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@ConditionalOnExpression if property is present
Sort ArrayList of custom Objects by propertyCreate the perfect JPA entityDealing with “Xerces hell” in Java/Maven?Spring Boot @ConditionalOnProperty behaviorZuul router with Spring application.yml routes won't work as expectedHow can I get the keys from application.properties within other properties files served by Spring Boot Config Server?Prefix for nested configuration properties in springSpring boot read array from YAML (properties) fileConfigurationProperties binding a property name with a number in from a yaml file@GetMapping with array parameters by application.yml
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I have application.yml that has a property and it takes an array/list like this
tokens:
token:
- name: one
site: chicago
token:
- name: two
site: 'st. louis'
How do I use @ConditionalOnExpression such that just the presence of tokens in application.yml suffice?
I have tried @ConditionalOnProperty("tokens") and @CondtionalOnProperty(prefix="tokens", value= "token". It does not work. Even the official doc suggests that with lists/arrays it won't work great.
java spring spring-boot
edited Apr 7 at 3:54
Aditya Gupta
1,02721322
asked Mar 25 at 2:46
Faraz DurraniFaraz Durrani
2,93421137
add a comment |
I have application.yml that has a property and it takes an array/list like this
tokens:
token:
- name: one
site: chicago
token:
- name: two
site: 'st. louis'
How do I use @ConditionalOnExpression such that just the presence of tokens in application.yml suffice?
I have tried @ConditionalOnProperty("tokens") and @CondtionalOnProperty(prefix="tokens", value= "token". It does not work. Even the official doc suggests that with lists/arrays it won't work great.
java spring spring-boot
edited Apr 7 at 3:54
Aditya Gupta
1,02721322
asked Mar 25 at 2:46
Faraz DurraniFaraz Durrani
2,93421137
Why would you want to do that? It will be hard to maintain a property which is either present or absent. Programmer will have to go through the code to figure out what property to add for enabling. It would be better to have a second boolean propertytokenPresent.
– Aditya Gupta
Mar 25 at 3:28
This is a very good advise. The trouble is, I am developing an application that will be added as a dependency in other projects. I don't want them to add unnecessary properties. You know what I mean?
– Faraz Durrani
Mar 25 at 3:32
Yeah. I did something like this few months back. Will add an answer now.
– Aditya Gupta
Mar 25 at 3:36
add a comment |
I have application.yml that has a property and it takes an array/list like this
tokens:
token:
- name: one
site: chicago
token:
- name: two
site: 'st. louis'
How do I use @ConditionalOnExpression such that just the presence of tokens in application.yml suffice?
I have tried @ConditionalOnProperty("tokens") and @CondtionalOnProperty(prefix="tokens", value= "token". It does not work. Even the official doc suggests that with lists/arrays it won't work great.
java spring spring-boot
edited Apr 7 at 3:54
Aditya Gupta
1,02721322
asked Mar 25 at 2:46
Faraz DurraniFaraz Durrani
2,93421137
I have application.yml that has a property and it takes an array/list like this
tokens:
token:
- name: one
site: chicago
token:
- name: two
site: 'st. louis'
How do I use @ConditionalOnExpression such that just the presence of tokens in application.yml suffice?
I have tried @ConditionalOnProperty("tokens") and @CondtionalOnProperty(prefix="tokens", value= "token". It does not work. Even the official doc suggests that with lists/arrays it won't work great.
java spring spring-boot
java spring spring-boot
edited Apr 7 at 3:54
Aditya Gupta
1,02721322
asked Mar 25 at 2:46
Faraz DurraniFaraz Durrani
2,93421137
edited Apr 7 at 3:54
Aditya Gupta
1,02721322
asked Mar 25 at 2:46
Faraz DurraniFaraz Durrani
2,93421137
edited Apr 7 at 3:54
Aditya Gupta
1,02721322
edited Apr 7 at 3:54
Aditya Gupta
1,02721322
edited Apr 7 at 3:54
Aditya Gupta
1,02721322
1,02721322
asked Mar 25 at 2:46
Faraz DurraniFaraz Durrani
2,93421137
asked Mar 25 at 2:46
Faraz DurraniFaraz Durrani
2,93421137
asked Mar 25 at 2:46
Faraz DurraniFaraz Durrani
2,93421137
2,93421137
Why would you want to do that? It will be hard to maintain a property which is either present or absent. Programmer will have to go through the code to figure out what property to add for enabling. It would be better to have a second boolean propertytokenPresent.
– Aditya Gupta
Mar 25 at 3:28
This is a very good advise. The trouble is, I am developing an application that will be added as a dependency in other projects. I don't want them to add unnecessary properties. You know what I mean?
– Faraz Durrani
Mar 25 at 3:32
Yeah. I did something like this few months back. Will add an answer now.
