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java iterator throwing awt-eventqueue exception


Is Java “pass-by-reference” or “pass-by-value”?How do I efficiently iterate over each entry in a Java Map?What is the difference between public, protected, package-private and private in Java?How do I read / convert an InputStream into a String in Java?When to use LinkedList over ArrayList in Java?How do I generate random integers within a specific range in Java?Iterate through a HashMapHow do I convert a String to an int in Java?Creating a memory leak with JavaException when removing elements from ArrayList?






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0















I'm writing a program that adds items to a list and uses an iterator to print all of the items to a JTextArea. I'm a little confused because I thought it was because if there is no next, I'm trying to print a null statement, but doesn't the condition of the while loop check if there's a next object in the iterator?



I know the issue is only with the println, since if I remove it the program works fine. However, is there a way I can access the next object in the iterator as a string?



while (iter.hasNext())

System.out.println(iter.next().toString());
i++;
r = i + " x " + formatter.formatLineItem(iter.next());



Here's the stack trace:



 Exception in thread "AWT-EventQueue-0" 
java.lang.IndexOutOfBoundsException: Index 2 out-of-bounds for length 2
at java.base/jdk.internal.util.Preconditions.outOfBounds(Preconditions.java:64)
at java.base/jdk.internal.util.Preconditions.outOfBoundsCheckIndex(Preconditions.java:70)
at java.base/jdk.internal.util.Preconditions.checkIndex(Preconditions.java:248)
at java.base/java.util.Objects.checkIndex(Objects.java:372)
at java.base/java.util.ArrayList.get(ArrayList.java:440)
at Invoice$1.next(Invoice.java:56)
at Invoice$1.next(Invoice.java:48)
at Invoice.format(Invoice.java:80)


It's throwing a "AWT-Eventqueue-0" exception. I'm currently using the println to be able to see what exactly which items are in the iterator because I want to classify each item by name. However, I want to be able to access the string of the item that's in the iterator.










share|improve this question



















  • 3





    You call iter.next() twice after only one check to iter.hasNext(). Also, is this a custom Iterator? If there's no more elements then next() should throw NoSuchElementException, not IndexOutOfBoundsException.

    – Slaw
    Mar 23 at 16:53












  • How can I refer to the same iter.next for both calls?

    – Jamie L.
    Mar 23 at 16:55











  • Store the result in a local variable, then use the variable to reference the element.

    – Slaw
    Mar 23 at 16:55

















0















I'm writing a program that adds items to a list and uses an iterator to print all of the items to a JTextArea. I'm a little confused because I thought it was because if there is no next, I'm trying to print a null statement, but doesn't the condition of the while loop check if there's a next object in the iterator?



I know the issue is only with the println, since if I remove it the program works fine. However, is there a way I can access the next object in the iterator as a string?



while (iter.hasNext())

System.out.println(iter.next().toString());
i++;
r = i + " x " + formatter.formatLineItem(iter.next());



Here's the stack trace:



 Exception in thread "AWT-EventQueue-0" 
java.lang.IndexOutOfBoundsException: Index 2 out-of-bounds for length 2
at java.base/jdk.internal.util.Preconditions.outOfBounds(Preconditions.java:64)
at java.base/jdk.internal.util.Preconditions.outOfBoundsCheckIndex(Preconditions.java:70)
at java.base/jdk.internal.util.Preconditions.checkIndex(Preconditions.java:248)
at java.base/java.util.Objects.checkIndex(Objects.java:372)
at java.base/java.util.ArrayList.get(ArrayList.java:440)
at Invoice$1.next(Invoice.java:56)
at Invoice$1.next(Invoice.java:48)
at Invoice.format(Invoice.java:80)


It's throwing a "AWT-Eventqueue-0" exception. I'm currently using the println to be able to see what exactly which items are in the iterator because I want to classify each item by name. However, I want to be able to access the string of the item that's in the iterator.










share|improve this question



















  • 3





    You call iter.next() twice after only one check to iter.hasNext(). Also, is this a custom Iterator? If there's no more elements then next() should throw NoSuchElementException, not IndexOutOfBoundsException.

    – Slaw
    Mar 23 at 16:53












  • How can I refer to the same iter.next for both calls?

    – Jamie L.
    Mar 23 at 16:55











  • Store the result in a local variable, then use the variable to reference the element.

    – Slaw
    Mar 23 at 16:55













0












0








0








I'm writing a program that adds items to a list and uses an iterator to print all of the items to a JTextArea. I'm a little confused because I thought it was because if there is no next, I'm trying to print a null statement, but doesn't the condition of the while loop check if there's a next object in the iterator?



