mar 23 at 20:33
Please turn on Option Strict. This is a 2 part process. First for the current project - In Solution Explorer double click My Project. Choose Compile on the left. In the Option Strict drop-down select ON. Second for future projects - Go to the Tools Menu -> Options -> Projects and Solutions -> VB Defaults. In the Option Strict drop-down select ON. This will save you from bugs at runtime.
– Mary
Mar 23 at 20:33
add a comment |
2 Answers
2
active
oldest
votes
Although this code has not been tested it should give you some ideas of how to proceed. As far as the formatting is concerned - right pew, wrong church. Number.ToString("00")
Private AlarmTime As DateTime
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
AlarmTime = DateTime.Now.AddMinutes(NumericUpDown1.Value)
Timer1.Enabled = True
End Sub
Private Sub Timer1_Tick(sender As Object, e As EventArgs) Handles Timer1.Tick
Dim TimeLeft As TimeSpan = AlarmTime - DateTime.Now
Dim MinutesLeft As Integer = TimeLeft.Minutes
Label1.Text = MinutesLeft.ToString("00")
If AlarmTime >= DateTime.Now Then
Alarm.Show()
Timer1.Enabled = False
End If
End Sub
answered Mar 23 at 21:04
MaryMary
4,5362921
add a comment |
The right way to do this is like this:
DateTime.Now.Minute.ToString("00")
answered Mar 26 at 8:17
Faiz InfyFaiz Infy
785
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Although this code has not been tested it should give you some ideas of how to proceed. As far as the formatting is concerned - right pew, wrong church. Number.ToString("00")
Private AlarmTime As DateTime
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
AlarmTime = DateTime.Now.AddMinutes(NumericUpDown1.Value)
Timer1.Enabled = True
End Sub
Private Sub Timer1_Tick(sender As Object, e As EventArgs) Handles Timer1.Tick
Dim TimeLeft As TimeSpan = AlarmTime - DateTime.Now
Dim MinutesLeft As Integer = TimeLeft.Minutes
Label1.Text = MinutesLeft.ToString("00")
If AlarmTime >= DateTime.Now Then
Alarm.Show()
Timer1.Enabled = False
End If
End Sub
answered Mar 23 at 21:04
MaryMary
4,5362921
add a comment |
Although this code has not been tested it should give you some ideas of how to proceed. As far as the formatting is concerned - right pew, wrong church. Number.ToString("00")
Private AlarmTime As DateTime
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
AlarmTime = DateTime.Now.AddMinutes(NumericUpDown1.Value)
Timer1.Enabled = True
End Sub
Private Sub Timer1_Tick(sender As Object, e As EventArgs) Handles Timer1.Tick
Dim TimeLeft As TimeSpan = AlarmTime - DateTime.Now
Dim MinutesLeft As Integer = TimeLeft.Minutes
Label1.Text = MinutesLeft.ToString("00")
If AlarmTime >= DateTime.Now Then
Alarm.Show()
Timer1.Enabled = False
End If
End Sub
answered Mar 23 at 21:04
MaryMary
4,5362921
add a comment |
Although this code has not been tested it should give you some ideas of how to proceed. As far as the formatting is concerned - right pew, wrong church. Number.ToString("00")
Private AlarmTime As DateTime
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
AlarmTime = DateTime.Now.AddMinutes(NumericUpDown1.Value)
Timer1.Enabled = True
End Sub
Private Sub Timer1_Tick(sender As Object, e As EventArgs) Handles Timer1.Tick
Dim TimeLeft As TimeSpan = AlarmTime - DateTime.Now
Dim MinutesLeft As Integer = TimeLeft.Minutes
Label1.Text = MinutesLeft.ToString("00")
If AlarmTime >= DateTime.Now Then
Alarm.Show()
Timer1.Enabled = False
End If
End Sub
answered Mar 23 at 21:04
MaryMary
4,5362921
Although this code has not been tested it should give you some ideas of how to proceed. As far as the formatting is concerned - right pew, wrong church. Number.ToString("00")
Private AlarmTime As DateTime
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
AlarmTime = DateTime.Now.AddMinutes(NumericUpDown1.Value)
Timer1.Enabled = True
End Sub
Private Sub Timer1_Tick(sender As Object, e As EventArgs) Handles Timer1.Tick
Dim TimeLeft As TimeSpan = AlarmTime - DateTime.Now
Dim MinutesLeft As Integer = TimeLeft.Minutes
Label1.Text = MinutesLeft.ToString("00")
If AlarmTime >= DateTime.Now Then
Alarm.Show()
Timer1.Enabled = False
End If
End Sub
answered Mar 23 at 21:04
MaryMary
4,5362921
answered Mar 23 at 21:04
MaryMary
4,5362921
answered Mar 23 at 21:04
MaryMary
4,5362921
answered Mar 23 at 21:04
MaryMary
4,5362921
4,5362921
add a comment |
add a comment |
The right way to do this is like this:
DateTime.Now.Minute.ToString("00")
answered Mar 26 at 8:17
Faiz InfyFaiz Infy
785
add a comment |
The right way to do this is like this:
DateTime.Now.Minute.ToString("00")
answered Mar 26 at 8:17
Faiz InfyFaiz Infy
785
add a comment |
The right way to do this is like this:
DateTime.Now.Minute.ToString("00")
answered Mar 26 at 8:17
Faiz InfyFaiz Infy
785
The right way to do this is like this:
DateTime.Now.Minute.ToString("00")
answered Mar 26 at 8:17
Faiz InfyFaiz Infy
785
answered Mar 26 at 8:17
Faiz InfyFaiz Infy
785
answered Mar 26 at 8:17
Faiz InfyFaiz Infy
785
answered Mar 26 at 8:17
Faiz InfyFaiz Infy
785
785
add a comment |
add a comment |
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What type of variable is
min? Are you performing addition or concatenation? If addition: You cannot format the number before you display it.DateTime.Now.ToString("mm")will be converted back into an integer (integers have no format) before being added withNumericUpDown2.Value.– Visual Vincent
Mar 23 at 20:08
3
Set Option Strict On. No matter what type
minis, the rest of the code is gluing a number to a string.– Nat Pongjardenlarp
Mar 23 at 20:12
min is string and if i display text to any label and add NumericUpDown2.Value i get ineffectual numbers. e.g min = 10 and NumericUpDown2.Value = 15 i get this: 1015 :/
– Nightels
Mar 23 at 20:15
You are appending strings here! To get the integer values added, you should be using some parsing mechanism such as
Integer.Parsehere. But first of all, set option strict on and the rest will become visible.– preciousbetine
Mar 23 at 20:32
1
Please turn on Option Strict. This is a 2 part process. First for the current project - In Solution Explorer double click My Project. Choose Compile on the left. In the Option Strict drop-down select ON. Second for future projects - Go to the Tools Menu -> Options -> Projects and Solutions -> VB Defaults. In the Option Strict drop-down select ON. This will save you from bugs at runtime.
– Mary
Mar 23 at 20:33