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use matrix columns in linear fit


How to sort a dataframe by multiple column(s)Drop data frame columns by nameread.table returning character matrix, would like numericDummy Variables for Data Frame Containing only PredictorsHow to write and read matrix from file without column names?Using 'scan' to read into a matrix in RHow can I read a matrix from a txt file in R?How can I make predictor variables into a matrix?Sort a matrix by last columnMultiple regression in R with matrix columns in model






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-1















How to use one column of a numeric matrix as target variable and the remaining columns as predictors?



Somehow this doesn't work



# read matrix with 14 columns
d <- read.table("myfile.txt")

# target variable is last column
y <- d[,14]
x <- d[,-14]
my.fit <- y~x









share|improve this question

















  • 2





    There are at least a couple of major problems with your approach. Have you ever done a linear regression in R before? You don't give a function for controlling your data. Your independent variable is literally a pile of numbers. You might start by looking up "r linear regression".

    – shea
    Mar 24 at 4:41


















-1















How to use one column of a numeric matrix as target variable and the remaining columns as predictors?



Somehow this doesn't work



# read matrix with 14 columns
d <- read.table("myfile.txt")

# target variable is last column
y <- d[,14]
x <- d[,-14]
my.fit <- y~x









share|improve this question

















  • 2





    There are at least a couple of major problems with your approach. Have you ever done a linear regression in R before? You don't give a function for controlling your data. Your independent variable is literally a pile of numbers. You might start by looking up "r linear regression".

    – shea
    Mar 24 at 4:41














-1












-1








-1


1






How to use one column of a numeric matrix as target variable and the remaining columns as predictors?



Somehow this doesn't work



# read matrix with 14 columns
d <- read.table("myfile.txt")

# target variable is last column
y <- d[,14]
x <- d[,-14]
my.fit <- y~x









share|improve this question














How to use one column of a numeric matrix as target variable and the remaining columns as predictors?



Somehow this doesn't work



# read matrix with 14 columns
d <- read.table("myfile.txt")

# target variable is last column
y <- d[,14]
x <- d[,-14]
my.fit <- y~x






r






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 24 at 4:25









quantum_wellquantum_well

374314




374314







  • 2





    There are at least a couple of major problems with your approach. Have you ever done a linear regression in R before? You don't give a function for controlling your data. Your independent variable is literally a pile of numbers. You might start by looking up "r linear regression".

    – shea
    Mar 24 at 4:41













  • 2





    There are at least a couple of major problems with your approach. Have you ever done a linear regression in R before? You don't give a function for controlling your data. Your independent variable is literally a pile of numbers. You might start by looking up "r linear regression".

    – shea
    Mar 24 at 4:41








2




2





There are at least a couple of major problems with your approach. Have you ever done a linear regression in R before? You don't give a function for controlling your data. Your independent variable is literally a pile of numbers. You might start by looking up "r linear regression".

– shea
Mar 24 at 4:41






There are at least a couple of major problems with your approach. Have you ever done a linear regression in R before? You don't give a function for controlling your data. Your independent variable is literally a pile of numbers. You might start by looking up "r linear regression".

– shea
Mar 24 at 4:41













1 Answer
1






active

oldest

votes


















0














You can just do:



data(mtcars) #get some preinstalled data


model <- lm(mpg ~ ., data = mtcars) #fit the model

summary(model) #get the summary



This does a linear regression of mpg against all other variables. No further processing required.






share|improve this answer























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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    You can just do:



    data(mtcars) #get some preinstalled data


    model <- lm(mpg ~ ., data = mtcars) #fit the model

    summary(model) #get the summary



    This does a linear regression of mpg against all other variables. No further processing required.






    share|improve this answer



























      0














      You can just do:



      data(mtcars) #get some preinstalled data


      model <- lm(mpg ~ ., data = mtcars) #fit the model

      summary(model) #get the summary



      This does a linear regression of mpg against all other variables. No further processing required.






      share|improve this answer

























        0












        0








        0







        You can just do:



        data(mtcars) #get some preinstalled data


        model <- lm(mpg ~ ., data = mtcars) #fit the model

        summary(model) #get the summary



        This does a linear regression of mpg against all other variables. No further processing required.






        share|improve this answer













        You can just do:



        data(mtcars) #get some preinstalled data


        model <- lm(mpg ~ ., data = mtcars) #fit the model

        summary(model) #get the summary



        This does a linear regression of mpg against all other variables. No further processing required.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 24 at 9:16









        HumpelstielzchenHumpelstielzchen

        2,3211422




        2,3211422



























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