I know the issue is only with the println, since if I remove it the program works fine. However, is there a way I can access the next object in the iterator as a string?



while (iter.hasNext())

System.out.println(iter.next().toString());
i++;
r = i + " x " + formatter.formatLineItem(iter.next());



Here's the stack trace:



 Exception in thread "AWT-EventQueue-0" 
java.lang.IndexOutOfBoundsException: Index 2 out-of-bounds for length 2
at java.base/jdk.internal.util.Preconditions.outOfBounds(Preconditions.java:64)
at java.base/jdk.internal.util.Preconditions.outOfBoundsCheckIndex(Preconditions.java:70)
at java.base/jdk.internal.util.Preconditions.checkIndex(Preconditions.java:248)
at java.base/java.util.Objects.checkIndex(Objects.java:372)
at java.base/java.util.ArrayList.get(ArrayList.java:440)
at Invoice$1.next(Invoice.java:56)
at Invoice$1.next(Invoice.java:48)
at Invoice.format(Invoice.java:80)


It's throwing a "AWT-Eventqueue-0" exception. I'm currently using the println to be able to see what exactly which items are in the iterator because I want to classify each item by name. However, I want to be able to access the string of the item that's in the iterator.










share|improve this question
















I'm writing a program that adds items to a list and uses an iterator to print all of the items to a JTextArea. I'm a little confused because I thought it was because if there is no next, I'm trying to print a null statement, but doesn't the condition of the while loop check if there's a next object in the iterator?



I know the issue is only with the println, since if I remove it the program works fine. However, is there a way I can access the next object in the iterator as a string?



while (iter.hasNext())

System.out.println(iter.next().toString());
i++;
r = i + " x " + formatter.formatLineItem(iter.next());



Here's the stack trace:



 Exception in thread "AWT-EventQueue-0" 
java.lang.IndexOutOfBoundsException: Index 2 out-of-bounds for length 2
at java.base/jdk.internal.util.Preconditions.outOfBounds(Preconditions.java:64)
at java.base/jdk.internal.util.Preconditions.outOfBoundsCheckIndex(Preconditions.java:70)
at java.base/jdk.internal.util.Preconditions.checkIndex(Preconditions.java:248)
at java.base/java.util.Objects.checkIndex(Objects.java:372)
at java.base/java.util.ArrayList.get(ArrayList.java:440)
at Invoice$1.next(Invoice.java:56)
at Invoice$1.next(Invoice.java:48)
at Invoice.format(Invoice.java:80)


It's throwing a "AWT-Eventqueue-0" exception. I'm currently using the println to be able to see what exactly which items are in the iterator because I want to classify each item by name. However, I want to be able to access the string of the item that's in the iterator.







java iterator






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 23 at 16:49







Jamie L.

















asked Mar 23 at 16:45









Jamie L.Jamie L.

194




194







  • 3





    You call iter.next() twice after only one check to iter.hasNext(). Also, is this a custom Iterator? If there's no more elements then next() should throw NoSuchElementException, not IndexOutOfBoundsException.

    – Slaw
    Mar 23 at 16:53












  • How can I refer to the same iter.next for both calls?

    – Jamie L.
    Mar 23 at 16:55











  • Store the result in a local variable, then use the variable to reference the element.

    – Slaw
    Mar 23 at 16:55












  • 3





    You call iter.next() twice after only one check to iter.hasNext(). Also, is this a custom Iterator? If there's no more elements then next() should throw NoSuchElementException, not IndexOutOfBoundsException.

    – Slaw
    Mar 23 at 16:53












  • How can I refer to the same iter.next for both calls?

    – Jamie L.
    Mar 23 at 16:55











  • Store the result in a local variable, then use the variable to reference the element.

    – Slaw
    Mar 23 at 16:55







3




3





You call iter.next() twice after only one check to iter.hasNext(). Also, is this a custom Iterator? If there's no more elements then next() should throw NoSuchElementException, not IndexOutOfBoundsException.

– Slaw
Mar 23 at 16:53






You call iter.next() twice after only one check to iter.hasNext(). Also, is this a custom Iterator? If there's no more elements then next() should throw NoSuchElementException, not IndexOutOfBoundsException.

– Slaw
Mar 23 at 16:53














How can I refer to the same iter.next for both calls?

– Jamie L.
Mar 23 at 16:55





How can I refer to the same iter.next for both calls?

– Jamie L.
Mar 23 at 16:55













Store the result in a local variable, then use the variable to reference the element.

– Slaw
Mar 23 at 16:55





Store the result in a local variable, then use the variable to reference the element.

– Slaw
Mar 23 at 16:55












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