– Aditya Gupta
Mar 25 at 3:36
add a comment |
Why would you want to do that? It will be hard to maintain a property which is either present or absent. Programmer will have to go through the code to figure out what property to add for enabling. It would be better to have a second boolean propertytokenPresent.
– Aditya Gupta
Mar 25 at 3:28
This is a very good advise. The trouble is, I am developing an application that will be added as a dependency in other projects. I don't want them to add unnecessary properties. You know what I mean?
– Faraz Durrani
Mar 25 at 3:32
Yeah. I did something like this few months back. Will add an answer now.
– Aditya Gupta
Mar 25 at 3:36
Why would you want to do that? It will be hard to maintain a property which is either present or absent. Programmer will have to go through the code to figure out what property to add for enabling. It would be better to have a second boolean property
tokenPresent.– Aditya Gupta
Mar 25 at 3:28
Why would you want to do that? It will be hard to maintain a property which is either present or absent. Programmer will have to go through the code to figure out what property to add for enabling. It would be better to have a second boolean property
tokenPresent.– Aditya Gupta
Mar 25 at 3:28
This is a very good advise. The trouble is, I am developing an application that will be added as a dependency in other projects. I don't want them to add unnecessary properties. You know what I mean?
– Faraz Durrani
Mar 25 at 3:32
This is a very good advise. The trouble is, I am developing an application that will be added as a dependency in other projects. I don't want them to add unnecessary properties. You know what I mean?
– Faraz Durrani
Mar 25 at 3:32
Yeah. I did something like this few months back. Will add an answer now.
– Aditya Gupta
Mar 25 at 3:36
Yeah. I did something like this few months back. Will add an answer now.
– Aditya Gupta
Mar 25 at 3:36
add a comment |
2 Answers
2
active
oldest
votes
You can use @Conditional(YourCondition.class)
Quoating from docs:
A single condition that must be matched in order for a component to be
registered. Conditions are checked immediately before the
bean-definition is due to be registered and are free to veto
registration based on any criteria that can be determined at that
point.
Illustration:
@Conditional(MyCondition.class)
@Controller
public class Box
...
public class MyCondition implements Condition
@Override
public boolean matches(ConditionContext context, AnnotatedTypeMetadata metadata)
Environment env = context.getEnvironment();
return null == env.getProperty("tokens.token[0].name");
Here, en.getProperty will return null in case of missing property.
edited Mar 25 at 5:58
Faraz Durrani
2,93421137
answered Mar 25 at 4:12
Aditya GuptaAditya Gupta
1,02721322
In theory,ConditionalOnPropertywould accomplish this.
– Makoto
Mar 25 at 4:18
Yeah, but here you can write your logic insideMyConditionclass.
– Aditya Gupta
Mar 25 at 5:02
@AdityaGupta ty. i edited you answer a bit. If I ask forenv.getProperty("tokens"), it always returns null. I have to give full property only then it actually returns a value instead of null.
– Faraz Durrani
Mar 25 at 5:57
Looks good. Thanks for updating.
– Aditya Gupta
Mar 25 at 17:42
add a comment |
@Faraz Durrani try this concept you will get...
@Component
@EnableConfigurationProperties
@ConfigurationProperties(prefix = "tokens")
public class ServiceClass
private String token;
...
answered Mar 25 at 4:26
kumarkumar
274110
1
No Kumar this is totally off. Sorry.
– Faraz Durrani
Mar 25 at 6:00
i done a sample on this and it's working for me ...better to try this....
– kumar
Mar 25 at 9:27
yes I understand kumar. But my question is different. I think you misunderstood the question.
– Faraz Durrani
Mar 26 at 2:43
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use @Conditional(YourCondition.class)
Quoating from docs:
A single condition that must be matched in order for a component to be
registered. Conditions are checked immediately before the
bean-definition is due to be registered and are free to veto
registration based on any criteria that can be determined at that
point.
Illustration:
@Conditional(MyCondition.class)
@Controller
public class Box
...
public class MyCondition implements Condition
@Override
public boolean matches(ConditionContext context, AnnotatedTypeMetadata metadata)
Environment env = context.getEnvironment();
return null == env.getProperty("tokens.token[0].name");
Here, en.getProperty will return null in case of missing property.
edited Mar 25 at 5:58
Faraz Durrani
2,93421137
answered Mar 25 at 4:12
Aditya GuptaAditya Gupta
1,02721322
In theory,ConditionalOnPropertywould accomplish this.
– Makoto
Mar 25 at 4:18
Yeah, but here you can write your logic insideMyConditionclass.
– Aditya Gupta
Mar 25 at 5:02
@AdityaGupta ty. i edited you answer a bit. If I ask forenv.getProperty("tokens"), it always returns null. I have to give full property only then it actually returns a value instead of null.
– Faraz Durrani
Mar 25 at 5:57
Looks good. Thanks for updating.
– Aditya Gupta
Mar 25 at 17:42
add a comment |
You can use @Conditional(YourCondition.class)
Quoating from docs:
A single condition that must be matched in order for a component to be
registered. Conditions are checked immediately before the
bean-definition is due to be registered and are free to veto
registration based on any criteria that can be determined at that
point.
Illustration:
@Conditional(MyCondition.class)
@Controller
public class Box
...
public class MyCondition implements Condition
@Override
public boolean matches(ConditionContext context, AnnotatedTypeMetadata metadata)
Environment env = context.getEnvironment();
return null == env.getProperty("tokens.token[0].name");
Here, en.getProperty will return null in case of missing property.
edited Mar 25 at 5:58
Faraz Durrani
2,93421137
answered Mar 25 at 4:12
Aditya GuptaAditya Gupta
1,02721322
In theory,ConditionalOnPropertywould accomplish this.
– Makoto
Mar 25 at 4:18
Yeah, but here you can write your logic insideMyConditionclass.
– Aditya Gupta
Mar 25 at 5:02
@AdityaGupta ty. i edited you answer a bit. If I ask forenv.getProperty("tokens"), it always returns null. I have to give full property only then it actually returns a value instead of null.
– Faraz Durrani
Mar 25 at 5:57
Looks good. Thanks for updating.
– Aditya Gupta
Mar 25 at 17:42
add a comment |
You can use @Conditional(YourCondition.class)
Quoating from docs:
A single condition that must be matched in order for a component to be
registered. Conditions are checked immediately before the
bean-definition is due to be registered and are free to veto
registration based on any criteria that can be determined at that
point.
Illustration:
@Conditional(MyCondition.class)
@Controller
public class Box
...
public class MyCondition implements Condition
@Override
public boolean matches(ConditionContext context, AnnotatedTypeMetadata metadata)
Environment env = context.getEnvironment();
return null == env.getProperty("tokens.token[0].name");
Here, en.getProperty will return null in case of missing property.
edited Mar 25 at 5:58
Faraz Durrani
2,93421137
answered Mar 25 at 4:12
Aditya GuptaAditya Gupta
1,02721322
You can use @Conditional(YourCondition.class)
Quoating from docs:
A single condition that must be matched in order for a component to be
registered. Conditions are checked immediately before the
bean-definition is due to be registered and are free to veto
registration based on any criteria that can be determined at that
point.
Illustration:
@Conditional(MyCondition.class)
@Controller
public class Box
...
public class MyCondition implements Condition
@Override
public boolean matches(ConditionContext context, AnnotatedTypeMetadata metadata)
Environment env = context.getEnvironment();
return null == env.getProperty("tokens.token[0].name");
Here, en.getProperty will return null in case of missing property.
edited Mar 25 at 5:58
Faraz Durrani
2,93421137
answered Mar 25 at 4:12
Aditya GuptaAditya Gupta
1,02721322
edited Mar 25 at 5:58
Faraz Durrani
2,93421137
edited Mar 25 at 5:58
Faraz Durrani
2,93421137
edited Mar 25 at 5:58
Faraz Durrani
2,93421137
2,93421137
answered Mar 25 at 4:12
Aditya GuptaAditya Gupta
1,02721322
answered Mar 25 at 4:12
Aditya GuptaAditya Gupta
1,02721322
answered Mar 25 at 4:12
Aditya GuptaAditya Gupta
1,02721322
1,02721322
In theory,ConditionalOnPropertywould accomplish this.
– Makoto
Mar 25 at 4:18
Yeah, but here you can write your logic insideMyConditionclass.
– Aditya Gupta
Mar 25 at 5:02
@AdityaGupta ty. i edited you answer a bit. If I ask forenv.getProperty("tokens"), it always returns null. I have to give full property only then it actually returns a value instead of null.
– Faraz Durrani
Mar 25 at 5:57
Looks good. Thanks for updating.
– Aditya Gupta
Mar 25 at 17:42
add a comment |
In theory,ConditionalOnPropertywould accomplish this.
– Makoto
Mar 25 at 4:18
Yeah, but here you can write your logic insideMyConditionclass.
– Aditya Gupta
Mar 25 at 5:02
@AdityaGupta ty. i edited you answer a bit. If I ask forenv.getProperty("tokens"), it always returns null. I have to give full property only then it actually returns a value instead of null.
– Faraz Durrani
Mar 25 at 5:57
Looks good. Thanks for updating.
– Aditya Gupta
Mar 25 at 17:42
In theory,
ConditionalOnProperty would accomplish this.– Makoto
Mar 25 at 4:18
In theory,
ConditionalOnProperty would accomplish this.– Makoto
Mar 25 at 4:18
Yeah, but here you can write your logic inside
MyCondition class.– Aditya Gupta
Mar 25 at 5:02
Yeah, but here you can write your logic inside
MyCondition class.– Aditya Gupta
Mar 25 at 5:02
@AdityaGupta ty. i edited you answer a bit. If I ask for
env.getProperty("tokens"), it always returns null. I have to give full property only then it actually returns a value instead of null.– Faraz Durrani
Mar 25 at 5:57
@AdityaGupta ty. i edited you answer a bit. If I ask for
env.getProperty("tokens"), it always returns null. I have to give full property only then it actually returns a value instead of null.– Faraz Durrani
Mar 25 at 5:57
Looks good. Thanks for updating.
– Aditya Gupta
Mar 25 at 17:42
Looks good. Thanks for updating.
– Aditya Gupta
Mar 25 at 17:42
add a comment |
@Faraz Durrani try this concept you will get...
@Component
@EnableConfigurationProperties
@ConfigurationProperties(prefix = "tokens")
public class ServiceClass
private String token;
...
answered Mar 25 at 4:26
kumarkumar
274110
1
No Kumar this is totally off. Sorry.
– Faraz Durrani
Mar 25 at 6:00
i done a sample on this and it's working for me ...better to try this....
– kumar
Mar 25 at 9:27
yes I understand kumar. But my question is different. I think you misunderstood the question.
– Faraz Durrani
Mar 26 at 2:43
add a comment |
@Faraz Durrani try this concept you will get...
@Component
@EnableConfigurationProperties
@ConfigurationProperties(prefix = "tokens")
public class ServiceClass
private String token;
...
answered Mar 25 at 4:26
kumarkumar
274110
1
No Kumar this is totally off. Sorry.
– Faraz Durrani
Mar 25 at 6:00
i done a sample on this and it's working for me ...better to try this....
– kumar
Mar 25 at 9:27
yes I understand kumar. But my question is different. I think you misunderstood the question.
– Faraz Durrani
Mar 26 at 2:43
add a comment |
@Faraz Durrani try this concept you will get...
@Component
@EnableConfigurationProperties
@ConfigurationProperties(prefix = "tokens")
public class ServiceClass
private String token;
...
answered Mar 25 at 4:26
kumarkumar
274110
@Faraz Durrani try this concept you will get...
@Component
@EnableConfigurationProperties
@ConfigurationProperties(prefix = "tokens")
public class ServiceClass
private String token;
...
answered Mar 25 at 4:26
kumarkumar
274110
answered Mar 25 at 4:26
kumarkumar
274110
answered Mar 25 at 4:26
kumarkumar
274110
answered Mar 25 at 4:26
kumarkumar
274110
274110
1
No Kumar this is totally off. Sorry.
– Faraz Durrani
Mar 25 at 6:00
i done a sample on this and it's working for me ...better to try this....
– kumar
Mar 25 at 9:27
yes I understand kumar. But my question is different. I think you misunderstood the question.
– Faraz Durrani
Mar 26 at 2:43
add a comment |
1
No Kumar this is totally off. Sorry.
– Faraz Durrani
Mar 25 at 6:00
i done a sample on this and it's working for me ...better to try this....
– kumar
Mar 25 at 9:27
yes I understand kumar. But my question is different. I think you misunderstood the question.
– Faraz Durrani
Mar 26 at 2:43
1
1
No Kumar this is totally off. Sorry.
– Faraz Durrani
Mar 25 at 6:00
No Kumar this is totally off. Sorry.
– Faraz Durrani
Mar 25 at 6:00
i done a sample on this and it's working for me ...better to try this....
– kumar
Mar 25 at 9:27
i done a sample on this and it's working for me ...better to try this....
– kumar
Mar 25 at 9:27
yes I understand kumar. But my question is different. I think you misunderstood the question.
– Faraz Durrani
Mar 26 at 2:43
yes I understand kumar. But my question is different. I think you misunderstood the question.
– Faraz Durrani
Mar 26 at 2:43
add a comment |
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Why would you want to do that? It will be hard to maintain a property which is either present or absent. Programmer will have to go through the code to figure out what property to add for enabling. It would be better to have a second boolean property
tokenPresent.– Aditya Gupta
Mar 25 at 3:28
This is a very good advise. The trouble is, I am developing an application that will be added as a dependency in other projects. I don't want them to add unnecessary properties. You know what I mean?
– Faraz Durrani
Mar 25 at 3:32
Yeah. I did something like this few months back. Will add an answer now.
– Aditya Gupta
Mar 25 at 3:36